M L2 T–2 is the dimensional formula for (a) Moment of inertia (b) Pressure (c) Elasticity (d) Couple acting on a body

M L2 T–2 is the dimensional formula for (a) Moment of inertia (b) Pressure (c) Elasticity (d) Couple acting on a body
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The dimensional formula ML⁻¹T⁻² corresponds to – (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Description : The dimensional formula ML⁻¹T⁻² corresponds to – (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Last Answer : (1) Modulus of elasticity Explanation: M Li- T-2 is the dimension of any quantity that is force per unit area such as Pressure or Stress, Young's Modulus, Bulk Modulus, Modulus of Rigidity, ... the ratio of the stress applied to a body or substance to the resulting strain within the elastic limit.

The dimensional formula ML–1T –2 corresponds to (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Description : The dimensional formula ML–1T –2 corresponds to (1) Modulus of elasticity (2) Viscosity (3) Moment of a force (4) Thrust

Last Answer : Modulus of elasticity

Euler's formula states that the buckling load for a column of length , both ends hinged and whose least moment of inertia and modulus of elasticity of the material of the column are and respectively, is given by the relation (A) P = ²EI/l² (B) P = /EI (C) P = /l² (D) P = ²EI/l

Description : Euler's formula states that the buckling load for a column of length , both ends hinged and whose least moment of inertia and modulus of elasticity of the material of the column are and respectively, is given by the relation (A) P = ²EI/l² (B) P = /EI (C) P = /l² (D) P = ²EI/l

Last Answer : (A) P = ²EI/l²

If M, I, R, E, F, and Y are the bending moment, moment of inertia, radius of curvature, modulus of elasticity stress and the depth of the neutral axis at section, then (A) M/I = R/E = F/Y (B) I/M = R/E = F/Y (C) M/I = E/R = E/Y (D) M/I = E/R = Y/F

Description : If M, I, R, E, F, and Y are the bending moment, moment of inertia, radius of curvature, modulus of  elasticity stress and the depth of the neutral axis at section, then  (A) M/I = R/E = F/Y (B) I/M = R/E = F/Y (C) M/I = E/R = E/Y (D) M/I = E/R = Y/F

Last Answer : (C) M/I = E/R = E/Y

The dimensional formula of bulk modulus of elasticity is same as that of the (A) Pressure (B) Density (C) Force (D) None of these

Description : The dimensional formula of bulk modulus of elasticity is same as that of the (A) Pressure (B) Density (C) Force (D) None of these

Last Answer : Option A

A couple consists of a force P acting at a point A whose coordinates are (-1,2,4) m and force - F acting at a point whose coordinates are (2,3, -2)m. If F = 3i + 2j - 4k in kg units the moment of the couple in kg - m units would be a.8i - 6j - 3k b.12i - 3j + k c.16i - 12j - 6k d.4i - 3j + k e.8i + 5j + 3k

Description : A couple consists of a force P acting at a point A whose coordinates are (-1,2,4) m and force - F acting at a point whose coordinates are (2,3, -2)m. If F = 3i + 2j - 4k in kg units the moment of the couple in kg - m ... .8i - 6j - 3k b.12i - 3j + k c.16i - 12j - 6k d.4i - 3j + k e.8i + 5j + 3k

Last Answer : a. 8i - 6j - 3k

When all the forces acting on a body lie in one plane and their lines of action meet at one point, the forces a.constitute a moment b.constitute a couple c.are known as coplaner-concurrent forces. d.are known as non-coplaner forces e.107 dynes

Description : When all the forces acting on a body lie in one plane and their lines of action meet at one point, the forces a.constitute a moment b.constitute a couple c.are known as coplaner-concurrent forces. d.are known as non-coplaner forces e.107 dynes

Last Answer : c. are known as coplaner-concurrent forces.

