What is the average for the following set of measurements 27 c?

What is the average for the following set of measurements 27 c?
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Last Answer : ANSWER: Y -- 360 MILLIREM

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The average molecular weight of a flue gas having the composition by volume as CO2 = 25%, O2 = 25%, N2 = 50% will be (A) 27.6 (B) 23 (C) 47.3 (D) 42.9

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The average of four consecutive even numbers is 27. The largest of these numbers is: (A) 36 (B) 32 (C) 30 (D) 28

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Last Answer : Answer: C Four consecutive even number = x, x+2,x+4,x+6. According to question, x+x+2x+4x+6/4=27. 4x+12/4 = 27 4x =108 - 12=96. x=96/4=24. Hence , The largest number =x+4= 24+6=30. The numbers are 24, 26 28, and 30 , which addition is 108 which average is 27, So biggest is 30

A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the programmer Rs.60,000 per month and the tester Rs.50,000 per month. The average productivity for the team is 8 FP per person month. Which of the following represents the projected cost of the project? (1) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

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Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Description : Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Last Answer : B Let the speed of jagging be x km/hr Total time taken = (27/18 hrs + 4.5 hrs) =(1.5 hrs + 4.5 hrs) =6 hrs Total distance covered = (27+4.5 x) km Therefore (27 +4.5x) / 6= 27 27+4.5x = 162 4.5x = 135 X=135/4.5 =30 So jagging speed is 30 km/hr

A bus and a truck are available to cross a jungle. The speed of the truck is thrice that of the bus. The capacity of the truck is 60 persons and that of bus is 40 persons. The average occupancy of the bus is twice that of the truck. The tickets for the bus and the truck cost Re 1 and Re 1.50 respectively. What is the ratio of the average rupee collection of the truck to that of the bus in a day? Assume there is no wastage time between trips and the occupancy of the bus/truck is defined as the ratio of the actual number of persons boarding it and its capacity. a) 9:17 b) 17:9 c) 8:27 d) 27:8 e) None of these

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Last Answer :  Answer: D Average Rupee collection = Speed× capacity × Occupancy × Ticket rate Ratio of average Rupee collection of truck to that of bus= product of above rate According to question, (3×60×1×1.5):(1×40×2×1)= 270:80=27:8

M, N and O amounted plot. M invests 24 flat for 27months, N invests 18 flat for 24 months and O puts 48 plat for 27 months. If the rent of the plot is Rs.44649 then what is the average amount paid by M & O? a) 18116.5 b) 18265.5 c) 16878.5 d) 12688.5

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Last Answer :  Answer: B) Ratio of M, N, O is, 24*27:18*24:48*27 =3:2:6 Amount paid by M&O=44649*3/11+ 44649*6/11 =Rs.36531 Average amount paid by M&O =36531/2 =Rs.18265.5

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Description : Harish buys petrol at rs 21, Rs.24 and Rs.27 per litre for 3 successive years. What approximately is the average cost per litre of petrol if he spends Rs.12000 each year? A) 23.74 B) 54.76 C) 24.66 D) 28.99

Last Answer : A)  Total quantity of petrol consumed in 3 yr = (12000/21 +12000/24+12000/27) =12000(1/2 + 1/24 + 1/27) =12000(72+63+56/1512) =12000(191/1512) =(2292000/1512)litres Total amount spent = rs(3 *12000) = Rs.36000 Average cost = Rs(36000*1512/2292000) =Rs.23.74

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The sum of 2 numbers is 216, and their HCF is 27. How many such pairs of numbers exist? (A pair a unique set of 2 numbers, so (a, b) and (b, a) will be considered as 1 pair). a) 0 b) 1 c) 2 d) 3 e) 4

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Last Answer : Let the numbers be a,b A = 27m, b = 27n where m, n are co-prime 27(m + n) = 216, or m+n = 8 M = 1, n = 7 and m = 3, n = 5 are the only 2 co – prime pairs possible. So we have 2 pairs: (27 , 189) and ( 81, 135) Answer: c)

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