The optimum dissolved oxygen level (in mg/litre) required for survival of aquatic organisms is : (1) 4 – 6 (2) 2 – 4 (3) 8 – 10 (4) 12 – 16

The optimum dissolved oxygen level (in mg/litre) required for survival of aquatic organisms is : (1) 4 – 6 (2) 2 – 4 (3) 8 – 10 (4) 12 – 16
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 4 – 6
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The optimum dissolved oxygen level (in mg/litre) required for survival of aquatic organisms is - (1) 4 - 6 (2) 2 - 4 (3) 8 - 10 (4) 12 - 16

Description : The optimum dissolved oxygen level (in mg/litre) required for survival of aquatic organisms is - (1) 4 - 6 (2) 2 - 4 (3) 8 - 10 (4) 12 - 16

Last Answer : (1) 4 - 6 Explanation: Oxygen is one of several dissolved gases important to aquatic systems. Dissolved oxygen is necessary to maintain aerobic conditions in surface waters and is ... approach saturation - that concentration which is in equilibrium with the partial pressure of atmospheric oxygen.

Lagoons used for purification of polluted water (A) Are large shallow artificial lakes also known as clarification lakes, maturation ponds or oxidation ponds (B) Use micro-organisms/bacteria in presence of dissolved oxygen (C) Gives an excellent final effluent (with 3 to 4 lagoons arranged in series) having suspended solid < 1 mg/litre and BOD = 3.8 mg/litre (D) All (A), (B) & (C)

Description : Lagoons used for purification of polluted water (A) Are large shallow artificial lakes also known as clarification lakes, maturation ponds or oxidation ponds (B) Use micro-organisms/bacteria in presence of dissolved oxygen (C) Gives an ... 1 mg/litre and BOD = 3.8 mg/litre (D) All (A), (B) & (C)

Last Answer : (D) All (A), (B) & (C)

One degree of hardness of water means a content of salts of (A) 10.25 mg/litre (B) 12.25 mg/litre (C) 14.25 mg/litre (D) 16.25 mg/litre

Description : One degree of hardness of water means a content of salts of  (A) 10.25 mg/litre  (B) 12.25 mg/litre  (C) 14.25 mg/litre  (D) 16.25 mg/litre

Last Answer : (C) 14.25 mg/litre 

For the survival of fish in a river stream, the minimum dissolved oxygen is prescribed A. 3 ppm B. 4 ppm C. 5 ppm D. 10 ppm

Description : For the survival of fish in a river stream, the minimum dissolved oxygen is prescribed A. 3 ppm B. 4 ppm C. 5 ppm D. 10 ppm

Last Answer : ANS: B

The detrimental effect on organism and water quality with temperature rise of aquatic system is the reduction of __________ of water. (A) Dissolved oxygen content (B) Biological oxygen demand (C) Vapor pressure (D) All (A), (B) and (C)

Description : The detrimental effect on organism and water quality with temperature rise of aquatic system is the reduction of __________ of water. (A) Dissolved oxygen content (B) Biological oxygen demand (C) Vapor pressure (D) All (A), (B) and (C)

Last Answer : (A) Dissolved oxygen content

For existence of aquatic life in water, the dissolved oxygen content in it, should not be less than __________ ppm. (A) 10000 (B) 5 (C) 500 (D) 1000

Description : For existence of aquatic life in water, the dissolved oxygen content in it, should not be less than __________ ppm. (A) 10000 (B) 5 (C) 500 (D) 1000

Last Answer : (B) 5

Presence of carbonaceous matter in the sewage (A) Causes reduction in its dissolved oxygen content thereby endangering the life of aquatic creatures (B) Reduces sulphate ions to sulphides causing obnoxious smell (C) Increases the quantity of chlorine used for its purification (D) All (A), (B) and (C)

Description : Presence of carbonaceous matter in the sewage (A) Causes reduction in its dissolved oxygen content thereby endangering the life of aquatic creatures (B) Reduces sulphate ions to sulphides causing obnoxious ... quantity of chlorine used for its purification (D) All (A), (B) and (C)

Last Answer : (D) All (A), (B) and (C)