A single force and a couple acting in the same plane upon a rigid body (A) Balance each other (B) Cannot balance each other (C) Produce moment of a couple (D) Are equivalent

Description : A single force and a couple acting in the same plane upon a rigid body  (A) Balance each other  (B) Cannot balance each other  (C) Produce moment of a couple  (D) Are equivalent 

Last Answer : (B) Cannot balance each other 

The torque acting on a system is zero. Which of the following will be conserved? a.Angular velocity b.Linear momentum c.107 dynes d.Angular momentum e.Moment of inertia

Description : The torque acting on a system is zero. Which of the following will be conserved? a.Angular velocity b.Linear momentum c.107 dynes d.Angular momentum e.Moment of inertia

Last Answer : d. Angular momentum

What is the moment of inertia acting on a semicircle of radius 20 mm about the asymmetrical axes? a. 125.663 x 103 mm4 b. 17600 mm4 c. 1500 mm4 d. 8800 mm4

Description : What is the moment of inertia acting on a semicircle of radius 20 mm about the asymmetrical axes? a. 125.663 x 103 mm4 b. 17600 mm4 c. 1500 mm4 d. 8800 mm4

Last Answer : b. 17600 mm4

What is the moment of inertia acting on a circle of diameter 50 mm? a. 122.71 x 103 mm4 b. 306.79 x 103 mm4 c. 567.23 x 103 mm4 d. 800 x 103 mm4

Description : What is the moment of inertia acting on a circle of diameter 50 mm? a. 122.71 x 103 mm4 b. 306.79 x 103 mm4 c. 567.23 x 103 mm4 d. 800 x 103 mm4

Last Answer : b. 306.79 x 103 mm4

What is the moment of inertia acting on a rectangle of width 15 mm and depth 40 mm about base by using theorem of parallel axes? a. 320 x 103 mm4 b. 300 x 103 mm4 c. 240 x 103 mm4 d. 80 x 103 mm

Description : What is the moment of inertia acting on a rectangle of width 15 mm and depth 40 mm about base by using theorem of parallel axes? a. 320 x 103 mm4 b. 300 x 103 mm4 c. 240 x 103 mm4 d. 80 x 103 mm

Last Answer : a. 320 x 103 mm4

Moment of inertia acting on a semi-circle about symmetrical axes is given as _______ a. 1.57 r4 b. 0.055 r4 c. 0.392 r4 d. 0.11 r4

Description : Moment of inertia acting on a semi-circle about symmetrical axes is given as _______ a. 1.57 r4 b. 0.055 r4 c. 0.392 r4 d. 0.11 r4

Last Answer : c. 0.392 r4

If the positive and negative shear force diagram areas are not equal, it can be concluded that a.shear force diagram has been wrongly drawn b.there is at least one couple acting on the beam c.107 dynes d.there are at least two maxima for bending moment e.bending moment does not change sign

Description : If the positive and negative shear force diagram areas are not equal, it can be concluded that a.shear force diagram has been wrongly drawn b.there is at least one couple acting on the beam c.107 dynes d.there are at least two maxima for bending moment e.bending moment does not change sign

Last Answer : b. there is at least one couple acting on the beam

Two non-collinear parallel equal forces acting in opposite direction (A) Balance each other (B) Constitute a moment (C) Constitute a couple (D) Constitute a moment of couple

Description : Two non-collinear parallel equal forces acting in opposite direction  (A) Balance each other  (B) Constitute a moment  (C) Constitute a couple  (D) Constitute a moment of couple 

Last Answer : (C) Constitute a couple 

A sudden jump anywhere on the Bending moment diagram of a beam is caused by (a) Couple acting at that point (b) Couple acting at some other point (c) Concentrated load at the point (d) Uniformly distributed load or Uniformly varying load on the beam

Description : A sudden jump anywhere on the Bending moment diagram of a beam is caused by (a) Couple acting at that point (b) Couple acting at some other point (c) Concentrated load at the point (d) Uniformly distributed load or Uniformly varying load on the beam

Last Answer : (a) Couple acting at that point

A system exhibiting S.H.M. must possess – (1) Elasticity as well as inertia (2) Elasticity, inertia and an external force (3) Elasticity only (4) Inertia only

Description : A system exhibiting S.H.M. must possess – (1) Elasticity as well as inertia (2) Elasticity, inertia and an external force (3) Elasticity only (4) Inertia only

Last Answer : (1) Elasticity as well as inertia Explanation: Basic conditions to execute simple harmonic motion are: (i) There must be an elastic restoring force acting on the system, (ii) the system ... of the system should be directly proportional to its displacement and is always directed to mean position.

