Is 54 kL equal to 540000 dL?

Is 54 kL equal to 540000 dL?
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Suggestions on removing a RAT or KL?

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Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr`

Description : Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr`

Last Answer : Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr` A. KOH B. `O_(2)` C. `I_(2)` D. KOD

Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr`

Description : Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr`

Last Answer : Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr` A. KOH B. `O_(2)` C. `I_(2)` D. KOD

iodine is liberated from Kl solution when treated with:

Description : iodine is liberated from Kl solution when treated with:

Last Answer : iodine is liberated from Kl solution when treated with: A. (A) `ZnSO_4` B. (B) `CuSO_4 ` C. (C) `NiSO_4 ` D. (D) `FeSO_4`

25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0

Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated ... 56 mL B. 112 mL C. 168 mL D. 224 mL

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... . 0.8 g C. 4.2 g D. 0.98 g

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)

Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... 37.2 mL C. 5.6 mL D. 22.4 mL

To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes

Description : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes

Last Answer : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of ... strength of `H_(2)O_(2)` is 1.344 L

If line KL is a bisector of FH at point J which statements is true?

Description : If line KL is a bisector of FH at point J which statements is true?

Last Answer : With the limited information provided by the question, the onlystatement which must be true is FJ = JH.

What numbers are from Least to greatest 8.200 ML 0.005 KL 8.1 L?

Description : What numbers are from Least to greatest 8.200 ML 0.005 KL 8.1 L?

Last Answer : 0.005KL, 8.1 L, 8.200 ML (ML = megalitres).

In the diagram below which distance represents the distance from point J to kl?

Description : In the diagram below which distance represents the distance from point J to kl?

Last Answer : JM

In the diagram below which distance represents the distance from point J to kl?

Description : In the diagram below which distance represents the distance from point J to kl?

Last Answer : JM

What numbers are from Least to greatest 8.200 ML 0.005 KL 8.1 L?

Description : What numbers are from Least to greatest 8.200 ML 0.005 KL 8.1 L?

Last Answer : 0.005KL, 8.1 L, 8.200 ML (ML = megalitres).

The individual mass transfer co-efficients (moles/m2s) for absorption of a solute from a gas mixture into a liquid solvent are, KL = 4.5 and KG = 1.5. The slope of the equilibrium line is 3. Which of the following resistance (s) is (are) controlling? (A) Liquid side (B) Gas side (C) Interfacial (D) Both liquid and gas side

Description : The individual mass transfer co-efficients (moles/m2s) for absorption of a solute from a gas mixture into a liquid solvent are, KL = 4.5 and KG = 1.5. The slope of the equilibrium line is 3. Which of ... A) Liquid side (B) Gas side (C) Interfacial (D) Both liquid and gas side

Last Answer : (B) Gas side

In a vapor-liquid contacting equipment, the overall gas phase mass transfer co-efficient (M.T.C), KG is related to individual co-efficients (KG and KL ) as (A) KG = 1/KG + m/KL (B) 1/KG = 1/KG + m/KL (C) 1/KG = 1/KL + m/KG (D) KG = 1/KL + m/KG

Description : In a vapor-liquid contacting equipment, the overall gas phase mass transfer co-efficient (M.T.C), KG is related to individual co-efficients (KG and KL ) as (A) KG = 1/KG + m/KL (B) 1/KG = 1/KG + m/KL (C) 1/KG = 1/KL + m/KG (D) KG = 1/KL + m/KG

Last Answer : (B) 1/KG = 1/KG + m/KL

Pick out the wrong statement. (A) Reciprocal of the resistance to heat flow is called thermal conductance (B) Unit of thermal conductance is W/°K (C) Thermal conductance of a wall of thickness 'L', thermal conductivity 'k' and heat flow area 'A' is kL/A (D) None of these

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Last Answer : (C) Thermal conductance of a wall of thickness 'L', thermal conductivity 'k' and heat flow area 'A' is kL/A