An identified source of irrigation water has ion concentrations of Na+ , Ca++ and Mg++ as 20, 10 and 8 milliequivalents per litre, respectively. The SAR of this water is approximately : a) 2.06 b) 6.67 c) 2.67 d) zero

Description : An identified source of irrigation water has ion concentrations of Na+ , Ca++ and Mg++ as 20, 10 and 8 milliequivalents per litre, respectively. The SAR of this water is approximately : a) 2.06 b) 6.67 c) 2.67 d) zero

Last Answer : b) 6.67

If a 2% solution of sewage sample is incubated for 5 days at 20°C and the dissolved oxygen depletion was found to be 8 mg/l. The BOD of the sewage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l

Description : If a 2% solution of sewage sample is incubated for 5 days at 20°C and the dissolved oxygen depletion was found to be 8 mg/l. The BOD of the sewage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l

Last Answer : ANS: D

If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l

Description : If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l

Last Answer : ANS: D

Phenolic water generated in coke ovens & by-product plant attached to an integrated steel plant containing phenol in concentration of less than 100 mg/litre can be removed by (A) Chlorination (B) Treating in biological oxygen pond (C) Chemical coagulation (D) None of these

Description : Phenolic water generated in coke ovens & by-product plant attached to an integrated steel plant containing phenol in concentration of less than 100 mg/litre can be removed by (A) Chlorination (B) Treating in biological oxygen pond (C) Chemical coagulation (D) None of these

Last Answer : (B) Treating in biological oxygen pond

Pick out the wrong statement.(A) Biological oxygen demand (BOD) is a characteristic and not a constituent of water (B) BOD is a measure of the amount of oxygen which will be demanded & used in 5 days by the biological decomposition of the organic matter present in water stream present as food for the living organism (C) BOD is expressed in mg/litre (typically, BOD=2.5 mg/litre for potable water) (D) None of these

Description : Pick out the wrong statement. (A) Biological oxygen demand (BOD) is a characteristic and not a constituent of water (B) BOD is a measure of the amount of oxygen which will be demanded & used in 5 days ... BOD is expressed in mg/litre (typically, BOD=2.5 mg/litre for potable water) (D) None of these

Last Answer : (D) None of these

Pick out the correct statement. (A) Chemical oxygen demand (COD) is a measure of chemically oxidisable organic matter present in water (B) COD is determined by oxidising the organic matter present in water with potassium dichromate in cone, sulphuric acid solution at boiling temperature for specified time (C) COD is related to BOD of a given waste in water but the relationship varies for different wastes. Typically COD of potable water may be 1-2 mg/litre (D) All (A), (B) and (C)

Description : Pick out the correct statement. (A) Chemical oxygen demand (COD) is a measure of chemically oxidisable organic matter present in water (B) COD is determined by oxidising the organic matter present in water with potassium dichromate ... of potable water may be 1-2 mg/litre (D) All (A), (B) and (C)

Last Answer : (D) All (A), (B) and (C)

A river with an inflow of domestic sewage rich in organic waste may result in (a) an increased production of fish due to biodegradable nutrients (b) death of fish due to lack of oxygen (c) drying of the river very soon due to algal bloom (d) increased population of aquatic food web organisms.

Description : A river with an inflow of domestic sewage rich in  organic waste may result in  (a) an increased production of fish due to  biodegradable nutrients (b) death of fish due to lack of oxygen ( ... of the river very soon due to algal bloom (d) increased population of aquatic food web  organisms.

Last Answer : (d) increased population of aquatic food web  organisms.

A lake which is rich in organic waste may result in (a) increased population of aquatic organisms due to minerals (b) drying of the lake due to algal bloom (c) increased population of fish due to lots of nutrients (d) mortality of fish due to lack of oxygen.

Description : A lake which is rich in organic waste may result in (a) increased population of aquatic organisms due  to minerals (b) drying of the lake due to algal bloom (c) increased population of fish due to lots of  nutrients (d) mortality of fish due to lack of oxygen.

Last Answer : (d) mortality of fish due to lack of oxygen.

A river with an inflow of domestic sewage rich in organic waste may result in (a) an increased production of fish due to biodegradable nutrients (b) death of fish due to lack of oxygen (c) drying of the river very soon due to algal bloom (d) increased population of aquatic food web organisms.