A system exhibiting S.H.M. must possess (1) Elasticity as well as inertia (2) Elasticity, inertia and an external force (3) Elasticity only (4) Inertia only

Description : A system exhibiting S.H.M. must possess (1) Elasticity as well as inertia (2) Elasticity, inertia and an external force (3) Elasticity only (4) Inertia only

Last Answer : Elasticity as well as inertia

Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2

Description : Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2

Last Answer : d. mr 2

Calculate the moment of inertia about the axis parallel to welds and shift it to CG by considering thickness of welds t. a) tɜ+2000t b) None of the listed c) 250000 t d) 125000 t

Description : Calculate the moment of inertia about the axis parallel to welds and shift it to CG by considering thickness of welds t. a) tɜ+2000t b) None of the listed c) 250000 t d) 125000 t

Last Answer : c) 250000 t

Newton's second law states that the net force acting on a body is equal to the body's time rate of change of: w) acceleration x) mass y) momentum z) inertia

Description : Newton's second law states that the net force acting on a body is equal to the body's time rate of change of: w) acceleration x) mass y) momentum z) inertia

Last Answer : ANSWER: Y -- MOMENTUM

Burge formula Q = 19.6 (A/L2/3) cumecs is based upon (A) Rainfall and drainage area (B) Run off and drainage area (C) Drainage area and its shape (D) Drainage area

Description : Burge formula Q = 19.6 (A/L2/3) cumecs is based upon (A) Rainfall and drainage area (B) Run off and drainage area (C) Drainage area and its shape (D) Drainage area

Last Answer : Answer: Option C

Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the permeability of the vacuum. If `M = m

Description : Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the permeability of the vacuum. If `M = m

Last Answer : Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the ... . `mu_(0) = [ML^(2)T^(-1)I]`

A single force and a couple acting in the same plane upon a rigid body?

Description : A single force and a couple acting in the same plane upon a rigid body?

Last Answer : A single force and a couple acting in the same plane upon a rigid body cannot balance each other.

The units of moment of inertia are a.kgm4 b.kg-m2 c.kg/m2 d.kg/m e.m4

Description : The units of moment of inertia are a.kgm4 b.kg-m2 c.kg/m2 d.kg/m e.m4

Last Answer : c. kg/m2

The units of moment of inertia of an area are a.kg - m b.m4 c.kg - m4 d.kg - m3 e.(kg - m)2

Description : The units of moment of inertia of an area are a.kg - m b.m4 c.kg - m4 d.kg - m3 e.(kg - m)2

Last Answer : b. m4

Calculate the Polar moment of inertia in m 4 of a single motor system from the following data: C = 8 GN/m 2 , L=9m, I = 600 Kg-m 2 , f=10 Hz a) 0.00027b) 0.00032 c) 0.00045 d) 0.00078

Description : Calculate the Polar moment of inertia in m 4 of a single motor system from the following data: C = 8 GN/m 2 , L=9m, I = 600 Kg-m 2 , f=10 Hz a) 0.00027b) 0.00032 c) 0.00045 d) 0.00078

Last Answer : a) 0.00027

The units of moment of inertia of mass are (A) kg m² (B) m 4 (C) kg/m² (D) kg/m

Description : The units of moment of inertia of mass are  (A) kg m²  (B) m 4  (C) kg/m²  (D) kg/m 

Last Answer : (A) kg m² 

The units of moment of inertia of an area are (A) kg m² (B) m 4 (C) kg/m² (D) m

Description : The units of moment of inertia of an area are  (A) kg m²  (B) m 4  (C) kg/m²  (D) m

Last Answer : (B) m 4 

If Z and I are the section modulus and moment of inertia of the section, the shear force F and bending moment M at a section are related by (A) F = My/I (B) F = M/Z (C) F = dM/dx (D) F Mdx

Description : If Z and I are the section modulus and moment of inertia of the section, the shear force F and bending moment M at a section are related by (A) F = My/I (B) F = M/Z (C) F = dM/dx (D) F Mdx

Last Answer : (C) F = dM/dx

A 8 metre long simply supported rectangular beam which carries a distributed load 45 kg/m. experiences a maximum fibre stress 160 kg/cm2 . If the moment of inertia of the beam is 640 cm4 , the overall depth of the beam is (A) 10 cm (B) 12 cm (C) 15 cm (D) 18 cm

Description : A 8 metre long simply supported rectangular beam which carries a distributed load 45 kg/m. experiences a maximum fibre stress 160 kg/cm2 . If the moment of inertia of the beam is 640 cm4 , the overall depth of the beam is (A) 10 cm (B) 12 cm (C) 15 cm (D) 18 cm

Last Answer : (A) 10 cm

The horizontal angles from the boat between A and B and B and C, the stations on the shore are 1 2. The distances AB = L1 and BC = L2 2 at C between the boat and station B between A and C at B). (A) 1 2) = (L2 1/L1 2) = K (B) t 2 = 360° - 1 2 (C) 2 = sin /(K + ) (D) All the above

