Is longer 6 km or 6345 m?

Is longer 6 km or 6345 m?
by

1 Answer

Answer :

What is the answer ?
by

Related questions

What is 6345 divided by 7?

Description : What is 6345 divided by 7?

Last Answer : 906.4286

Is 6 km greater or smaller or equal than 660 m?

Description : Is 6 km greater or smaller or equal than 660 m?

Last Answer : 6 km equals 6000 m which is greater than 660 m

Witch is bigger 6 km or 660 m?

Description : Witch is bigger 6 km or 660 m?

Last Answer : 6 km

The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Description : The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2

Last Answer : Ans:(d)

If the length of overland flow from the critical point to the mouth of drain is 13.58 km and difference in level between the critical point and drain mouth is 10 m, the inlet time is A. 2 hours B. 4 hours C. 6 hours D. 8 hours

Description : If the length of overland flow from the critical point to the mouth of drain is 13.58 km and difference in level between the critical point and drain mouth is 10 m, the inlet time is A. 2 hours B. 4 hours C. 6 hours D. 8 hours

Last Answer : ANS: D

Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these

Description : Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these

Last Answer : Answer: Option B

In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is (A) 0.64 (B) 6.25 (C) 0.16 (D) None of these

Description : In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is (A) 0.64 (B) 6.25 (C) 0.16 (D) None of these

Last Answer : Answer: Option C

Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs

Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs

Last Answer : Answer: Option B

Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

Description : A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

Last Answer : Answer- A(100m) Explanation: Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr Distance covered in 6 minutes =[(1/60)*6] km = (1/10)km = 100 m. Distance between the thief and policeman = (200 – 100) m = 100 m.

Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Description : Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Last Answer : A Let the distance travelled be x km x/30 – x/45 = 2 (3x – 2x) / 90 = 2 x/90 = 2 x = 180km Time taken to travel 180 km at 30 km/hr = 180 / 30 = 6 hrs So ganesh started 6 hrs before 8 pm That is 2 pm Required speed = distance / time =(180/5) =36 km/hr

The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Description : The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Last Answer : D Assume that they meet x hours after 6 a.m. Then, Bus 1, starting from salem, travels x hours till the bus meet. Distance travelled by bus 1 in x hours =20x km bus 2, starting from trichy , travels (x−1) hours ... +30=50x 200=50x X=4 Hence, the bus meet 4 hours after 6 a.m., i.e. at 10a.m

A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Description : A goodstrain of 700 m runs at a speed of 165 km/hr. A person traveling in it observes that the mail train moving in opposite direction takes 30 seconds to cross him. Find the speed of the mail train, if it is 750 m long. A) 8.4 m/s B) 5.3 m/s C) 2.5 m/s D) 6.8 m/s

Last Answer : ANSWER:C Explanation:  Speed of goods train = 165km/hr  length of mail train (P) = 750m  length of goods train (Q) = 700m  Alternately, we can directly use the formula:  Time = ( p+q) / (v1+v2) sec  ( ...  45.833+v2 = 48.333  V2 = 2.5 m/s  Therefore the speed of the mail train is 2.5 m/s

A train leaves Mumbai for chennai at 6 : 45 a.m. and goes at the rate of 100 km/h. Another train leaves Chennai for Mumbai at 4.30a.m. and goes at the rate of 120 km/h. If the distance between both is 1240 km, at what distance from Mumbai will the two trains meet? A) 210km B) 324km C) 115km D) 440km

Description : A train leaves Mumbai for chennai at 6 : 45 a.m. and goes at the rate of 100 km/h. Another train leaves Chennai for Mumbai at 4.30a.m. and goes at the rate of 120 km/h. If the distance between both is 1240 km, at what distance from Mumbai will the two trains meet? A) 210km B) 324km C) 115km D) 440km

Last Answer : ANSWER: D  Explanation:  Given speed of the first train = 100kmph  speed of the second train = 120kmph  The second train leaving Chennai starts its journey earlier and it travels = 120 *(6.45a.m. ... train covers 4.40 *100 = 440 km  Therefore the first train meet to the second train at 440km

If a Rajdhani train running at the speed of 25 m/s and covers 0.8 km long chunk in 6 minutes, then the length of the train is: A) 8.2 B) 6.7 C) 7.5 D) 9.3

Description : If a Rajdhani train running at the speed of 25 m/s and covers 0.8 km long chunk in 6 minutes, then the length of the train is: A) 8.2 B) 6.7 C) 7.5 D) 9.3

Last Answer : ANSWER:A Explanation:  Speed of the train = 25 m/s.  Length of the chunk = 0.8 km  = 800 meters Time taken to cross the chunk = 6 minutes  = (6*60) seconds  = 360 seconds  Let the length of the train be y ... +y = 9000  y = 8200 m  i.e., y = 8.2 km  Hence the length of the train is 8.2 km

How much longer is 6.3 cm to 2.5 m in cm?

