A, B and C play cricket. A's runs are to B's runs and B's runs are to C's as 3:2 , 3:2. They get altogether 342 runs. How many runs did A make? A) 162 B) 108 C) 72 D) 78 E) None

A, B and C play cricket. A's runs are to B's runs and B's runs are to C's as 3:2 , 3:2. They get altogether 342 runs. How many runs did A make? A) 162 B) 108 C) 72 D) 78 E) None
by

1 Answer

Answer :

Answer: A

A:B = 3:2 = 9:6;

B:C = 3:2 = 6:4 (making B equal)

Therefore, A:B:C = 9:6:4

Therefore, the runs made by A = (9/19) X 342 = 162.
by

Related questions

If a certain amount X is divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/3 of what C gets, which of the following is true A) C’s Share = 1053 and X = 1666 B) A’s Share = 238 and X = 1638 C) B’s Share = 234 and X = 1666 D) C’s Share = 1053 and X = 1638 E) A’s Share = 351 and X = 1638

Description : If a certain amount X is divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/3 of what C gets, which of the following is true A) C's Share = 1053 and X = 1666 B) A's Share = ... s Share = 234 and X = 1666 D) C's Share = 1053 and X = 1638 E) A's Share = 351 and X = 1638

Last Answer : Answer: D A= 2/3 B; B= 1/3C; A:B = 2:3 ; B:C = 1:3; A:B:C = 2:3:9 C = 9/14 * 1638 = 1053 X=1638

Rs.432 is divided amongst three workers A, B and C such that 8 times A’s share is equal to 12 times B’s share which is equal to 6 times C’s share. How much did A get? A) Rs.192 B) Rs.133 C) Rs.144 D) Rs.128 E) None

Description : Rs.432 is divided amongst three workers A, B and C such that 8 times A’s share is equal to 12 times B’s share which is equal to 6 times C’s share. How much did A get? A) Rs.192 B) Rs.133 C) Rs.144 D) Rs.128 E) None

Last Answer : Answer: C 8 times AA's share = 12 times BB's share = 6 times CC's share Note that this is not the same as the ratio of their wages being 8:12:68:12:6 In this case, find out the L.C.M of 8, 12 and 6 and divide ... 2x + 4x = 432 => 9x = 432 or x = 48. Hence, A who gets 3x will get 3 * 48 = Rs.144.

A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Description :  A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Last Answer : Answer: B 25 paise = 25/100 Rs, 50 paise = 50/100 Rs So value ratio of these coins become = 3*(25/100) : 4*(50/100) : 6*(1) = 3/4 : 2 : 6 = 3 : 8 : 24 So 25 paise coins value= [3/(3+8+24)] * ... 100/50) = 144 So 1 paise coins value= [24/(3+8+24)] * 315 = Rs 216, so coins = 215 * (100/100) = 216

Rs 5750 is divided among A, B, and C such that if their share be reduced by Rs 10, Rs 15 and Rs 25 respectively, the reminder amounts with them shall be in the ratio 4 : 6 : 9. What was C’s share then? A) Rs 2700 B) Rs 2725 C) Rs 2750 D) Rs 2625 E) None of these

Description : Rs 5750 is divided among A, B, and C such that if their share be reduced by Rs 10, Rs 15 and Rs 25 respectively, the reminder amounts with them shall be in the ratio 4 : 6 : 9. What was C’s share then? A) Rs 2700 B) Rs 2725 C) Rs 2750 D) Rs 2625 E) None of these

Last Answer : Answer: B When the shares reduce, the total amount will also reduce which is to be divided among them. So after reducing shares by Rs 10, Rs 15 and Rs 25 respectively, total amount is 5750 - (10+15+25) = ... share shall be [9/(4+6+9)] * 5700 = 2700 Actually C would have received = 2700 + 25=2725

Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by ‘A’ is Rs 40,000, out of a total annual profit of Rs 33,000, C’s share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Description : Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by A' is Rs 40,000, out of a total annual ... share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Last Answer : Answer: A Sum invested by A , B and C is 5 * 12:7 * 12:6 * 6 + 3 * 6 or 60 : 84 : 54 or 10 : 14 : 9 :: Share of C = ( 9 / 33 ) * 33000 = Rs. 9000

