A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

 A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298
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1 Answer

Answer :

Answer: B

 Let x be the maximum marks,

 Then (50% of x)+60 = (75% of x)-40

 x/2 +60 = 3x/4 -20

 60+20 = 3x/4 – x/ 2

X=320

 Hence maximum marks = 320

 Minimum pass marks = 320/2 + 60 = 220


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Description : What percent of a day in 12 hours? a) 25 b) 60 c) 45 d) 20 e) 50

Last Answer : Answer: E  Total hours in a day = 24 Required percent = 12/24 ×100  = 50%

The average of marks obtained by 60 students in a computer examination is 18. If the average marks of passed students is 20and that of the failed students is 8, what is the number of students who passed the examination? A) 100 B) 75 C) 50 D) 85

Description : The average of marks obtained by 60 students in a computer examination is 18. If the average marks of passed students is 20and that of the failed students is 8, what is the number of students who passed the examination? A) 100 B) 75 C) 50 D) 85 

Last Answer : C Let the number of passed students be x. Then total marks = 60 × 18= 20x + (60– x) × 8 1080= 20x + 480– 8x 12x = 600 ∴ x = 50 ∴ number of passed students = 50

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8

Description : In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8 

Last Answer : C)  let the number of paper be x total mark earned him = 82x then,, 82x+32+28= 97x 15x=60 x= 4 =number of subjects

True value has been 50 whereas measured value is 40 then the percentage error in the reading

Description : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be ______.  (A) 20% (B) 40% (C) 50% (D) 30%

Last Answer : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be 20%. 

If aggregates completely pass through a sieve of size 75 mm and are retained on a sieve of size 60 mm, the particular aggregate will be flaky if its minimum dimension is less than (A) 20.5 mm (B) 30.5 mm (C) 40.5 mm (D) 50.5 mm

Description : If aggregates completely pass through a sieve of size 75 mm and are retained on a sieve of size 60 mm, the particular aggregate will be flaky if its minimum dimension is less than (A) 20.5 mm (B) 30.5 mm (C) 40.5 mm (D) 50.5 mm

Last Answer : Answer: Option C

How do you write an algorithm which takes students marks and grades them as follows Mark greater than 60 Pass?

Description : How do you write an algorithm which takes students marks and grades them as follows Mark greater than 60 Pass?

Last Answer : Need answer

Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?

Description : Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?

Last Answer : Just divide it.