WHat is the journey time if a train leaves at 12 24 and reaches at 14 12?

WHat is the journey time if a train leaves at 12 24 and reaches at 14 12?
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1 hour and 48 minutes.
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A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Last Answer : 3) 840 km

If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)

A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Description : A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Last Answer : C Let the speed of the van be x km/hr And that of the train be y km/hr 360/x+1440/y = 24 --------------->A Dividing by 24 on both sides 15/x+60/y = 1 ---------1 And 600/x +1200/y =25 Dividing by ... 720/y =9 Y=80 Put y value in A 360/x = 24-18 X=360/6 X=60 Ratio of speeds = 60:80 = 3:4

Starting from point A, Ajit walks 14 metres towards west, he then turns to his right and walks 14 metres and then turns to his left and walks 10 metres. He again turns to his left and walks 14 metres and reaches to the point E. The shortest distance between A and E is (A) 38 (B) 42 (C) 52 (D) 24

Description : Starting from point A, Ajit walks 14 metres towards west, he then turns to his right and walks 14 metres and then turns to his left and walks 10 metres. He again turns to his left and walks 14 metres and reaches to the point E. The shortest distance between A and E is (A) 38 (B) 42 (C) 52 (D) 24

Last Answer : Answer: D

P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24

Description : The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24

Last Answer : ANSWER:B  Explanation:  First train leaves at 8.00am and second leaves at 9.00am  So,first train that is , from ooty to Chennai has covered  75 km distance in 1 hr.  So , distance left by between the station = ... the trains will meet , 3 hr after second train left  i.e., 9.00 am +3 = 12.00 pm

Mr. Grumper grumbles about bad time-keeping trains like everybody else. On one particular morning he was justified, though. The train left on time for the one hour journey and it arrived 5 minutes late. However, Mr. Grumper's watch showed it to be 3 minutes early, so he adjusted his watch by putting it forward 3 minutes. His watch kept time during the day, and on the return journey in the evening the train started on time, according to his watch, and arrived on time, according to the station clock. If the train traveled 25 percent faster on the return journey than it did on the morning journey, was the station clock fast or slow, and by how much? -Riddles

Description : Mr. Grumper grumbles about bad time-keeping trains like everybody else. On one particular morning he was justified, though. The train left on time for the one hour journey and it arrived 5 minutes late. ... did on the morning journey, was the station clock fast or slow, and by how much? -Riddles

Last Answer : The station clock is 3 minutes fast. The morning journey took 65 minutes, and the evening journey therefore took 52 minutes, and the train arrived 57 minutes after it should have left, that is, 3 minutes early.

A train travels between two stations 15 km apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform retardation, the maximum speed attained by the train during the journey will by a.125 km/hr b.107 dynes c.80 km/hr d.100 km/hr e.60 km/hr

Description : A train travels between two stations 15 km apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform retardation, the maximum speed attained by the train during the journey will by a.125 km/hr b.107 dynes c.80 km/hr d.100 km/hr e.60 km/hr

Last Answer : d. 100 km/hr

A train travels between two stations 15 km, apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform relardation, the maximum speed attained by the train, during, the journey, will be a.60 km/hr b.80 km/hr c.125 km/hr d.100 km/hr e.107 dynes

Description : A train travels between two stations 15 km, apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform relardation, the maximum speed attained by the train, during, the journey, will be a.60 km/hr b.80 km/hr c.125 km/hr d.100 km/hr e.107 dynes

Last Answer : d. 100 km/hr

A train starts its journey from a stationary position and after running for 1 minute in parallel, 30 m / s speed is obtained. Determine the speed of the train in 1 minute ?

Description : A train starts its journey from a stationary position and after running for 1 minute in parallel, 30 m / s speed is obtained. Determine the speed of the train in 1 minute ?

