Is 5 km 500 m?

Is 5 km 500 m?
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What percent of 2 km is 500 m?

Description : What percent of 2 km is 500 m?

Last Answer : n − 1

If diameter of a wheel is 1.26 m, what the distance covered in 500 revolutions? (a) 1.38 km (b) 4.64 km (c) 2.46 km (d) 1.98 km

Description : If diameter of a wheel is 1.26 m, what the distance covered in 500 revolutions? (a) 1.38 km (b) 4.64 km (c) 2.46 km (d) 1.98 km

Last Answer : (d) 1.98 km

Pick up the incorrect statement from the following: (A) Lead is the average horizontal straight distance between the borrow pit and the place of spreading soil (B) The lead is calculated for each block of the excavated area (C) The unit of lead is 50 m for a distance upto 500 m (D) The unit of lead is 1 km where the lead exceeds 2 km

Description : Pick up the incorrect statement from the following: (A) Lead is the average horizontal straight distance between the borrow pit and the place of spreading soil (B) The lead is calculated for each block of the ... a distance upto 500 m (D) The unit of lead is 1 km where the lead exceeds 2 km

Last Answer : (D) The unit of lead is 1 km where the lead exceeds 2 km

The approximate length of the coastline of India is – (1) 5.500 km (2) 6,000 km (3) 6,500 km (4) 7,000 km

Description : The approximate length of the coastline of India is – (1) 5.500 km (2) 6,000 km (3) 6,500 km (4) 7,000 km

Last Answer : (4) 7,000 km Explanation: India has a land frontier of 15,200 km and a coastline of 7,517 km. Length of Coastline of Indian mainland is 6100 km. Coastline of Indian mainland is surrounded by Arabian Sea in the west, Bay of Bengal in the east, and Indian Ocean in the south.

Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s.b. 2 c. 2.5 d. 5

Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5

Last Answer : b. 2

The approximate length of the coastline of India is (1) 5,500 km (2) 6,000 km (3) 6,500 km (4) 7,000 km

Description : The approximate length of the coastline of India is (1) 5,500 km (2) 6,000 km (3) 6,500 km (4) 7,000 km 

Last Answer : 7,000 km

The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed? -Science

Description : The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed? -Science

Last Answer : Average speed=total distancetime=50010=50Average speed=total distancetime=50010=50 km/hr Ratio of average speed to maximum speed= 50:90=5:9

A jet aeroplane travelling at the speed of 500 km/hr ejects its products of combustion at speed of 1500 km/hr relative to jet plane.

Description : A jet aeroplane travelling at the speed of 500 km/hr ejects its products of combustion at speed of 1500 km/hr relative to jet plane.

Last Answer : A jet aeroplane travelling at the speed of 500 km/hr ejects its products of combustion at speed ... latter with respect to an observer on the ground?

For design purposes, the normal rate of infiltration of ground water into the sewer, is A. 500 litres/km/cm B. 1000 litres/km/cm C. 1500 litres/km/cm D. 2000 litres/km/cm

Description : For design purposes, the normal rate of infiltration of ground water into the sewer, is A. 500 litres/km/cm B. 1000 litres/km/cm C. 1500 litres/km/cm D. 2000 litres/km/cm

Last Answer : ANS: D

What is the propagation delay when a signal is transmitter by an earth station to a geosynchronous satellite about 38,500 km above earth’s equator and then received by the same earth station? A. 256 msec B. 128 msec C. 300 msec D. 400 msec

Description : What is the propagation delay when a signal is transmitter by an earth station to a geosynchronous satellite about 38,500 km above earth’s equator and then received by the same earth station? A. 256 msec B. 128 msec C. 300 msec D. 400 msec

Last Answer : A. 256 msec

Express Parcel Post is all about value for money. It costs just INR 25 within the city for 2 kg parcels and INR 40 for towns within 500 km. Above statement is a) True b) False

Description : Express Parcel Post is all about value for money. It costs just INR 25 within the city for 2 kg parcels and INR 40 for towns within 500 km. Above statement is a) True b) False

Last Answer : a) True

For C band Synthetic Aperture Radar (SAR) with Doppler band width of 1300 Hz, the coherence length loch is: (A) 130 km (B) 230 km (C) 250 km (D) 500 km

Description : For C band Synthetic Aperture Radar (SAR) with Doppler band width of 1300 Hz, the coherence length loch is: (A) 130 km (B) 230 km (C) 250 km (D) 500 km

Last Answer : Answer: Option B

If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour

Description : If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour

Last Answer : Answer: Option C

How many km can an electric car go? A] 500 Km B] 700 km C] 450 km D] 100km

Description : How many km can an electric car go? A] 500 Km B] 700 km C] 450 km D] 100km

Last Answer : C] 450 km

The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Description : The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Last Answer : 300 kJ

Which cable length has the highest attenuation? ∙ A. 1 km ∙ B. 2 km ∙ C. 95 ft. ∙ D. 500 ft.

