What decimal is less than 0.35 0.5 0.36 0.29 0.53?

What decimal is less than 0.35 0.5 0.36 0.29 0.53?
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Answer :

0.01 is less than any of them.
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Cube strength of controlled concrete to be used for pre-tensioned and post-tensioned work respectively should not be less than (A) 35 MPa and 42 MPa (B) 42 MPa and 35 MPa (C) 42 MPa and 53 MPa (D) 53 MPa and 42 MPa

Description : Cube strength of controlled concrete to be used for pre-tensioned and post-tensioned work respectively should not be less than (A) 35 MPa and 42 MPa (B) 42 MPa and 35 MPa (C) 42 MPa and 53 MPa (D) 53 MPa and 42 MPa

Last Answer : Answer: Option B

21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Description : 21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Last Answer : Difference between each successive tam is factorial of number starting from 2, like 23-21 = 2, then 29-23 = 6 means 3!, then 53-29 = 24 means 4!, then next difference is 173-53 = 120 means 5!, so next difference would be 6! i.e. 720 so term will be 173+720 = 893. Answer: b)

A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body is (A) 3.53 kN (B) 33.3 kN (C) 35.3 kN (D) None of these

Description : A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body is (A) 3.53 kN (B) 33.3 kN (C) 35.3 kN (D) None of these

Last Answer : Answer: Option C

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

The volume of a bag of cement in cubic meters is about a) 0.035* b) 0.35 c) 0.53 d) .053

Description : The volume of a bag of cement in cubic meters is about a) 0.035* b) 0.35 c) 0.53 d) .053

Last Answer : a) 0.035*

36 – 0.036 × 100 = ? a) 3.6 b) 36.6 c) 29.6 d) 32.4 e) None of these

Description : 36 – 0.036 × 100 = ? a) 3.6 b) 36.6 c) 29.6 d) 32.4 e) None of these

Last Answer : ? = 36 – 3.6 = 32.41 Answer: d)

In how many articles of Indian Constitution, Directive principles of the state policy are mentioned? (1) From Article 36-51 (2) From Article 36-52 (3) From Article 36-53 (4) From Article 36-54

Description : In how many articles of Indian Constitution, Directive principles of the state policy are mentioned? (1) From Article 36-51 (2) From Article 36-52 (3) From Article 36-53 (4) From Article 36-54

Last Answer : (1) From Article 36-51 Explanation: From Article 36-51. DPSP was borrowed from Irish constitution.

An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is– (1) 17 (2) 19 (3) 36 (4) 53

Description : An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is– (1) 17 (2) 19 (3) 36 (4) 53

Last Answer : (2) 19 Explanation: Mass Number = number of protons (atomic number) + nu.sriber of neutrons. So as per the question, 36= number of neutrons + 17. Number of neutrons= 36 -17= 19

60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Description : 60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Last Answer : b) 44 kg

An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is (1) 17 (2) 19 (3) 36 (4) 53

Description : An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is (1) 17 (2) 19 (3) 36 (4) 53

Last Answer : 19

Determine the standing wave ratio of a 300-Ω line whose load is 400+j150 Ω. A. 3.55 B. 1.67 C. 5.53 D. 3.35

Description : Determine the standing wave ratio of a 300-Ω line whose load is 400+j150 Ω. A. 3.55 B. 1.67 C. 5.53 D. 3.35

Last Answer : B. 1.67

The number of positive integral values of m satisfying the inequalities 8m + 35 > 75 and 5m + 18 < 53 is -Maths 9th

Description : The number of positive integral values of m satisfying the inequalities 8m + 35 > 75 and 5m + 18 < 53 is -Maths 9th

Last Answer : answer:

Find the Brewster angle of a wave transmitted from a medium of permittivity 4 to a medium of permittivity 2. a) 35.26 b) 53.62 c) 26.35 d) 62.53

Description : Find the Brewster angle of a wave transmitted from a medium of permittivity 4 to a medium of permittivity 2. a) 35.26 b) 53.62 c) 26.35 d) 62.53

Last Answer : a) 35.26

Grade A eggs are of — gm. Weight ? a. 35 to 40 b. 40 to 45 c. 45 to 50 d. 50 to 53

Description : Grade A eggs are of — gm. Weight ? a. 35 to 40 b. 40 to 45 c. 45 to 50 d. 50 to 53

Last Answer : d. 50 to 53

3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Description : 3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Last Answer : ? + 75 = 52 + 58 = 110 ? = 110 – 75 = 35 Answer: e)

The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

What is 5.53 to nearest one decimal place?