Last Answer : Here , the initial velocity , u = 0 m / s end velocity , v = 30 m / s time , t = 1 min = 60 sec we know , acceleration , a = (v- u) / t = (30- 0) / 60 = 0.5 m / s ^ 2 Acceleration = 0.5 m / s ^ 2

How can I get food during train journey?

Description : How can I get food during train journey?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these

Description : It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these

Last Answer : Let the speed of the train be x km/hr and that of the car be y km/hr. Then, 120/x+480/y= 8 1/x+4/y=1/15 ....(i) And, 200/x+400/y=25/3 1/x+2/y=1/24 ....(ii) Solving (i) and (ii), we get: x = 60 and y = 80. Ratio of speeds = 60 : 80 = 3 : 4. Answer: c)

Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Description : Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Last Answer : C) Given x= 168 , y = 112 Required average speed = (2xy / x + y) km/hr = 2 * 168 *112 / 168 + 112 = 37632 / 280 =134.4 km/hr

A train p starts from delhi at 8pm and reaches kanyakumari at 10pm. While another train q starts from kanyakumari at 8pm and reaches delhi at 11pm. The two trains will cross each other at. A) 9.24pm B) 9.10pm C) 9.02pm D) 9.12pm

Description : A train p starts from delhi at 8pm and reaches kanyakumari at 10pm. While another train q starts from kanyakumari at 8pm and reaches delhi at 11pm. The two trains will cross each other at. A) 9.24pm B) 9.10pm C) 9.02pm D) 9.12pm

Last Answer : ANSWER: D Explanation:  Suppose the distance between delhi and kanyakumari is x km  The time taken by p to cover x km = 2hrs  The time taken by q to cover x km = 3hrs  Therefore speed of p = distance / time  = x ... = 1/y  5y = 6  y = (6/5 * 60)min= 72min  So the two trains meet at 9.12pm

Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Description : Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Last Answer : C Time taken by Siva = 8 h Time taken by Anirudh = 7 h For your convenience take the product of times taken by both as a distance. Then the distance = 56km Since, Siva covers half of the distance in 2 ... by them = 28/15 = 1 hr 52 min Thus , they will cross each other at 6 : 52am.

The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs covering a distance of 1600 km. the speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Description : The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs ... speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Last Answer : D Let the speed in return journey be x km/hr Then speed in upward journey = 150 /100 x = (3/2 x)km/hr Average speed = (2*3x/2*x) / (3x/2 +x) =3x2 / (5x/2) =6x2 / 5x =6x/5 km/hr Therefore (1600 ... 192x = 8000 X = 41.66 Speed in upward journey = (3/2 x ) km/hr =(3/2*41.66) =62.49 km/hr 

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

Two goods trains having equal lengths, take 30 seconds and 45 seconds respectively to cross a telegraph post. If the length of each train is 360 meters, in what time (in seconds) will they cross each other when traveling in opposite direction? A) 36 B) 12 C) 24 D) 48

Description :  Two goods trains having equal lengths, take 30 seconds and 45 seconds respectively to cross a telegraph post. If the length of each train is 360 meters, in what time (in seconds) will they cross each other when traveling in opposite direction? A) 36 B) 12 C) 24 D) 48

Last Answer : ANSWER:A  Explanation:  Speed of train = distance /time  = 360/30 m/s  = 12 m/s  Speed of train 2 = distance /time  = 360 /45 m/s  = 8 m/s  If 2 trains are moving in opposite ... +360 = 720 m  Time = distance/speed  = (720/20) = 36 Seconds Hence the required answer is 36 seconds

A man wnt uphill with a speed of 20 km.p.h. and came downhill with a speed of 30 km p.h. The average speed for his journey was (a) 25 km. p.h. (b) 22 1/2 km. p.h. (c) 24 km. p.h. (d) 25 1/2 km. p.h.

Description : A man wnt uphill with a speed of 20 km.p.h. and came downhill with a speed of 30 km p.h. The average speed for his journey was (a) 25 km. p.h. (b) 22 1/2 km. p.h. (c) 24 km. p.h. (d) 25 1/2 km. p.h.

