What are the typical lengths for a tape measure?

What are the typical lengths for a tape measure?
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1 Answer

Answer :

Standard tape measures run anywhere from 10 feet to 35 feet long. However, tape measures come in a variety of sizes. There are measuring tapes as long as 300 feet available at home improvement stores such as The Home Depot.
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Codes consisting of lines of varying widths or lengths that arecomputer-readable are known as– (A) an ASCII code (B) a magnetic tape (C) an OCR scanner (D) a bar code (E) None of these

Description : Codes consisting of lines of varying widths or lengths that arecomputer-readable are known as– (A) an ASCII code (B) a magnetic tape (C) an OCR scanner (D) a bar code (E) None of these

Last Answer : a bar code

Codes consisting of lines of varying widths or lengths that are computer - readable are known as _______: a) an ASCII code b) a magnetic tape c) an OCR scanner d) a bar code e) None of The Above

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The magnitude of ‘sag correction’ during measurement of lengths by taping is proportional to the : (a) Cube of the weight of the tape, in kg per m run (b) Cube root of the weight of the tape, in kg per m run (c) Square of the weight of the tape, in kg per m run (d) Square root of the weight of the tape, in kg per m run

Description : The magnitude of sag correction' during measurement of lengths by taping is proportional to the : (a) Cube of the weight of the tape, in kg per m run (b) Cube root of the weight of the tape, in kg per m run ... the tape, in kg per m run (d) Square root of the weight of the tape, in kg per m run

Last Answer : (c) Square of the weight of the tape, in kg per m run

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Description : What is 22.9 on a tape measure?

Last Answer : It is 22 9/10 lots of the measurement unit.

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Description : What is 1.9 cm on a tape measure?

Last Answer : It is a length of 1.9 centimetres.

What is the first increment on a tape measure?

Description : What is the first increment on a tape measure?

Last Answer : What is the answer ?

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Description : Air gap readings should be periodicly taken for electrical generation equipment. The best tool to use to take these measurements is a ___________. A. cloth (non-metalic) tape measure B. dial indicator C. inside micrometer D. tapered, long blade, feeler gage

Last Answer : Answer: D

The unit KIPS is used to measure the speed of: a) Processor b) Disk drive c) Printer d) Tape drive e) None of these

Description : The unit KIPS is used to measure the speed of: a) Processor b) Disk drive c) Printer d) Tape drive e) None of these

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You plan to measure your tape recorder’s SNR. What test equipment will you need?

Description : You plan to measure your tape recorder’s SNR. What test equipment will you need?

Last Answer : A VTVM and a signal generator.

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Description : How to Read a Tape Measure

Last Answer : How to Read a Tape Measure Introduction Reading a tape measure is fairly simple. At some point, you may need to learn this method. Everyone is presented with the need for this device at one time or ... hand. Take extra care and check the measurement 2 or 3 times to be sure that they are correct.

Which of the following is not a typical attribute of goods? (a) output can be inventoried ; (b) aspects of quality difficult to measure (c) output can be resold ; (c) production and consumption are separate

Description : Which of the following is not a typical attribute of goods? (a) output can be inventoried ; (b) aspects of quality difficult to measure (c) output can be resold ; (c) production and consumption are separate

Last Answer : (b) aspects of quality difficult to measure

Why would an atheist, or group of atheists, go to such lengths to try and convince believers that God doesn't exist?

Description : Why would an atheist, or group of atheists, go to such lengths to try and convince believers that God doesn't exist?

Last Answer : Why do you not ask the same question of theists?

Why is it so hard for some people to imagine what incredible lengths they would go to to get something to eat, if they were literally starving to death?

Description : Why is it so hard for some people to imagine what incredible lengths they would go to to get something to eat, if they were literally starving to death?

Last Answer : Living in a country where obesity is rampant might have something to do with it.

Why is it that when you fold your fingers down, they are all the same length, but when you put them straight up they are all different lengths?