A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share? A) Rs. 500 B) Rs. 1500 C) Rs. 2000 D) Rs.2500 E) NONE

Description : A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share? A) Rs. 500 B) Rs. 1500 C) Rs. 2000 D) Rs.2500 E) NONE

Last Answer : Answer: C Let the shares of A, B, C, D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x−3x=1000 ⇒x=1000. B's share =Rs.2x=Rs.(2×1000)= Rs. 2000

One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE

Description : One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE

Last Answer : Answer: B Given, the Ratio of A's last year and present year salary = 3:5. Let salary be 3x and 5x respectively. Also, the Ratio of B's in last year and present year salary = 2:3 Let salary be 2y and 3y ... i) and (ii), we get :- y=1200 and x=640. Hence, A's present salary is 5x=5 640=3200.

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Description : 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C ... . What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Last Answer : Answer: B A : B : C : D 2*2*3 : 3*2*3 : 3*5*3 : 3*5*4 4 : 6 : 15 : 20 B and C together = [(6+15)/(4+6+15+20)] * 180 = 84

The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%

Description : The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%

Last Answer : Answer: B If 20% of boys and 45% of girls come by bus, then 80% of boys and 55% of girls opt transport other than bus. Let total number of students in school = x So boys who opt other transport are (80/100) * 6/(6+5 ... (24x/55) + (x/4) = 151x/220 So required % = [(151x/220)/x] * 100 = 68 7/11 %

The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Description : The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Last Answer : Answer: A A/B = 15/16 and B/C = 17*18 So A : B : C = 15*17 : 16*17 : 16*18 = 255 : 272 : 288 So C’s salary = [288/(255+272+288)] * 1,87,450= Rs 66,240

A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Description : A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

Last Answer : Answer: B Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. ∴ 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 ⇒ 2k + 1.50k + 1.25k = 114  ⇒ 4.75k = 114 ⇒ k = 24. 50 paise value = 1.5x = 1.5*24 = 36

A cricket player had a certain average of runs for his 43 innings. In his 44th innings, he is bowled out for no score on his part. This brings down his average by 4runs. His new average of runs is ? A) 172 B) 182 C) 166 D) 162

Description : A cricket player had a certain average of runs for his 43 innings. In his 44th innings, he is bowled out for no score on his part. This brings down his average by 4runs. His new average of runs is ? A) 172 B) 182 C) 166 D) 162

Last Answer : A) Let the cricket player’s average of runs for his 43 innings be X runs. Total number of runs in 43innings=43x According to the question, [43x + 0]/ 44= x-4 43x = 44x – 176 x = 176 new average of runs = 176-4 =>172

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

How is solution for LCM of 108 135 162 is?

Description : How is solution for LCM of 108 135 162 is?

Last Answer : 1620

Brother A and B had some savings in the ratio 5:6. They decided to buy a gift for their sister, sharing the cost in the ratio 4:5. After they bought, A is left with three-fourth of his amount, while B is left with Rs.497. Then, the value of the gift is a) 215 b) 115 c) 315 d) 415 e) None of these

Description : Brother A and B had some savings in the ratio 5:6. They decided to buy a gift for their sister, sharing the cost in the ratio 4:5. After they bought, A is left with three-fourth of his amount, while B is left with Rs.497. Then, the value of the gift is a) 215 b) 115 c) 315 d) 415 e) None of these

Last Answer : Answer: C Let the savings of A and B are 5x, 6x and the share cost of gift are 4y, 5y respectively. According to question, For A, 5x-4y=3/4×5x =>x=16y/5 For B, 6x-5y=497 =>6×16y/5-5y=497 =>y=35 Cost of gift=4y+5y=9×35 =315

Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 11 : 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360

Description : Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that ... 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360

Last Answer : Answer: A Let the sums of money received by A, B and C be x, y and z respectively. Then x - 10 : y - 20 : z -15 is 11a : 18a : 24a When $10, $20 and $15 are removed, we are removing a total of $45 from ... or a= 20 We know that z - 15 = 24a = (24 * 20) = 480 Therefore, z = 480 + 15 = $495

If I get Bs and Cs in high school, am I still going to be able to get into a decent college?