Description : What is 5.53 to nearest one decimal place?

Last Answer : It is: 5.5

How do you Round 5.53 to one decimal place?

Description : How do you Round 5.53 to one decimal place?

Last Answer : It is 5.5 because the digit 3 is less than 5

How do you Round 5.53 to one decimal place?

Description : How do you Round 5.53 to one decimal place?

Last Answer : It is 5.5 because the digit 3 is less than 5

What is the benefit of 150 MB 36 minutes 36 SMS offer for 29 Taka ?

Description : What is the benefit of 150 MB 36 minutes 36 SMS offer for 29 Taka ?

Last Answer : Yes, of course it is beneficial because it gives you 36 minutes which costs 36 rupees plus 150 MB which costs 20 rupees and 36 SMS.

Sakthi running at 27 kmph alongside a railway track in 272 metres ahead of the engine of a 240 metres long train running at 135 kmph in the same direction. In how much time will the train pass sakthi? A) 24 B) 29 C) 36 D) 17

Description :  Sakthi running at 27 kmph alongside a railway track in 272 metres ahead of the engine of a 240 metres long train running at 135 kmph in the same direction. In how much time will the train pass sakthi? A) 24 B) 29 C) 36 D) 17

Last Answer : ANSWER:D  Explanation:  Speed of the train = 135 kmph  Speed of sakthi = 27 kmph  Speed of train relative to sakthi = (135-27) kmph  =108 kmph  We have to find the time in seconds, so convert ... of the train = Distance / Time  Therefore Time taken = ( 512 / 30) sec  = 17 sec

Convert octal 115 to decimal. 53) A) 7710 B) 9810 C) 6810 D) 7410

Description : Convert octal 115 to decimal. 53) A) 7710 B) 9810 C) 6810 D) 7410

Last Answer : A) 7710

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

What does 8 29 - 2 35 equal?

Description : What does 8 29 - 2 35 equal?

Last Answer : 8 and 2/9 = 74/9 = 370/452 and 3/5 = 13/5 = 117/45370 - 117 = 253/45 = 5 and 28/45

The normal serum CO2 content is (A) 18–20 meq/L (B) 24–29 meq/L (C) 30–34 meq/L (D) 35–38 meq/L

Description : The normal serum CO2 content is (A) 18–20 meq/L (B) 24–29 meq/L (C) 30–34 meq/L (D) 35–38 meq/L

Last Answer : Answer : B

Insulin is a dimmer. The number of amino acids in the A and B chain respectively is (A) 19 and 28 (B) 21 and 30 (C) 25 and 35 (D) 29 and 38

Description : Insulin is a dimmer. The number of amino acids in the A and B chain respectively is (A) 19 and 28 (B) 21 and 30 (C) 25 and 35 (D) 29 and 38

Last Answer : Answer : B

The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Description : The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Last Answer : (b) 37.29 kN

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29

The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19 , 29 and 34 respectively is (a) 1994 (b) 1494 (c) 1394 (d) 1496

Description : The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19 , 29 and 34 respectively is (a) 1994 (b) 1494 (c) 1394 (d) 1496

Last Answer : 1394 Hint: Note that 20 -4 = 6; 25 -19 = 6;35-29= 6;40- 34 = 6 Required number = L.C.M. of ( 20, 25, 35 and 40)-6

A 35 yr old pt she is on phenytoin since she was 29 due to partial epilipsy she didn’t have any attack since. She want to stop taking the drug due to facial hair growth: a. It is reasonable to stop it now b. Stop it after 6 months c. Stop after 10 years d. Don’t stop it

Description : A 35 yr old pt she is on phenytoin since she was 29 due to partial epilipsy she didn’t have any attack since. She want to stop taking the drug due to facial hair growth: a. It is reasonable to stop it now b. Stop it after 6 months c. Stop after 10 years d. Don’t stop it

Last Answer : a. It is reasonable to stop it now

In the following question, select the odd number pair from the given alternatives. Options: 1) 93 -97 2) 84 -— 88 3) 54-58 4) 29-35

Description : In the following question, select the odd number pair from the given alternatives.  Options: 1) 93 -97 2) 84 -— 88 3) 54-58 4) 29-35 

Last Answer : Correct Answer: 29 -— 35 

If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

Description : If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, ... , the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

Last Answer : Answer: Option C

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

What is 7.29 rounding to 1 decimal place?

Description : What is 7.29 rounding to 1 decimal place?

