Why Estimate the sum of 12.3 and 9.75?

Why Estimate the sum of 12.3 and 9.75?
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because it is hard to do the math
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Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla this brress is doins centinuously infinite46. The perimeter of 7 th triangle is \( ( \) in \( cm ) \)a) \( \frac{3}{4} \)b) \( \frac{5}{8} \)c) \( \frac{9}{8} \)d) \( \frac{7}{8} \)47. The sum of perimeter of all triangle is (in \( cm \) )a) 144b) 625c) 400d) 16948. The area of all the triangle is (in sq cm)a) 576b) \( 144 \sqrt{3} \)c) \( 169 \sqrt{3} \)d) \( 192 \sqrt{3} \)49. The sum of perimeter of first 6 triangle is (in \( cm \) )a) 120b) \( \frac{567}{4} \)c) \( \frac{569}{4} \)d) 14450. The side of the 5th triangle is (in \( cm \) )a) 6b) \( 1.5 \)c) \( 0.75 \)d) 3

Description : Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla this brress is doins centinuously infinite46. The perimeter of 7 th triangle is \( ( \) in \( cm ) \)a) \( \ ... of the 5th triangle is (in \( cm \) )a) 6b) \( 1.5 \)c) \( 0.75 \)d) 3

Last Answer : Each side of an equilateral triand 12 is \( 24 cm \) the mid - point of its sides are joined to form another tranpla ... ( 1.5 \) c) \( 0.75 \) d) 3

The energy consumption and production patterns in a chemical plant over a 9 month period is provided in the table below; Month 1 2 3 4 5 6 7 8 9 Production in Tonnes / month 493 297 381 479 585 440 234 239 239 Energy Consumption MWh /month 78.2 75.7 76.3 76.1 78.1 70.7 73.7 64.4 72.1 Estimate the cumulative energy savings at end of the 9th month and give your inference on the result ? ( consider 9 month data for evaluation for predicted energy consumption)

Description : The energy consumption and production patterns in a chemical plant over a 9 month period is provided in  the table below; Month 1 2 3 4 5 6 7 8 9 Production in Tonnes / month 493 ... and give your inference on the  result ? ( consider 9 month data for evaluation for predicted energy consumption)

Last Answer : It is required to use the equations Y= mX + C and  nC + mΣX = ΣY  cΣX + mΣX2 = ΣXY Month X =  Production in  Tonnes /  month Y =Energy  Consumption MWh  /month  X 2 XY 1 493 78.2 ... 73.7 54756 17240.63 8 239 64.4 57121 15402.96 9 239 72.1 57121 17228.98 3387 665.3 1410683 253221

The energy required per unit mass to grind limestone particles of very large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond's law) of the energy to grind the particles from a very large size to 50 μm is (A) 6.35 kWh/ton (B) 9.0 kWh/ton (C) 18 kWh/ton (D) 25.4 kWh/ton

Description : The energy required per unit mass to grind limestone particles of very large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond's law) of the energy to grind the particles from a very large size to 50 μm is (A) 6.35 kWh/ton (B) 9.0 kWh/ton (C) 18 kWh/ton (D) 25.4 kWh/ton

Last Answer : (C) 18 kWh/ton

A project activity has several components as indicated below; S. No. Activity Preceded by Duration (in Weeks) 1 A - 8 2 B A 6 3 C A 12 4 D B 4 5 E D 5 6 F B 12 7 G E& F 9 8 H C 8 9 I F & H 5 10 J I & G 6 d. Prepare a PERT chart, estimate the duration of the project and identify the critical path.

Description : A project activity has several components as indicated below; S.  No. Activity Preceded by Duration (in  Weeks) 1 A - 8 2 B A 6 3 C A 12 4 D B 4 5 E D 5 6 F B 12 7 G E& F ... H 5 10 J I & G 6 d. Prepare a PERT chart, estimate the duration of the project and identify the  critical path.

Last Answer : PERT Diagram based on Activity on Arrow  .  E  D 5 G B 5 9 J, 6 A 6 F,12 I ,5 8 c 12 H 8 OR  PERT Diagram based on Activity on Node …………………….6 marks a. Critical Path: A-B-F-G-J …………………….1 mark  b. Estimated Project Duration: 41 weeks

The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to complete the project using the effort formula of basic COCOMO given below: E = a(KLOC)b Assume that the values of a and b are 2.5 and 1.0 respectively. (A) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Description : The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to ... ) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Last Answer : (C) 62.5 person months 

How much money would you estimate you have earned in your entire life (total lump sum)?

Description : How much money would you estimate you have earned in your entire life (total lump sum)?

Last Answer : $15,000 time 7 = 105,000 + 2000 = $107,000 then again I’m only 33

When should you estimate a sum or difference?