Last Answer : 24 km.p.h.

In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid Rs.156 for a journey of 16 km and another person paid Rs.204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is (A) 236 (B) 240 (C) 248 (D) 256

Description : In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid Rs.156 for a journey of 16 km and another person paid Rs.204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is (A) 236 (B) 240 (C) 248 (D) 256

Last Answer : Answer: B

There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 km/hr while Varun sails on a boat at a speed of about 24km/hr. If the flow of water current is at the speed of 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48

Description : There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 ... 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48 

Last Answer : ANSWER:B Explanation: As Arun swims both the ways at the speed of 30km/hr, the average speed of swimming is 30 km/hr Being a boat sailor, varun moves downstream at speed =24 +12=36km/hr and upstream at speed = 24-12= ... Upstream Speed])] = (36*12)/0.5(36+12) km/hr = 432/24 km/hr = 18 km/hr

Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr

A train crosses a long bridge of length 12 km and a standing girl in 600 seconds and 24 seconds respectively. What will be the length of the train? A) 275 B) 480 C) 389 D)225

Description : A train crosses a long bridge of length 12 km and a standing girl in 600 seconds and 24 seconds respectively. What will be the length of the train? A) 275 B) 480 C) 389 D)225

Last Answer : ANSWER:B Explanation: Time taken to cross the bridge(12 km) = 600 seconds.  Speed of the train = Distance / Time  = 12/600 km/s = 12000/600 m/s = 20m/s Train crosses a girl in 24 seconds. ... = Speed of the train x Time Taken  = (20 *24)m  = 480m  Hence the required length is 480 m.

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

What is the area of a triangle with the side lenghts 12 and 14 and 24?

Description : What is the area of a triangle with the side lenghts 12 and 14 and 24?

Last Answer : Area of triangle: 0.5*12*14*sin(134.6183417) = 16 square unitsrounded to the nearest whole number

The “in-principle” license is valid for _____months within which the entities must fulfil the requirements. A. 12 Months B. 14 Months C. 18 Months D. 24 Months E. None of the Above

Description : The “in-principle” license is valid for _____months within which the entities must fulfil the requirements. A. 12 Months B. 14 Months C. 18 Months D. 24 Months E. None of the Above

Last Answer : C. 18 Months Explanation: The ―in-principle‖ license is valid for 18 months within which the entities must fulfil the requirements.

The fertilized eggs of Catla take about _ to _ hrs for hatching at 30°C (a) 10 to 12 (b) 12 to 14 (c) 14 to 18 (d) 18 to 24

Description : The fertilized eggs of Catla take about _ to _ hrs for hatching at 30°C (a) 10 to 12 (b) 12 to 14 (c) 14 to 18 (d) 18 to 24

Last Answer : (d) 18 to 24

Sides of triangles are (i) 3 cm, 4 cm, 6 cm. (ii) 4 cm, 5 cm, 6 cm. (iii) 7 cm, 24 cm, 25 cm (iv) 5 cm, 12 cm, 14 cm. Which of these is right triangle?(a) (i) (b) (ii) (c) (iii) (d) (iv)

Description : Sides of triangles are (i) 3 cm, 4 cm, 6 cm. (ii) 4 cm, 5 cm, 6 cm. (iii) 7 cm, 24 cm, 25 cm (iv) 5 cm, 12 cm, 14 cm. Which of these is right triangle?(a) (i) (b) (ii) (c) (iii) (d) (iv)

Last Answer : (c) (iii)

A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Description : A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Last Answer : 4) 1/12

Income from Salary is explained in the section …………………… A) 12 to 14 B) 15 to 17 C) 18 to 22 D) 24 to 26

Description : Income from Salary is explained in the section …………………… A) 12 to 14 B) 15 to 17 C) 18 to 22 D) 24 to 26

Last Answer : B) 15 to 17

A party was held in which a grandmother, father, mother, four sons, their wives and one son and two daughters to each of the sons were present. The number of females present in the party is: (A) 12 (B) 14 (C) 18 (D) 24

Description : A party was held in which a grandmother, father, mother, four sons, their wives and one son and two daughters to each of the sons were present. The number of females present in the party is: (A) 12 (B) 14 (C) 18 (D) 24

Last Answer : Answer: B

The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Description : The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Last Answer : Answer: A

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

You have 12 hours before your space craft embarks on a life long journey...