Description : Why is it that when you fold your fingers down, they are all the same length, but when you put them straight up they are all different lengths?

Last Answer : Mine don’t. But can you touch your elbows behind your back?

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Description : What's the nastiest or strangest thing you've ever pawed through; what are the greatest lengths you've ever gone to try to find or retrieve something of monetary or sentimental value that you've lost?

Last Answer : I’ve walked for miles to heal a wounded relationship.

What lengths would you do to assure someone does not get on the roadway drunk?

Description : What lengths would you do to assure someone does not get on the roadway drunk?

Last Answer : I would be prepared to steal the distributor cap, or take the keys to drive the car and the person home myself. There is no excuse for drink driving, and it is irresponsible to let a friend do ... when a friend drink drives, you are putting their life at risk, as well as innocent road users.

Non morning people: What’s the most extreme lengths you’ve gone to wake up early in the morning?

Description : Non morning people: What’s the most extreme lengths you’ve gone to wake up early in the morning?

Last Answer : My go-to is always just staying up

I have three colors, each with a different meaning. When I'm old they become dull, but when I'm new they are gleaming. I help keep people safe, but sometimes they hate me. You won't see me in a forest, but you will in a big city. Some of me have short lengths, and some of me have long. And in the time that the longest of me take, you could sing a very long song. When my colors change, people get happy or sad, and when you guess what I am, you will be very glad. What am I? -Riddles

Description : I have three colors, each with a different meaning. When I'm old they become dull, but when I'm new they are gleaming. I help keep people safe, but sometimes they hate me. You won't see me in a forest, ... get happy or sad, and when you guess what I am, you will be very glad. What am I? -Riddles

Last Answer : A Stoplight.

If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Description : If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Last Answer : LET EACH SIDE BE X 6X+11X+15X=96 32X=96 X=3 SIDES=6 3=18 11 3=33 15 3=45 AREA OF TRIANGLE BY HERONS FORMULA=S=96/2=48 WHOLE UNDERROOT 48 48-18 48-33 48-45 UNDERROOT=12 4 30 15 3 4 3 15ROOT2 180 ... bh/2 180root2=18 h/2 360root2=18h h=20 root2 But root 2=1.4(approx) h=20 1.4(approx) h=28cm(approx).

If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Description : If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Last Answer : (d) Given, the length of two sides of a triangle are 5 cm and 1.5 cm, respectively. Let sides AB = 5 cm and CA = 1.5 cm We know that, a closed figure formed by three intersecting lines ( ... options (a), (b) and (c) satisfy the above inequality but option (d) does not satisfy the above inequality.

Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Last Answer : No, it is not possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm because here we see that sum of the lengths of two sides is equal to third side i.e., 4+3 ... , the sum of any two sides of a triangle is greater than its third side, so given statement is not correct.

If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Description : If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Last Answer : LET EACH SIDE BE X 6X+11X+15X=96 32X=96 X=3 SIDES=6 3=18 11 3=33 15 3=45 AREA OF TRIANGLE BY HERONS FORMULA=S=96/2=48 WHOLE UNDERROOT 48 48-18 48-33 48-45 UNDERROOT=12 4 30 15 3 4 3 15ROOT2 180 ... bh/2 180root2=18 h/2 360root2=18h h=20 root2 But root 2=1.4(approx) h=20 1.4(approx) h=28cm(approx).

If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Description : If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Last Answer : (d) Given, the length of two sides of a triangle are 5 cm and 1.5 cm, respectively. Let sides AB = 5 cm and CA = 1.5 cm We know that, a closed figure formed by three intersecting lines ( ... options (a), (b) and (c) satisfy the above inequality but option (d) does not satisfy the above inequality.

Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Last Answer : No, it is not possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm because here we see that sum of the lengths of two sides is equal to third side i.e., 4+3 ... , the sum of any two sides of a triangle is greater than its third side, so given statement is not correct.

Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Description : Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Last Answer : We know that, each angle of a rectangle is right angle (i.e., 90°) and its opposite sides are equal and parallel. To construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm, use the ... AD and CD. Thus, ABCD is the required rectangle with adjacent sides of length 5 cm and 3.5 cm.

A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Description : A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Last Answer : we know that , all sides of a rhombus are equal and the diagonals of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4cm and 6cm ... ) From Eqs. (i) and (ii), AB = BC = CD = DA Hence , ABCD is a rhombus.

Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Description : Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Last Answer : To construct a triangle ABC in which AB = 3.6 cm, AC = 3.0 cm and BC = 4. 8 cm, use the following steps. 1.Draw a line segment BC of length 4.8 cm. 2.From B, point A is at a distance of 3.6 ... 3.Joining BP, we obtain angle bisector of ∠B. 4.Flere, ∠ABC=39° Thus, ∠ABD = ∠DBC = 1/2 x 139° = 19.5°

A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Description : A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Last Answer : We know that, all sides of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4 cm and 6 cm use the following steps. 1.Draw ... B and D. 6.Now, join AB, BC, CD, and DA . Thus, ABCD is the required rhombus.

Is it possible to construct a triangle with lengths of its sides 5cm, 3cm and 8cm? Give reason for your answer. -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides 5cm, 3cm and 8cm? Give reason for your answer. -Maths 9th

Last Answer : Solution :- No, since sum of two sides is equal to third side. (5 cm + 3 cm = 8 cm)

Is it possible to construct a triangle with lengths of its sides as 7 cm, 8 cm and 5 cm? Give reason for your answer. -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides as 7 cm, 8 cm and 5 cm? Give reason for your answer. -Maths 9th

Last Answer : Solution :- Yes, because in each case sum of two sides is greater than the third side.

Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm

The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of other chord from the centre? -Maths 9th

Description : The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of other chord from the centre? -Maths 9th

Last Answer : There are two parallel chords of length 8 cm and 6 cm. The distance between center and shortest chord (6cm chord) is 4cm. So, the perpendicular distance from the center to the shortest chord is 4cm. The ... 32+42 =5. Since the radius is 5. The distance from center to largest chord is 52−42 =3.

The lengths of the sides of a triangle are 7 cm, 13 cm and 12 cm. -Maths 9th

Description : The lengths of the sides of a triangle are 7 cm, 13 cm and 12 cm. -Maths 9th

Last Answer : Let, a = 7 cm, b = 13 cm, c = 12 cm ∴ s = (a + b + c)/2 = (7 +13 +12)/2 = 32/2 = 16 cm Area of △ ABC = under root( √s(s -a) (s - b)(s -c)) = under root( √16(16 - 7)(16 - 13)(16 - 12) = ... 24 √3 cm2 Also, Area of △ ABC = 1/2AC.BD 24 √3 = 1/2 x 12 x BD ⇒ BD = (24 √3 x 2)/12 = 4 √3 cm

The lengths of two adjacent sides of a parallelogram are 17 cm and 12 cm. -Maths 9th

Description : The lengths of two adjacent sides of a parallelogram are 17 cm and 12 cm. -Maths 9th

Last Answer : For △BCD: Let a = 17 cm, b = 12 cm, c = 25 cm So its semi-perimeter, s = (a + b + c)/2 = (17 + 12 + 25)/2 = 27 cm ∴ Area of △BCD = root under(√(s -a)(s - b)(s - c)) = ... △BCD = 2 x 90 = 180 cm2 Also, area of parallelogram ABCD = DC x AE ∴ 180 = 12 x AE ⇒ AE = 180/12 = 15 cm

If the length of hypotenuse of a right angled triangle is 5 cm and its area is 6 sq cm, then what are the lengths of the remaining sides? -Maths 9th

Description : If the length of hypotenuse of a right angled triangle is 5 cm and its area is 6 sq cm, then what are the lengths of the remaining sides? -Maths 9th

Last Answer : Let one of the remaining sides be x cm.Then, other side = \(\sqrt{5^2-x^2}\) cm∴ Area = \(rac{1}{2} imes{x} imes\sqrt{25-x^2}\) = 6⇒ \(x\sqrt{25-x^2}\) = 12 ⇒ x2(25 - x2) = 144⇒ 25x2 - x4 = 144 ⇒ x4 - 25x2 ... (x2 - 16) (x2 - 9) = 0 ⇒ x2 = 16 or x2 = 9 ⇒ x = 4 or 3∴ The two sides are 4 cm and 3 cm.

