An intersection is a point where two or more lines/curves meet or cross. How many intersections are there in the figure given below?

An intersection is a point where two or more lines/curves meet or cross. How many intersections are there in the figure given below? 

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AP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m (in the given figure). Show that AP || BQ. -Maths 9th

Description : AP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m (in the given figure). Show that AP || BQ. -Maths 9th

Last Answer : Given In the figure l || m, AP and BQ are the bisectors of ∠EAB and ∠ABH, respectively. To prove AP|| BQ Proof Since, l || m and t is transversal. Therefore, ∠EAB = ∠ABH [alternate interior ... ∠PAB and ∠ABQ are alternate interior angles with two lines AP and BQ and transversal AB. Hence, AP || BQ.

AP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m (in the given figure). Show that AP || BQ. -Maths 9th

Description : AP and BQ are the bisectors of the two alternate interior angles formed by the intersection of a transversal t with parallel lines l and m (in the given figure). Show that AP || BQ. -Maths 9th

Last Answer : Given In the figure l || m, AP and BQ are the bisectors of ∠EAB and ∠ABH, respectively. To prove AP|| BQ Proof Since, l || m and t is transversal. Therefore, ∠EAB = ∠ABH [alternate interior ... ∠PAB and ∠ABQ are alternate interior angles with two lines AP and BQ and transversal AB. Hence, AP || BQ.

Find the angle of intersection of the curves `x y=a^2a n dx^2+y^2=2a^2`

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A line passes through the point of intersection of the lines 100x + 50y – 1 = 0 and 75x + 25y + 3 = 0 and makes equal intercepts on the axes. -Maths 9th

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Last Answer : (d) x + 2y = 2Let the required equation make intercept on x-axis = 2a ⇒ intercept made on y-axis = a ∴ Eqn of the given line in the intercept from:\(rac{x}{2a}+rac{y}{a}=1\) ...(i)Since the line ... 1 ⇒ a = 1.∴ Required equation of line : \(rac{x}{2 imes1}+rac{y}{1}=1\) ⇒ x + 2y = 2.

Find the equation of the line which passes through the point of intersection of the lines 2x – y + 5 = 0 -Maths 9th

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Last Answer : (a) 45º 3x + y - 7 = 0 ⇒ y = -3x + 7 ⇒ Slope (m1) = -3 x + 2y + 9 = 0 ⇒ y = \(rac{-x}{2}\) - \(rac{9}{2}\) ⇒ Slope (m2) = \(-rac{1}{2}\)If θ is the angle between the given lines, then tan θ = \(\ ... \bigg|rac{-rac{5}{2}}{1+rac{3}{2}}\bigg|\)= \(\bigg|rac{-rac{5}{2}}{rac{5}{2}}\bigg|\) = 1∴ θ = 45°.

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Description : In a theodolite the line passing through the intersection of the horizontal and vertical cross hairs and the optical centre of the object glass and its continuation, is known as (a) Horizontal axis (b) Vertical axis (c) Line of collination (d) Line of sight (e) Either of c or d above*

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Find the equation of normals of the following curves at the given points: (i) Curve`y^(2)=4 ax" at point "(at^(2), 2at)`. (ii) Curve `y= e^(x)" at poi

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Find the equation of tangents of the following curves at the given points: (i) Curve`x^(2) = 25` at point (3, 4) (ii) Curve `y = 2x^(3) + 2x^(2) - 8x+

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Forces are called concurrent when their lines of action meet in (A) One point (B) Two points (C) Plane (D) Perpendicular planes

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When all the forces acting on a body lie in one plane and their lines of action meet at one point, the forces a.constitute a moment b.constitute a couple c.are known as coplaner-concurrent forces. d.are known as non-coplaner forces e.107 dynes

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Last Answer : c. are known as coplaner-concurrent forces.

The forces which meet at one point but their lines of action do not lie in one plane, are called a.Coplanar noncurrent forces b.Non-coplanar nonconcurrent forces c.Intersecting forces d.Coplanar concurrent forces e.

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A rigid body is in equilibrium under the action of these forces when a.These forces are equal b.The lines of action of these forces are parallel c.The lines of action of these forces meet in a point d.(A) and (B) above e.(B) and (C) above

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The forces, which meet at one point, but their lines of action do not lie in a plane, are called (A) Coplanar non-concurrent forces (B) Non-coplanar concurrent forces(C) Non-coplanar non-concurrent forces (D) Intersecting forces

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If a rigid body is in equilibrium under the action of three forces, then (A) These forces are equal (B) The lines of action of these forces meet in a point (C) The lines of action of these forces are parallel (D) Both (B) and (C) above

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Last Answer : (D) Both (B) and (C) above

The forces, which meet at one point, but their lines of action do not lie in a plane, are called?

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Find the equation of normal to the curves `x=t^2, y=2t+1` at point

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The torque and current curves for a three-phase induction motor with a cage rotor, are shown in the illustration. Which of the following statements is true concerning the depicted curves? EL-0056 A. As slip increases, rotor reactance decreases. B. The pullout point on the torque curve is about seven times the normal full load torque value. C. At stand still, stator current is 150% of normal. D. If the motor is loaded to the point where 40% slip has resulted, it will stall.

Description : The torque and current curves for a three-phase induction motor with a cage rotor, are shown in the illustration. Which of the following statements is true concerning the depicted curves? EL-0056 A. As slip ... D. If the motor is loaded to the point where 40% slip has resulted, it will stall.

Last Answer : Answer: D

Transition curves are introduced at either end of a circular curve, to obtain (A) Gradually decrease of curvature from zero at the tangent point to the specified quantity at the junction of the transition curve with main curve (B) Gradual increase of super-elevation from zero at the tangent point to the specified amount at the junction of the transition curve with main curve (C) Gradual change of gradient from zero at the tangent point to the specified amount at the junction of the transition curve with main curve (D) None of these

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Last Answer : (B) Gradual increase of super-elevation from zero at the tangent point to the specified amount at the junction of the transition curve with main curve

Which of the following is NOT closely associated with a non-magnetic Phase Diagram? w) Eutectic Temperature (pron: you-tek-tik) x) Curie Point y) Solidus z) Liquidus Curves

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A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : This answer was deleted by our moderators...

If circles are drawn taking two sides of a triangle as diameter, prove that the point of intersection of these circles lie on the third side. -Maths 9th

Description : If circles are drawn taking two sides of a triangle as diameter, prove that the point of intersection of these circles lie on the third side. -Maths 9th

Last Answer : Solution :- Given: Two circles are drawn on sides AB and AC of a △ABC as diameters. The circles intersects at D. To prove: D lies on BC Construction: Join A and D Proof: ∠ADB = 90° (Angle in the semi-circle ... + 90° => ∠ADB + ∠ADC = 180° => BDC is a straight line. Hence, D lies On third side BC.