Description : A river with an inflow of domestic sewage rich in organic waste may result in (a) an increased production of fish due to biodegradable nutrients (b) death of fish due to lack of oxygen (c) drying of the river very soon due to algal bloom (d) increased population of aquatic food web organisms.

Last Answer : (b) death of fish due to lack of oxygen

A lake which is rich in organic waste may result in (a) increased population of aquatic organisms due to minerals (b) drying of the lake due to algal bloom (c) increased population of fish due to lots of nutrients (d) mortality of fish due to lack of oxygen.

Description : A lake which is rich in organic waste may result in (a) increased population of aquatic organisms due to minerals (b) drying of the lake due to algal bloom (c) increased population of fish due to lots of nutrients (d) mortality of fish due to lack of oxygen.

Last Answer : (d) mortality of fish due to lack of oxygen.

Dissolved oxygen (DO) should not be less than _____________ mg/L of water. (a) 14 (b) 3 (c) 5 (d) 2

Description : Dissolved oxygen (DO) should not be less than _____________ mg/L of water. (a) 14 (b) 3 (c) 5 (d) 2

Last Answer : Ans:(c)

(2) amount of oxygen used for biochemical oxidation Explanation: Biochemical oxygen demand or B.O.D. is the amount of dissolved oxygen needed by aerobic biological organisms in a body of water to break down organic material present in a given water sample at certain temperature over a specific time period. The term also refers to a chemical procedure for determining this amount. This is not a precise quantitative test, although it is widely used as an indication of the organic quality of water.

Description : (2) amount of oxygen used for biochemical oxidation Explanation: Biochemical oxygen demand or B.O.D. is the amount of dissolved oxygen needed by aerobic biological organisms in a body of water to ... quantitative test, although it is widely used as an indication of the organic quality of water.

Last Answer : The addition of gypsum to port-land cement helps in : (1) increasing the strength of cement (2) rapid setting of cement (3) preventing rapid setting of cement (4) reduction in the cost of cement

BOD of raw municipal sewage may be in the range of about __________ mg/litre. (A) 1-2 (B) 5-10 (C) 150-300 (D) 2000-3000

Description : BOD of raw municipal sewage may be in the range of about __________ mg/litre. (A) 1-2 (B) 5-10 (C) 150-300 (D) 2000-3000

Last Answer : (C) 150-300

COD of raw municipal sewage may be in the range of about __________ mg/litre. (A) 1-2 (B) 5-10 (C) 90-120 (D) 1500-2500

Description : COD of raw municipal sewage may be in the range of about __________ mg/litre. (A) 1-2 (B) 5-10 (C) 90-120 (D) 1500-2500

Last Answer : (C) 90-120

Maximum permissible residual chlorine in treated water should be __________ mg/litre. (A) 0.001 to 0.01 (B) 0.2 to 0.3 (C) 2 to 3 (D) 5 to 10

Description : Maximum permissible residual chlorine in treated water should be __________ mg/litre. (A) 0.001 to 0.01 (B) 0.2 to 0.3 (C) 2 to 3 (D) 5 to 10

Last Answer : (B) 0.2 to 0.3

10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 mL of 1.0 M Mohr salt solution was added c

Description : 10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 mL of 1.0 M Mohr salt solution was added c

Last Answer : 10g sample of bleaching powder was dissolved into water to make the solution one litre. To this solution 35 ... Cl_(2)` approximately is (mol wt = 71)

The half life of a radioactive element is 8-days. How long it take to reduce it from 10 mg to 5 mg? A. 4 days B. 12 days C. 16 days D. 8 days (Answer) E. None of these

Description : The half life of a radioactive element is 8-days. How long it take to reduce it from 10 mg to 5 mg? A. 4 days B. 12 days C. 16 days D. 8 days (Answer) E. None of these

Last Answer : D. 8 days (Answer)

In sewage, the solids in mg per litre is A. 100 to 500 B. 500 to 1000 C. 1000 to 1500 D. 1500 to 2000

Description : In sewage, the solids in mg per litre is A. 100 to 500 B. 500 to 1000 C. 1000 to 1500 D. 1500 to 2000