The lengths of the perpendiculars drawn from any point in the interior of an equilateral -Maths 9th

Description : The lengths of the perpendiculars drawn from any point in the interior of an equilateral -Maths 9th

Last Answer : (a) \(rac{2}{\sqrt3}\) (p1 + p2 + p3) Let each side of equilateral ΔPQR = a units. O is any point in the interior of DΔPQR ⇒ OD = p1, OE = p2 and OF = p3 are perpendiculars on sides PQ, PR and QR respectively. ∴ Area of ... }{4}a^2\) = \(rac{a}{2}(p_1+p_2+p_3)\) ⇒ \(rac{2}{\sqrt3}\) (p1 + p2 + p3)

The lengths of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of this triangle is -Maths 9th

Description : The lengths of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of this triangle is -Maths 9th

Last Answer : (b) 72 cm2Here sm = \(rac{9+12+15}{2}\) = 18 cm, where lengths of medians are m1 = 9 cm, m2 = 12 cm, m3 = 15 cm.∴ Area of triangle = \(rac{4}{3}\sqrt{18(18-9)(18-12)(18-15)}\) cm2= \(rac{4}{3}\sqrt{18 imes9 imes6 imes3}\) cm2 = \(rac{4}{3}\) x 9 x 6 cm2 = 72 cm2.

What is the radius of a circle inscribed in a triangle having side lengths 35 cm, 44 cm and 75 cm? -Maths 9th

Description : What is the radius of a circle inscribed in a triangle having side lengths 35 cm, 44 cm and 75 cm? -Maths 9th

Last Answer : (d) 6 cmLet a = 35 cm, b = 44 cm, c = 75 cm. Thens = \(rac{a+b+c}{2}\) = \(rac{34+44+75}{2}\) cm = 77 cm∴ Area if triangle = \(\sqrt{77(77-35)(77-44)(77-75)}\) cm2= \(\sqrt{77 imes42 ... ) cm2 = 462 cm2∴ Radius of incircle = \(rac{ ext{Area}}{ ext{semi-perimeter}}\) = \(rac{462}{77}\) cm = 6 cm.

If the lengths of a sides of a triangle are in the ratio 4 : 5 : 6 and the in-radius of the triangle is 3 cm, -Maths 9th

Description : If the lengths of a sides of a triangle are in the ratio 4 : 5 : 6 and the in-radius of the triangle is 3 cm, -Maths 9th

Last Answer : (b) 7.5 cm.Area of a triangle = \(rac{1}{2}\)x base x height= In-radius x semi-perimeter of the Δ \(\big[ ext{Using r =}rac{\Delta}{s}\big]\)Let the sides of triangle be 4x, 5x and 6x respectively. Given: In-radius = 3 ... x \(rac{15x}{2}\) = \(rac{6x}{2}\) x h ⇒ h = \(rac{45}{6}\) = 7.5 cm.

