Standard free energy (∆G°) of hydrolysis of phosphoenolpyruvate is (A) –61.9 KJ/mol (B) –43.1 KJ/mol (C) –14.2 KJ/mol (D) –9.2 KJ/mol

Standard free energy (∆G°) of hydrolysis of phosphoenolpyruvate is (A) –61.9 KJ/mol (B) –43.1 KJ/mol (C) –14.2 KJ/mol (D) –9.2 KJ/mol
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Standard free energy (∆G°) of hydrolysis of creatine phosphate is (A) -–51.4 KJ/mol (B) –43.1 KJ/mol (C) –30.5 KJ/mol (D) –15.9 KJ/mol

Description : Standard free energy (∆G°) of hydrolysis of creatine phosphate is (A) -–51.4 KJ/mol (B) –43.1 KJ/mol (C) –30.5 KJ/mol (D) –15.9 KJ/mol

Last Answer : Answer : B

Standard free energy (∆G°) of hydrolysis of ADP to AMP + Pi is (A) –43.3 KJ/mol (B) –30.5 KJ/mol (C) –27.6 KJ/mol (D) –15.9 KJ/mol

Description : Standard free energy (∆G°) of hydrolysis of ADP to AMP + Pi is (A) –43.3 KJ/mol (B) –30.5 KJ/mol (C) –27.6 KJ/mol (D) –15.9 KJ/mol

Last Answer : Answer : C

Standard free energy (∆G°) of hydrolysis of ATP to ADP + Pi is (A) –49.3 KJ/mol (B) –4.93 KJ/mol (C) –30.5 KJ/mol (D) –20.9 KJ/mol

Description : Standard free energy (∆G°) of hydrolysis of ATP to ADP + Pi is (A) –49.3 KJ/mol (B) –4.93 KJ/mol (C) –30.5 KJ/mol (D) –20.9 KJ/mol

Last Answer : Answer : C

Given that the standard free energy change (∆G°) for the hydrolysis of ATP is –7.3 K cal/mol and that for the hydrolysis of Glucose 6-phosphate is –3.3 Kcal/mol, the ∆G° for the phosphorylation of glucose is Glucose + ATP → Glucose 6– Phosphate + ADP. (A) –10.6 Kcal/mol (B) –7.3 Kcal/mol (C) –4.0 Kcal/mol (D) +4.0 Kcal/mol

Description : Given that the standard free energy change (∆G°) for the hydrolysis of ATP is -7.3 K cal/mol and that for the hydrolysis of Glucose 6-phosphate is -3.3 Kcal/mol, the ∆G° for the phosphorylation of glucose is Glucose + ATP → ... -10.6 Kcal/mol (B) -7.3 Kcal/mol (C) -4.0 Kcal/mol (D) +4.0 Kcal/mol

Last Answer : Answer : C

The standard free energy of hydrolysis of terminal phosphate group of ATP is (A) –7,300 cal/mol (B) –8,300 cal/mol (C) 10,000 cal/mol (D) +7,300 cal/mol

Description : The standard free energy of hydrolysis of terminal phosphate group of ATP is (A) –7,300 cal/mol (B) –8,300 cal/mol (C) 10,000 cal/mol (D) +7,300 cal/mol

Last Answer : A

Under standard conditions (A) The free energy change ∆G°, is equal to 0 (B) The standard free energy change ∆G, is equal to 0 (C) The free energy change, ∆G°, is equal to the standard free energy change, ∆G° (D) Keq is equal to 1

Description : Under standard conditions (A) The free energy change ∆G°, is equal to 0 (B) The standard free energy change ∆G, is equal to 0 (C) The free energy change, ∆G°, is equal to the standard free energy change, ∆G° (D) Keq is equal to 1

Last Answer : C

Given standard enthalpy of formation of `CO(-110 "KJ mol"^(-1))` and `CO_(2)(-394 "KJ mol"^(-1))`. The heat of combustion when one mole of graphite bu

Description : Given standard enthalpy of formation of `CO(-110 "KJ mol"^(-1))` and `CO_(2)(-394 "KJ mol"^(-1))`. The heat of combustion when one mole of graphite bu

Last Answer : Given standard enthalpy of formation of `CO(-110 "KJ mol"^(-1))` and `CO_(2)(-394 "KJ mol"^(-1))`. The heat ... B. `-284` KJ C. `-394` KJ D. `-504` KJ

If a reaction has an enthalpy of -54.32 kJ/mol and an entropy of -354.2 J/(K*mol), what is the Gibbs free Energy at 54.3(degrees c)?

