Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs

Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration
1.25 m/sec2
 to overtake a vehicle moving at a speed 30 km ph, is
(A) 5.0 secs
(B) 6.12 secs
(C) 225.48 secs
(D) 30 secs
by

1 Answer

Answer :

Answer: Option B
by

Related questions

Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these

Description : Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these

Last Answer : Answer: Option B

What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Description : What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Last Answer : c. 78.94 mts/sec2

The total length of a valley formed by two gradients - 3% and + 2% curve between the two tangent points to provide a rate of change of centrifugal acceleration 0.6 m/sec2 , for a design speed 100 kmph, is (A) 16.0 m (B) 42.3 m (C) 84.6 m (D) None of these

Description : The total length of a valley formed by two gradients - 3% and + 2% curve between the two tangent points to provide a rate of change of centrifugal acceleration 0.6 m/sec2 , for a design speed 100 kmph, is (A) 16.0 m (B) 42.3 m (C) 84.6 m (D) None of these

Last Answer : Answer: Option C

A crate weighing 40 kg rests on a cart moving with an acceleration W. The coefficient of friction between the cart and the crate is a.2.45 m/sec2 b.4.00 m/sec2 c.0.25 m/sec2 d.4.16 m/sec2 e.1.25 m/sec2

Description : A crate weighing 40 kg rests on a cart moving with an acceleration W. The coefficient of friction between the cart and the crate is a.2.45 m/sec2 b.4.00 m/sec2 c.0.25 m/sec2 d.4.16 m/sec2 e.1.25 m/sec2

Last Answer : a. 2.45 m/sec2

In which case power required would be more a.In lifting up a weight of 100 kg at a velocity of 3 m/sec but accelerating upwards at 0.5 m/sec b.In lowering a weight of 100 kg along an a inclined plane at an angle of 45? with c.In lifting up a weight of 100 kg at a constant speed of 3 m/sec d.In lowering the weight at a constant speed of 3 m/sec e.In lowering the weight at a velocity of 3 m/sec and acceleration of 1 m/sec2

Description : In which case power required would be more a.In lifting up a weight of 100 kg at a velocity of 3 m/sec but accelerating upwards at 0.5 m/sec b.In lowering a weight of 100 kg along an a inclined plane ... speed of 3 m/sec e.In lowering the weight at a velocity of 3 m/sec and acceleration of 1 m/sec2

Last Answer : a. In lifting up a weight of 100 kg at a velocity of 3 m/sec but accelerating upwards at 0.5 m/sec

In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is (A) 0.64 (B) 6.25 (C) 0.16 (D) None of these

Description : In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is (A) 0.64 (B) 6.25 (C) 0.16 (D) None of these

Last Answer : Answer: Option C

A body whose true weight is 14 kg appears to weigh 15 kg when weighed with the help of a spring balance in a moving lift. The acceleration of the lift at the time was a.1 m/sec2 b.0.7 m/sec2 c.0.5 m/sec2 d.1.4 m/sec2 e.0.35 m/sec2

Description : A body whose true weight is 14 kg appears to weigh 15 kg when weighed with the help of a spring balance in a moving lift. The acceleration of the lift at the time was a.1 m/sec2 b.0.7 m/sec2 c.0.5 m/sec2 d.1.4 m/sec2 e.0.35 m/sec2

Last Answer : b. 0.7 m/sec2

A train overtakes two girls walking along a railway track. The first girl walks at 9 km/hr. The other girl walks at 10.8 km/hr. The train needs 16.8 and 17 seconds respectively to overtake them. What is the speed of the train if both the girls are walking in the same direction as the train? A) 25 m/s B) 45 m/s C) 30m/s D) 40m/s

Description :  A train overtakes two girls walking along a railway track. The first girl walks at 9 km/hr. The other girl walks at 10.8 km/hr. The train needs 16.8 and 17 seconds respectively to overtake them. What is the speed of the ... in the same direction as the train? A) 25 m/s B) 45 m/s C) 30m/s D) 40m/s