Description : Which cable length has the highest attenuation? ∙ A. 1 km ∙ B. 2 km ∙ C. 95 ft. ∙ D. 500 ft.

Last Answer : B. 2 km

For transmission of power over a distance of 500 km, the transmission voltage should be in the range (a) 150 to 220 kV (b) 100 to 120 kV (c) 60 to 100 kV (d) 20 to 50 kV

Description : For transmission of power over a distance of 500 km, the transmission voltage should be in the range (a) 150 to 220 kV (b) 100 to 120 kV (c) 60 to 100 kV (d) 20 to 50 kV

Last Answer : (a) 150 to 220 kV

What is the rupture length of 2004 Sumatra-Andaman earthquake? (A) 500 km (B) 5000 km (C) 1200 km (D) None of these

Description : What is the rupture length of 2004 Sumatra-Andaman earthquake? (A) 500 km (B) 5000 km (C) 1200 km (D) None of these

Last Answer : (C) 1200 km 

For a 500 Hz frequency excitation, a 50 km long power line will be modeled as

Description : For a 500 Hz frequency excitation, a 50 km long power line will be modeled as

Last Answer : For a 500 Hz frequency excitation, a 50 km long power line will be modeled as long line

A car is travelling at 90 km/hour on a rough road where the coefficient of friction between the road and the tyre is 0.5. The distance the car will skid before stopping when the brakes are jammed suddenly would be a.127.4 m b.95.55 m c.63.7 m d.31.85 m e.90 m

Description : A car is travelling at 90 km/hour on a rough road where the coefficient of friction between the road and the tyre is 0.5. The distance the car will skid before stopping when the brakes are jammed suddenly would be a.127.4 m b.95.55 m c.63.7 m d.31.85 m e.90 m

Last Answer : c. 63.7 m

A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in 10 sec. The distance between the locomotive and the wagons at this instant assuming that the forces acting on the train are unaltered would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Description : A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in ... would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Last Answer : d. 0.5 m

Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Description : Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Last Answer : Convert all to metres: 5 km = 5000 m 14 cm = 0.14 m 7 cm = 0.07 m Find the radius: Radius = Diameter 2 Radius = 0.14 2 = 0.07 m Find the amount of water that flowed out in an hour: Volume ... hours needed: Number of hours = 154 77 = 2 hours It takes 2 hours to fill up the tank to rise by 7 cm

Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Description : Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Last Answer : Volume of water discharged through the pipe = Volume increase of the tank First, consider the pipe. Volume discharge through pipe = length breadth speed time Let the time taken to fill the tank to 3 m depth be t. ... the tank V=150 100 3 cu. m ⇒ V=450 100 Therefore, 450t=450 100 ⇒ t=100 hours

Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Description : Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Last Answer : answer:

5 km = m?

Description : 5 km = m?

Last Answer : 5000m.

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

Description : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

Last Answer : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 1024 kg, R = 6400 km).

How is 6200 m bigger than 5 km?

Description : How is 6200 m bigger than 5 km?

Last Answer : 5km = 5000m and 6200 is bigger than 5000

Is 4.5 km more than 5000 m?

Description : Is 4.5 km more than 5000 m?

Last Answer : No, it is only 4500 m.

The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km

Description : The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km

Last Answer : Ans:(b)

The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Description : The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Last Answer : Ans:(d)

If the over land flow from the critical point to the drain is 8 km and the difference in level is 12.4 m, the inlet time is A. 2 hours B. 3 hours C. 4 hours D. 5 hours

Description : If the over land flow from the critical point to the drain is 8 km and the difference in level is 12.4 m, the inlet time is A. 2 hours B. 3 hours C. 4 hours D. 5 hours

Last Answer : ANS: C

Which one of the following parameters is accurate for DGPS? (A) Positional accuracies ~ 1 - 2 m if rover is less than 1-2 km from the reference station (B) Positional accuracies ~ 2 - 5m if rover is less than 2-5 fm from the reference station (C) Positional accuracies ~ 5 - 10 m if rover is less than 5-10 km from reference station (D) Positional accuracies ~ 5 - 10 m if rover is less than 25 km

Description : Which one of the following parameters is accurate for DGPS? (A) Positional accuracies ~ 1 - 2 m if rover is less than 1-2 km from the reference station (B) Positional accuracies ~ 2 - 5m if rover is ... -10 km from reference station (D) Positional accuracies ~ 5 - 10 m if rover is less than 25 km

Last Answer : Answer: Option A

Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs

Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs

Last Answer : Answer: Option B

A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Description : A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Last Answer : Answer – B (50 km/hr) Explanation – Let speed be S Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10 S- 5 = (125/10)x(18/5) S-5 = 45 S=50 km/hr

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

For a 300-m optical fiber cable with a bandwidth distance product of 600 MHz-km, determine the bandwidth. ∙ A. 5 GHz ∙ B. 1 GHz ∙ C. 2 GHz

Description : For a 300-m optical fiber cable with a bandwidth distance product of 600 MHz-km, determine the bandwidth. ∙ A. 5 GHz ∙ B. 1 GHz ∙ C. 2 GHz

