In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam secured `39%` marks and got 36 marks more than the p

In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam secured `39%` marks and got 36 marks more than the p
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In an examination, Salim secured `52%` marks and got 114 marks more than the pass marks and A zam ... (a) The pass mark. (b) The pass percentage.
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In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

In an examination, x and y secured 732 and 864 marks respectively. If y secured `72%` marks then find the percentage of marks secured by x.

Description : In an examination, x and y secured 732 and 864 marks respectively. If y secured `72%` marks then find the percentage of marks secured by x.

Last Answer : In an examination, x and y secured 732 and 864 marks respectively. If y secured `72%` marks then find the percentage of marks secured by x.

A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Description :  A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Last Answer : Answer: B  Let x be the maximum marks,  Then (50% of x)+60 = (75% of x)-40  x/2 +60 = 3x/4 -20  60+20 = 3x/4 – x/ 2 X=320  Hence maximum marks = 320  Minimum pass marks = 320/2 + 60 = 220

In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Description : In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Last Answer : Answer: A Difference = 672-126 = 546 According to the question, 70% of total aggregate = 546 Total aggregate marks = 546 × 100 /70  = 54600/70  = 780

Which of the following indicates evaluation? Options: A) Ram got 45 marks out of 200 B) Mohan got 38 percent marks in English C) Shyam got First Division in final examination D) All the above

Description : Which of the following indicates evaluation? Options: A) Ram got 45 marks out of 200 B) Mohan got 38 percent marks in English C) Shyam got First Division in final examination D) All the above

Last Answer : D) All the above

Which of the following indicates evaluation ? (A) Ram got 45 marks out of 200 (B) Mohan got 38 percent marks in English (C) Shyam got First Division in final examination (D) All the above

Description : Which of the following indicates evaluation ? (A) Ram got 45 marks out of 200 (B) Mohan got 38 percent marks in English (C) Shyam got First Division in final examination (D) All the above 

Last Answer : (D) All the above 

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Description : The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Last Answer : Since the class marks are equally spaced. ∴ Class size = 114 - 104 = 10 If a is a class mark and h is size of class interval, then lower limit and upper limit of the class interval area a - h / 2 and a + h / ... are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Description : The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Last Answer : Since the class marks are equally spaced. ∴ Class size = 114 - 104 = 10 If a is a class mark and h is size of class interval, then lower limit and upper limit of the class interval area a - h / 2 and a + h / ... are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.

Is 36 yards and 2 feet greater than 114 yards and 2 inches?

Description : Is 36 yards and 2 feet greater than 114 yards and 2 inches?

Last Answer : No it isn't.

Boron content in borax (suhaga) is (a) 11% (b) 25%(c) 19% (d) 39%

Description : Boron content in borax (suhaga) is (a) 11% (b) 25%(c) 19% (d) 39%

Last Answer : (a) 11%

A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Description : A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Last Answer : C) Let the requird mean score be ‘x’ Then (30*70)+(15*41)+55x = 63*100 2100+615+55x=6300 2715+55x=6300 55x=3585 X=65.181

In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298

Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298

Last Answer : Answer: D  Let the maximum marks be x.  Aashika’s marks = 32% of x  Aashika secured 1328 marks  Therefore, 32% of x = 1328  ⇒ 32/100 × x = 1328  x = (1328 × 100)/32  x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.

Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989

Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989 

Last Answer : Answer: C  If Gowthaman had scored 26 marks more, he could have scored 25%  Therefore, Mike required 424 + 26 = 450 marks  Let the maximum marks be x.  Then 25 % of x = 450  (25/100) × x = 450  x = (450 × 100)/25 x = 45000/25 x = 1800

In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately. -Maths 10th

Description : In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately. -Maths 10th

Last Answer : Let P has obtained x in mathematics and y in science. Then by the problem, x+y=28.......(1). If P would have got 3 marks more in mathematics, then P would have got (x+3) in mathematics ... P obtained 12 marks in mathematics and 16 in science. or, P obtained 9 marks in mathematics and 19 in science.