Last Answer : ANS: B

Dose of chlorine for disinfection of water is about __________ mg/litre of water. (A) 0.01 (B) 0.1 (C) 0.3 (D) 1

Description : Dose of chlorine for disinfection of water is about __________ mg/litre of water. (A) 0.01 (B) 0.1 (C) 0.3 (D) 1

Last Answer : (D) 1

Which is the best and the most effective method for the removal of organic contaminant present in the polluted water in very small quantity (say < 200 mg/litre)? (A) Lagooning (B) Activated carbon adsorption (C) Biological oxidation pond (D) Chemical coagulation

Description : Which is the best and the most effective method for the removal of organic contaminant present in the polluted water in very small quantity (say < 200 mg/litre)? (A) Lagooning (B) Activated carbon adsorption (C) Biological oxidation pond (D) Chemical coagulation

Last Answer : (B) Activated carbon adsorption

The ensure proper growth of children's teeth, the quantity of fluoride used in water mains, is (A) 1 mg/litre (B) 2 mg/litre (C) 3 mg/litre (D) 5 mg/litre

Description : The ensure proper growth of children's teeth, the quantity of fluoride used in water mains, is (A) 1 mg/litre (B) 2 mg/litre (C) 3 mg/litre (D) 5 mg/litre

Last Answer : (A) 1 mg/litre

For plain chlorination of water, the quantity of chlorine used, is (A) 0.1 mg/litre (B) 0.2 mg/litre (C) 0.3 mg/litre (D) 0.5 mg/litre

Description : For plain chlorination of water, the quantity of chlorine used, is (A) 0.1 mg/litre (B) 0.2 mg/litre (C) 0.3 mg/litre (D) 0.5 mg/litre

Last Answer : (D) 0.5 mg/litre

In slow sand filters, the turbidity of raw water can be removed only up to (A) 60 mg/litre (B) 75 mg/litre (C) 100 gm/litre (D) 150 mg/litre

Description : In slow sand filters, the turbidity of raw water can be removed only up to  (A) 60 mg/litre  (B) 75 mg/litre  (C) 100 gm/litre  (D) 150 mg/litre 

Last Answer : (A) 60 mg/litre 

The maximum permissible hardness for public supplies is (A) 95 mg/litre (B) 105 mg/litre (C) 115 mg/litre(D) 125 mg/litre

Description : The maximum permissible hardness for public supplies is  (A) 95 mg/litre  (B) 105 mg/litre  (C) 115 mg/litre (D) 125 mg/litre

Last Answer : (C) 115 mg/litre

48 g of `SO_(3)` , 12.8 g of `SO_(2)` and 9.6 g of `O_(2)` are present in one litre . The respective active masses will be

Description : 48 g of `SO_(3)` , 12.8 g of `SO_(2)` and 9.6 g of `O_(2)` are present in one litre . The respective active masses will be

Last Answer : 48 g of `SO_(3)` , 12.8 g of `SO_(2)` and 9.6 g of `O_(2)` are present in one litre . The respective active ... .6 , 0.4 and 0.2 D. 1.0 , 0.5 and 1.5

A tank can be filled by an inlet tap at the rate of 8 litres per minute. A leak in the bottom of a tank can empty the full tank in 16 hours. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 80 hours. How many litres does the tank hold? A) 8000 litre B) 9560 litre C) 8525 litre D) 9600 litre

Description : A tank can be filled by an inlet tap at the rate of 8 litres per minute. A leak in the bottom of a tank can empty the full tank in 16 hours. When the tank is full, the inlet is opened and due to ... hours. How many litres does the tank hold? A) 8000 litre B) 9560 litre C) 8525 litre D) 9600 litre

Last Answer : D Part emptied by the leak in 1 hour = 1/16 part filled by (leak & inlet open) in 1 hour = 1/80 Part filled by the inlet tap in 1 hour = 1/16 – 1/80 = 1/20 Inlet tap fills the tank in = 20 hours Inlet tap fills water at the rate of 8 litres a minute. Capacity of tank = 20 * 60 * 8= 9600 litre