Description : If I get Bs and Cs in high school, am I still going to be able to get into a decent college?

Last Answer : answer:Talk to a guidance counselor. Do they have them at your school? Here is the school’s admission webpage: http://www.berklee.edu/admissions/general/admissions_requirements.html I edited and added this also: http://www.berklee.edu/admissions/general/audition_interview.html

Three active partners A, B, C start a work. Twice of A's capital is equal to 6 times of B's capital is nine times C's capital. If B's profit is Rs. 7500. Then find the total profit. a) 30750 b) 30833 c) 45250 d) 32745

Description : Three active partners A, B, C start a work. Twice of A's capital is equal to 6 times of B's capital is nine times C's capital. If B's profit is Rs. 7500. Then find the total profit. a) 30750 b) 30833 c) 45250 d) 32745

Last Answer : Answer: B) The capital of C be y. The capital of B be 9y. The capital of A be 54y/2 = 27y Ratio of A:B:C =27y:9y:y Total =7500/9*37=Rs 30833.

3 partners A , B, C starts a business. 4 times of A's capital is equal to 6 times of B's Capital and B's Capital is 8 times of C's capital if profit of B is Rs.6300. Then find the average profit A and C A) 7000.50 B) 5118.75 C) 4475.25 D) none

Description : 3 partners A , B, C starts a business. 4 times of A's capital is equal to 6 times of B's Capital and B's Capital is 8 times of C's capital if profit of B is Rs.6300. Then find the average profit A and C A) 7000.50 B) 5118.75 C) 4475.25 D) none

Last Answer : Answer: B)  Let the capital of C be y  Let the capital of B be 8y  Let the capital of A be 48y/4=12y  Ratio of their profit is ,  A:B:C = 12y : 8y :y  =12:8:1  Total of A&C =6300/8 *13  =Rs .10237.5  Average profit of A&C  =10237.5/2 =Rs.5118.75

Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Description : Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Last Answer : Answer: E Brass in A = 3/5 * 50 = 30 kg, Brass in B = 4/7 * 70 = 40 kg Total brass = 30+40 = 70 kg So copper in mixture is (50+70) – 70 = 50 kg So copper to brass = 50 : 70=5:7

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Description : Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Last Answer : Answer: B Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100=54.8%

The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen.Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Description : The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen. Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Last Answer : Answer: A P present age = 33-9 = 24 M = 24 – 9 =15 D – M = 24 D – 15 = 24 D = 24+15 = 39 15:39 = 5:13 X = 13

Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Description : Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Last Answer : Answer: A milk = 7/9 and water = 2/9 – in 1st vessel milk = 4/9 and water = 5/9 – in 2nd vessel (7/9 + 4/9)/ (2/9 + 5/9) = 11:7

If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Description :  If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Last Answer : Answer: C [ b – (40/100)a] = (3/5)b. So we get a = b. 1:1

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these

Description : Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these 

Last Answer : Answer: D F/2 = S/3= T/6 T = 2S = 3F F + S + T = 1870 T( 1/3 +1/2 + 1 ) = 1870 T= 1870 x 6/11 = 170 x 6 = 1020 Or the third part is a multiple of 6 and is large

A sum of 12600 is to be distributed between A, B and C. For every rupee A gets, B gets 80p and for every rupee B gets, C get 90 paise. Find the amount get by C. A) 3200 B) 3600 C) 4200 D) 4600 E) None of these

Description : A sum of 12600 is to be distributed between A, B and C. For every rupee A gets, B gets 80p and for every rupee B gets, C get 90 paise. Find the amount get by C. A) 3200 B) 3600 C) 4200 D) 4600 E) None of these

Last Answer : Answer: B Ratio of money between A and B – 100:80 and that of B and C – 100:90 so the ratio between A : B :C – 100:80:72 so 252x = 12600, x = 50. So C get = 50*72 = 3600