In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8

Description : In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8 

Last Answer : C)  let the number of paper be x total mark earned him = 82x then,, 82x+32+28= 97x 15x=60 x= 4 =number of subjects

In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam? A) 10 B) 12 C) 14 D) 20

Description : In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam? A) 10 B) 12 C) 14 D) 20

Last Answer : Answer: D)  Let the number of paper be A. Then total marks earned him = 75A from questions, 75A + 33+ 27= 78A 3A = 60=> A=20 = number of subjects

Rupesh secures 495 marks out of 750 in his annual examination. Find the percentage of marks obtained by him. -Maths

Description : Rupesh secures 495 marks out of 750 in his annual examination. Find the percentage of marks obtained by him. -Maths

Last Answer : answer:

What is the strategy to get higher marks in the examination book ?

Description : What is the strategy to get higher marks in the examination book ?

Last Answer : The writing must be beautiful. Must be clearly written. You have to keep a certain distance from one line to another. What is asked in the question should be written in a short order, that ... point should be noted. Try to give something from yourself without writing the language of the whole book.

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

Description : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

Last Answer : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25 ... the probability that he gets more than 18 marks?

The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Description : The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Last Answer : Answer – B (100) Explanation – Let the number of passed candidates be a Then total marks =>120 x 35 = 39 a + (120 – a) x 15 4200 = 39 a + 1800 – 15 a a = 100

In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Description : In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Last Answer : C. 29,30,31

What are the characteristics of Continuous and Comprehensive Evaluation ? (a) It increases the workload on students by taking multiple tests. (b) It replaces marks with grades. (c) It evaluates every aspect of the student. (d) It helps in reducing examination phobia. Select the correct answer from the codes given below: (A) (a), (b), (c) and (d) (B) (b) and (d) (C) (a), (b) and (c) (D) (b), (c) and (d)

Description : What are the characteristics of Continuous and Comprehensive Evaluation ? (a) It increases the workload on students by taking multiple tests. (b) It replaces marks with grades. (c) It evaluates every aspect of the student. (d) It helps in ... ) and (d) (C) (a), (b) and (c) (D) (b), (c) and (d)

Last Answer : Answer: D

The average of marks obtained by 60 students in a computer examination is 18. If the average marks of passed students is 20and that of the failed students is 8, what is the number of students who passed the examination? A) 100 B) 75 C) 50 D) 85

Description : The average of marks obtained by 60 students in a computer examination is 18. If the average marks of passed students is 20and that of the failed students is 8, what is the number of students who passed the examination? A) 100 B) 75 C) 50 D) 85 

Last Answer : C Let the number of passed students be x. Then total marks = 60 × 18= 20x + (60– x) × 8 1080= 20x + 480– 8x 12x = 600 ∴ x = 50 ∴ number of passed students = 50

In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200

Description : In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200 

Last Answer :  A)  let the number of candidates be A total marks of candidates = 72A after detecting error the change of marks for one candidate = 90 - 66 = 24 marks change of marks for 94 candidates = 94*24 = ... after detecting error of N candidates = 64A then, 72A- 2256= 64A , 8A=2256 A=282

Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5

Description : Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5 

Last Answer : Answer: B) Maximum total marks = 5 120 = 600 Marks scored by Saravanan = 90/100*600=540 Let the marks scored by him in the 5 subjects be 18x,14x,15x,21x and 22x respectively. 18x + 14x + 15x + 21x + ... A' grade i.e. 0.85 120 = 102 Therefore, he has got an A' grade in 3 subjects.

Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98

Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98

Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7

Why did Salim need credit? -SST 10th

Description : Why did Salim need credit? -SST 10th

Last Answer : Salim needed credit to purchase the raw materials for the manufacture of shoes.

What is the meaning of the name Shakib Salim ?

Description : What is the meaning of the name Shakib Salim ?

Last Answer : The name Shakib Salim means bright and healthy.

What is the meaning of the name Salim Shadman ?

Description : What is the meaning of the name Salim Shadman ?

Last Answer : The name Salim Shadman means healthy and happy.

What is the name-meaning Salim ?