The base of a right prism is a trapezium. The lengths of the parallel sides are 8 cm and 14 cm and the distance between the parallel -Maths 9th

Description : The base of a right prism is a trapezium. The lengths of the parallel sides are 8 cm and 14 cm and the distance between the parallel -Maths 9th

Last Answer : Area of trapezium =12×h(AB+CD) =12×8×(8+14)=12×8×(8+14) =4×22=88cm2=4×22=88cm2 = Volume of prism = Height of prism ×× area of base ⇒height×88=1056 (given)⇒height×88=1056 (given) ⇒height×88=105688⇒height×88=105688 ⇒12cm =12×h(AB+CD)

Let a, b, c be the lengths of the sides of a right angled triangle, the hypotenuse having the length c, then a + b is -Maths 9th

Description : Let a, b, c be the lengths of the sides of a right angled triangle, the hypotenuse having the length c, then a + b is -Maths 9th

Last Answer : answer:

If a, b, c are the lengths of the sides of a non-equilateral triangle, then -Maths 9th

Description : If a, b, c are the lengths of the sides of a non-equilateral triangle, then -Maths 9th

Last Answer : https://discuss.aiforkids.in/36748/if-are-the-lengths-of-the-sides-non-equilateral-triangle-then

In an equilateral triangle if a, b and c denote the lengths of the perpendicular from A, B and C respectively on the opposite sides, then -Maths 9th

Description : In an equilateral triangle if a, b and c denote the lengths of the perpendicular from A, B and C respectively on the opposite sides, then -Maths 9th

Last Answer : b=2c=3​⇒⇒b=3​c=23​​cosA=2bcb2+c2−a2​⇒23​​=33+43​−a2​⇒233​​=415​−a2 ⇒a2=415​−43​​⇒a=1.673278 We know sinaa​=2R1​⇒R=2asina​=221​​=41​

The lengths of the sides a, b, c of a ΔABC are connected by the relation a^2 + b^2 = 5c^2. The angle between medians drawn to the sides 'a' and 'b' is -Maths 9th

Description : The lengths of the sides a, b, c of a ΔABC are connected by the relation a^2 + b^2 = 5c^2. The angle between medians drawn to the sides 'a' and 'b' is -Maths 9th

Last Answer : Let median through C be CF. AF=FB=c2 CF=122(a2+b2)−c2−−−−−−−−−−−−√=3c2 CG=c where G is the centroid and GF=c2 34( ... +M2b+9c24 c2=(23M2a)+(23M2b) BC2=AG2+BG2 So medians through A and B are perpendicular.

In a trapezoid ABCD, side BC is parallel to side AD. Also, the lengths of the sides AB, BC, CD and AD are 8, 2, 8 and 10 units respectively -Maths 9th

Description : In a trapezoid ABCD, side BC is parallel to side AD. Also, the lengths of the sides AB, BC, CD and AD are 8, 2, 8 and 10 units respectively -Maths 9th

Last Answer : answer:

The line through the points (4, 3) and (2, 5) cuts off intercepts of lengths λ and μ on the axes. Which one of the following is correct ? -Maths 9th

Description : The line through the points (4, 3) and (2, 5) cuts off intercepts of lengths λ and μ on the axes. Which one of the following is correct ? -Maths 9th

Last Answer : (c) a, b, c are in H.P. only for all m As the points A(a, ma), B[b, (m + 1)b] and C[c, (m + 2)c] are collinear. Area of Δ ABC should be equal to zero.⇒ \(rac{1}{2}\)[x1(y2 - y3) + x2(y3 - y1) + ... - bc = 0 ⇒ ab + bc = 2ac ⇒ b = \(rac{2ac}{a+c}\)∴ a, b, c are harmonic progression (H.P.) for all m.

A soccer ball is packaged in a cubic box with side lengths of 22 cm. Assuming that the ball touches all faces of the box, calculate what percentage of the volume of the box is wasted space Write it step by step pls?

Description : A soccer ball is packaged in a cubic box with side lengths of 22 cm. Assuming that the ball touches all faces of the box, calculate what percentage of the volume of the box is wasted space Write it step by step pls?

Last Answer : one centimetre

A soccer ball is packaged in a cubic box with side lengths of 22 cm. Assuming that the ball touches all faces of the box, calculate what percentage of the volume of the box is wasted space?

Description : A soccer ball is packaged in a cubic box with side lengths of 22 cm. Assuming that the ball touches all faces of the box, calculate what percentage of the volume of the box is wasted space?

Last Answer : one centimetre