Last Answer : ANSWER:B Explanation:  First girl speed = 9km/hr  = 9 * 5 / 18 m/s  = 5/2 m/s  = 2.5 m/s  second girl speed = 10.8 km/hr  = 10.8 * 5/18 m/s  = 54/18  = 3 m/s  Let the speed of the train ... x - 3) * 17  16.8x - 42 = 17x - 51  0.2x = 9  x = 45  Therefore the speed of the train is 45 m/s

A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is (A) 1 in 40 (B) 1 in 50 (C) 1 in 60 (D) 1 in 70

Description : A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is (A) 1 in 40 (B) 1 in 50 (C) 1 in 60 (D) 1 in 70

Last Answer : Answer: Option A

A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64

Description : A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64

Last Answer : e. 7.64

The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec

Description : The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec

Last Answer : a. 12 rad/sec

A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2

Description : A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2

Last Answer : d. 10 m/sec2

If V is the design speed in km/hour and R is the radius of the curve of a hill road, the super￾elevation (A) e = V / 127 R (B) e = V² / 127 R (C) e = V ²/ 225 R (D) e = V / 225 R

Description : If V is the design speed in km/hour and R is the radius of the curve of a hill road, the super￾elevation (A) e = V / 127 R (B) e = V² / 127 R (C) e = V ²/ 225 R (D) e = V / 225 R

Last Answer : Answer: Option C

A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Description : A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Last Answer : a. 500 KJ

The number of revolutions through which a pulley will rotate from rest if its angular acceleration is increased uniformly from zero to 12 rad per sec2 during 4 sec and then uniformly decreased to 0 rad per sec2 during the next 3 sec would be a.46.4 b.26.74 c.11.6 d.3.2 e.17.7

Description : The number of revolutions through which a pulley will rotate from rest if its angular acceleration is increased uniformly from zero to 12 rad per sec2 during 4 sec and then uniformly decreased to 0 rad per sec2 during the next 3 sec would be a.46.4 b.26.74 c.11.6 d.3.2 e.17.7

Last Answer : b. 26.74

For a vehicle moving with a speed of 80 km per hour, the brake reaction time, in ordinary cases, is (A) 1 sec (B) 1.5 sec (C) 2.0 sec(D) 2.5 sec

Description : For a vehicle moving with a speed of 80 km per hour, the brake reaction time, in ordinary cases, is (A) 1 sec (B) 1.5 sec (C) 2.0 sec (D) 2.5 sec

Last Answer : Answer: Option D

Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m

Description : Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m

Last Answer : Answer: Option C

The maximum comfortable retardation applied to moving vehicles, is (A) 3.42 m/sec2 (B) 4.42 m/sec2 (C) 5.56 m/sec2 (D) 7.80 m/sec2

Description : The maximum comfortable retardation applied to moving vehicles, is (A) 3.42 m/sec2 (B) 4.42 m/sec2 (C) 5.56 m/sec2 (D) 7.80 m/sec2

Last Answer : Answer: Option A

2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Description : 2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr

If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Description : If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Last Answer : Answer: Option C

If the gross vehicle weight of a truck is 30 tonne and rolling resistance is 30 kg/tonne, then the tractive effort required to keep the truck moving at a uniform speed is (A) 30 kg (B) 300 kg (C) 900 kg (D) 1000 kg

Description : If the gross vehicle weight of a truck is 30 tonne and rolling resistance is 30 kg/tonne, then the tractive effort required to keep the truck moving at a uniform speed is (A) 30 kg (B) 300 kg (C) 900 kg (D) 1000 kg

Last Answer : (C) 900 kg

A jet of water of cross-sectional area 20 sq. cm impinges on a plate at an angle of 60? with a velocity of 10 m/sec. Neglecting the friction between the jet and plate (density of water 1000/9.81 kgm-1 sec2 per cubic meter), the force exerted by the jet on the plate would be in the range a.15 - 20 kg b.20 - 25 kg c.5 - 10 kg d.25 - 30 kg e.10 - 15 kg

