How do you write an algorithm which takes students marks and grades them as follows Mark greater than 60 Pass?

How do you write an algorithm which takes students marks and grades them as follows Mark greater than 60 Pass?
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The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

Description : The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

Last Answer : C) According to the question, 90*126=(4*0)+(60*116)+(24*118)+2y 11340=6960+2832+2y 2y=1548 y=774

Write the data type of variables that should be used to store : 1. Marks of students 2. Grades of students (Grade can be ‘A or ‘B’ or ‘C’) -Technology

Description : Write the data type of variables that should be used to store : 1. Marks of students 2. Grades of students (Grade can be ‘A or ‘B’ or ‘C’) -Technology

Last Answer : (i) int data type(ii) char data type

A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Description :  A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Last Answer : Answer: B  Let x be the maximum marks,  Then (50% of x)+60 = (75% of x)-40  x/2 +60 = 3x/4 -20  60+20 = 3x/4 – x/ 2 X=320  Hence maximum marks = 320  Minimum pass marks = 320/2 + 60 = 220

What are the characteristics of Continuous and Comprehensive Evaluation ? (a) It increases the workload on students by taking multiple tests. (b) It replaces marks with grades. (c) It evaluates every aspect of the student. (d) It helps in reducing examination phobia. Select the correct answer from the codes given below: (A) (a), (b), (c) and (d) (B) (b) and (d) (C) (a), (b) and (c) (D) (b), (c) and (d)

Description : What are the characteristics of Continuous and Comprehensive Evaluation ? (a) It increases the workload on students by taking multiple tests. (b) It replaces marks with grades. (c) It evaluates every aspect of the student. (d) It helps in ... ) and (d) (C) (a), (b) and (c) (D) (b), (c) and (d)

Last Answer : Answer: D

The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Description : The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Last Answer : NEED ANSWER

The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Description : The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Last Answer : (b) Since, the difference between mid value is 5. So, the corresponding class to the class mark 20 must have difference 5. Therefore, option (c) and (d) are wrong. Since, the mid value is 20 which can get only, if we take option (b)

In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

Description : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

Last Answer : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25 ... the probability that he gets more than 18 marks?

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

Why is the letter mark at 60 marks ?

Description : Why is the letter mark at 60 marks ?

Last Answer : 80 is called LETTER marks. Because , L = 12 , E = 5 , T = 20 , T = 20 , E = 5 , R = 18. (12 + 5 + 20 + 20 + 5 + 16 = 60) The sum of the numbers is 60.

Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Description : Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Last Answer : see in book okay!!!

Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Description : Construct a histogram for the marks of the student given below : - Marks 0-10,10-30,30-45,45-50,50-60 and number of students 8,32,18,10,6 -Maths 9th

Last Answer : see in book okay!!!

The mean marks obtained by a class of 40 students is 65. The mean marks of half of the students is found to be 45. The mean marks of the remaining students is (A) 85 (B) 60 (C) 70 (D) 65

Description : The mean marks obtained by a class of 40 students is 65. The mean marks of half of the students is found to be 45. The mean marks of the remaining students is (A) 85 (B) 60 (C) 70 (D) 65

Last Answer : Answer: A

The average of marks obtained by 60 students in a computer examination is 18. If the average marks of passed students is 20and that of the failed students is 8, what is the number of students who passed the examination? A) 100 B) 75 C) 50 D) 85

Description : The average of marks obtained by 60 students in a computer examination is 18. If the average marks of passed students is 20and that of the failed students is 8, what is the number of students who passed the examination? A) 100 B) 75 C) 50 D) 85 

Last Answer : C Let the number of passed students be x. Then total marks = 60 × 18= 20x + (60– x) × 8 1080= 20x + 480– 8x 12x = 600 ∴ x = 50 ∴ number of passed students = 50

Students of two university appeared for a common test of maximum 60 marks. The average of their marks for university 1 & university 2 are 39 & 42 respectively. If the no of students of university 1 is twice the no of students of university 2. Then what is the average marks of all students of both the university? A) 40 B) 42 C) 26 D) 36

Description : Students of two university appeared for a common test of maximum 60 marks. The average of their marks for university 1 & university 2 are 39 & 42 respectively. If the no of students of university 1 is twice the no ... the average marks of all students of both the university? A) 40 B) 42 C) 26 D) 36