Last Answer : 7.3

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

Convert decimal 31 to octal. 29) A) 378 B) 438 C) 338 D) 308

Description : Convert decimal 31 to octal. 29) A) 378 B) 438 C) 338 D) 308

Last Answer : A) 378

What is the decimal value of 2 1? 35) A) 1 B) 4 C) 2 D) 0

Description : What is the decimal value of 2 1? 35) A) 1 B) 4 C) 2 D) 0

Last Answer : C) 2

What is the decimal value of 2 1? 35) A) 1 B) 4 C) 2 D) 0

Description : What is the decimal value of 2 1? 35) A) 1 B) 4 C) 2 D) 0

Last Answer : C) 8716

The thiazolidinediones are mainly used as: A. Sole drug in type 1 diabetes mellitus B. Sole drug in type 2 diabetes mellitus C. Addon drug to a sulfonylurea and/or a biguanide in type 2 diabetes mellitus D. Addon drug to insulin in type 1 diabetes mellitus (p. 250) 18.33 1 8 . 3 3 C 18.34 1 8 . 3 4 B 18.35 1 8 . 3 5 D 18.36 1 8 . 3 6 C

Description : The thiazolidinediones are mainly used as: A. Sole drug in type 1 diabetes mellitus B. Sole drug in type 2 diabetes mellitus C. Addon drug to a sulfonylurea and/or a biguanide in type 2 diabetes mellitus D. Addon drug to insulin in type 1 ... 18.34 1 8 . 3 4 B 18.35 1 8 . 3 5 D 18.36 1 8 . 3 6 C

Last Answer : C. Addon drug to a sulfonylurea and/or a biguanide in type 2 diabetes mellitus

12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.

A 53-year-old man presented with hypertension of 150/110 mmHg. He is generally asymptomatic and has no previous medical history of note. He is a smoker of 5 cigarettes daily and drinks modest quantities of alcohol. He takes no prescribed medications. Examination reveals a BMI of 33.5 kg/2 but nil else. The following detail his investigations: Serum sodium 146 mmol/l (NR 133-145) Serum potassium 3.2 mmol/l (NR 3.5 - 5) Urinary potassium excretion 42 mmol/l (NR less than 30) What is the likely diagnosis? 1) Adrenocortical adenoma 2) Bartter's syndrome 3) Liddle's syndrome 4) Liquorice ingestion 5) Pheochromocytoma

Description : A 53-year-old man presented with hypertension of 150/110 mmHg. He is generally asymptomatic and has no previous medical history of note. He is a smoker of 5 cigarettes daily and drinks ... Adrenocortical adenoma 2) Bartter's syndrome 3) Liddle's syndrome 4) Liquorice ingestion 5) Pheochromocytoma

Last Answer : Answers-1 This patient is most likely to have Conn's syndrome as reflected by the hypokalaemic hypertension. Liquorice ingestion or Liddle's syndrome are again possible causes of ... hypertension (often diastolic hypertension), muscular weakness, paresthesias, headache, polyuria, and polydipsia."

What is in between .35 and .36?

Description : What is in between .35 and .36?

Last Answer : It is .355

Which of these numbers is prime - a. 35 or b. 36 or c. 37 or d. 38 or e. 39?

Description : Which of these numbers is prime - a. 35 or b. 36 or c. 37 or d. 38 or e. 39?

Last Answer : The answer is c. 3735 = 5 x 736 = 2 x 2 x 3 x 339 = 3 x 13

Rights of Minorities, including their due representation in the government, are provided in Article _________ ofthe Constitution. A. 35 B. 36 C. Both 35 and 36 D. None of these 99

Description : Rights of Minorities, including their due representation in the government, are provided in Article _________ ofthe Constitution. A. 35 B. 36 C. Both 35 and 36 D. None of these 99

Last Answer : ANSWER: B

Horizontal distance travelled by a ball if it's thrown with initial velocity of 20 m s-1 at an angle of 30° is A. 24 m B. 56 m C. 35.3 m D. 36.3 m

Description : Horizontal distance travelled by a ball if it's thrown with initial velocity of 20 m s-1 at an angle of 30° is A. 24 m B. 56 m C. 35.3 m D. 36.3 m

Last Answer : 35.3 m

1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)

25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36

Description : 25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36

Last Answer : The series is 3×5+10=25,4×6+10=34,5×7+10=45,6×8+10=58,7×9+10=73,8× 10+10=90,9×11+10=109 Hence missing term=34 Answer: b)