The energy required per unit mass to grind limestone particles of very large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond's law) of the energy to grind the particles from a very large size to 50 μm is (A) 6.35 kWh/ton (B) 9.0 kWh/ton (C) 18 kWh/ton (D) 25.4 kWh/ton

The energy required per unit mass to grind limestone particles of very
large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond's law) of the
energy to grind the particles from a very large size to 50 μm is
(A) 6.35 kWh/ton
(B) 9.0 kWh/ton
(C) 18 kWh/ton
(D) 25.4 kWh/ton
by

1 Answer

Answer :

(C) 18 kWh/ton
by

Related questions

Work index is defined as the (A) Gross energy (kWh/ton of feed) needed to reduce very large feed to such a size that 80% of the product passes through a 100 micron screen (B) Energy needed to crush one tonne of feed to 200 microns (C) Energy (kWh/ton of feed) needed to crush small feed to such a size that 80% of the product passes a 200 mesh screen (D) Energy needed to crush one ton of feed to 100 microns

Description : Work index is defined as the (A) Gross energy (kWh/ton of feed) needed to reduce very large feed to such a size that 80% of the product passes through a 100 micron screen (B) Energy needed to crush ... of the product passes a 200 mesh screen (D) Energy needed to crush one ton of feed to 100 microns

Last Answer : (A) Gross energy (kWh/ton of feed) needed to reduce very large feed to such a size that 80% of the product passes through a 100 micron screen

Pick out the correct statement. (A) Plastic chips are called non-cohesive solids (B) Kick's crushing law is, P/m = K . ln (D̅sa /Ds̅b ) (C) Communition is a generic term for size enlargement operation (D) Energy required in kwh per ton of product, such that 80% of it passes through a 200 mesh screen, is called 'Work index'

Description : Pick out the correct statement. (A) Plastic chips are called non-cohesive solids (B) Kick's crushing law is, P/m = K . ln (D̅sa /Ds̅b ) (C) Communition is a generic term for size enlargement ... per ton of product, such that 80% of it passes through a 200 mesh screen, is called 'Work index'

Last Answer : (B) Kick's crushing law is, P/m = K . ln (D̅sa /Ds̅b )

The work index in Bond's law for crushing of solids has the following dimensions (A) No units (dimensionless) (B) kWh/ton (C) kW/ton (D) kWh.m1/2 /ton

Description : The work index in Bond's law for crushing of solids has the following dimensions (A) No units (dimensionless) (B) kWh/ton (C) kW/ton (D) kWh.m1/2 /ton

Last Answer : (B) kWh/ton

Work index is the gross energy (kWh/tonne of feed) necessary to reduce a very large feed to such a size that 80% of product particles will pass through a 0.1 mm screen. The value of work index determined for wet grinding should be multiplied with __________ to get the same for dry grinding. (A) 1.0 (B) 0.5 (C) 1.34 (D) 4.34

Description : Work index is the gross energy (kWh/tonne of feed) necessary to reduce a very large feed to such a size that 80% of product particles will pass through a 0.1 mm screen. The value of work index determined for wet grinding should ... to get the same for dry grinding. (A) 1.0 (B) 0.5 (C) 1.34 (D) 4.34

Last Answer : (C) 1.34

A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle system (in SI units) is given below : Δ P/L = 375 × 10 3 VOM + 10.94 × 10 6 V2 OM (SI units) If water is to be used as the fluidising medium, the minimum fluidisation velocity, VOM is (A) 12 mm/s (B) 16 mm/s (C) 24 mm/s (D) 28 mm/s

Description : A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle ... fluidisation velocity, VOM is (A) 12 mm/s (B) 16 mm/s (C) 24 mm/s (D) 28 mm/s

Last Answer : (B) 16 mm/s

A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle system (in SI units) is given below: Δ P/L = 375 × 10 3 VOM + 10.94 × 10 6 V2 OM (SI units) If water is to be used as the fluidising medium, in actual operation, the above bed has a height = 1 m. What is the porosity of the fluidised bed? (A) 0.2 (B) 0.5 (C) 0.7 (D) 0.8

Description : A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle system ... What is the porosity of the fluidised bed? (A) 0.2 (B) 0.5 (C) 0.7 (D) 0.8