Graetz number is given by (A) mCp /kL (B) kL/mCp (C) mCp /kµ (D) kµ/mC

Description : Graetz number is given by (A) mCp /kL (B) kL/mCp (C) mCp /kµ (D) kµ/mC

Last Answer : (A) mCp /kL

Maintain 850 OC for 1 hour (soaking time).  Cool the material to 60 OC in 4 hours. a) Calculate the efficiency of the furnace, if the specific heat of steel is 0.12 kcal/kgOC and fuel oil consumption per batch is 1400 litres.  GCV of fuel oil - 10200 kcal/kg,  Cost of fuel oil - Rs. 46,000/kL,  Sp. gr. of fuel oil - 0.92. b) Due to high cost of oil, the plant management decides to convert to a lower operating cost LPG fired furnace lined on the inside with ceramic fibre insulation and with an operating efficiency of 80%, for same requirement. The investment towards installation of the new furnace is Rs. 50 lakhs. Calculate the Return on Investment, if the plant operates two batches per day and 250 days in a year.  Cost of LPG - Rs. 75/kg,  GCV of LPG - 12500 kcal/kg.

Description : In a heat treatment shop, steel components are heat-treated in batches of 80 Tons. The  heat treatment cycle is as follows;  Increase temperature from 30 OC to 850 OC in 3 hours.  ... efficiency of 80%, for same requirement. The investment towards installation of  the new furnace is Rs. 50

Last Answer : Quantity of steel treated per batch - 80 Tons a. Efficiency of Furnace: Useful heat supplied to steel - 80000 x 0.12 x (850 - 30)   = 7872000 kcal/batch .1 mark Total heat ... = Rs. 64400/batch Efficiency of new LPG furnace - 80% Heat supplied in new LPG furnace - 7872000/0.8

In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg

Description : In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg 

Last Answer : Constant pressure process Final condition of steam is dry saturated Enthalpy of dry steam = hg= hf + hfg =2776.2 KJ/Kg .Given Latent heat of vaporization = hfg = hg - hf =2776.2-762.6 =2013.6 KJ/Kg Initial condition ... hfg = 762.6+0.8 X 2013.6 =2373.48 KJ/Kg Heat added = hg-hw = 402.72 KJ/kg

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Protein bound iodine in blood is present to the extent of _______ / dL (A) 3–8 mg (B) 4–8 mg (C) 3–8 gm (D) 4–8 gm

Description : Protein bound iodine in blood is present to the extent of _______ / dL (A) 3–8 mg (B) 4–8 mg (C) 3–8 gm (D) 4–8 gm

Last Answer : Answer : A

Normal range of total tri-iodothyronine in serum is (A) 0.1–0.2 ng/dl (B) 0.1–0.2 µg/dl (C) 0.8–2.4 ng/dl (D) 0.8–2.4 µg/dl

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Normal range of total thyroxine in serum is (A) 0.8–2.4 ng/dl (B) 0.8–2.4 µg/dl (C) 5–12 ng/dl (D) 5–12 µg/dl

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Normal serum free testosterone in adult women varies between (A) 0.0–0.2 ng/dl (B) 0.3–2 ng/dl (C) 10–30 ng/dl (D) 50–100 ng/dl

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Normal serum free testosterone in adult men varies between (A) 1–5 ng/dl (B) 6–9 ng/dl (C) 10–30 ng/dl (D) 50–100 ng/dl 214 MCQs IN BIOCHEMISTRY

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Plasma zinc level is (A) 10–50 µg/dl (B) 50–150 µg/dl (C) 150–250 µg/dl (D) 250–500 µg/dl

Description : Plasma zinc level is (A) 10–50 µg/dl (B) 50–150 µg/dl (C) 150–250 µg/dl (D) 250–500 µg/dl

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The normal range of plasma copper is (A) 25–50 µg/dl (B) 50–100 µg/dl (C) 100–200 µg/dl (D) 200–400 µg/dl