(a) Draw a diagram of human respiratory system and label the following: (i) part where air is filtered by fine hair and mucus (ii) part which terminates in balloon – like structures (iii) balloon – like structures where exchange of gases takes place. (iv) part which separates chest cavity from abdominal cavity. (b) Why is the rate of breathing in aquatic organisms much faster than in terrestrial organisms? -Biology

Description : (a) Draw a diagram of human respiratory system and label the following: (i) part where air is filtered by fine hair and mucus (ii) part which terminates in balloon - like structures (iii) ... (b) Why is the rate of breathing in aquatic organisms much faster than in terrestrial organisms? -Biology

Last Answer : (a) (b) Quantity of dissolved oxygen is fairly low in water as compared to the amount of oxygen in air. Aquatic organisms therefore have to breath faster than terrestrial organisms to absorb the required amount of oxygen from the water.

$ Anarobic respiration occurs in the aquatic organisms. ! Aquatic organisms are never autotrophic.

Description : $ Anarobic respiration occurs in the aquatic organisms. ! Aquatic organisms are never autotrophic.

Last Answer : $ Anarobic respiration occurs in the aquatic organisms. ! Aquatic organisms are never autotrophic. A. If both ... D. If both As and R are wrong.

$ Viruses are at a border line position between living and non living. ! Phytoplanktons are those living organisms which are aquatic.

Description : $ Viruses are at a border line position between living and non living. ! Phytoplanktons are those living organisms which are aquatic.

Last Answer : $ Viruses are at a border line position between living and non living. ! Phytoplanktons are those living ... wrong D. If both As and R are wrong.

For the aquatic organisms, the source of food is – (1) Phytoplankton (2) Sea Weed (3) Aqua plankton (4) Zooplankton

Description : For the aquatic organisms, the source of food is – (1) Phytoplankton (2) Sea Weed (3) Aqua plankton (4) Zooplankton

Last Answer : (4) Zooplankton Explanation: Zooplankton are a type of heterotrophic plankton that range from microscopic organisms to large species, such as jellyfish.

Benthic organisms are affected the most by (a) light reaching the forest floor (b) surface turbulence of water (c) sediment characteristics of aquatic ecosystems (d) water-holding capacity of soil

Description : Benthic organisms are affected the most by (a) light reaching the forest floor (b) surface turbulence of water (c) sediment characteristics of aquatic ecosystems (d) water-holding capacity of soil

Last Answer : c) sediment characteristics of aquatic ecosystems

Match the organisms in column-I with habitats in column-II. Column-I Column-II A. Halophiles (i) Hot springs B. Thermoacidophiles (ii) Aquatic environment C. Methanogens (iii)Guts of ruminants D. Cyanobacteria (iv) Salty area Select the correct answer from the options given below. (a) A-(iv), B-(i), C-(iii), D-(ii) (b) A-(i), B-(ii), C-(iii), D-(iv) (c) A-(iii), B-(iv), C-(ii), D-(i) (d) A-(ii), B-(iv), C-(iii), D-(i)

Description : Match the organisms in column-I with habitats in column-II. Column-I Column-II A. Halophiles (i) Hot springs B. Thermoacidophiles (ii) Aquatic environment C. Methanogens (iii)Guts of ruminants D. Cyanobacteria (iv) Salty area Select the correct ... , C-(ii), D-(i) (d) A-(ii), B-(iv), C-(iii), D-(i)

Last Answer : (a) A-(iv), B-(i), C-(iii), D-(ii)

What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone [Pb. CET 2001] (A) 22.4 litre (B) 2.016 litre (C) 2.24 litre (D) 20.16 litre

Description : What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone [Pb. CET 2001] (A) 22.4 litre (B) 2.016 litre (C) 2.24 litre (D) 20.16 litre

Last Answer : (B) 2.016 litre

pH value of soil is maintained at __________ by the addition of fertiliser for optimum growth and health of the plant. (A) 4-5 (B) 7-8 (C) 9-10 (D) 12-13

Description : pH value of soil is maintained at __________ by the addition of fertiliser for optimum growth and health of the plant. (A) 4-5 (B) 7-8 (C) 9-10 (D) 12-13

Last Answer : (B) 7-8

Which one of the following statements is wrong? (a) Algae increase the level of dissolved oxygen in the immediate environment. (b) Algin is obtained from red algae, and carrageenan from brown algae. (c) Agar-agar is obtained from Gelidium and Gracilaria. (d) Laminaria and Sargassum are used as food.