Last Answer : Answer: A) Let number of students of university2 be N and the no of students of university 1 be 2N the average of university1 and university 2 is 39 and 42 total marks of university 1 students and university 2 ... 78N and N*42 =42N average of both university,  =(78N+42N) /(N+2N) = 40 marks

Those teachers are popular among students who (A) develop intimacy with them (B) help them solve their problems (C) award good grades (D) take classes on extra tuition fee

Description : Those teachers are popular among students who (A) develop intimacy with them (B) help them solve their problems (C) award good grades (D) take classes on extra tuition fee

Last Answer : (B) help them solve their problems

The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 35 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Description : The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark ... integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Last Answer : D Average = Sum of observations/Number of observations Given, average score in a bank examination of 13 students of a class is 50. Sum of total scores = 13 50= 650 Given, if the scores of the top five students are not ... b + c + d + e = 290 ⇒46+ 47 + 48+ 49 +e = 290 ⇒e = 100

The percentage of marks obtained by a student in a monthly test is as follows: What is the probability that the student gets more than 75% marks in a

Description : The percentage of marks obtained by a student in a monthly test is as follows: What is the probability that the student gets more than 75% marks in a

Last Answer : The percentage of marks obtained by a student in a monthly test is as follows: What is the ... student gets more than 75% marks in a test?

School based assessment is primarily based on the principle that Options: A) teachers know their learners’ capabilities better than external examiners B) students should at all costs get high grades C) schools are more efficient than external bodies of examination D) assessment should be very economical

Description : School based assessment is primarily based on the principle that Options: A) teachers know their learners' capabilities better than external examiners B) students should at all costs get high ... schools are more efficient than external bodies of examination D) assessment should be very economical

Last Answer : A) teachers know their learners’ capabilities better than external examiners 

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

What do you think about paying students to get good grades?

Description : What do you think about paying students to get good grades?

Last Answer : I’m all for motivating them to do well, but we’d be far better off to teach them how much a good education pays off in the first place.

What grades do students take the Aspire test?

Description : What grades do students take the Aspire test?

Last Answer : Need answer

What are the best schools on the east coast that accept students with mediocre grades?

Description : What are the best schools on the east coast that accept students with mediocre grades?

Last Answer : Community colleges are not only more affordable but provide an excellent education even for those with mediocre grades. These colleges are more readily accepting of their applicants.

Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them. -Maths 9th

Description : Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them. -Maths 9th

Last Answer : Clearly, the mean score of two sections A and B is same

Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them. -Maths 9th

Description : Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them. -Maths 9th

Last Answer : Clearly, the mean score of two sections A and B is same

A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Description : A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Last Answer : C) Let the requird mean score be ‘x’ Then (30*70)+(15*41)+55x = 63*100 2100+615+55x=6300 2715+55x=6300 55x=3585 X=65.181

The average marks obtained by a student in Tamil, english, maths, science, and social together is 65% above the average mark obtained in maths and science together. How many more marks exceeded by the average of maths and science together than the sum of the tamil and english together? A) 50 B) 65 C) Data insufficient D) None of these

Description : The average marks obtained by a student in Tamil, english, maths, science, and social together is 65% above the average mark obtained in maths and science together. How many more marks exceeded by the average of ... of the tamil and english together? A) 50 B) 65 C) Data insufficient D) None of these

Last Answer : C) According to the question  There is no other information about the marks in any one of the subject. The data gives is insufficient to answer the question.

How do you punctuate single words in quotation marks... does the placement of the quotation mark depend upon the punctuation used?

Description : How do you punctuate single words in quotation marks... does the placement of the quotation mark depend upon the punctuation used?

Last Answer : I use British English, and we would always place the full stop or question mark outside of the quotation marks, as in your third example. However, I wouldn’t put T in quotation marks in the first place.

I can fill a room with out being seen, for your eyes I do not need. I can be felt, but can never feel; can be heard, but can never hear. I have many thoughts, but never think. I say many things, but never speak. I can tell a story with no words. Through my waves I am heard. I am your life, your love and sad goodbye. I resound in your every laugh and cry. I mark time, and time marks me. The past, present and future, through me you’ll see. What am I? -Riddles

Description : I can fill a room with out being seen, for your eyes I do not need. I can be felt, but can never feel; can be heard, but can never hear. I have many thoughts, but never think. I say many things ... mark time, and time marks me. The past, present and future, through me you'll see. What am I? -Riddles

Last Answer : Music.