Description : How much longer is 6.3 cm to 2.5 m in cm?

Last Answer : What is the answer ?

A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Description : A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Last Answer : a. 2 km

A car is travelling at 90 km/hour on a rough road where the coefficient of friction between the road and the tyre is 0.5. The distance the car will skid before stopping when the brakes are jammed suddenly would be a.127.4 m b.95.55 m c.63.7 m d.31.85 m e.90 m

Description : A car is travelling at 90 km/hour on a rough road where the coefficient of friction between the road and the tyre is 0.5. The distance the car will skid before stopping when the brakes are jammed suddenly would be a.127.4 m b.95.55 m c.63.7 m d.31.85 m e.90 m

Last Answer : c. 63.7 m

A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes

Description : A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes

Last Answer : c. 7800

A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in 10 sec. The distance between the locomotive and the wagons at this instant assuming that the forces acting on the train are unaltered would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Description : A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in ... would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Last Answer : d. 0.5 m

A gun fires shell with a muzzle velocity of 600 m/sec. The angle of inclination of the gun so that the shell hits a target at a distance of 32 km at level 100 m higher than the gun would be approximately? a.60? b.45? c.30? d.15? e.Either of (A) and (C)

Description : A gun fires shell with a muzzle velocity of 600 m/sec. The angle of inclination of the gun so that the shell hits a target at a distance of 32 km at level 100 m higher than the gun would be approximately? a.60? b.45? c.30? d.15? e.Either of (A) and (C)

Last Answer : e. Either of (A) and (C)

A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long? -Science

Description : A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long? -Science

Last Answer : Given Lenght of Train = 100m , velocity = 72 km/hr = 20 m/s, Lenght of the Bridge =2 Km. Total distance covered by the train to fully pass the bridge = 2000 + 100 = 2100 m So, time taken time=distancevelocity=210020=105sectime=distancevelocity=210020=105sec

Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Description : Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Last Answer : speed=distancetimespeed=distancetime or time=distancespeedtime=distancespeed For travelling 1 km with 3 km/hr, Time taken = 1/3 hr = 20 min Now he has to reach school in 30 min,So he has cover another 1 km in = 30 -20 =10 min= 1/6 hr So speed should = distance /time= 1/(1/6) = 6 km/hr

Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Description : Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Last Answer : Convert all to metres: 5 km = 5000 m 14 cm = 0.14 m 7 cm = 0.07 m Find the radius: Radius = Diameter 2 Radius = 0.14 2 = 0.07 m Find the amount of water that flowed out in an hour: Volume ... hours needed: Number of hours = 154 77 = 2 hours It takes 2 hours to fill up the tank to rise by 7 cm

Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Description : Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Last Answer : Volume of water discharged through the pipe = Volume increase of the tank First, consider the pipe. Volume discharge through pipe = length breadth speed time Let the time taken to fill the tank to 3 m depth be t. ... the tank V=150 100 3 cu. m ⇒ V=450 100 Therefore, 450t=450 100 ⇒ t=100 hours

Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Description : Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Last Answer : answer:

5 km = m?

Description : 5 km = m?

Last Answer : 5000m.

What percent of 2 km is 500 m?

Description : What percent of 2 km is 500 m?

Last Answer : n − 1

A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i

Description : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i

Last Answer : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m

Two trains 120 m and 80 m in length are running in opposite directions with velocities 42 km/h and 30 km/h respectively.

Description : Two trains 120 m and 80 m in length are running in opposite directions with velocities 42 km/h and 30 km/h respectively.

Last Answer : Two trains 120 m and 80 m in length are running in opposite directions with velocities 42 km/h ... In what time will they completely cross each other?