Description : If a reaction has an enthalpy of -54.32 kJ/mol and an entropy of -354.2 J/(K*mol), what is the Gibbs free Energy at 54.3(degrees c)?

Last Answer : DeltaG = DeltaH - TDeltaS dG = -54.32 kJ/mol - (54'32+273)K(-354.2J/molK) NB Thevtemperature is quoted in Kelvin(K) and the Entropy must be converted to kJ by dividing by '1000'/ Hence dG = ... 115.94 kJ/mol dG = (+)61.61 kJ/mol Since dG is positive, the reaction is NOT thermodynamically feasible.

If ∆G°= –2.3RT log Keq, the free energy for the reaction will be A BC + 10moles 10moles 10moles (A) –4.6 RT (B) –2.3 RT (C) +2.3 RT (D) +4.6 RT

Description : If ∆G°= –2.3RT log Keq, the free energy for the reaction will be A BC + 10moles 10moles 10moles (A) –4.6 RT (B) –2.3 RT (C) +2.3 RT (D) +4.6 RT

Last Answer : Answer : C

For the given reaction , `A(g) rarr 2B(g) , Delta_(r)H= 30 kJ//"mole" Delta_(r)S = 150 J//mol` at `300 K` If `C_(P,A) = 20 J//K mol` and `C_(P,B) = 20

Description : For the given reaction , `A(g) rarr 2B(g) , Delta_(r)H= 30 kJ//"mole" Delta_(r)S = 150 J//mol` at `300 K` If `C_(P,A) = 20 J//K mol` and `C_(P,B) = 20

Last Answer : For the given reaction , `A(g) rarr 2B(g) , Delta_(r)H= 30 kJ//"mole" Delta_(r)S = 150 J//mol` at ... G` is negative D. At `T = 200, Delta G` is zero

The correct values of ionization enthalpies(in KJ `"mol"^(-1)`) of Si, P, Cl, and S respectively are: a)`786, 1012, 999, 1256` b)`1012, 786, 999, 1256

Description : The correct values of ionization enthalpies(in KJ `"mol"^(-1)`) of Si, P, Cl, and S respectively are: a)`786, 1012, 999, 1256` b)`1012, 786, 999, 1256

Last Answer : The correct values of ionization enthalpies(in KJ `"mol"^(-1)`) of Si, P, Cl, and S respectively are: ... . `786,1012,1256,999` D. `786,999,1012,1256`

An element has successive ionization enthalpies as 940 (first),2080,3090,4140,7030,7870,16000 and 19500 kJ `mol^(-1)`. To which group of the periodic

Description : An element has successive ionization enthalpies as 940 (first),2080,3090,4140,7030,7870,16000 and 19500 kJ `mol^(-1)`. To which group of the periodic

Last Answer : An element has successive ionization enthalpies as 940 (first),2080,3090,4140,7030,7870,16000 and 19500 kJ `mol^(- ... belong? A. 14 B. 15 C. 16 D. 17

The heat of combustion of carbon and monoxide are -394 and -285 KJ `mol^(-1)` respectively. The heat of formation of CO in KJ `mol^(-1)` is :-

Description : The heat of combustion of carbon and monoxide are -394 and -285 KJ `mol^(-1)` respectively. The heat of formation of CO in KJ `mol^(-1)` is :-

Last Answer : The heat of combustion of carbon and monoxide are -394 and -285 KJ `mol^(-1)` respectively. The heat of formation ... B. `-109` C. `+218` D. `-218`

The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` . The enthalpy change for the reaction `2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g)` is :

Description : The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` . The enthalpy change for the reaction `2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g)` is :

Last Answer : The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` . The enthalpy change for the reaction `2NH_(3)(g) ... mol^(-1)` D. `-92.0 KJ mol^(-1)`

For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta S = 66 JK^(-1)mol^(-1)`. The temperature at

Description : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta S = 66 JK^(-1)mol^(-1)`. The temperature at

Last Answer : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta ... :- A. 373 K B. 413 K C. 463 K D. 493 K

The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is …….., Given `Delta H=30.5 KJ mol^(-1)` and `Delta S

Description : The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is …….., Given `Delta H=30.5 KJ mol^(-1)` and `Delta S

Last Answer : The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is .., ... 362.12 K` C. `262.12 K` D. `562.12 K`

For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :-

Description : For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :-

Last Answer : For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :- A. 160 KJ B. 163.6 KJ C. 186.4 KJ D. 180 KJ