The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Description : The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Last Answer : Answer: A a^2 + b^2 + c^2 = 5000 a:b:c = 3:4:5 50x^2 = 5000. X = 10. 5x – 3x = 2*10 = 20

One year ago the ratio between rahul salary and rohit salary is 4:5. The ratio between their individual salary of the last year and current year is 2:3 and 3:5 respectively. If the total current salary of rahul and rohit is 4300. Then find the current salary of rahul. a) 1200 b) 1800 c) 2400 d) 3600 e) None of these

Description : One year ago the ratio between rahul salary and rohit salary is 4:5. The ratio between their individual salary of the last year and current year is 2:3 and 3:5 respectively. If the total current salary of rahul ... find the current salary of rahul. a) 1200 b) 1800 c) 2400 d) 3600 e) None of these

Last Answer : Answer: B 4x and 5x is the last year salry of rahul and rohit respectively Rahul last year to rahul current year = 2/3 Rohit last year to rohit current year = 3/5 Current of rahul + current of rohit = 4300 (3/2)*4x + (5/3)*5x = 4300. X = 300. So rahul current DDsalary = 3/2 * 4* 300 = 1800

Two alloys contain platinum and gold in the ratio of 1:2 and 1:3 respectively. A third alloy C is formed by mixing alloys one and alloy two in the ratio of 3:4. Find the percentage of gold in the mixture a) 79.2/7% b) 71.2/7% c) 73.2/7% d) 71.3/7% e) None of these

Description : Two alloys contain platinum and gold in the ratio of 1:2 and 1:3 respectively. A third alloy C is formed by mixing alloys one and alloy two in the ratio of 3:4. Find the percentage of gold in the mixture a) 79.2/7% b) 71.2/7% c) 73.2/7% d) 71.3/7% e) None of these

Last Answer : Answer: D Platinum = 1/3 and 1/4 gold = 2/3 and 3/4 Alloy one and two are mixed in the ratio of 3:4, so ratio of platinum and gold in final ratio – 2:5 So gold % = (5/7)*100 71.3/7%

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Description : A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Last Answer : Answer: B milk = 4x and water = 3x milk = 4x – 14*4/7 and water = 3x – 14*3/7 + 14 4x – 8: 3x + 8 = 3:4 X = 8, so milk = 8*4 = 32 litres

An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

Description : An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

Last Answer : Answer: B Let initial employees be 7x and then 4x similarly initial wages be 3y and then 5y so total wage = 21xy initially and then 20xy so wages decreases and ratio = 21:20

Two candles of same height are lighted at the same time. The first is consumed in 6 hours and second in 4 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the first and second candles becomes 2:1? a) 1 hour b) 2 hour c) 3 hour d) 4 hour e) None of these

Description : Two candles of same height are lighted at the same time. The first is consumed in 6 hours and second in 4 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between ... becomes 2:1? a) 1 hour b) 2 hour c) 3 hour d) 4 hour e) None of these

Last Answer : Answer: C Let height of both candles is ‘h’ and let after t times ratio between the height be 2:1 h – t*h/6 : h – t*h/4 = 2:1 t = 3

An amount of money is to be distributed among P, Q and R in the ratio of 5:4:7 respectively. If the total share of P and R is 3 times the share of Q, what is definitely Q’s share? a) 2000 b) 4000 c) 6000 d) Data inadequate e) None of these

Description : An amount of money is to be distributed among P, Q and R in the ratio of 5:4:7 respectively. If the total share of P and R is 3 times the share of Q, what is definitely Q’s share? a) 2000 b) 4000 c) 6000 d) Data inadequate e) None of these

Last Answer : Answer: D 

Ramana divides two sums of money among his four sons Ganesh, Mahesh, Anil and Sunil. The first sum is divided in the ratio 4: 3: 2: 1 and second in the ratio 5: 6: 7: 8. If the second sum is twice the first, the largest total is received by a) Ganesh b) Mahesh c) Anil d) Sunil e) Both Ganesh and Mahesh