Last Answer : The name-meaning Salim is perfect

Tombs of Salim Chisti, Kabulbag mosque, Jama Masjid, Purana Qila, Fatehpur Sikri

Description : Tombs of Salim Chisti, Kabulbag mosque, Jama Masjid, Purana Qila, Fatehpur Sikri

Last Answer : Find the incorrect pair from set B and write the correct one: Set A' Set B' (a) Tombs of ... (c) Jama Masjid Sambhal (d) Purana Qila Ajmer

The quantity of Orange available at vendor A is approximately what percent more than that of Apple available at vendor B? 1) 61.52% 2) 68.4% 3) 82% 4) 90% 5) 71.43%

Description : The quantity of Orange available at vendor A is approximately what percent more than that of Apple available at vendor B? 1) 61.52% 2) 68.4% 3) 82% 4) 90% 5) 71.43%

Last Answer : 5) 71.43%

What is the share of Punjab in the total population of Pakistan: A. 60% B. 52% C. 48% D. None of these

Description : What is the share of Punjab in the total population of Pakistan: A. 60% B. 52% C. 48% D. None of these

Last Answer : ANSWER: C

What is the share of Punjab in the total population of Pakistan: A. 60% B. 52% C. 48% D. None of these

Description : What is the share of Punjab in the total population of Pakistan: A. 60% B. 52% C. 48% D. None of these

Last Answer : ANSWER: C

How much shareholding is must for the promoters of insurance companies after their listing? A) 40% B) 50% C) 49% D) 52% E) None of these

Description : How much shareholding is must for the promoters of insurance companies after their listing? A) 40% B) 50% C) 49% D) 52% E) None of these

Last Answer : B) 50% Explanation: Promoters of insurance companies will be forced to maintain their shareholding at 50 per cent even after listing under the guidelines proposed by the insurance regulator ... Insurance Regulatory and Development Authority of India s (IRDAI) draft guidelines for listed companies.

How much percentage of Indian land is prone to earthquakes? a. 52% b. 54% c. 59% d. 60%

Description : How much percentage of Indian land is prone to earthquakes? a. 52% b. 54% c. 59% d. 60%

Last Answer : c. 59%

Out of 50 quadrats studied, if Echinochloa is found in 26 quadrats, its frequency of occurrence would be a). 13% b). 26% c). 52% d). 68%

Description : Out of 50 quadrats studied, if Echinochloa is found in 26 quadrats, its frequency of occurrence would be a). 13% b). 26% c). 52% d). 68%

Last Answer : c). 52%

By selling a mobile at 52% discount, a seller incurs a loss of 8%. The marked price of the product is 18000 Rs. At what percent discount the seller should sell the mobile so as to have a profit of 33%.

Description : By selling a mobile at 52% discount, a seller incurs a loss of 8%. The marked price of the product is 18000 Rs. At what percent discount the seller should sell the mobile so as to have a profit of 33%.

Last Answer : Since, Marked Price = 18000 Therefore, Selling Price = 18000*0.48 = 8640 Loss of 8% is there Therefore, Cost price = 8640/0.92 = 9391.30Rs To have profit of 33% The Selling Price should be = 9391. ... should be 18000 - 12490.42 = 5509.58Rs Discount% should be [5509.58/18000]*100 = 30.60 ≈ 31%.

A jar full of whiskey contains 52% alcohol. A part of this ****** is replaced by another containing 31% alcohol and now the percentage of alcohol was found to be 38%. The quantity of ****** replaced is a) 3/2 b) 2/3 c) 4/3 d) 2/7 e) None

Description : A jar full of whiskey contains 52% alcohol. A part of this whisky is replaced by another containing 31% alcohol and now the percentage of alcohol was found to be 38%. The quantity of whisky replaced is a) 3/2 b) 2/3 c) 4/3 d) 2/7 e) None

Last Answer : B Concentration of alcohol in 1st Jar = 52% Concentration of alcohol in 2nd Jar = 31% After the mixing, Concentration of alcohol in the mixture = 38% By rule of allegation, Hence ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2 i.e., 2/3 part of the whisky is replaced.