Description : When should you estimate a sum or difference?

Last Answer : When the exact number is not required, only a ball park figureor an order of magnitude. This could be forced upon you when you donot have exact values for the two quantities involved.

When should you estimate a sum or difference?

Description : When should you estimate a sum or difference?

Last Answer : When the exact number is not required, only a ball park figureor an order of magnitude. This could be forced upon you when you donot have exact values for the two quantities involved.

Estimate by rounding to the nearest ten.​ Then, find the sum.221122plus+33554455​_​_The estimated sum is nothing.?

Description : Estimate by rounding to the nearest ten.​ Then, find the sum.221122plus+33554455​_​_The estimated sum is nothing.?

Last Answer : Estimate by rounding to the nearest ten.​ Then, find the sum.221122plus+33554455​_​_The estimated sum is nothing.

Estimate the sum or difference of 612,797+811,035?

Description : Estimate the sum or difference of 612,797+811,035?

Last Answer : 1423832

The basic approach to Earned Value is toA. Sum up the Work Package Earned Values to calculate the Earned Value of the Control Account and ultimately the Project B. Multiply the percent complete by the value of the Work Package to calculate the "Earned Value" for that package C. Estimate a percent complete for each WBS Work Package D. All of the above

Description : The basic approach to Earned Value is to A. Sum up the Work Package Earned Values to calculate the Earned Value of the Control  Account and ultimately the Project  B. Multiply the percent complete by ... that package  C. Estimate a percent complete for each WBS Work Package  D. All of the above

Last Answer : D. All of the above

In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 days and 8 kg to 10 kg (C) 105 days to 120 days and 18 kg to 21 kg (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg

The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24

Description : The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24

Last Answer : ANSWER:B  Explanation:  First train leaves at 8.00am and second leaves at 9.00am  So,first train that is , from ooty to Chennai has covered  75 km distance in 1 hr.  So , distance left by between the station = ... the trains will meet , 3 hr after second train left  i.e., 9.00 am +3 = 12.00 pm

What number is a multiple of 6 and 12 and has the sum of 9 numbers?

Description : What number is a multiple of 6 and 12 and has the sum of 9 numbers?

Last Answer : All multiples of 12 are also multiples of 6 and they all can bewritten as the sum of nine numbers.

The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

What is the output of the following code? >>> a=(2,3,4) >>> sum(a,3) a) Too many arguments for sum() method b) The method sum() doesn’t exist for tuples c) 12 d) 9

Description : What is the output of the following code? >>> a=(2,3,4) >>> sum(a,3) a) Too many arguments for sum() method b) The method sum() doesn’t exist for tuples c) 12 d) 9

Last Answer : c) 12

Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by ‘A’ is Rs 40,000, out of a total annual profit of Rs 33,000, C’s share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Description : Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by A' is Rs 40,000, out of a total annual ... share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Last Answer : Answer: A Sum invested by A , B and C is 5 * 12:7 * 12:6 * 6 + 3 * 6 or 60 : 84 : 54 or 10 : 14 : 9 :: Share of C = ( 9 / 33 ) * 33000 = Rs. 9000

Find three consecutive odd integers whose sum is (-75)?

Description : Find three consecutive odd integers whose sum is (-75)?

Last Answer : Those three odd integers are 43, 45, and 47.

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

The ratio of marks obtained by Vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. A) 150 B) 200 C) 400 D) 450 E) None

Description : The ratio of marks obtained by Vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. A) 150 B) 200 C) 400 D) 450 E) None

Last Answer : Answer: B The sum of the marks=6x+5x=11x But the sum of the marks is given as 275=11x. We get x=25x=25 therefore, Vinod's marks is 6x=1506x=150 and Basu's marks = 5x=125. ... Therefore, if their combined average of their percentage is 137.5 then the total marks would be 137.568.75 100=200

A, B and C are 3 partners in a business. Their investments are respectively Rs 2000, Rs 4,000 and Rs 3,000. A gets 30% of total profit for managing the business. The remaining profit is divided among them in the ratio of their investments. At the end of the year, the profit of Ais Rs 1100 less than the sum of the profit of B and C. What amount of income will C get? A) Rs 2100.75 B) Rs 2887.5 C) Rs 2705.75 D) Rs 2546.25

Description : A, B and C are 3 partners in a business. Their investments are respectively Rs 2000, Rs 4,000 and Rs 3,000. A gets 30% of total profit for managing the business. The remaining profit is divided among them in the ratio ... of income will C get? A) Rs 2100.75 B) Rs 2887.5 C) Rs 2705.75 D) Rs 2546.25

Last Answer : Answer: B) The ratio of profit of A, B and C is 2000:4000:3000=2:4:3. Let the annual profit be P. Then, A will get 0.3p for managing the business. And, remaining 0.7p will be distributed in the ratio of their ... ⇒ 7/9 0.7p−2/9 0.7p−0.3p=1100 ⇒ p=12,375 So, C's share=3/9 0.7p=Rs 2887.5

Estimate. Then find the product.27×9?

