Write an expression for equilibrium constant with respect to concerntration.

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Write an expression for equilibrium constant with respect to concerntration.

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Last Answer : According to the formula ΔG° = -nFE° = – 2 × 96500 ×1.05 or ΔG° = -202650 J mol-1 = -202.65 KJ mol-1 Now ΔG° ⇒ -202650 J Mol-1 R = 8.314 J/Mol/K, T = 298 K

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Last Answer : Ans. Activities are used in place of molar Conc. These represent the concentration or pressure with respect to standard state.

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Last Answer : (B) Conversion

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Last Answer : (A) Activation energy

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Last Answer : (C) Reactant concentration at equilibrium condition is zero

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Last Answer : (A) Retards the rate of reaction

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Last Answer : (B) Increases with pressure

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Last Answer : (D) Molar concentration of the reactants

Description : Pick out the correct statement. (A) A catalyst speeds up the forward reaction but slows shown the reverse reaction (B) Addition of catalyst changes the equilibrium constant (C) Pressure changes do not change the equilibrium concentrations (D) The composition of equilibrium is changed by catalyst

Last Answer : (C) Pressure changes do not change the equilibrium concentrations

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Last Answer : (C) The rate constant for a first order reaction does not change on changing the concentration units

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Last Answer : (B) Activation energy

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Last Answer : (D) All (A), (B) and (C)

Description : For the reversible reaction A ⇌ 2B, if the equilibrium constant K is 0.05 mole/litre; starting from initially 2 moles of A and zero moles of B, how many moles will be formed at equilibrium? (A) 0.253 (B) 0.338 (C) 0.152 (D) 0.637

Last Answer : (B) 0.338