Last Answer : C. 2 GHz

Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike speed is 20 km/hr and his walking speed is 1 km/hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Description : A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Last Answer : ANSWER:C Explanation:  Speed of goods train = 165km/hr  length of mail train (P) = 750m  length of goods train (Q) = 700m  Alternately, we can directly use the formula:  Time = ( p+q) / (v1+v2) sec  ( ...  45.833+v2 = 48.333  V2 = 2.5 m/s  Therefore the speed of the mail train is 2.5 m/s

A person runs on the platform of 90 m at a speed of 5km/hr in the same direction of the passenger train. Find the time taken by the train to cross the running person if speed of the train is 35.5 km/hr? (Length of train = Length of platform) A) 5.32sec B) 7.5sec C) 12.6sec D) 10.62sec

Description : A person runs on the platform of 90 m at a speed of 5km/hr in the same direction of the passenger train. Find the time taken by the train to cross the running person if speed of the train is 35.5 km/hr? (Length of train = Length of platform) A) 5.32sec B) 7.5sec C) 12.6sec D) 10.62sec

Last Answer : ANSWER:D Explanation: speed of the train = 35.5 km/hr speed of the person = 5 km/hr As the train and the running person move in same direction, their speed values are subtracted to find the relative ...  =10.62 sec  Hence, the time taken by the train to cross the running person is 10.62 sec

A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Description : A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Last Answer : ANSWER : C Explanation: Relative speed = distance / time = (140 / 4.5) m/s = 31.11 m/s Convert m/s into km/hr  31.11 m/s = (31.11 * 18 / 50 km/hr  = (560 / 5) km/hr  = ... train (by sitting) = (112 - 25) km/hr = 87 km/hr  Therefore the speed of goods train is 87 km/hr.

If a Rajdhani train running at the speed of 25 m/s and covers 0.8 km long chunk in 6 minutes, then the length of the train is: A) 8.2 B) 6.7 C) 7.5 D) 9.3

Description : If a Rajdhani train running at the speed of 25 m/s and covers 0.8 km long chunk in 6 minutes, then the length of the train is: A) 8.2 B) 6.7 C) 7.5 D) 9.3

Last Answer : ANSWER:A Explanation:  Speed of the train = 25 m/s.  Length of the chunk = 0.8 km  = 800 meters Time taken to cross the chunk = 6 minutes  = (6*60) seconds  = 360 seconds  Let the length of the train be y ... +y = 9000  y = 8200 m  i.e., y = 8.2 km  Hence the length of the train is 8.2 km

A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec

Description : A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec

Last Answer : ANSWER:B Explanation: Length of the train = 170 m Length of the bridge = 80 m Therefore, length of the train + length of the bridge = (170 + 80) m = 250m Speed of the train = 22.5 km/hr Speed ... .25m/sec Therefore, time taken by the train to cross the bridge = 250 m/6.25 m/sec. = 40 seconds.

A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Description : A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Last Answer : a. 2 km

A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes

Description : A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes

Last Answer : c. 7800

A gun fires shell with a muzzle velocity of 600 m/sec. The angle of inclination of the gun so that the shell hits a target at a distance of 32 km at level 100 m higher than the gun would be approximately? a.60? b.45? c.30? d.15? e.Either of (A) and (C)

Description : A gun fires shell with a muzzle velocity of 600 m/sec. The angle of inclination of the gun so that the shell hits a target at a distance of 32 km at level 100 m higher than the gun would be approximately? a.60? b.45? c.30? d.15? e.Either of (A) and (C)

Last Answer : e. Either of (A) and (C)

A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long? -Science

Description : A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long? -Science

Last Answer : Given Lenght of Train = 100m , velocity = 72 km/hr = 20 m/s, Lenght of the Bridge =2 Km. Total distance covered by the train to fully pass the bridge = 2000 + 100 = 2100 m So, time taken time=distancevelocity=210020=105sectime=distancevelocity=210020=105sec

Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Description : Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Last Answer : speed=distancetimespeed=distancetime or time=distancespeedtime=distancespeed For travelling 1 km with 3 km/hr, Time taken = 1/3 hr = 20 min Now he has to reach school in 30 min,So he has cover another 1 km in = 30 -20 =10 min= 1/6 hr So speed should = distance /time= 1/(1/6) = 6 km/hr

A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i

Description : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i

Last Answer : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m

Two trains 120 m and 80 m in length are running in opposite directions with velocities 42 km/h and 30 km/h respectively.

Description : Two trains 120 m and 80 m in length are running in opposite directions with velocities 42 km/h and 30 km/h respectively.

Last Answer : Two trains 120 m and 80 m in length are running in opposite directions with velocities 42 km/h ... In what time will they completely cross each other?

Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a wire 10 km long having resistance of `10

Description : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a wire 10 km long having resistance of `10

Last Answer : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a ... copper is `8.9xx10^(3) kg m^(-3)`.