The dimensional formula ML–1T–2 corresponds to –

The dimensional formula ML–1T–2 corresponds to –
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Answer :

Modulus of Elasticity
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The dimensional formula ML–1T –2 corresponds to (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Description : The dimensional formula ML–1T –2 corresponds to (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Last Answer : Modulus of elasticity

The dimensional formula ML⁻¹T⁻² corresponds to – (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Description : The dimensional formula ML⁻¹T⁻² corresponds to – (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Last Answer : (1) Modulus of elasticity Explanation: M Li- T-2 is the dimension of any quantity that is force per unit area such as Pressure or Stress, Young's Modulus, Bulk Modulus, Modulus of Rigidity, ... the ratio of the stress applied to a body or substance to the resulting strain within the elastic limit.

The dimensions of modulus of elasticity are a.MLT-2 b.107 dynes c.MLT-1 d.ML-2T-1 e.ML-1T-2

Description : The dimensions of modulus of elasticity are a.MLT-2 b.107 dynes c.MLT-1 d.ML-2T-1 e.ML-1T-2

Last Answer : e. ML-1T-2

Dimension of modulus of elasticity is (a) ML–2T–2 (b) M–1L–1T–2 (c) ML–1T–2 (d) ML–1T–1

Description : Dimension of modulus of elasticity is (a) ML–2T–2 (b) M–1L–1T–2 (c) ML–1T–2 (d) ML–1T–1

Last Answer : Ans:(c)

Te dimensions of frequency are a.107 dynes b.MLT c.L-1 d.T-1 e.L-1T-1

Description : Te dimensions of frequency are a.107 dynes b.MLT c.L-1 d.T-1 e.L-1T-1

Last Answer : d. T-1

Using force, length and time as fundamental quantities, the dimensions of mass would be a.FL-2T+2 b.FL-1T+2 c.FL-1T+1 d.107 dynes e.FL-2T+1

Description : Using force, length and time as fundamental quantities, the dimensions of mass would be a.FL-2T+2 b.FL-1T+2 c.FL-1T+1 d.107 dynes e.FL-2T+1

Last Answer : b. FL-1T+2

[L^1M^1T^-1] is an expression for __________.

Description : [L^1M^1T^-1] is an expression for __________.

Last Answer : [L1M1T-1] is an expression for __________. (A) force (B) energy (C) pressure (D) momentum

Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V 340/30; cruise: LRC, at FL330 outside air temperature -30C. Find estimated trip fuel and time. a. 4,800kg / 01hr 45min b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

Description : Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V ... b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

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Dimension of Rydberg constant is a) LT-1 b) L-1 c) (LT)-1 d) L-1T

Description : Dimension of Rydberg constant is a) LT-1 b) L-1 c) (LT)-1 d) L-1T

Last Answer : b) L-1

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Description : Is there a formula to find the center (center of mass/centroid) of 3 dimensional objects?

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Define dimensions and dimensional formula of physical quantities. Give few examples of dimensional formula.

Description : Define dimensions and dimensional formula of physical quantities. Give few examples of dimensional formula.

Last Answer : Define dimensions and dimensional formula of physical quantities. Give few examples of dimensional formula.

Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the permeability of the vacuum. If `M = m

Description : Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the permeability of the vacuum. If `M = m

Last Answer : Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the ... . `mu_(0) = [ML^(2)T^(-1)I]`

M L2 T–2 is the dimensional formula for (a) Moment of inertia (b) Pressure (c) Elasticity (d) Couple acting on a body

Description : M L2 T–2 is the dimensional formula for (a) Moment of inertia (b) Pressure (c) Elasticity (d) Couple acting on a body

Last Answer : Ans:(d)

The dimensional formula for universal gravitational constant is – (1) M⁻¹L³T² (2) ML²T⁻² (3) M⁻² (4) M⁻¹L³T⁻²

Description : The dimensional formula for universal gravitational constant is – (1) M⁻¹L³T² (2) ML²T⁻² (3) M⁻² (4) M⁻¹L³T⁻²

Last Answer : (4) M⁻¹L³T⁻² Explanation: Universal Constant of Gravitation is represented by G and is derived from Newton's law of gravitation.

The dimensional formula of bulk modulus of elasticity is same as that of the (A) Pressure (B) Density (C) Force (D) None of these

Description : The dimensional formula of bulk modulus of elasticity is same as that of the (A) Pressure (B) Density (C) Force (D) None of these

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The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp)`?

Description : The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp)`?

Last Answer : The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp ... )` C. `1.0xx10^(-15)` D. `6.0xx10^(-13)`

The formula to calculate maximum urea clearance is U V× B , where U denotes (A) Concentration of urea in urine in gm/24hr (B) Concentration of urea in urine in mg/100 ml (C) Concentration of urea in blood in mg/100 ml (D) Volume of urine in ml/mt

Description : The formula to calculate maximum urea clearance is U V× B , where U denotes (A) Concentration of urea in urine in gm/24hr (B) Concentration of urea in urine in mg/100 ml (C) Concentration of urea in blood in mg/100 ml (D) Volume of urine in ml/mt

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How do you get part of a url that corresponds only to the Google image that's picked?

Description : How do you get part of a url that corresponds only to the Google image that's picked?

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The dimension MLT⁻² corresponds to (1) force (2) work done (3) acceleration (4) velocity

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