Description : Ramana divides two sums of money among his four sons Ganesh, Mahesh, Anil and Sunil. The first sum is divided in the ratio 4: 3: 2: 1 and second in the ratio 5: 6: 7: 8. If the second sum is ... first, the largest total is received by a) Ganesh b) Mahesh c) Anil d) Sunil e) Both Ganesh and Mahesh

Last Answer : Answer: A Let the first sum be 4x, 3x, 2x, x Second sum be 5y, 6y, 7y, 8y The second sum is twice the first sum 26y = 20x; 13y = 10x Take y=10 x= 13 G:M:A:S 4X+5Y: 3X+6Y: 2X +7Y: X+8Y 102: 99: 96: 93

A bus and a truck are available to cross a jungle. The speed of the truck is thrice that of the bus. The capacity of the truck is 60 persons and that of bus is 40 persons. The average occupancy of the bus is twice that of the truck. The tickets for the bus and the truck cost Re 1 and Re 1.50 respectively. What is the ratio of the average rupee collection of the truck to that of the bus in a day? Assume there is no wastage time between trips and the occupancy of the bus/truck is defined as the ratio of the actual number of persons boarding it and its capacity. a) 9:17 b) 17:9 c) 8:27 d) 27:8 e) None of these

Description : A bus and a truck are available to cross a jungle. The speed of the truck is thrice that of the bus. The capacity of the truck is 60 persons and that of bus is 40 persons. The average occupancy of the bus is twice ... boarding it and its capacity. a) 9:17 b) 17:9 c) 8:27 d) 27:8 e) None of these

Last Answer :  Answer: D Average Rupee collection = Speed× capacity × Occupancy × Ticket rate Ratio of average Rupee collection of truck to that of bus= product of above rate According to question, (3×60×1×1.5):(1×40×2×1)= 270:80=27:8

Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = 50; Z = 40 B) Y = 40; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

Description : Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = ... ; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

Last Answer : Answer: C Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x) i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x) i.e., 7x, 21x/2 and 14x Required ratio = 7x:21x/2: ... of 8 = 6 total seats 8+6=14 Now compare ratios of all 7:21/2:14=>14:21:28 =>2:3:4

The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be as old as the present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years

Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his 20 coins and Marat loses 30 coins. Now, the ratio of gold coins with them is 41:34:46, respectively. How many coins did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these

Description : Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his ... did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these 

Last Answer : Answer: A 41x+40+34x+20+46x+30=4325 =>121x=4325-90 =>x=35 Required answer, number of coins received by parat =34x+20=34×35+20=1210

Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 marks in Hindi, 62 marks in Sanskrit, 68 marks in Mathematics and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these

Description : Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 ... and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these

Last Answer : Answer: D Total of maximum marks of all subjects=105×5=525 75% of 525=525 ×60/100= 315 Obtained marks of foru subjects (Hindi, Sanskrit, mathematics and English) =69+62+68+51=250 So, the obtained marks in Science=315-250=65

A bag contains 25p coins, 50p coins and 1 rupee coins whose values are in the ratio of 8:4:2.If the total values of coins is X and the total amount in rupees is Y,then which of the following is true A) X = 840; Y = 360 B) X = 966; Y = 345 C) X = 840; Y = 280 D) X = 740; Y = 260 E) None of these

Description : A bag contains 25p coins, 50p coins and 1 rupee coins whose values are in the ratio of 8:4:2.If the total values of coins is X and the total amount in rupees is Y,then which of the following is true A) X = 840; Y = 360 B) X = 966; Y = 345 C) X = 840; Y = 280 D) X = 740; Y = 260 E) None of these

Last Answer : Answer: A Value is given in the ratio 8:4:2. By option, (8x*0.25) + (4x*0.5) + (2x*1) = 840. So X=840 Y=360

Two candles of same height are lighted at the same time. The first is consumed in 3 hours and second in 2 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the first and second candles becomes 2:1? A) 2 hour B) 2.5 hour C) 4 hour D) 1.5 hour E) None of these

Description : Two candles of same height are lighted at the same time. The first is consumed in 3 hours and second in 2 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the ... 2:1? A) 2 hour B) 2.5 hour C) 4 hour D) 1.5 hour E) None of these

