Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?
Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0