Description : The horizontal angles from the boat between A and B and B and C, the stations on the shore are 1 2. The distances AB = L1 and BC = L2 2 at C between the boat and station B between A and C at B). (A) 1 2) = (L2 1/L1 2) = K (B) t 2 = 360° - 1 2 (C) 2 = sin /(K + ) (D) All the above

Last Answer : (D) All the above

A beam of length L is pinned at both ends and is subjected to a concentrated bending couple of moment M at its centre. The maximum bending moment in the beam is (A) M (B) M/2 (C) M/3 (D) ML/2

Description : A beam of length L is pinned at both ends and is subjected to a concentrated bending couple of  moment M at its centre. The maximum bending moment in the beam is  (A) M (B) M/2  (C) M/3  (D) ML/2 

Last Answer : (A) M

The relationship among twisting moment(T) acting on a rotating shaft, power in watt(W), and angular velocity in radian per second(w) will be (a) T = W/w (b) W = Tw (c) W = T/w (d) none of these

Description : The relationship among twisting moment(T) acting on a rotating shaft, power in watt(W), and angular velocity in radian per second(w) will be (a) T = W/w (b) W = Tw (c) W = T/w (d) none of these

Last Answer : (b) W = Tw

Which of the following pair will have identical dimensions? a.Pressure and surface tension b.Work and kinetic energy c.Momentum and force d.Moment of inertia and angular momentum e.None of the above

Description : Which of the following pair will have identical dimensions? a.Pressure and surface tension b.Work and kinetic energy c.Momentum and force d.Moment of inertia and angular momentum e.None of the above

Last Answer : c. Momentum and force

The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where IG = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface, and x = Depth of centre of gravity of the immersed surface from the liquid surface) (A) (IG/ ) - (B) (IG/ ) - (C) ( /IG) + (D) (IG/ ) +

Description : The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where IG = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface, ... (IG/ ) - (B) (IG/ ) - (C) ( /IG) + (D) (IG/ ) +

Last Answer : Answer: Option D

The ratio of moment of inertia of a circular body about x axis to that about y axis is a.? b.? c.1?4 d.1 e.

Description : The ratio of moment of inertia of a circular body about x axis to that about y axis is a.? b.? c.1?4 d.1 e.

Last Answer : e. 1

The moment of inertia of a body does not depend upon a.The angular velocity of the body b.Mass of the body c.The distribution of mass in the body d.The axis of rotation of the body e.None of the above

Description : The moment of inertia of a body does not depend upon a.The angular velocity of the body b.Mass of the body c.The distribution of mass in the body d.The axis of rotation of the body e.None of the above

Last Answer : a. The angular velocity of the body

The moment of inertia of a body does not depend upon its – (1) axis of rotation (2) angular velocity (3) form of mass (4) distribution of mass

Description : The moment of inertia of a body does not depend upon its – (1) axis of rotation (2) angular velocity (3) form of mass (4) distribution of mass

Last Answer : (2) angular velocity Explanation: Moment of inertia is the mass property of a rigid body that determines the torque needed for a desired angular acceleration about an axis of rotation. Moment of inertia ... of moments of inertia of the masses making up the whole object, under the same conditions.

In linear motion, the energy is given by 1⁄2mv2. Similarly, in rotational motion, the rotational energy is given by A. 1/2 × I × ω; where I: moment of inertia of the body, ω: angular velocity B. 1/2 × I² × ω; where I: moment of inertia of the body, ω: angular velocity C. 1/2 × I × ω²; where I: moment of inertia of the body, ω: angular velocity D. 1/2 × I² × ω²; where I: moment of inertia of the body, ω: angular velocity

Description : In linear motion, the energy is given by 1⁄2mv2. Similarly, in rotational motion, the rotational energy is given by A. 1/2 I ω; where I: moment of inertia of the body, ω: angular velocity B. 1/ ... angular velocity D. 1/2 I² ω²; where I: moment of inertia of the body, ω: angular velocity

Last Answer : 1/2 × I × ω²; where I: moment of inertia of the body, ω: angular velocity

Total angular momentum of a body is given by A. I × ω; where I: moment of inertia of the body, ω: angular velocity B. I² × ω; where I: moment of inertia of the body, ω: angular velocity C. I² × ω²; where I: moment of inertia of the body, ω: angular velocity D. I × ω²; where I: moment of inertia of the body, ω: angular velocity