Description : The normal range of plasma copper is (A) 25–50 µg/dl (B) 50–100 µg/dl (C) 100–200 µg/dl (D) 200–400 µg/dl

Last Answer : Answer : C

Normal plasma iron level is (A) 50100 µg/dl (B) 100150 µg/dl (C) 50175 µg/dl (D) 250400 µg/dl

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Last Answer : Answer : C

Serum magnesium level ranges between (A) 2–3 mg/dl (B) 3–5 mg/dl (C) 6–8 mg/dl (D) 9–11 mg/dl

Description : Serum magnesium level ranges between (A) 2–3 mg/dl (B) 3–5 mg/dl (C) 6–8 mg/dl (D) 9–11 mg/dl

Last Answer : Answer : A

The product of serum calcium concentration (mg/dl) and serum inorganic phosphorous concentration (mg/dl) is decreased in (A) Rickets (B) Hypoparathyroidism (C) Hyperparathyroidism (D) Renal failure

Description : The product of serum calcium concentration (mg/dl) and serum inorganic phosphorous concentration (mg/dl) is decreased in (A) Rickets (B) Hypoparathyroidism (C) Hyperparathyroidism (D) Renal failure

Last Answer : Answer : A

The product of serum calcium concentration (mg/dl) and serum inorganic phosphorous concentration (mg/dl) in children is about (A) 30 (B) 40 (C) 50 (D) 60

Description : The product of serum calcium concentration (mg/dl) and serum inorganic phosphorous concentration (mg/dl) in children is about (A) 30 (B) 40 (C) 50 (D) 60

Last Answer : Answer : C

The product of serum calcium concentration (mg/dl) and serum inorganic phosphorous concentration (mg/dl) in adults is about (A) 30 (B) 40 (C) 50 (D) 60

Description : The product of serum calcium concentration (mg/dl) and serum inorganic phosphorous concentration (mg/dl) in adults is about (A) 30 (B) 40 (C) 50 (D) 60

Last Answer : Answer : A

Which of the normal range of ionized calcium in plasma is (A) 2-4 mg/dl (B) 2-4 mEq/L (C) 4-5 mg/dl (D) 4-5 mEq/L

Description : Which of the normal range of ionized calcium in plasma is (A) 2-4 mg/dl (B) 2-4 mEq/L (C) 4-5 mg/dl (D) 4-5 mEq/L

Last Answer : Answer : C

The normal range of plasma calcium is (A) 3-5 mg/dl (B) 5-10 mg/dl (C) 9-11 mg/dl (D) 11-15 mg/dl

Description : The normal range of plasma calcium is (A) 3-5 mg/dl (B) 5-10 mg/dl (C) 9-11 mg/dl (D) 11-15 mg/dl

Last Answer : Answer : C

Enzyme catalyzed hydrolysis of proteins produces amino acid of the form (A) D (B) DL (C) L (D) Racemic

Description : Enzyme catalyzed hydrolysis of proteins produces amino acid of the form (A) D (B) DL (C) L (D) Racemic

Last Answer : Answer : C

The normal concentration of vitamin A in blood in I.V/dl: (A) 20–55 (B) 24–60 (C) 30–65 (D) 35–70

Description : The normal concentration of vitamin A in blood in I.V/dl: (A) 20–55 (B) 24–60 (C) 30–65 (D) 35–70

Last Answer : Answer : B

Normal range of serum globulin is (A) 2.0–3.6 mg/dl (B) 2.0–3.6 gm/dl (C) 3.5–5.5 mg/dl (D) 3.5–5.5 gm/dl

Description : Normal range of serum globulin is (A) 2.0–3.6 mg/dl (B) 2.0–3.6 gm/dl (C) 3.5–5.5 mg/dl (D) 3.5–5.5 gm/dl

Last Answer : Answer : B