Last Answer : Answer: D Height of both candles are same i.e. h First one takes 3 hours to burn completely, so in one hour = h/3 Similarly second one will burn in one hour = h/2 Let after t time, ratio between their height is 2:1 so, ... given 2:1, h - t*(h/3) / h - t*(h/2) = 2/1 Solving we get t = 1.5

The incomes of A and B are in the ratio 1 : 2 and their expenditures are in the ratio 2 : 5. If A saves Rs 20,000 and B saves Rs 35,000, what is the total income of A and B? A) Rs 30,000 B) Rs 70,000 C) Rs 90,000 D) Rs 60,000 E) Rs 80,000

Description : The incomes of A and B are in the ratio 1 : 2 and their expenditures are in the ratio 2 : 5. If A saves Rs 20,000 and B saves Rs 35,000, what is the total income of A and B? A) Rs 30,000 B) Rs 70,000 C) Rs 90,000 D) Rs 60,000 E) Rs 80,000

Last Answer : Answer: C Income of A = x, of B = 2x Expenditure of A = 2y, of B = 5y Savings is (income – expenditure). So x – 2y = 20,000 2x – 5y = 35,000 Solve the equations, x = 30,000 So total = x+2x = 3x = 3*30,000 = 90,000

Rs 650 was divided among 3 children A,B,C in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much? A) C, Rs 246 B) C, Rs 264 C) B, Rs 18 D) A, Rs 246 E) A, Rs 264

Description : Rs 650 was divided among 3 children A,B,C in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much? A) C, Rs 246 B) C, Rs 264 C) B, Rs 18 D) A, Rs 246 E) A, Rs 264

Last Answer : Answer: E New ratio = 1/2 : 1/4 : 1/7 = 14 : 7 : 4 So both ratio suggests that C has not gained any money, rather he has lose the money. For both ratio find the shares of A and B With ratio 2 : 4 : 7 ... [7/(14+7+4)] * 650 = 182 B has also lose the money, A gain the money and = 364 - 100 = 264

The ratio of the incomes of A and B last year was 9 : 13. Ratio of their incomes of last year to this year is 9 : 10 and 13 : 15 respectively. The sum of their present incomes is Rs 50,000. What is the present income of B? A) Rs 32,000 B) Rs 24,000 C) Rs 20,000 D) Rs 30,000 E) None of these

Description : The ratio of the incomes of A and B last year was 9 : 13. Ratio of their incomes of last year to this year is 9 : 10 and 13 : 15 respectively. The sum of their present incomes is Rs 50,000. What is the present income of B? A) Rs 32,000 B) Rs 24,000 C) Rs 20,000 D) Rs 30,000 E) None of these

Last Answer : Answer: D ratio of the incomes of A and B last year was 9x : 13y Now given that ratio of the incomes of A and B last year was 9 : 13. So 9x/13y = 9/13 This gives x = y Total of incomes of A ... = 50,000 This gives x = 2,000 So present income of B = 15y = 15x = 15*2000 = 30,000

A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in class 12 is 420, find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

Description : A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in ... find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

Last Answer : Answer: D Let number of students in 4 sections be A, B, C, D respectively. Then 1/2 of A = 1/3 of b = 1/4 of C = 1/5 of D So A : B : C : D = 2 : 3 : 4 : 5 [When A/2 = B/3 = C/4, then ratio A: B : C = 2 : 3 : 4] So students in 1st and 2nd section = [(2+3)/(2+3+4+5)] * 420 = 150

When 7 is added to the numerator and denominator of the fraction, then the new ratio of numerator and denominator becomes 13:19, what is the original ratio ? A) 11:13 B) 7:9 C) 4:7 D) Can’t be determined E) None of these

Description : When 7 is added to the numerator and denominator of the fraction, then the new ratio of numerator and denominator becomes 13:19, what is the original ratio ? A) 11:13 B) 7:9 C) 4:7 D) Can’t be determined E) None of these

Last Answer : Answer: D  X+7/y+7 = 13/19 x and y are different variable, so original fraction cannot be determined