How does stretch mark cream allow stretch marks to go away?

Description : How does stretch mark cream allow stretch marks to go away?

Last Answer : Stretch mark cream does not really work as stretch marks are result from damage below the skin's surface. Putting a cream on top of the skin will help it's appearance as it will moisturize it, but will not remove stretch marks.

Mark the correct option a) Documents means any matter expressed or described upon any substance b means of letter, figures or marks. b) Words printed, lithographed or photographed are documents c) A map or plan is a document d) An inscription on a metal plate or stone and caricature are documents. e) All the above

Description : Mark the correct option a) Documents means any matter expressed or described upon any substance b  means of letter, figures or marks. b) Words printed, lithographed or photographed are documents c) A ... d) An inscription on a metal plate or stone and caricature are documents. e) All the above

Last Answer : e) All the above

Mark correct option related to preservation period a) All records of mail department except due mail & sorting list 1 year b) Book of post marks(MS 18) & Postman book (MS-27) 1 ½ year c) Enumeration returns (MS-6) 2 years d) All monthly statistical registers 3 years e) All of the above

Description : Mark correct option related to preservation period a) All records of mail department except due mail & sorting list 1 year b) Book of post marks(MS 18) & Postman book (MS-27) 1 ½ year c) Enumeration returns (MS-6) 2 years d) All monthly statistical registers 3 years e) All of the above

Last Answer : e) All of the above

Choose the proper alternative given in the codes to replace the question mark. Bee-Honey, Cow-Milk, Teacher-? (A) Intelligence (B) Marks (C) Lessons (D) Wisdom

Description : Choose the proper alternative given in the codes to replace the question mark. Bee-Honey, Cow-Milk, Teacher-? (A) Intelligence (B) Marks (C) Lessons (D) Wisdom

Last Answer : (D) Wisdom

In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

While Lilo was playing with a toy tractor, she rolled it over an ink drop. The image on the right shows the ink drop and the marks on the floor left by tractor’s wheels. The diameter of the back wheel of the tractor is 1.5 times that of its front wheel. What is the number of revolutions made by the front wheel between the ink drop and the last mark?

Description : While Lilo was playing with a toy tractor, she rolled it over an ink drop. The image on the right shows the ink drop and the marks on the floor left by tractor's wheels. The diameter of the back ... is the number of revolutions made by the front wheel between the ink drop and the last mark?

Last Answer : 6

In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam secured `39%` marks and got 36 marks more than the p

Description : In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam secured `39%` marks and got 36 marks more than the p

Last Answer : In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam ... (a) The pass mark. (b) The pass percentage.

What is the reason behind the adoption of 'GRADE' system instead of our old' MARKS' system? Options: A) It will improve the quality of assessment. B) It will improve teacher student relationship. C) It will eliminate the differentiation between students on marks basis. D) Grading system is easier than marks system.

Description : What is the reason behind the adoption of 'GRADE' system instead of our old' MARKS' system? Options: A) It will improve the quality of assessment. B) It will improve teacher student ... eliminate the differentiation between students on marks basis. D) Grading system is easier than marks system.

Last Answer : C) It will eliminate the differentiation between students on marks basis. 

The blood groups of 30 students of class VIII are recorded as follows: -Maths 9th

Description : The blood groups of 30 students of class VIII are recorded as follows: -Maths 9th

Last Answer : Frequency Distribution Table Blood group O is most common as it has highest frequency, i.e., 12. Blood group AB is rarest as it has lowest frequency, i.e., 3.

The term ’Evaluation’ and ’Assessment’ could be discriminated as follows Options: A) Assessment is limited to coverage achievement whereas evaluation is qualitative in character B) Evaluation is concerned with the effective aspects of achievement whereas assessment judges the cognitive aspects C) Evaluation involves the measurement as well as diagnosis of students’ attainments, whereas assessment is concerned with only scholastic attainments. D) Assessment is an attempt to measure the pupil as whole whereas evaluation is concerned with his achievement only

Description : The term 'Evaluation' and 'Assessment' could be discriminated as follows Options: A) Assessment is limited to coverage achievement whereas evaluation is qualitative in character B) Evaluation is ... an attempt to measure the pupil as whole whereas evaluation is concerned with his achievement only

Last Answer : C) Evaluation involves the measurement as well as diagnosis of students’ attainments, whereas assessment is concerned with only scholastic attainments. 