Description : You have 12 hours before your space craft embarks on a life long journey...

Last Answer : i'd do a lot of girls i'd always wanted to do, after that i'd eat some spareribs even though i'm a vegitarian, after that i'd probably listen to Boston's don't look back album, i'd say if ... girls, and i do mean a lot, and in all positions etc. i'd just misbehave and might even miss the flight

Shreya travel the first part of her journey at 160 kmph and the second part at 240 kmph and cover the total distance of 3840 km to her destination in 20 hours. How long did the first part of her journey last? a) 8 hrs b) 12 hrs c) 16 hrs d) 10 hrs

Description : Shreya travel the first part of her journey at 160 kmph and the second part at 240 kmph and cover the total distance of 3840 km to her destination in 20 hours. How long did the first part of her journey last? a) 8 hrs b) 12 hrs c) 16 hrs d) 10 hrs

Last Answer : B The total time of journey = 20 hours. Let 'x' hours be the time that shreya travelled at 160 kmph Therefore, 20-x hours would be time that she travelled at 240 kmph. Hence, she would have covered x*160+( ... 20-x)*240 =3840 160x +4800-240x =3840 240x-160x=4800-3840 80x= 960 X=960/80=12 hrs

A leaf spring consists of 3 extra full length leaves and 14 graduated length leaves. The maximum force that can act on the spring is 70kN and the distance between eyes of the spring is 1.2m. Width and thickness of the leaves are 100mm and 12mm respectively. If modulus of elasticity is 207000N/mm², calculate the initial nip. (a) 26.8mm (b) 24.9mm (c) 22.5mm (d)23.1mm

Description : A leaf spring consists of 3 extra full length leaves and 14 graduated length leaves. The maximum force that can act on the spring is 70kN and the distance between eyes of the spring is 1.2m. Width and thickness of the ... /mm², calculate the initial nip. (a) 26.8mm (b) 24.9mm (c) 22.5mm (d)23.1mm

Last Answer : b) 24.9mm

Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Description :  Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr

A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms per hour, should he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Description : A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms ... he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Last Answer : Let x' be the distance between house and station. Time taken to travel a distance of x at the speed of 10km/hr, T1 = x/10 hours Time taken to travel a distance of x at the speed of 15km/hr, T2 = x/15 hours we ... the station at 5 pm, speed = 60/5 = 12 km/hr [12 pm - 5pm, time = 5 hours] Answer: a)

The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

12. What is characteristic of the oral route? a) Fast onset of effect b) Absorption depends on GI tract secretion and motor function c) A drug reaches the blood passing the liver d) The sterilization of medicinal forms is obligatory

Description : 12. What is characteristic of the oral route? a) Fast onset of effect b) Absorption depends on GI tract secretion and motor function c) A drug reaches the blood passing the liver d) The sterilization of medicinal forms is obligatory

Last Answer : b) Absorption depends on GI tract secretion and motor function

A girl throws a 2 kilogram rock vertically upward. It reaches a maximum height of 5 meters. What is the kinetic energy of the rock the instant it leaves the girl's hand?

Description : A girl throws a 2 kilogram rock vertically upward. It reaches a maximum height of 5 meters. What is the kinetic energy of the rock the instant it leaves the girl's hand?