Description : A jet of water of cross-sectional area 20 sq. cm impinges on a plate at an angle of 60? with a velocity of 10 m/sec. Neglecting the friction between the jet and plate (density of water 1000/9.81 kgm-1 sec2 per cubic meter), the ... a.15 - 20 kg b.20 - 25 kg c.5 - 10 kg d.25 - 30 kg e.10 - 15 kg

Last Answer : a. 15 - 20 kg

If V is the design speed of vehicles in km/hour, the change of radial acceleration in metres/sec3 , is (A) 65/(70 + V) (B) 60/(70 + V) (C) 70/(65 + V) (D) 70/(60 + V)

Description : If V is the design speed of vehicles in km/hour, the change of radial acceleration in metres/sec3 , is (A) 65/(70 + V) (B) 60/(70 + V) (C) 70/(65 + V) (D) 70/(60 + V)

Last Answer : Answer: Option C

The total value of extra widening required at a horizontal curve on a two lane hill road of radius 42 m for a design speed of 50 kmph and for vehicles with wheel base 6 m, is (A) 0.500 m (B) 0.589 m (C) 1.089 m (D) 0.089 m

Description : The total value of extra widening required at a horizontal curve on a two lane hill road of radius 42 m for a design speed of 50 kmph and for vehicles with wheel base 6 m, is (A) 0.500 m (B) 0.589 m (C) 1.089 m (D) 0.089 m

Last Answer : Answer: Option C

The force which produces an acceleration of 1 m/sec2 in a mass of 1 kg is called a.100 ergs b.one Newton c.one watt d.One erg e.one joule

Description : The force which produces an acceleration of 1 m/sec2 in a mass of 1 kg is called a.100 ergs b.one Newton c.one watt d.One erg e.one joule

Last Answer : b. one Newton

The absolute minimum sight distance required for stopping a vehicle moving with a speed of 80 kmph, is (A) 120 m (B) 200 m (C) 640 m (D) None of these

Description : The absolute minimum sight distance required for stopping a vehicle moving with a speed of 80 kmph, is (A) 120 m (B) 200 m (C) 640 m (D) None of these

Last Answer : Answer: Option A

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

Description : A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed ... as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

Last Answer : Answer-D (81 km/hr) Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and 5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) ... - 12.75 => 0.1x = 2.25 => x = 22.5 Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.

Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Description : Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Last Answer : A Suppose the arin is overtaken x hrs after 8.30 a.m Then distance covered by arun in x hrs = distance covered by the owner in(x-1/2) hrs 40x =55(x-1/2) 40x = 55x -55/2 55x – 40x =55/2 15x=55/2 X = 55/2*1/15 x=55/30 x= 1hr 50mins so the thief is overtaken at 10.20 a.m

A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Description : A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Last Answer : Answer – B (50 km/hr) Explanation – Let speed be S Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10 S- 5 = (125/10)x(18/5) S-5 = 45 S=50 km/hr

A Superfast train overtakes two persons walking along a railway track. The first one walks at 9 km/hr. The other one walks at 10.8 km/hr. The train needs 16.8and 17seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train? A) 250 kmph B) 487kmph C) 162kmph D) 312kmph

Description : A Superfast train overtakes two persons walking along a railway track. The first one walks at 9 km/hr. The other one walks at 10.8 km/hr. The train needs 16.8and 17seconds respectively to overtake them. ... are walking in the same direction as the train? A) 250 kmph B) 487kmph C) 162kmph D) 312kmph

Last Answer : ANSWER:C Explanation:  Given that the first one walks at 9 km/hr convert the speed in the unit of m/sec  9 km/hr = (9*5/18) m/s  = 5/2 m/s  = 2.5 m/s  Another one walks at 10.8 km/hr ... the speed in the unit of km/hr  Speed of the train = (45*18/5)kmph  Speed of the train = 162 km/ hr

If V is speed in km/hour and R is radius of the curve, the super-elevation e is equal to (A) V²/125 R (B) V²/225 R (C) V²/325 R

Description : If V is speed in km/hour and R is radius of the curve, the super-elevation e is equal to (A) V²/125 R (B) V²/225 R (C) V²/325 R