Description : Estimate. Then find the product.27×9?

Last Answer : 12

Estimate 9.391 + 2.8 to the nearest whole number?

Description : Estimate 9.391 + 2.8 to the nearest whole number?

Last Answer : 12.1909999999999

Estimate 9.391 + 2.8 to the nearest whole number?

Description : Estimate 9.391 + 2.8 to the nearest whole number?

Last Answer : 12.1909999999999

Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into heating the roof. The specific heat of concrete is about 900 J/kg, and the density is about 2,300 kg/m3 .  a. 7.9 °C  b. 8.9°C  c. 9.9°C  d. 10.9°C formula: ΔQ = m c ΔT

Description : Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into ... °C  b. 8.9°C  c. 9.9°C  d. 10.9°C formula: ΔQ = m c ΔT

Last Answer : 7.9 °C

I'm curious. What would you estimate to be the average price for a 12 pack of Coca Cola where you live? Include the recycling fee if any.

Description : I'm curious. What would you estimate to be the average price for a 12 pack of Coca Cola where you live? Include the recycling fee if any.

Last Answer : $4 for a 12 pack of any of the Coke products (suburban Atlanta) at Kroger.

what does 5/12 estimate to?

Description : what does 5/12 estimate to?

Last Answer : 0.4167

Petri is working for Nokia in Finland. He has completed 10 months of his 12-month project, budgeted at $800,000. His earned value analysis shows that variance at completion is $75,000. What is the estimate at completion value for this project? Select one: a. 725,000 b. -725,000 c. -$875,000 d. $875,000 e. $800,000

Description : Petri is working for Nokia in Finland. He has completed 10 months of his 12-month project, budgeted at $800,000. His earned value analysis shows that variance at  completion is $75,000. What is the estimate at completion value ... : a. 725,000 b. -725,000 c. -$875,000 d. $875,000 e. $800,000

Last Answer : d. $875,000

The concrete roof of a house is 10 m by 8 m and 10 cm thick (4"). Estimate the total heat the roof would absorb over the 12 day?  a. 1.3 x 108 J  b 2.3 x 108 J  c. 3.3 x 108 J  d. 4.3 x 108 J formula: ΔQ = ΔQ/Δtx Δt

Description : The concrete roof of a house is 10 m by 8 m and 10 cm thick (4"). Estimate the total heat the roof would absorb over the 12 day?  a. 1.3 x 108 J  b 2.3 x 108 J  c. 3.3 x 108 J  d. 4.3 x 108 J formula: ΔQ = ΔQ/Δtx Δt

Last Answer : 1.3 x 108 J

The likely estimate on equivalent power wastage for a leakage from 7 bar compressed air system through 1.6 mm orifice size is ____ a) 0.2 kW b) 3.0 kW c) 0.8 kW d) 12 kW

Description : The likely estimate on equivalent power wastage for a leakage from 7 bar compressed air system through 1.6 mm orifice size is ____ a) 0.2 kW b) 3.0 kW c) 0.8 kW d) 12 kW

Last Answer : c) 0.8 kW

Which is bigger 9/10 or 0.75?

Description : Which is bigger 9/10 or 0.75?

Last Answer : 9/10 = 0.9, which is more than 0.75.

What is -9.75 minus 8 34?

Description : What is -9.75 minus 8 34?

Last Answer : 1

What is the nearest whole number 9.75?

Description : What is the nearest whole number 9.75?

Last Answer : It is 10

How much does 75 go into 9,000?

Description : How much does 75 go into 9,000?

Last Answer : 120 times.

A 75 year old man presents with a long history of shortness of breath and ankle oedema. His serum biochemistry shows sodium 122 mmols/l and potassium of 2.9 mmols/l. He now complains of weakness.Which of the following is likely to explain the above biochemical picture? 1) Addison's Disease 2) Nephrotic syndrome 3) Primary hyperaldosteronism 4) SIADH 5) Diuretic therapy

Description : A 75 year old man presents with a long history of shortness of breath and ankle oedema. His serum biochemistry shows sodium 122 mmols/l and potassium of 2.9 mmols/l. He now complains of ... ? 1) Addison's Disease 2) Nephrotic syndrome 3) Primary hyperaldosteronism 4) SIADH 5) Diuretic therapy

Last Answer : Answers-5 The long history of his symptoms and serum biochemistry suggests that his condition is due to treatment with frusemide for CCF.

