How far away from the surface of the Earth does the acceleration due to gravity become ½ of its value at the surface of Earth? It is at a (a) Distance equal to radius (b) Distance equal to half the radius (c) Distance equal to twice the radius (d) Distance equal to 0.414 times the radius

How far away from the surface of the Earth does the acceleration due to gravity become ½ of its value at the surface of Earth? It is at a (a) Distance equal to radius (b) Distance equal to half the radius (c) Distance equal to twice the radius (d) Distance equal to 0.414 times the radius
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Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Description : Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Last Answer : (A) (1/2π). √(g/r)

A imaginary planet has half the mass and half the radius of the earth. The acceleration of gravity at its surface would be a.9.8 m/s2 b.107 dynes c.4.9 m/s2 d.19.6 m/s2 e.2.45 m/s2

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At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface,

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Assuming uniform density of the core, the acceleration due to gravity below the Earth's surface is A. inversely proportional to the square of the distance from the center of the Earth B. inversely proportional to the distance from the center of the Earth C. directly proportional to the square of the distance from the center of the Earth D. directly proportional to the distance from the center of the Earth

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An object with a mass of 5 kilograms is a distance of 5 meters above the surface of the earth. If the acceleration due to gravity is 10 meters per second squared, the potential energy of the object relative to the surface of the earth is: w) 10 joules x) 20 joules y) 100 joules z) 250 joules e) none of the above

Description : An object with a mass of 5 kilograms is a distance of 5 meters above the surface of the earth. If the acceleration due to gravity is 10 meters per second squared, the potential energy of the object relative to the ... is: w) 10 joules x) 20 joules y) 100 joules z) 250 joules e) none of the above

Last Answer : ANSWER: Z -- 250 JOULES

If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

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A force applied to a rocket gives it an upward acceleration equal to 2 times the acceleration of gravity. The magnitude of the force is equal to: w) the weight of the rocket x) twice the weight of the rocket y) three times the weight of the rocket z) four times the weight of the rocket

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An artificial satellite stays in the orbit around the Earth because (a) The Earth’s gravity does not act on the satellite due to the great distance between them (b) The Earth’s attraction produces the necessary centripetal acceleration (c) The Earth’s attraction is balanced by the attraction of other planets (d) There is an engine in the satellite that constantly applies an upward force to balance its weight

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Two bodies of equal mass are moving in circular paths at equal speed. The first body moves in a circle whose radius is twice as great as that of the second. The ratio of the centripetal or radial acceleration of the first body to that of the second is: w) 1 to 4 x) 1 to 3 y) 1 to 2 z) 1 to 1

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Last Answer : ANSWER: Y -- 1 TO 2

A hiker stands at the bottom of steep hill. The hiker may follow a straight line path to the top of the hill, a distance of 300 feet, or she may follow a zig-zag path to the top of the hill and walk a distance of 600 feet. The work done by the force of gravity along the zig-zag path is how many times the work going along the straight path? Is it: w) equal x) twice y) 4 times z) 8 times?

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Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

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A person can jump higher on the moon's surface than on the earth because – (1) the moon's surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

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If a body weighs 12N on the surface of the earth, how much will it weigh on the surface of the moon where acceleration due to gravity is only one-sixth of that on earth's surface? (1) 12N (2) 2N (3) 10N (4) 6N

Description : If a body weighs 12N on the surface of the earth, how much will it weigh on the surface of the moon where acceleration due to gravity is only one-sixth of that on earth's surface? (1) 12N (2) 2N (3) 10N (4) 6N

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A person can jump higher on the moon’s surface than on the earth because : (1) the moon’s surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Description : A person can jump higher on the moon’s surface than on the earth because : (1) the moon’s surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

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Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 10^3 km and its mass is 6.4 × 10^23 kg.

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If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

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If the distance between the earth and the sun were twice what it is now, the gravitational force exerted on the earth by the sun would be (a) twice as large as it is now (b) four times as large as it is now (c) half of what it is now (d) one-fourth of what it is now

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If the distance between the earth and moon were halved, the force of the attraction between them would be: w) one fourth as great x) one half as great y) twice as great z) four times as great

Description : If the distance between the earth and moon were halved, the force of the attraction between them would be: w) one fourth as great x) one half as great y) twice as great z) four times as great 

Last Answer : ANSWER: Z -- FOUR TIMES AS GREAT

Weight of a person at a height of 2R from the centre of the earth, where R is the radius of the earth- (1) remains same (2) becomes half (3) becomes twice (4) becomes one-fourth

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The most economical section of a rectangular channel is one which has hydraulic mean depth or hydraulic radius equal to (A) Half the depth (B) Half the breadth (C) Twice the depth (D) Twice the breadth

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Two bodies are moving in circular paths of equal radii. If the speed of the first body is twice that of the second, the centripetal acceleration of the first body is how many times greater than that of the second body?