Last Answer : Answer: Option B

A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Description : A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Last Answer : ANSWER:C Explanation:  Speed of goods train = 165km/hr  length of mail train (P) = 750m  length of goods train (Q) = 700m  Alternately, we can directly use the formula:  Time = ( p+q) / (v1+v2) sec  ( ...  45.833+v2 = 48.333  V2 = 2.5 m/s  Therefore the speed of the mail train is 2.5 m/s

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Last Answer : (D) GV²/gR

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 km/hr while Varun sails on a boat at a speed of about 24km/hr. If the flow of water current is at the speed of 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48

Description : There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 ... 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48 

Last Answer : ANSWER:B Explanation: As Arun swims both the ways at the speed of 30km/hr, the average speed of swimming is 30 km/hr Being a boat sailor, varun moves downstream at speed =24 +12=36km/hr and upstream at speed = 24-12= ... Upstream Speed])] = (36*12)/0.5(36+12) km/hr = 432/24 km/hr = 18 km/hr

25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M

While calculating the overtaking sight distance, the height of the object above road surface, is assumed (A) 50 cm (B) 75 cm (C) 100 cm (D) 120 cm

Description : While calculating the overtaking sight distance, the height of the object above road surface, is assumed (A) 50 cm (B) 75 cm (C) 100 cm (D) 120 cm

Last Answer : Answer: Option D

If brakes of vehicles are effective, the vehicle-running at 30 km/hour comes to a stop in (A) 10 metres (B) 12 metres (C) 15 metres (D) 18 metres

Description : If brakes of vehicles are effective, the vehicle-running at 30 km/hour comes to a stop in (A) 10 metres (B) 12 metres (C) 15 metres (D) 18 metres

Last Answer : Answer: Option B

Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.

Non-passing sight distance along a road is the longest distance at which the driver of a moving vehicle, may see an obstacle on the pavement (A) 10 cm high (B) 25 cm high (C) 50 cm high (D) 100 cm high

Description : Non-passing sight distance along a road is the longest distance at which the driver of a moving vehicle, may see an obstacle on the pavement (A) 10 cm high (B) 25 cm high (C) 50 cm high (D) 100 cm high

Last Answer : Answer: Option A

The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Description : The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Last Answer : Ans:(d)

If the axial length of a drainage basin is 35 km and its form factor is 0.2, the total area of the basin is (A) 205 sq. km. (B) 215 sq. km. (C) 225 sq. km. (D) 245 sq. km.

Description : If the axial length of a drainage basin is 35 km and its form factor is 0.2, the total area of the basin is (A) 205 sq. km. (B) 215 sq. km. (C) 225 sq. km. (D) 245 sq. km.

Last Answer : Answer: Option D

The corona loss in a 50 Hz system is 0.25 kW/ph/km. At a frequency of 60 Hz, the corona loss

Description : The corona loss in a 50 Hz system is 0.25 kW/ph/km. At a frequency of 60 Hz, the corona loss would be   (a) 0.30 kW/ph/km (b) 0.36 kW/ph/km (c) 028 kW/ph/km (d) 0.21 kW/ph/km

Last Answer : The corona loss in a 50 Hz system is 0.25 kW/ph/km. At a frequency of 60 Hz, the corona loss would be 028 kW/ph/km

A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010

Description : A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010

Last Answer : b. 8 x 106

A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr

The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

Description : The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

Last Answer : a. 1.27 x 108

A train crosses a long bridge of length 12 km and a standing girl in 600 seconds and 24 seconds respectively. What will be the length of the train? A) 275 B) 480 C) 389 D)225

Description : A train crosses a long bridge of length 12 km and a standing girl in 600 seconds and 24 seconds respectively. What will be the length of the train? A) 275 B) 480 C) 389 D)225

Last Answer : ANSWER:B Explanation: Time taken to cross the bridge(12 km) = 600 seconds.  Speed of the train = Distance / Time  = 12/600 km/s = 12000/600 m/s = 20m/s Train crosses a girl in 24 seconds. ... = Speed of the train x Time Taken  = (20 *24)m  = 480m  Hence the required length is 480 m.