Last Answer : (C) 0.7

The usual energy consumption in electric arc furnace steel making is __________ KWh/ton of steel. (A) 60 - 100 (B) 400 - 700 (C) 1200 -1500 (D) 2000 - 2300

Description : The usual energy consumption in electric arc furnace steel making is __________ KWh/ton of steel. (A) 60 - 100 (B) 400 - 700 (C) 1200 -1500 (D) 2000 - 2300

Last Answer : (B) 400 - 700

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

. Kick's law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick's constant is (A) kW. sec/kg (B) kWh/kg (C) kWh/sec. kg (D) kg/sec

Description : . Kick's law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick's constant is (A) kW. sec/kg (B) kWh/kg (C) kWh/sec. kg (D) kg/sec

Last Answer : (A) kW. sec/kg

In a 100 TPD Sponge Iron plant, the sponge iron is fed to the Induction melting furnace, producing molten steel at 88% yield. The Energy consumption details are as follows: Coal Consumption : 130 TPD GCV of coal : 4500 kcal/kg Power Purchased from Grid : 82400 kWh / day Specific Energy consumption for Kiln producing Sponge Iron: 120 kWh / ton sponge iron Calculate the following 1. Specific Energy Consumption of Induction melting furnace in terms of kWh/ton of molten steel 2. Specific Energy Consumption of the entire plant, in terms of kcal/kg of molten steel (product). 3. Total Energy Consumption of Plant in Tons of Oil Equivalent (TOE )

Description : In a 100 TPD Sponge Iron plant, the sponge iron is fed to the Induction melting furnace,  producing molten steel at 88% yield. The Energy consumption details are as follows: Coal Consumption : 130 ... molten  steel (product). 3. Total Energy Consumption of Plant in Tons of Oil Equivalent (TOE )

Last Answer :  a) Specific Energy Consumption of Induction Melting Furnace  Molten Steel Production from the Induction melting furnace per day  = 100 x 88/100 = 88 TPD Total Energy Consumption of the Plant = 82400 kWh ... mark c) Total Energy consumption of Plant in ToE  = 655864000/107  = 65.586 ToE

Energy consumed for crushing one ton of material ranges from __________ kWh. (A) 0.01 to 0.1 (B) 0.5 to 1.5 (C) 2 to 3.5 (D) 4 to 5

Description : Energy consumed for crushing one ton of material ranges from __________ kWh. (A) 0.01 to 0.1 (B) 0.5 to 1.5 (C) 2 to 3.5 (D) 4 to 5

Last Answer : (B) 0.5 to 1.5

Bond crushing law (A) Calls for relatively less energy for the smaller product particles, than does the Rittinger law (B) Is less realistic in estimating the power requirements of commercial crushers (C) States that the work required to form particle of any size from very large feed is proportional to the square root of the volume to surface ratio of the product (D) States that the work required for the crushing is proportional to the new surface created

Description : Bond crushing law (A) Calls for relatively less energy for the smaller product particles, than does the Rittinger law (B) Is less realistic in estimating the power requirements of commercial crushers ( ... (D) States that the work required for the crushing is proportional to the new surface created

Last Answer : (A) Calls for relatively less energy for the smaller product particles, than does the Rittinger law

Carbonaceous particles having size less than 1 μm are called (A) Grit (B) Aggregates (C) Aerosols (D) Smoke

Description : Carbonaceous particles having size less than 1 μm are called (A) Grit (B) Aggregates (C) Aerosols (D) Smoke

Last Answer : (D) Smoke

5-200 μm size particles are called (A) Colloids or aerosols (B) Powder (C) Dust (D) Smoke

Description : 5-200 μm size particles are called (A) Colloids or aerosols (B) Powder (C) Dust (D) Smoke

Last Answer : (A) Colloids or aerosols

Production of one ton of cement requires about __________ tons of limestone. (A) 0.6 (B) 1.2 (C) 2.2 (D) 3.8

Description : Production of one ton of cement requires about __________ tons of limestone. (A) 0.6 (B) 1.2 (C) 2.2 (D) 3.8

Last Answer : (B) 1.2

Particles having diameter greater than 75 μm (micrometer = 10 -6 mm) are called (A) Grit (B) Dust (C) Powder (D) Smoke

Description : Particles having diameter greater than 75 μm (micrometer = 10 -6 mm) are called (A) Grit (B) Dust (C) Powder (D) Smoke

Last Answer : (A) Grit

Which one is not an energy consumption benchmark parameter? a) kcal/kWh of electricity generated b) kg/ oC. c) kW/ton of refrigeration d) kWh/kg of yarn

Description : Which one is not an energy consumption benchmark parameter? a) kcal/kWh of electricity generated b) kg/ oC. c) kW/ton of refrigeration d) kWh/kg of yarn

Last Answer : b) kg/ oC.