Description : Two bodies are moving in circular paths of equal radii. If the speed of the first body is twice that of the second, the centripetal acceleration of the first body is how many times greater than that of the second body?

Last Answer : ANSWER: 4

Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.

Description : Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.

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Show that acceleration due to gravity at height h above the Earth’s surface is gh = g(R/R + h)^2

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If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

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If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

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If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

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When the velocity of an enzymatic reaction equals Vmax, substrate concentration is (A) Half of Km (B) Equal to Km (C) Twice the Km (D) Far above the Km

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Description : At the Center of earth Acceleration due to gravity (g) is?

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If the earth were to skin faster, how does acceleration due to gravity at the poles?

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The Michaelis constant, Km is (A) Numerically equal to ½ Vmax (B) Dependent on the enzyme concentration (C) Independent of pH (D) Numerically equal to the substrate concentration that gives half maximal velocity

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State the formula for acceleration due to gravity at depth ‘d’ and altitude ‘h’ Hence show that their ratio is equal to ((R - d)/(R - 2h))

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The acceleration due to gravity at the equator – (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth's centripetal acceleration

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The sensation of weightlessness in a spacecraft in an orbit is due to the – (1) Absence of gravity outside (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside (3) Presence of gravity outside but not inside the spacecraft (4) Fact that spacecraft in the orbit has no energy

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Last Answer : (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside Explanation: Weightlessness in space is caused by the simple physical factors that cause the limitation of gravity. ... . Many people believe that a lack of gravity is the root cause for weightlessness in space.

The sensation of weightlessness in a spacecraft in an orbit is due to the (1) absence of gravity outside (2) acceleration in the orbit which is equal to the acceleration due to gravity outside (3) presence of gravity outside but not inside the spacecraft (4) fact that spacecraft in the orbit has no energy

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Last Answer :  acceleration in the orbit which is equal to the acceleration due to gravity outside

The acceleration due to gravity at the equator (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth’s centripetal acceleration

Description : The acceleration due to gravity at the equator (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth’s centripetal acceleration 

Last Answer : is less than that at the poles

In Joule's experiment, an insulated container contains 20 kg of waterinitially at 25°C. It is stirred by an agitator, which is made to turn by aslowly falling body weighing 40 kg through a height of 4 m. The process isrepeated 500 times. The acceleration due to gravity is 9.8 ms-2. Neglectingthe heat capacity of agitator, the temperature of water (in °C) is(A) 40.5(B) 34.4(C) 26.8(D) 25

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Last Answer : (B) 34.4

The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

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The length of a wire is increased by 1 mm on the application of a certain load. In a wire of the same material but of twice the length and half the radius, the same force will produce an elongation of (a) 0.5 mm (b) 2 mm (c) 4 mm (d) 8 mm

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Last Answer : (d) 8 mm

At high altitudes it is difficult to cook eggs or vegetables properly because of (a) High boiling point of water and low atmospheric pressure (b) Low boiling point of water and low atmospheric pressure (c) Low value of acceleration due to gravity (d) High atmospheric pressure and low billing point of water

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If is the difference in level between end points separated by , then the slope correction is [(h²/2l) + (h 4 /8l3 )]. The second term may be neglected if the value of in a 20 m distance is less than (A) ½ m (B) 1 m (C) 2 m (D) 3 m

Description : If is the difference in level between end points separated by , then the slope correction is [(h²/2l) + (h 4 /8l3 )]. The second term may be neglected if the value of in a 20 m distance is less than (A) ½ m (B) 1 m (C) 2 m (D) 3 m

Last Answer : (D) 3 m

The value of acceleration due to gravity is maximum at

Description : The value of acceleration due to gravity is maximum at

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As we go from Equator to North pole the value of `S, the acceleration due to gravity (1) remains the same (2) decreases (3) increases (4) None of the above

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As we go from Equator to North pole the value of ‘g’, the acceleration due to gravity (1) remains the same (2) decreases (3) increases (4) None of the above

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Last Answer : increases

Two negative point charges are 2 meters apart and repel each other with a force of 2 newtons. When the distance between the charges is doubled, the force between them is w) one fourth as great x) one half as great y) twice as great z) four times as great

Description : Two negative point charges are 2 meters apart and repel each other with a force of 2 newtons. When the distance between the charges is doubled, the force between them is w) one fourth as great x) one half as great y) twice as great z) four times as great

Last Answer : ANSWER: W -- ONE FOURTH AS GREAT

A particle of mass m moves in a circular path of radius r at constant speed v. Its KE is (a) mv2/r (b) ½ Iw (c) ½ mv2 (d) ½ mrw2

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Acceleration of free fall depends on the A. surface B. weight of object C. distance from center of Earth D. size of object

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Last Answer : weight of object