In a morse test for a 2 cylinder, 2 S SI engine, the brake power was 9 kW. Whereas the brake power of individual cylinders with spark cut off were 4.25 kW and 3.75 kW. The mecheffic of the engine is (a) 90% (b) 80% (c) 45.5% (d) 52.5%

Description : In a morse test for a 2 cylinder, 2 S SI engine, the brake power was 9 kW. Whereas the brake power of individual cylinders with spark cut off were 4.25 kW and 3.75 kW. The mecheffic of the engine is (a) 90% (b) 80% (c) 45.5% (d) 52.5%

Last Answer : Ans :a

A measurement of -75 dBm, C-message weighted, would be _________ dBrnc. A. 8 B. 7 C. 9 D. 15

Description : A measurement of -75 dBm, C-message weighted, would be _________ dBrnc. A. 8 B. 7 C. 9 D. 15

Last Answer : D. 15

The ratio of pure gold in 18 carat gold is --------? A. 0.5 B. 0.9 C. 0.8.5 D. 0.75 (Answer)

Description : The ratio of pure gold in 18 carat gold is --------? A. 0.5 B. 0.9 C. 0.8.5 D. 0.75 (Answer)

Last Answer : D. 0.75 (Answer)

The area of the triangular region, in the following figure, bounded by the lines 2x-y=1 and x+2y=13 and Y-axis is (a) 11.25 sq.units (b) 9.75 sq.units (c) 16.25 sq,units (d) 18.75 sq.units

Description : The area of the triangular region, in the following figure, bounded by the lines 2x-y=1 and x+2y=13 and Y-axis is (a) 11.25 sq.units (b) 9.75 sq.units (c) 16.25 sq,units (d) 18.75 sq.units

Last Answer : (a) 11.25 sq.units

The torque on a conductor with flux density 23 units, current 1.6A and area 6.75 units will be a) 248.4 b) 192.6 c) 175.4 d) 256.9

Description : The torque on a conductor with flux density 23 units, current 1.6A and area 6.75 units will be a) 248.4 b) 192.6 c) 175.4 d) 256.9

Last Answer : a) 248.4

Pick up the incorrect statement from the following: (A) The water entering the slow sand filters should be treated by 9.386 coagulants (B) The depth of water on the filter should be twice the depth of the filter sand (C) When the filter head is 0.75 times the depth of filter sand, the water obtained is purest (D) All the above

Description : Pick up the incorrect statement from the following:  (A) The water entering the slow sand filters should be treated by 9.386 coagulants  (B) The depth of water on the filter should be twice the ... is 0.75 times the depth of filter sand, the water obtained is purest  (D) All the above 

Last Answer : (D) All the above 

An object having 10 kg mass weighs 9.81 kg on a spring balance. The value of 'g' at this place is (A) 10 m/sec² (B) 9.81 m/sec² (C) 9.75 m/sec² (D) 9 m/sec

Description : An object having 10 kg mass weighs 9.81 kg on a spring balance. The value of 'g' at this place is (A) 10 m/sec² (B) 9.81 m/sec² (C) 9.75 m/sec² (D) 9 m/sec

Last Answer : Answer: Option A

A mass of 5kg is 100m above a given datum where local g = 9.75 m/s2 . Find the gravitational force in newtons. (Formula: Fg= mg/k )  a. 48.75 N  b. 50 N  c. 45 N  d. None of the above

Description : A mass of 5kg is 100m above a given datum where local g = 9.75 m/s2 . Find the gravitational force in newtons. (Formula: Fg= mg/k )  a. 48.75 N  b. 50 N  c. 45 N  d. None of the above

Last Answer : 48.75 N

The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these

Description : The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these

Last Answer : Distance travelled by first train in one hour = 60 x 1 = 60 km Therefore, distance between two train at 9 a.m. = 330 – 60 = 270 km Now, Relative speed of two trains = 60 + 75 = 135 km/hr Time of meeting of two trains =270/135=2 hrs. Therefore, both the trains will meet at 9 + 2 = 11 A.M. Answer: c)

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

What is the difference between the number of passengers of Sapt Kranti Exp in 2011 and that of Rajdhani Exp in 2006? 1) 1.5 lakh 2) 1 lakh 3) 0.5 lakh 4) 0.75 lakh 5) 0.9 lakh

Description : What is the difference between the number of passengers of Sapt Kranti Exp in 2011 and that of Rajdhani Exp in 2006? 1) 1.5 lakh 2) 1 lakh 3) 0.5 lakh 4) 0.75 lakh 5) 0.9 lakh

Last Answer : 2) 1 lakh

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101