Last Answer : ANSWER: 100 JOULES (accept 98 joules)

A passenger train 165 m long which is running at a speed of 30km/hr. In what time will it pass a man who is running at a speed of 3 km/hr in the opposite direction. In which the train is moving. A)14 sec B) 17sec C)16sec D)18sec

Description : A passenger train 165 m long which is running at a speed of 30km/hr. In what time will it pass a man who is running at a speed of 3 km/hr in the opposite direction. In which the train is moving. A)14 sec B) 17sec C)16sec D)18sec

Last Answer : ANSWER: D Explanation:  Speed of the train = 30 km/hr  Speed of man = 3 km/hr  Length of the train = 165m If direction is given in opposite direction then we add both speed.  That is (30 + 3 )= 33 km/hr ... can easily get the distance of m/s  So it cover 165 m  i.e., 165 * 6 /55 = 18 sec.

Sakthi running at 27 kmph alongside a railway track in 272 metres ahead of the engine of a 240 metres long train running at 135 kmph in the same direction. In how much time will the train pass sakthi? A) 24 B) 29 C) 36 D) 17

Description :  Sakthi running at 27 kmph alongside a railway track in 272 metres ahead of the engine of a 240 metres long train running at 135 kmph in the same direction. In how much time will the train pass sakthi? A) 24 B) 29 C) 36 D) 17

Last Answer : ANSWER:D  Explanation:  Speed of the train = 135 kmph  Speed of sakthi = 27 kmph  Speed of train relative to sakthi = (135-27) kmph  =108 kmph  We have to find the time in seconds, so convert ... of the train = Distance / Time  Therefore Time taken = ( 512 / 30) sec  = 17 sec

If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec

Description :  If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec 

Last Answer : ANSWER:C Explanation: Speed of the train = 90 km/hr Converting the speed into m/sec 90 km/hr = (90* 5/18)m/s = 25m/s length of the train = distance travelled we know distance = speed * ...  Time = distance / speed  = ( 1800/25) sec  = 72 seconds  Hence the required answer is 72 seconds

A passenger train travelling at 96 kmph completely crosses another train having half its length and travelling in opposite direction at 84 kmph, in 24 seconds. It also passes a railway platform in 90 seconds. The length of the platform is A) 1250 m B) 2258m C) 1600 m D) 3725m

Description : A passenger train travelling at 96 kmph completely crosses another train having half its length and travelling in opposite direction at 84 kmph, in 24 seconds. It also passes a railway platform in 90 seconds. The length of the platform is A) 1250 m B) 2258m C) 1600 m D) 3725m

Last Answer :  ANSWER:C  Explanation:  Let the length of the first train be x metres  Then, is x /2metres  Relative speed = (96+84)kmph  = 180 kmph  Convert km/hr into m/s,  = 180*5/18  = 50 m/s  Therefore (x ...  (800+y) = 90*480/18  y = 2400- 800  = 1600  Hence, the length of the platform is 1600 m

The three time estimates for the activities of the network shown in the given figure are shown above their arrows. The earliest expected time for the event 4, is (A) 19 (B) 14 (C) 24 (D) None of these

Description : The three time estimates for the activities of the network shown in the given figure are shown above their arrows. The earliest expected time for the event 4, is (A) 19 (B) 14 (C) 24 (D) None of these

Last Answer : (A) 19

A man goes to work at the same time each day and travels part of his journey facing forwards and the remainder facing backwards. When he returns at the end of his working day, he only faces forwards.How can this be? -Riddles

Description : A man goes to work at the same time each day and travels part of his journey facing forwards and the remainder facing backwards. When he returns at the end of his working day, he only faces forwards.How can this be? -Riddles

Last Answer : He works in the engine room of a liner! To get to work, he walks along the decks from his cabin facing forwards, and down the ladders between decks facing backwards. However, when he finishes, he only needs to face forwards to climb the ladders again and walk along the deck back to his cabin.

What time does the journey of electronics start ???

Last Answer : The journey of electronics begins: the time of the discovery of the transistor.

What time of year did the travelers on the Oregon Trail have to start their journey?

Description : What time of year did the travelers on the Oregon Trail have to start their journey?

Last Answer : Need answer