Description : Which one of the following statements is wrong? (a) Algae increase the level of dissolved oxygen in the immediate environment. (b) Algin is obtained from red algae, and carrageenan from brown ... Agar-agar is obtained from Gelidium and Gracilaria. (d) Laminaria and Sargassum are used as food.

Last Answer : (b) Algin is obtained from red algae, and carrageenan from brown algae

On nephelometry turbidity unit (NTU) is equal to the turbidity produced by (a) 1 mg SiO2 dissolved in 1 l of distilled water with the test being run according to absorption principle (b) 1 mg SiO2 dissolved in 1 l of distilled water with the test being run according t scattering principle (c) 1 mg Formazin dissolved in 1 l of distilled water with the test being run according to absorption principle (d) 1 mg Formazin dissolved in 1 l o f distilled water with the test being run according to scattering principle.

Description : On nephelometry turbidity unit (NTU) is equal to the turbidity produced by (a) 1 mg SiO2 dissolved in 1 l of distilled water with the test being run according to absorption principle (b) 1 ... Formazin dissolved in 1 l o f distilled water with the test being run according to scattering principle.

Last Answer : (d) 1 mg Formazin dissolved in 1 l o f distilled water with the test being run according to scattering principle.

With regard to standard of quality of drinking water as laid down by Indian Railway , the requirement (desirable) limit of total dissolved solids should not be more than---------- mg/l a)200 b) 300 c) 400 d) 500*

Description : With regard to standard of quality of drinking water as laid down by Indian Railway , the requirement (desirable) limit of total dissolved solids should not be more than---------- mg/l a)200 b) 300 c) 400

Last Answer : d) 500*

The concentration of Total Dissolved Solids (TDS) in drinking water should not exceed (A) 500 mg/L (B) 400 mg/L (C) 300 mg/L (D) 200 mg/L

Description : The concentration of Total Dissolved Solids (TDS) in drinking water should not exceed (A) 500 mg/L (B) 400 mg/L (C) 300 mg/L (D) 200 mg/L

Last Answer : (A) 500 mg/L

In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Description : In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Last Answer : C)1:2

Three of the following statements about enzymes are correct and one is wrong. Which one is wrong? (a) Enzymes require optimum pH for maximal activity. (b) Enzymes are denatured at high temperature but in certain exceptional organisms they are effective even at temperatures 80° - 90°C. (c) Enzymes are highly specific. (d) Most enzymes are proteins but some are lipids.

Description : Three of the following statements about enzymes are correct and one is wrong. Which one is wrong? (a) Enzymes require optimum pH for maximal activity. (b) Enzymes are denatured at high temperature but ... - 90°C. (c) Enzymes are highly specific. (d) Most enzymes are proteins but some are lipids.

Last Answer : (d) Most enzymes are proteins but some are lipids.

It is required to maintain a therapeutic concentration of 10 microgram/mL for 12 hours of a drug having half life of 1.386 hr and Vd of 5 L. The dose required in a sustained release product will be (A) 600 mg (B) 300 mg (C) 30 mg (D) 60 mg

Description : It is required to maintain a therapeutic concentration of 10 microgram/mL for 12 hours of a drug having half life of 1.386 hr and Vd of 5 L. The dose required in a sustained release product will be (A) 600 mg (B) 300 mg (C) 30 mg (D) 60 mg

Last Answer : (B) 300 mg

How do organisms use the properties of water for survival?

Description : How do organisms use the properties of water for survival?

Last Answer : Need answer

When organisms in the ecosphere diethey are broken down by bacteria.Nutrientssuch as nitratesare released back into the ecosphere.Why is this necessary for the survival of the other organisms in t?

Description : When organisms in the ecosphere diethey are broken down by bacteria.Nutrientssuch as nitratesare released back into the ecosphere.Why is this necessary for the survival of the other organisms in t?

Last Answer : What is the answer ?