What is the inter 1st year ap maths 1a pass marks?

Description : What is the inter 1st year ap maths 1a pass marks?

Last Answer : I am not sure what is being asked here

In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Description : In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Last Answer : Answer: A Difference = 672-126 = 546 According to the question, 70% of total aggregate = 546 Total aggregate marks = 546 × 100 /70  = 54600/70  = 780

In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

Description :  In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

Last Answer : Answer: B  Total marks in the test = (560 + 160) × 100 /25  = 720 ×100/25  = 72000/25  = 2880  Passing marks for girls =2880 × 60/100  = 1728  Required marks = 1728 – 216  = 1512

Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989

Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989 

Last Answer : Answer: C  If Gowthaman had scored 26 marks more, he could have scored 25%  Therefore, Mike required 424 + 26 = 450 marks  Let the maximum marks be x.  Then 25 % of x = 450  (25/100) × x = 450  x = (450 × 100)/25 x = 45000/25 x = 1800

A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that (a) Its velocity is constant (b) Its acceleration is constant (c) Its kinetic energy is constant (d) It moves in a circular path

Description : A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that (a) Its ... ) Its acceleration is constant (c) Its kinetic energy is constant (d) It moves in a circular path

Last Answer : Ans:(d)

In the somatic cell cycle (a) in G1 phase DNA content is double the amount of DNA present in the original cell (b) DNA replication takes place in S phase (c) a short interphase is followed by a long mitotic phase (d) G2 phase follows mitotic phase.

Description : In the somatic cell cycle (a) in G1 phase DNA content is double the amount of DNA present in the original cell (b) DNA replication takes place in S phase (c) a short interphase is followed by a long mitotic phase (d) G2 phase follows mitotic phase.

Last Answer : (b) DNA replication takes place in S phase

Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M’s locker number is 2 less than O’s lockers number. II. Lockers of N and P are next to each other. 14. If Q’s locker number is 54 and N’s locker number is greater than Q’s locker number, then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56

Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less ... , then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56

Last Answer : a) locker 52

In a mathematics test given to 15 students, the following marks (out of 100) are recorded : -Maths 9th

Description : In a mathematics test given to 15 students, the following marks (out of 100) are recorded : -Maths 9th

Last Answer : For Mean : As we know that ⇒ x̅ = 41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 52 + 60 / 15 x̅ = 822 / 15 = 54.8 ⇒ x̅ = 54.8 For Median : First of ... 52 For Mode : Make a frequency table for given data : Here, the marks 52 has the maximum frequency '3'. ∴ Mode = 52

In a school marks obtained by 80 students are given in the table. Draw a histogram. Also, make frequency polygon. -Maths 9th

Description : In a school marks obtained by 80 students are given in the table. Draw a histogram. Also, make frequency polygon. -Maths 9th

Last Answer : Here, class size = 135 - 305 = 10 ∴ Lower limit of first class interval is 305 - 10 / 2 = 300 Upper limit of first class interval is 305 + 10 / 2 = 310 Thus, first class interval is 300 - 310 Required histogram and frequency polygon is given on the graph paper .

Following is the frequency distribution of total marks obtained by the students of different section of class-IX. -Maths 9th

Description : Following is the frequency distribution of total marks obtained by the students of different section of class-IX. -Maths 9th

Last Answer : Since class intervals of the given frequency distribution are not of equal width. We would make modifications in the lengths of the rectangles in the histogram, so that the areas of rectangles are proportional ... lengths as given in the last column .The histogram of the data is given below.

In a mathematics test given to 15 students, the following marks (out of 100) are recorded : -Maths 9th

Description : In a mathematics test given to 15 students, the following marks (out of 100) are recorded : -Maths 9th

Last Answer : For Mean : As we know that ⇒ x̅ = 41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 52 + 60 / 15 x̅ = 822 / 15 = 54.8 ⇒ x̅ = 54.8 For Median : First of ... 52 For Mode : Make a frequency table for given data : Here, the marks 52 has the maximum frequency '3'. ∴ Mode = 52