The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l)` at `27^(@)C` is `-1366.5 kJ mol^(

Description : The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l)` at `27^(@)C` is `-1366.5 kJ mol^(

Last Answer : The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) + ... 1369. kJ` C. `-1364.0 kJ` D. `-1361.5 kJ`

The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 kJ / mol respectively. For the reaction `N_(2)

Description : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 kJ / mol respectively. For the reaction `N_(2)

Last Answer : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 ... is A. `-212` B. `+212` C. `+778` D. `-778`

If the enthaply change for the transition of liquid water to steam is 30 KJ `"mol"^(-1)` at `27^(@)` C . The entropy change for the process would be

Description : If the enthaply change for the transition of liquid water to steam is 30 KJ `"mol"^(-1)` at `27^(@)` C . The entropy change for the process would be

Last Answer : If the enthaply change for the transition of liquid water to steam is 30 KJ `"mol"^(-1)` at `27^(@)` C . The ... K^(-1)` D. `100 J mol^(-1)K^(-1)`

`DeltaH_"vaporisation"` (KJ/mol) are given for the hydrides of halogens in the following graph. The hydride HF will correspond to

Description : `DeltaH_"vaporisation"` (KJ/mol) are given for the hydrides of halogens in the following graph. The hydride HF will correspond to

Last Answer : `DeltaH_"vaporisation"` (KJ/mol) are given for the hydrides of halogens in the following graph. The hydride HF will ... . (B)Q C. (C)R D. (D)S

The value of `Delta_(0) " for " [Ti(H_(2)O)_(6)]^(3+)` is found to be 240 kJ `mol^(-1)` then predict the colour of the complex using the following tab

Description : The value of `Delta_(0) " for " [Ti(H_(2)O)_(6)]^(3+)` is found to be 240 kJ `mol^(-1)` then predict the colour of the complex using the following tab

Last Answer : The value of `Delta_(0) " for " [Ti(H_(2)O)_(6)]^(3+)` is found to be 240 kJ `mol^(-1)` then ... -34)J-sec,N_(A)=6xx10^(23)c=3xx10^(8) m//sec)`

Consider the following reactions at `1000^(@)C`. (A) `Zn_((s))+1/2 O_(2(g)) rarr ZnO_((s)), DeltaG^(@)=-360` kJ/mol (B) `C_("(gra)")+1/2 O_(2(g)) rarr

Description : Consider the following reactions at `1000^(@)C`. (A) `Zn_((s))+1/2 O_(2(g)) rarr ZnO_((s)), DeltaG^(@)=-360` kJ/mol (B) `C_("(gra)")+1/2 O_(2(g)) rarr

Last Answer : Consider the following reactions at `1000^(@)C`. (A) `Zn_((s))+1/2 O_(2(g)) rarr ZnO_((s)), DeltaG^( ... a) and (b) are true D. both (a) and (b) false

Ionization enthalpy of Li is 520 kJ mol^(-1) while that of F is 1681 kJ mol^(-1) . Explain.

Description : Ionization enthalpy of Li is 520 kJ mol^(-1) while that of F is 1681 kJ mol^(-1) . Explain.

Last Answer : Ionization enthalpy of Li is 520 kJ mol-1 while that of F is 1681 kJ mol-1. Explain.

What shows that the formation of CO 2 releases 393.5 kJ mol?

Description : What shows that the formation of CO 2 releases 393.5 kJ mol?

Last Answer : C(s) + O2(g) + CO2(g) + 393.5 kJ

At which temperature would a reaction with AH = -92 kJ/mol, AS = -0.199kJ/(mol·K) be spontaneous?

Description : At which temperature would a reaction with AH = -92 kJ/mol, AS = -0.199kJ/(mol·K) be spontaneous?

Last Answer : the answer is 400

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Description : Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Last Answer : Answer: C Observer 36/62, 39/63, 43/61, 48/64, ? series Upper part is increase by 3, 4, 5, 6 i.e 36+3= 39, 39+4 = 43, 43+5 = 48, 48 + 6 = 54.