A 30% (by volume) suspension of spherical sand particles in a viscous oil has a hindered settling velocity of 4.44 μm/s. If the Richardson Zaki hindered settling index is 4.5, then the terminal velocity of a sand grain is (A) 0.90 μm/s (B) 1 μm/s (C) 22.1 μm/s (D) 0.02 μm/s

Description : A 30% (by volume) suspension of spherical sand particles in a viscous oil has a hindered settling velocity of 4.44 μm/s. If the Richardson Zaki hindered settling index is 4.5, then the terminal velocity of a sand grain is (A) 0.90 μm/s (B) 1 μm/s (C) 22.1 μm/s (D) 0.02 μm/s

Last Answer : (B) 1 μm/s

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Production of one ton of paper in Indian paper industry consumes about __________ kWh of electricity. (A) 300 (B) 800 (C) 1400 (D) 2000

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Last Answer : (C) 1400

Oxygen molecule absorption peaks to electromagnetic wave are at what wavelengths? A. 1.35 cm and 1.7 mm B. 5 mm and 2.5 mm C. 5 cm and 2.5 cm D. 1.35 mm and 1.7 μm

Description : Oxygen molecule absorption peaks to electromagnetic wave are at what wavelengths? A. 1.35 cm and 1.7 mm B. 5 mm and 2.5 mm C. 5 cm and 2.5 cm D. 1.35 mm and 1.7 μm

Last Answer : B. 5 mm and 2.5 mm

Oxygen molecule absorption peaks to electromagnetic wave are at what wavelengths? A. 1.35 mm and 1.7 μm B. 1.35 cm and 1.7 mm C. 5 cm and 2.5 cm D. 5 mm and 2.5 mm

Description : Oxygen molecule absorption peaks to electromagnetic wave are at what wavelengths? A. 1.35 mm and 1.7 μm B. 1.35 cm and 1.7 mm C. 5 cm and 2.5 cm D. 5 mm and 2.5 mm

Last Answer : D. 5 mm and 2.5 mm

The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to complete the project using the effort formula of basic COCOMO given below: E = a(KLOC)b Assume that the values of a and b are 2.5 and 1.0 respectively. (A) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Description : The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to ... ) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Last Answer : (C) 62.5 person months 

The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10 -6 order) a) 25 b) 35 c) 40 d) 50

Description : The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10 -6 order) a) 25 b) 35 c) 40 d) 50

Last Answer : a) 25

Hardgrove Grindability index of four coal samples are given below. Which of them is the easiest to grind? (A) 50 (B) 70 (C) 85 (D) 100

Description : Hardgrove Grindability index of four coal samples are given below. Which of them is the easiest to grind? (A) 50 (B) 70 (C) 85 (D) 100

Last Answer : (D) 100

A compacted soil sample using 10% moisture content has a weight of 200 g and mass unit weight of 2.0 g/cm3 . If the specific gravity of soil particles and water are 2.7 and 1.0, the degree of saturation of the soil is (A) 11.1 % (B) 55.6 % (C) 69.6 % (D) None of these

Description : A compacted soil sample using 10% moisture content has a weight of 200 g and mass unit weight of 2.0 g/cm3 . If the specific gravity of soil particles and water are 2.7 and 1.0, the degree of saturation of the soil is (A) 11.1 % (B) 55.6 % (C) 69.6 % (D) None of these

Last Answer : (B) 55.6 %

Size measurement of ultrafine particles can be best expressed in terms of (A) Centimetre (B) Screen size (C) Micron (D) Surface area per unit mass

Description : Size measurement of ultrafine particles can be best expressed in terms of (A) Centimetre (B) Screen size (C) Micron (D) Surface area per unit mass

Last Answer : (D) Surface area per unit mass

As per chart on energy consumption the supply unit of furnace oil is ……… a. kWh c. kV b. kg. d. Watts

Description : As per chart on energy consumption the supply unit of furnace oil is ……… a. kWh c. kV b. kg. d. Watts

Last Answer : kg

As per pie chart on energy consumption the supply unit of the electricity is……….. a. kWh c. kV b. kg. d. Watts

Description : As per pie chart on energy consumption the supply unit of the electricity is……….. a. kWh c. kV b. kg. d. Watts

Last Answer : kwh

99. As per chart on energy consumption the supply unit of furnace oil is ……… a. kWh c. kV b. kg. d. Watts

Description : 99. As per chart on energy consumption the supply unit of furnace oil is ……… a. kWh c. kV b. kg. d. Watts

Last Answer : kg.