Description : Total angular momentum of a body is given by A. I ω; where I: moment of inertia of the body, ω: angular velocity B. I² ω; where I: moment of inertia of the body, ω: angular velocity C. I² ... the body, ω: angular velocity D. I ω²; where I: moment of inertia of the body, ω: angular velocity

Last Answer : I × ω; where I: moment of inertia of the body, ω: angular velocity

The moment of inertia of a body does not depend upon its (1) axis of rotation (2) angular velocity (3) form of mass (4) distribution of mass

Description : The moment of inertia of a body does not depend upon its (1) axis of rotation (2) angular velocity (3) form of mass (4) distribution of mass

Last Answer : angular velocity

If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Description : If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Last Answer : cosec(A) - sin(A) = l ⇒ 1/sin(A) - sin(A) = l ⇒ l² = 1/sin²(A) + sin²(A) - 2 --------- sec(A) - cos(A) = m ⇒ 1/cos(A) - cos(A) = m ⇒ m² = 1/cos²(A) + cos²(A) - 2 ---------- l²m² = [1/sin²(A) + ... A)) = = 1/(sin²(A)cos²(A)) ------------- ⇒ l²m² (l² + m² + 3) = sin²(A)cos²(A) / [sin²(A)cos²(A)] = 1

When an operating motor is connected to the controller shown in the illustration, the a path of current flow through the circuit is ____________. EL-0010 A. 'L1', stop button, start button, coil 'CR', 'L2' B. 'L1', stop button, 'CR' and 'M' contacts, 'M' coil, 'OL contacts, the 'CR' coil in parallel, 'L2' C. 'L1', stop button, jog button, 'CR' contact, 'CR' relay, 'L2' D. 'L1', stop button, start button, 'CR' contact, 'M' contact, 'CR' coil, 'L2'

Description : When an operating motor is connected to the controller shown in the illustration, the a path of current flow through the circuit is ____________. EL-0010 A. 'L1', stop button, start button, coil 'CR', 'L2' B. 'L1' ... L2' D. 'L1', stop button, start button, 'CR' contact, 'M' contact, 'CR' coil, 'L2'

Last Answer : Answer: B

The moment of a force is a.Equivalent to the algebraic sum of the moments acting on a body b.Equivalent to the sum of horizontal as well as vertical components of the moments on a body c.Equivalent to the sum of the moments acting on a body d.Equivalent to the sum of horizontal components of the moments on a body e.Equivalent to the vertical sum of the moments acting on a body

Description : The moment of a force is a.Equivalent to the algebraic sum of the moments acting on a body b.Equivalent to the sum of horizontal as well as vertical components of the moments on a body c.Equivalent ... of the moments on a body e.Equivalent to the vertical sum of the moments acting on a body

Last Answer : a. Equivalent to the algebraic sum of the moments acting on a body

Is there a formula to find the center (center of mass/centroid) of 3 dimensional objects?

Description : Is there a formula to find the center (center of mass/centroid) of 3 dimensional objects?

Last Answer : Yes

Define dimensions and dimensional formula of physical quantities. Give few examples of dimensional formula.

Description : Define dimensions and dimensional formula of physical quantities. Give few examples of dimensional formula.

Last Answer : Define dimensions and dimensional formula of physical quantities. Give few examples of dimensional formula.

The dimensional formula for universal gravitational constant is – (1) M⁻¹L³T² (2) ML²T⁻² (3) M⁻² (4) M⁻¹L³T⁻²

Description : The dimensional formula for universal gravitational constant is – (1) M⁻¹L³T² (2) ML²T⁻² (3) M⁻² (4) M⁻¹L³T⁻²

Last Answer : (4) M⁻¹L³T⁻² Explanation: Universal Constant of Gravitation is represented by G and is derived from Newton's law of gravitation.

The dimensional formula ML–1T–2 corresponds to –

Description : The dimensional formula ML–1T–2 corresponds to –

Last Answer : Modulus of Elasticity

As the train starts moving, a man sitting inside leans backwards because of (a) Inertia of rest (b) Inertia of motion (c) Moment of inertia (d) Conservation of mass

Description : As the train starts moving, a man sitting inside leans backwards because of (a) Inertia of rest (b) Inertia of motion (c) Moment of inertia (d) Conservation of mass

Last Answer : Ans:(a)