Coenzyme for phosphoenolpyruvate carboxykinase is (A) ATP (B) ADP (C) GTP (D) GDP

Description : Coenzyme for phosphoenolpyruvate carboxykinase is (A) ATP (B) ADP (C) GTP (D) GDP

Last Answer : Answer : C

The enzyme phosphoenolpyruvate carboxykinase catalyses the conversion of oxaloacetate to phosphoenolpyruvate requires (A) ATP (B) ADP (C) AMP (D) GTP

Description : The enzyme phosphoenolpyruvate carboxykinase catalyses the conversion of oxaloacetate to phosphoenolpyruvate requires (A) ATP (B) ADP (C) AMP (D) GTP

Last Answer : Answer : D

Pyruvate dehydrogenase a multienzyme complex is required for the production of (A) Acetyl-CoA (B) Lactate (C) Phosphoenolpyruvate (D) Enolpyruvate

Description : Pyruvate dehydrogenase a multienzyme complex is required for the production of (A) Acetyl-CoA (B) Lactate (C) Phosphoenolpyruvate (D) Enolpyruvate

Last Answer : Answer : A

A reaction which may be considered an isomerisation is (A) Glucose 6-Phosphate fructose 6 phosphate (B) 3-Phosphoglycerate 2-phosphoglycerate (C) 2-phosphoglycerate phosphoenolpyruvate (D) Pyruvate Lactate

Description : A reaction which may be considered an isomerisation is (A) Glucose 6-Phosphate fructose 6 phosphate (B) 3-Phosphoglycerate 2-phosphoglycerate (C) 2-phosphoglycerate phosphoenolpyruvate (D) Pyruvate Lactate

Last Answer : Answer : A

Erythrocytes under normal conditions and microorganisms under anaerobic conditions may accumulate (A) NADPH (B) Pyruvate (C) Phosphoenolpyruvate (D) Lactate

Description : Erythrocytes under normal conditions and microorganisms under anaerobic conditions may accumulate (A) NADPH (B) Pyruvate (C) Phosphoenolpyruvate (D) Lactate

Last Answer : Answer : D

In the glycolytic pathway, enolpyruvate is converted to ketopyruvate by (A) Pyruvate kinase (B) Phosphoenolpyruvate (C) Pyruvate dehydrogenase (D) Spontaneously

Description : In the glycolytic pathway, enolpyruvate is converted to ketopyruvate by (A) Pyruvate kinase (B) Phosphoenolpyruvate (C) Pyruvate dehydrogenase (D) Spontaneously

Last Answer : Answer : D

Two examples of substrate level phosphorylation in EM pathway of glucose metabolism are in the reactions of (A) 1,3 bisphosphoglycerate and phosphoenol pyruvate (B) Glucose-6 phosphate and Fructo-6-phosphate (C) 3 phosphoglyceraldehyde and phosphoenolpyruvate (D) 1,3 diphosphoglycerate and 2-phosphoglycerate

Description : Two examples of substrate level phosphorylation in EM pathway of glucose metabolism are in the reactions of (A) 1,3 bisphosphoglycerate and phosphoenol pyruvate (B) Glucose-6 phosphate ... phosphate (C) 3 phosphoglyceraldehyde and phosphoenolpyruvate (D) 1,3 diphosphoglycerate and 2-phosphoglycerate

Last Answer : A

An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol?

Description : An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol?

Last Answer : An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full? A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol

Given that standard heat enthalpy of `CH_(4), C_(2)H_(4)` and `C_(3)H_(8)` are -17.9, 12.5, -24.8 Kcal/mol. The `Delta H` for `CH_(4)+C_(2)Hrarr C_(3)

Description : Given that standard heat enthalpy of `CH_(4), C_(2)H_(4)` and `C_(3)H_(8)` are -17.9, 12.5, -24.8 Kcal/mol. The `Delta H` for `CH_(4)+C_(2)Hrarr C_(3)

Last Answer : Given that standard heat enthalpy of `CH_(4), C_(2)H_(4)` and `C_(3)H_(8)` are -17.9, 12.5, -24.8 Kcal ... . `-30.2` Kcal C. 55.2 Kcal D. `-19.4` Kcal

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Find the energy of a coil of inductance 18mH and current passing through it 1.25A.(in 10 -3 order) a) 14.06 b) 61 c) 46.1 d) 28.12

Description : Find the energy of a coil of inductance 18mH and current passing through it 1.25A.(in 10 -3 order) a) 14.06 b) 61 c) 46.1 d) 28.12

Last Answer : a) 14.06

Calculate the magnetic energy when the magnetic intensity in air is given as 14.2 units(in 10 -4 order) a) 1.26 b) 2.61 c) 6.12 d) 1.62

Description : Calculate the magnetic energy when the magnetic intensity in air is given as 14.2 units(in 10 -4 order) a) 1.26 b) 2.61 c) 6.12 d) 1.62

