Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

1 Answer

Answer :

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 1024 kg, R = 6400 km).

Related questions

Description : A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes

Last Answer : c. 7800

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Last Answer : (2) Surface area of the bottom of the vessel Explanation: The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. Static fluid pressure does not depend on the shape, total mass, or surface area of the liquid.

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Last Answer : (2) Surface area of the bottom of the vessel Explanation: The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity.

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Last Answer : Surface area of the bottom of the vessel

Description : Show that acceleration due to gravity at height h above the Earth’s surface is gh = g(R/R + h)^2

Last Answer : Show that acceleration due to gravity at height h above the Earth’s surface is gh = g \(\left(\frac{R}{R + h}\right)^2\) gh = g(R/R + h)2

Description : Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 10^3 km and its mass is 6.4 × 10^23 kg.

Last Answer : Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 103 km and its mass is 6.4 × 1023 kg.

Description : If a student drops a stone from a cliff of height 30 m and the time it takes to reach the ground is 2.6 s, then the acceleration due to gravity isA. 9 m s-2 B. 10 m s-2 C. 4 m s-2 D. 8.8 m s-2

Last Answer : 8.8 m s-2

Description : Mass of Earth when it's radius is 6400 km and gravitational field strength is 9.81 N kg-1 is A. 6.0 × 1024 kg B. 5 × 1023 kg C. 40 × 109 kg D. 9 × 1024 kg

Last Answer : 5 × 1023 kg

Description : In Joule's experiment, an insulated container contains 20 kg of waterinitially at 25°C. It is stirred by an agitator, which is made to turn by a slowly falling body weighing 40 kg through a height of 4 m. The process is repeated ... temperature of water (in °C) is (A) 40.5 (B) 34.4 (C) 26.8 (D) 25

Last Answer : (B) 34.4

Description : The mass, in kg, of the earth if its radius is 6400 km, will be a.6 x 1024 b.6 x 1025 c.107 dynes d.6 x 1023 e.6 x 1022

Last Answer : a. 6 x 1024

Description : An object with a mass of 5 kilograms is a distance of 5 meters above the surface of the earth. If the acceleration due to gravity is 10 meters per second squared, the potential energy of the object relative to the ... is: w) 10 joules x) 20 joules y) 100 joules z) 250 joules e) none of the above

Last Answer : ANSWER: Z -- 250 JOULES

Description : A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Last Answer : a. 2 km

Description : Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Last Answer : (A) (1/2π). √(g/r)

Description : A imaginary planet has half the mass and half the radius of the earth. The acceleration of gravity at its surface would be a.9.8 m/s2 b.107 dynes c.4.9 m/s2 d.19.6 m/s2 e.2.45 m/s2

Last Answer : d. 19.6 m/s2

Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Last Answer : (D) GV²/gR

Description : At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface,

Last Answer : At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of ... surface, given radius of Earth is 6400 km.

Description : How far away from the surface of the Earth does the acceleration due to gravity become ½ of its value at the surface of Earth? It is at a (a) Distance equal to radius (b) Distance equal to half the radius (c) Distance equal to twice the radius (d) Distance equal to 0.414 times the radius

Last Answer : Ans:(d)

Description : A person can jump higher on the moon's surface than on the earth because – (1) the moon's surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Last Answer : (2) the acceleration due to gravity in moon is smaller than that on the earth. Explanation: The acceleration due to the gravitational field of moon (g' = 1.62631 ms-2) is one-sixth of the acceleration due ... earth. It is due to this reason; a man can jump six times higher on moon than on earth.

Description : If a body weighs 12N on the surface of the earth, how much will it weigh on the surface of the moon where acceleration due to gravity is only one-sixth of that on earth's surface? (1) 12N (2) 2N (3) 10N (4) 6N

Last Answer : (2) 2N Explanation: Weight is mass x g. Since mass is constant and g is only 16thof that on the earth. The weight on the moon is only 16th of that on the earth.

Description : Assuming uniform density of the core, the acceleration due to gravity below the Earth's surface is A. inversely proportional to the square of the distance from the center of the Earth ... center of the Earth D. directly proportional to the distance from the center of the Earth

Last Answer : directly proportional to the distance from the center of the Earth

Description : A person can jump higher on the moon’s surface than on the earth because : (1) the moon’s surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Last Answer : the acceleration due to gravity in moon is smaller than that on the earth.

Description : In a construction site, a crane lifts 1000 kg of concrete mix to roof top at a height of 20 meters in 50 seconds. If the value of gravity 'g' due to earth is 10 m s-2, the power of elevator will be. -Physics

Last Answer : 4 KW (kilowatt)

Description : A ball is dropped from a height of 256 feet. The acceleration due to gravity is 32 feet per second squared. How many seconds will it take for the ball to reach the ground?

Last Answer : ANSWER: 4

Description : Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth’s surface.

Last Answer : Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth’s surface. ME = 5.98 × 1024 kg, R = 6.4 × 106 m.

Description : The angle of elevation of the antenna beam is 20°. Calculate the transmission-path distance for an ionospheric transmission that utilizes a layer of virtual height 200 km. Use flat-earth approximation. A. 966 km B. 2100 km C. 1100 km D. 405 km

Last Answer : C. 1100 km

Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Last Answer : A 100

Description : State the formula for acceleration due to gravity at depth ‘d’ and altitude ‘h’ Hence show that their ratio is equal to ((R - d)/(R - 2h))

Last Answer : State the formula for acceleration due to gravity at depth d' and altitude h' Hence show that ... small as compared to the radius of the Earth.