95. As per pie chart on energy consumption the supply unit of the electricity is……….. a. kWh c. kV b. kg. d. Watts

Description : 95. As per pie chart on energy consumption the supply unit of the electricity is……….. a. kWh c. kV b. kg. d. Watts

Last Answer : kwh

The likely estimate on equivalent power wastage for a leakage from 7 bar compressed air system through 1.6 mm orifice size is ____ a) 0.2 kW b) 3.0 kW c) 0.8 kW d) 12 kW

Description : The likely estimate on equivalent power wastage for a leakage from 7 bar compressed air system through 1.6 mm orifice size is ____ a) 0.2 kW b) 3.0 kW c) 0.8 kW d) 12 kW

Last Answer : c) 0.8 kW

Slugging in a fluidised bed can be avoided by using (A) Tall narrow vessel (B) Deep bed of solids (C) Shallow beds of solids and proper choice of particle size (D) Very large particles

Description : Slugging in a fluidised bed can be avoided by using (A) Tall narrow vessel (B) Deep bed of solids (C) Shallow beds of solids and proper choice of particle size (D) Very large particles

Last Answer : (C) Shallow beds of solids and proper choice of particle size

The normal values of over flow rates for sedimentation tanks using coagulant, ranges between A. 25,000 to 35,000 litres/sqm/day B. 40,000 to 50,000 litres/sqm/day C. 50,000 to 60,000 litres/sqm/day D. 80,000 to 100,000 litres/sqm/day

Description : The normal values of over flow rates for sedimentation tanks using coagulant, ranges between A. 25,000 to 35,000 litres/sqm/day B. 40,000 to 50,000 litres/sqm/day C. 50,000 to 60,000 litres/sqm/day D. 80,000 to 100,000 litres/sqm/day

Last Answer : ANS: C

Process B had no opening inventory. 13,500 units of raw material were transferred in at Rs 4.50 per unit. Additional material at Rs1.25per unit was added in process. Labour and overheads were Rs 6.25 per completed unit and Rs 2.50 per unit incomplete. If 11,750completed units were transferred out, what was the closing inventory in Process B? (a) Rs. 6562.50 (b) Rs. 12,250.00 (c) Rs. 14,437.50 (d) Rs. 25,375.00

Description : Process B had no opening inventory. 13,500 units of raw material were transferred in at Rs 4.50  per unit. Additional material at Rs1.25per unit was added in process. Labour and overheads were Rs 6.25  per completed unit and Rs ... 6562.50 (b) Rs. 12,250.00 (c) Rs. 14,437.50 (d) Rs. 25,375.00

Last Answer : (a) Rs 142,485

A project activity has several components as indicated below; S. No. Activity Preceded by Duration (in Weeks) 1 A - 8 2 B A 6 3 C A 12 4 D B 4 5 E D 5 6 F B 12 7 G E& F 9 8 H C 8 9 I F & H 5 10 J I & G 6 d. Prepare a PERT chart, estimate the duration of the project and identify the critical path.

Description : A project activity has several components as indicated below; S.  No. Activity Preceded by Duration (in  Weeks) 1 A - 8 2 B A 6 3 C A 12 4 D B 4 5 E D 5 6 F B 12 7 G E& F ... H 5 10 J I & G 6 d. Prepare a PERT chart, estimate the duration of the project and identify the  critical path.