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

Description : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

Last Answer : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 1024 kg, R = 6400 km).

Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a wire 10 km long having resistance of `10

Description : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a wire 10 km long having resistance of `10

Last Answer : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a ... copper is `8.9xx10^(3) kg m^(-3)`.

Is 236 km is equal to how many m?

Description : Is 236 km is equal to how many m?

Last Answer : Approximately 147.5 miles.

Is 4.8 km bigger than 4800 m?

Description : Is 4.8 km bigger than 4800 m?

Last Answer : Feel Free to Answer

Is 75000 m is equal to 750 km?

Description : Is 75000 m is equal to 750 km?

Last Answer : No! 75,000 metres are 75 kilometres.Note, there are 1,000 metres in 1 kilometres.

Is 4000 m greater than 40 km?

Description : Is 4000 m greater than 40 km?

Last Answer : What is the answer ?

Is 5 km 500 m?

Description : Is 5 km 500 m?

Last Answer : Need answer

Is 75000 m is equal to 750 km?

Description : Is 75000 m is equal to 750 km?

Last Answer : No! 75,000 metres are 75 kilometres.Note, there are 1,000 metres in 1 kilometres.

How many m in .9 km?

Description : How many m in .9 km?

Last Answer : 900

What is 10 km into m?

Description : What is 10 km into m?

Last Answer : The kilo- prefix means 1000→ 1 km = 1000 m→ 10 km = 10,000 m

Is 4000 m is greater than 40 km?

Description : Is 4000 m is greater than 40 km?

Last Answer : No because 4000 m equals 4 km which is less than 40 km

How is 6200 m bigger than 5 km?

Description : How is 6200 m bigger than 5 km?

Last Answer : 5km = 5000m and 6200 is bigger than 5000

Is 4.5 km more than 5000 m?

Description : Is 4.5 km more than 5000 m?

Last Answer : No, it is only 4500 m.

The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km

Description : The wavelength used in radar is (a) 10 m (b) Less than 5 cm (c) 100 m (d) 1,000 km

Last Answer : Ans:(b)

If the over land flow from the critical point to the drain is 8 km and the difference in level is 12.4 m, the inlet time is A. 2 hours B. 3 hours C. 4 hours D. 5 hours

Description : If the over land flow from the critical point to the drain is 8 km and the difference in level is 12.4 m, the inlet time is A. 2 hours B. 3 hours C. 4 hours D. 5 hours

Last Answer : ANS: C

What is the orbit height of a GPS satellite? A. 10,898 nmi B. 10,898 mi C. 10,898 km D. 10, 898 m

Description : What is the orbit height of a GPS satellite? A. 10,898 nmi B. 10,898 mi C. 10,898 km D. 10, 898 m

Last Answer : A. 10,898 nmi

The relation among various mass transfer co-efficients (M.T.C) for ideal gases is given by (where, Kc & Km are M.T.C. for equimolar counter diffusion with concentration & mole fraction respectively as the driving force. and, Kp= M.T.C. for diffusion of a gas through a stagnant inert gas with pressure as driving force.) (A) Kc = Kp = Km (B) Kc = Kp /RT = Km . RT/P (C) Kc = Kp . RT = Km . RT/p (D) None of these

Description : The relation among various mass transfer co-efficients (M.T.C) for ideal gases is given by (where, Kc & Km are M.T.C. for equimolar counter diffusion with concentration & mole fraction respectively as the driving ... (C) Kc = Kp . RT = Km . RT/p (D) None of these

Last Answer : (C) Kc = Kp . RT = Km . RT/p

A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km

Description : A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km

Last Answer : 54 km

Speed of snail as compared to speed of a car will be in units A. cm s-1 B. m s-1 C. km s-1 D. km h-1

Description : Speed of snail as compared to speed of a car will be in units A. cm s-1 B. m s-1 C. km s-1 D. km h-1

Last Answer :  cm s-1

Speed of sound in water is 1500 m s-1, depth of water when reflected sound waves are detected after 0.40 s is A. 700 m B. 600 km C. 600 m D. 750 km

Description : Speed of sound in water is 1500 m s-1, depth of water when reflected sound waves are detected after 0.40 s is A. 700 m B. 600 km C. 600 m D. 750 km

Last Answer : 600 m