Description : If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Last Answer : Answer: Option C

Description : Four persons rented a grassland. P grazed 48 goats for 3 months, Q grazed 20 goats for 5 months, R grazed 70 goats for 4 months and S grazed 42 goats for 3 months. If p’s share of rent is Rs.1420. Find the total rent of the field? A) 6410 B) 6200 C) 6400 D) 6300

Last Answer : Answer: A) Ratio of shares P,Q, R, S = 48*3 : 20 *5 : 70*4 :42*3 = 144 : 100: 280 : 126 = 72:50:140:63 Let total rent be Rs x Then P’s share = Rs. 72x/325 72x /325 = 1420 X = Rs.6410

Description : Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.

Last Answer : Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.

Description : When your mass is 96 kg. The acceleration due to gravity is 9.8 ms 2 . How much work against gravity do you do when you climb a flight of stairs 3.8 m high Answer in units of J.?

Last Answer : 4

Description : An artificial satellite stays in the orbit around the Earth because (a) The Earth's gravity does not act on the satellite due to the great distance between them (b) The Earth's attraction ... (d) There is an engine in the satellite that constantly applies an upward force to balance its weight

Last Answer : Ans:(b)

Description : At the Center of earth Acceleration due to gravity (g) is?

Last Answer : Zero

Description : If the earth were to skin faster, how does acceleration due to gravity at the poles?

Last Answer : Remains the same

Description : The escape velocity from the earth’s surface is about 1. 30 km/sec 2. 6 km/sec 3. 11.2 km/sec 4. 300 km/sec 15. The radiant energy of the sun is due to (a) Nuclear fission (b) Nuclear fusion (c) Sinking of the sun (d) Violent explosions

Last Answer : Ans:(c)

Description : If diameter of a wheel is 1.26 m, what the distance covered in 500 revolutions? (a) 1.38 km (b) 4.64 km (c) 2.46 km (d) 1.98 km

Last Answer : (d) 1.98 km

Description : What is the approximate height of a geostationary satellite from the surface of the earth? (1) 981 km (2) 15000 km (3) 35000 km (4) 55000 km

Last Answer : (3) 35000 km Explanation: A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level.

Description : Earth's atmosphere is an envelope of gases extending to a height of – (1) 100 km (2) 150 km (3) 200 km (4) 300 km

Last Answer : (3) 200 km Explanation: The atmosphere of the. Earth is an envelope of gases extending to a height of 200km.

Description : During the night when the F2 layer combines with F1 layer it falls to what approximate height? A. 250 km B. 350 km C. 300 km D. 400 km

Last Answer : C. 300 km

Description : Earth’s atmosphere is an envelope of gases extending to a height of (1) 100 km (2) 150 km (3) 200 km (4) 300 km

Last Answer : 200 km

Description : A roller coaster reaches a velocity of 20 m/s at a location where the radius of curvature is 40 m. Calculate the acceleration in m/s2? a.10 b.9 c.11 d.8 e.107 dynes

Last Answer : a. 10

Description : The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Last Answer : Ans:(d)

Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs

Last Answer : Answer: Option B

Description : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a wire 10 km long having resistance of `10

Last Answer : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a ... copper is `8.9xx10^(3) kg m^(-3)`.

Description : Calculate the number of molecules of methane in 0.50 m^3 of the gas at a pressure of 2.0 × 10^2 kPa and a temperature of exactly 300 K.

Last Answer : Calculate the number of molecules of methane in 0.50 m3 of the gas at a pressure of 2.0 × 102 kPa and a temperature of exactly 300 K.

Description : Calculate the characteristics impedance for a transmission line having L=0.5 mH/Km, C=0.08 µF and negligible R and G.

Last Answer : L=0.5 mH/Km C=0.08 µF

Description : Track structure for CC+8 t+ 2 t loaded trains is:- (a) 52 Kg 90 UTS;PSC 1540 sleepers/ Km.; 250 mm ballast. (b) 60 Kg 90 UTS;PSC 1660 sleepers/ Km.; 300 mm ballast.* (c) 52 Kg 72 UTS;PSC 1540 sleepers/ Km.; 300 mm ballast. (d) 90 R;PSC 1340 sleepers/ Km.; 250 mm ballast.

Last Answer : b) 60 Kg 90 UTS;PSC 1660 sleepers/ Km.; 300 mm ballast.*

Description : The parameters of Transmission line are R = 50 Ω/ km, L= 1mH/km ,C = 0.1µf/km, G = 2µV/km. calculate characteristic impedance.

Last Answer : The parameters of Transmission line are R = 50 Ω/ km, L= 1mH/km ,C = 0.1µf/km, G = 2µV/km. calculate characteristic impedance.

Description : Why is weightlessness experienced while orbiting the earth in space ships? (1) Inertia (2) Acceleration (3) Zero gravity (4) None of these

Last Answer : (4) None of these Explanation: The reason astronauts experience weightlessness which orbiting the earth in spaceships is that they are in free fall. A spacecraft in orbit is falling towards the Earth, because ... in its orbit fast enough that the path it follows is a curve that is a closed ellipse.

Description : For a 300-m optical fiber cable with a bandwidth distance product of 600 MHz-km, determine the bandwidth. ∙ A. 5 GHz ∙ B. 1 GHz ∙ C. 2 GHz

Last Answer : C. 2 GHz