On examination of an 8 years-old child you find 75 with carious exposure. On X-ray you find 35 missing. Your treatment is: A. Extraction of 75 allowing 36 to move mesially B. Pulpotomy on 75 and wait indefinitely C. Extraction of 75 and place a fixed space retainer to be replaced with fixed bridge. D. Extraction of 65 and 75

Description : On examination of an 8 years-old child you find 75 with carious exposure. On X-ray you find 35  missing. Your treatment is:  A. Extraction of 75 allowing 36 to move mesially  B. ... of 75 and place a fixed space retainer to be replaced with fixed bridge. D. Extraction of 65 and 75 

Last Answer : B. Pulpotomy on 75 and wait indefinitely  

Students of two university appeared for a common test of maximum 60 marks. The average of their marks for university 1 & university 2 are 39 & 42 respectively. If the no of students of university 1 is twice the no of students of university 2. Then what is the average marks of all students of both the university? A) 40 B) 42 C) 26 D) 36

Description : Students of two university appeared for a common test of maximum 60 marks. The average of their marks for university 1 & university 2 are 39 & 42 respectively. If the no of students of university 1 is twice the no ... the average marks of all students of both the university? A) 40 B) 42 C) 26 D) 36

Last Answer : Answer: A) Let number of students of university2 be N and the no of students of university 1 be 2N the average of university1 and university 2 is 39 and 42 total marks of university 1 students and university 2 ... 78N and N*42 =42N average of both university,  =(78N+42N) /(N+2N) = 40 marks

In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected with 240 more than the candidates got selected in Pondicherry. What was the number of candidates appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800

Description : In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected ... appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800

Last Answer : Answer: C  Pondichery and Tamilnadu had an equal number of candidates appeared  In Pondicherry, 18% candidates got selected from the total appeared candidates  In tamilnadu, 21% candidates ... > total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000

Explain the following: Only one-third of the students in Vietnam would pass the school-leaving examination -SST 10th

Description : Explain the following: Only one-third of the students in Vietnam would pass the school-leaving examination -SST 10th

Last Answer : French doesn't want Vietnamese to compete with them for better-paid jobs in Vietnam so, they plan the education system in the manner that only one-third of the students in Vietnam would pass ... of manual labour only. School children were taught that only French rule could ensure peace in Vietnam.

Before X-ray examination (coloured Xray) of the stomach, patients are given suitable salt of barium because. (1) barium is a good absorber of X-rays and helps stomach to appear clearly (2) barium salts are white in colour and this helps stomach to appear clearly (3) barium allows X-rays to pass through the stomach (4) barium salts are easily available

Description : Before X-ray examination (coloured Xray) of the stomach, patients are given suitable salt of barium because. (1) barium is a good absorber of X-rays and helps stomach to appear clearly (2) barium ... clearly (3) barium allows X-rays to pass through the stomach (4) barium salts are easily available

Last Answer : (1) barium is a good absorber of X-rays and helps stomach to appear clearly

Teaching in higher education implies Options: A) presenting the information given in the text book B) asking questions in the class and conducting examinations C) helping students prepare for and pass the examination D) helping students how to learn

Description : Teaching in higher education implies Options: A) presenting the information given in the text book B) asking questions in the class and conducting examinations C) helping students prepare for and pass the examination D) helping students how to learn

Last Answer : D) helping students how to learn 

The primary task of a teacher is Options: A) to teach the prescribed curriculum B) to prepare students to pass their examination C) to make them a thinking people D) to modify their behaviour according to the needs of our society and country.

Description : The primary task of a teacher is Options: A) to teach the prescribed curriculum B) to prepare students to pass their examination C) to make them a thinking people D) to modify their behaviour according to the needs of our society and country.

Last Answer : D) to modify their behaviour according to the needs of our society and country. 

The main objective of teaching at Higher Education Level is: Options: A) To prepare students to pass examination B) To develop the capacity to take decisions C) To give new information D) To motivate students to ask questions during lecture

Description : The main objective of teaching at Higher Education Level is: Options: A) To prepare students to pass examination B) To develop the capacity to take decisions C) To give new information D) To motivate students to ask questions during lecture

Last Answer : B) To develop the capacity to take decisions 

A teacher can be successful if he/she (A) helps students in becoming better citizens (B) imparts subject knowledge to students (C) prepares students to pass the examination (D) presents the subject matter in a well organized manner

Description : A teacher can be successful if he/she (A) helps students in becoming better citizens (B) imparts subject knowledge to students (C) prepares students to pass the examination (D) presents the subject matter in a well organized manner

Last Answer : (D) presents the subject matter in a well organized manner