Last Answer : PERT Diagram based on Activity on Arrow  .  E  D 5 G B 5 9 J, 6 A 6 F,12 I ,5 8 c 12 H 8 OR  PERT Diagram based on Activity on Node …………………….6 marks a. Critical Path: A-B-F-G-J …………………….1 mark  b. Estimated Project Duration: 41 weeks

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in _____. A. 1 Hour B. 5 Hours C. 8 Hours D. 10 Hours

Description : According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in _____. A. 1 Hour B. 5 Hours C. 8 Hours D. 10 Hours

Last Answer : ANSWER: D

According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in _____. A. 1 Hour B. 5 Hours C. 8 Hours D. 10 Hours

Description : According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in _____. A. 1 Hour B. 5 Hours C. 8 Hours D. 10 Hours

Last Answer : ANSWER: D

According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in-----? A. 2 hours B. 5 hours C. 8 hours D. 10 hours (Answer)

Description : According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in-----? A. 2 hours B. 5 hours C. 8 hours D. 10 hours (Answer)

Last Answer : D. 10 hours (Answer)

According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in------? A. 1 hours B. 5 hours C. 10 hours (Answer) D. 15 hours

Description : According to the definition of 1 KWh, a 100 watt bulb consumes one unit of electricity in------? A. 1 hours B. 5 hours C. 10 hours (Answer) D. 15 hours

Last Answer : C. 10 hours (Answer)

The density of lead is 12 grams per cm3. A lead brick has a mass of 1.5 kilograms. Its dimensions are 10 cm by 5 cm by 4 cm. Is it: w) More than 75% hollow x) Between 50 and 75% hollow y) Between 25 and 50% hollow z) Between 0 and 25% hollow

Description : The density of lead is 12 grams per cm3. A lead brick has a mass of 1.5 kilograms. Its dimensions are 10 cm by 5 cm by 4 cm. Is it: w) More than 75% hollow x) Between 50 and 75% hollow y) Between 25 and 50% hollow z) Between 0 and 25% hollow

Last Answer : ANSWER: Y -- BETWEEN 25 AND 50% HOLLOW

Pick out the wrong statement. (A) A refrigeration cycle violates the second law of thermodynamics (B) Refrigeration cycle is normally represented by a temperature vs. entropy plot (C) In a refrigerator, work required decreases as the temperature of the refrigerator and the temperature at which heat is rejected increases (D) One ton of refrigeration is equivalent to the rate of heat absorption equal to 3.53 kW

Description : Pick out the wrong statement. (A) A refrigeration cycle violates the second law of thermodynamics (B) Refrigeration cycle is normally represented by a temperature vs. entropy plot (C) In a refrigerator, ... (D) One ton of refrigeration is equivalent to the rate of heat absorption equal to 3.53 kW

Last Answer : (A) A refrigeration cycle violates the second law of thermodynamics

In a manufacturing plant, following data are gathered for a given month: Production - 1200 pieces; specific energy consumption - 1000 kWh/piece; variable energy consumption - 950 kWh/piece. The fixed energy consumption of the plant for the month Paper 1 –Set A with Solutions _______________________ Bureau of Energy Efficiency 6 is ------- a) 6,000 kWh b)10,000 kWh c) 12,000 kWh d) 60,000 kWh

Description : In a manufacturing plant, following data are gathered for a given month: Production - 1200 pieces; specific energy consumption - 1000 kWh/piece; variable energy consumption - 950 kWh/piece. The fixed energy consumption of the plant ... ----- a) 6,000 kWh b)10,000 kWh c) 12,000 kWh d) 60,000 kWh

Last Answer : d) 60,000 kWh

Mercury electrolytic cells are preferred over diaphragm electrolytic cell (for production of caustic soda), as it (A) Has larger production capacity per unit cell (B) Consumes less power per ton of Cl2 produced (C) Produces high purity (70%) caustic soda directly (D) All (A), (B) and (C)

Description : Mercury electrolytic cells are preferred over diaphragm electrolytic cell (for production of caustic soda), as it (A) Has larger production capacity per unit cell (B) Consumes less power per ton of Cl2 produced (C) Produces high purity (70%) caustic soda directly (D) All (A), (B) and (C)

Last Answer : (D) All (A), (B) and (C)

Which of the following gives the work required for size reduction of coal to -200 mesh in a ball mill most accurately? (A) Rittinger's law (B) Kick's law (C) Bond's law (D) None of these

Description : Which of the following gives the work required for size reduction of coal to -200 mesh in a ball mill most accurately? (A) Rittinger's law (B) Kick's law (C) Bond's law (D) None of these

Last Answer : (A) Rittinger's law