When a helical spring is cut into two halves, the stiffness of each half spring will be, (A) Same as original spring (B) Double of original spring (C) Half of original spring (D) One fourth of original spring

When a helical spring is cut into two halves, the stiffness of each half spring will be,

(A) Same as original spring

(B) Double of original spring

(C) Half of original spring

(D) One fourth of original spring
by

1 Answer

Answer :

(B) Double of original spring
by

Related questions

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The helix angle for double helical gears may be made up to (A) 45° (B) 60° (C) 75° (D) 90°

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A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

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A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

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Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

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Two close-coiled helical springs are equal in all respects except the number of turns. If the number of turns are in the ratio of 2:3, then the stiffness of the spring will be in the ratio of (a) 2:3 (b) 4:9 (c) 3:2 (d) 9:4

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Determine number of coils in a helical compression spring, if modulus of rigidity is 80 Gpa and spring stiffness is 50 N/ mm. Assume wire diameter and spring index as 8 mm and 5 respectively a. 11.8 turns b. 12.8 turns c. 13.3 turns d. None of the above

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If a close-coiled helical spring absorbs 50 N-mm of energy while extending by 5 mm, its stiffness will be (a) 2 N/mm (b) 4 N/mm (c) 6 N/mm (d) 10 N/mm

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A close-coiled helical spring of stiffness 30 N/mm is arranged in series with another such spring of stiffness 60 N/mm. The stiffness of composite unit is (a) 20 N/mm (b) 30 N/mm (c) 45 N/mm (d) 90 N/mm

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For two spring connected in series, the force acting on each spring is same and equal to half of the external force. a) True b) False

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If the initial volume of an ideal gas is compressed to one-half its original volume and to twice its original temperature, the pressure:  a. doubles  b. halves  c. quadruples  d. triples

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When two Belleville springs are in parallel, half force is obtained for a given deflection. a) Half force b) Double force c) Same force d) Can’t be determined

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The stiffness of solid shaft is more than the stiffness of hollow shaft with same weight. a) True b) False

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When two helical springs of equal lengths are arranged to form a cluster spring, then a. Shear stress in each spring will be equal b. Load taken by each spring will be half the total load c. Only A is correct d. Both A and B is correct

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The close-coiled helical springs ‘A’ and ‘B’ are of same material, same coil diameter, same wire diameter and subjected to same load. If the number of turns of spring ‘A’ is half that of spring ‘B’, the ratio of deflection of spring ‘A’ to spring ‘B’ is (a)1/2 (b) 1 (c) 2 (d) 4

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A helical spring of constant k is cut into four equal pieces and the four pieces are then combined in parallel. The equivalent spring constant will be (a) k/16 (b) k/4 (c) 4k (d) 16k

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Last Answer : (A) (4C - 1/4C - 4) + 0.615/C

For two springs in parallel, effective stiffness (k) is Where k 1 & k 2 are stiffness of springs 1 & 2 respectively (A) k 1 k 2 / (k 1 + k 2 ) (B) k 1 + k 2 (C) k 1 k 2 (D) (k 1 + k 2 ) / k 1 k 2

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Last Answer : (B) k 1 + k 2

For two springs in series, effective stiffness (k) is Where k 1 & k 2 are stiffness of springs 1 & 2 respectively (A) k 1 k 2 / (k 1 + k 2 ) (B) k 1 + k 2 (C) k 1 k 2 (D) (k 1 + k 2 ) / k 1 k 2

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Last Answer : (A) k 1 k 2 / (k 1 + k 2 )

Two springs of stiffness k1 and k2 are connected in series, the combined (A) k1k2/k1 + k2 (B) k1k2/k1 - k2 (C) k1 + k2 (D) k1 + k2/k1k2

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Last Answer : (A) k1k2/k1 + k2

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