Last Answer : a) 1.26

A 15-year-old girl was seen by her family physician because of increasing lethargy. She had a recent history of the "flu". Biochemistry tests show that she has renal impairement. serum sodium 140 mmol/L (137 - 144) serum potassium 4.2 mmol/L (3.5 - 4.9) serum urea 28 mol/L (2.5 - 7.5) serum creatinine 280 µmol/L (60 - 110) Her condition does not improve after several weeks on corticosteroid therapy, so a renal biopsy is performed. The biopsy demonstrates the presence of segmental sclerosis of 3 of 10 glomeruli identified in the biopsy specimen. Immunofluorescence studies and electron microscopy do not reveal evidence for immune deposits. What is the most appropriate advice to give regarding her condition? 1) She has an underlying malignancy 2) She may require a renal transplant in 10 years

Description : A 15-year-old girl was seen by her family physician because of increasing lethargy. She had a recent history of the "flu". Biochemistry tests show that she has renal impairement. ... will likely develop a restrictive lung disease 5) She will probably improve with additional corticosteroid therapy

Last Answer : Answers-2 The findings point to focal segmental glomerulosclerosis (FSGS), which leads to chronic renal failure in half of cases. The lack of resolution with corticosteroid therapy and the progression to chronic renal failure is what sets FSGS apart from minimal change disease.

f the mass is of 10 Kg, find the natural frequency in Hz of the free longitudinal vibrations. The displacement is 0.01mm. a) 44.14 b) 49.85 c) 43.43 d) 46.34

Description : f the mass is of 10 Kg, find the natural frequency in Hz of the free longitudinal vibrations. The displacement is 0.01mm. a) 44.14 b) 49.85 c) 43.43 d) 46.34

Last Answer : b) 49.85

Find the natural frequency in Hz of the free longitudinal vibrations if the displacement is 2mm. a) 11.14 b) 12.38 c) 11.43 d) 11.34

Description : Find the natural frequency in Hz of the free longitudinal vibrations if the displacement is 2mm. a) 11.14 b) 12.38 c) 11.43 d) 11.34

Last Answer : a) 11.14

A butt weld has been made by MMA in a 50mm thick impact tested steel plate. The welding electrode used was a basic type, 5mm diameter. The measured welding parameters for one of the runs was 250 amps, 24 volts, using DC+ve polarity, and a ROL:of 180mm per min. What would be the arc energy? a) Insufficient information given to calculate the arc energy b) 1.9 kJ/mm c) 1.87 kJ/mm d) 2.0 kJ/mm

Description : A butt weld has been made by MMA in a 50mm thick impact tested steel plate. The welding electrode used was a basic type, 5mm diameter. The measured welding parameters for one of the runs was 250 amps, 24 volts, using DC ... given to calculate the arc energy b) 1.9 kJ/mm c) 1.87 kJ/mm d) 2.0 kJ/mm

Last Answer : d) 2.0 kJ/mm

The primary acceptor, during CO2 fixation in C3 plants, is (a) phosphoenolpyruvate (PEP) (b) ribulose 1, 5-diphosphate (RuDP) (c) phosphoglyceric acid (PGA) (d) ribulose monophosphate (RMP).

Description : The primary acceptor, during CO2 fixation in C3 plants, is (a) phosphoenolpyruvate (PEP) (b) ribulose 1, 5-diphosphate (RuDP) (c) phosphoglyceric acid (PGA) (d) ribulose monophosphate (RMP).

Last Answer : (b) ribulose 1, 5-diphosphate (RuDP)

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per cycle is 1800 kJ/kg, then work output per cycle per kg of air is a. 879.1 kJ/ b. 890.2 kJ c. 895.3 kJ d. 973.5 kJ

Description : An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per ... kg of air is a. 879.1 kJ/ b. 890.2 kJ c. 895.3 kJ d. 973.5 kJ

Last Answer : ANSWER d. 973.5 kJ

How tall is 61 inches and 14 centimeters?

Description : How tall is 61 inches and 14 centimeters?

Last Answer : Need answer

If a fiber optic system has a rise time of 38.55 ns, the source rise time is 12 ns and the detector rise time is 12 ns, what is the cable rise time? A. 34.61 ns B. 14.55 ns C. 52.55 ns D. 26.25 ns

Description : If a fiber optic system has a rise time of 38.55 ns, the source rise time is 12 ns and the detector rise time is 12 ns, what is the cable rise time? A. 34.61 ns B. 14.55 ns C. 52.55 ns D. 26.25 ns

Last Answer : A. 34.61 ns

A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Description : A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Last Answer : (B) 11.77 kPa