A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

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A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

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Description : A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Last Answer : Let the distance be x km. then (x/40) + (x/6) = 13 + (48/60) = 69/5 Answer is: d)

Description : Shreya travel the first part of her journey at 160 kmph and the second part at 240 kmph and cover the total distance of 3840 km to her destination in 20 hours. How long did the first part of her journey last? a) 8 hrs b) 12 hrs c) 16 hrs d) 10 hrs

Last Answer : B The total time of journey = 20 hours. Let 'x' hours be the time that shreya travelled at 160 kmph Therefore, 20-x hours would be time that she travelled at 240 kmph. Hence, she would have covered x*160+( ... 20-x)*240 =3840 160x +4800-240x =3840 240x-160x=4800-3840 80x= 960 X=960/80=12 hrs

Description : In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid Rs.156 for a journey of 16 km and another person paid Rs.204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is (A) 236 (B) 240 (C) 248 (D) 256

Last Answer : Answer: B

Description : The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs ... speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Last Answer : D Let the speed in return journey be x km/hr Then speed in upward journey = 150 /100 x = (3/2 x)km/hr Average speed = (2*3x/2*x) / (3x/2 +x) =3x2 / (5x/2) =6x2 / 5x =6x/5 km/hr Therefore (1600 ... 192x = 8000 X = 41.66 Speed in upward journey = (3/2 x ) km/hr =(3/2*41.66) =62.49 km/hr 

Description : A boys rows to a certain place and comes back, but by mistake he covers 2/3rd more distance while coming back. The total time for this journey is 20 hours. The ratio of speed of boat to that of ... starting point from his present position? A) 2hr 13mints B)1hr 30 mins C) 2hr 30mins D)1hr 40 mins

Last Answer : ANSWER : A Explanation: let speed of boat and stream be 2x and x respectively So downstream speed = 2x+x = 3x, and upstream speed = 2x-x = x Let total distance between points is d km So he covered d ... with speed 3x = 48 km/hr(downstream) So time is 80/36 * 60 = 133.33 minutes = 2hr 13mins

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

Description : A man moved into a new house and decided he was tired after the journey and turned of all the lights and went to bed. The next morning he had killed 365 people how could this be? he does not sleep walk he slept like a baby -Riddles

Last Answer : he lived in a light house

Description : Jackson travels a distance of 100km in 5 hrs. How much faster in kilometer per hr, on an average, must he travel to make a journey in 5/3 hr less time? a) 5 km/hr b) 10km/hr c) 6 km/hr d) 8 km/hr

Last Answer : B Time required = (5 hrs – 5/3 hrs) =(5 hrs – 100 mints) = (5 hrs – 1hr 40 mints) = 3 hrs 20 mints = 3 1/3 hrs Required speed = (100*3/10) km/hr =30 km/hr Original speed = (100/5)km/hr = 20 km/hr Difference speed = required speed – original speed =(30-20) =10km/hr

Description : A car starts from rest and moves on a straight road with a uniform acceleration of 10 m/s2 for the first 10 s. During the next 10 s, the car move s with the velocity it has attained. What is the total distance covered by the car in 20 s? (a) 500 m (b) 1000 m (c) 1,500 m (d) 2,000 m

Last Answer : Ans:(c)

Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Last Answer : 3) 840 km

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

Description : How much area could be covered for giving one irrigation of 3" depth by a pumpset of one cusec output in the operation of 600 hours, if the water conveyance efficiency is 80 per cent ? (A) 180 acres (B) 320 acres (C) 240 acres (D) 160 acres (E) None of these

Last Answer : (C) 240 acres

Description : If a traveler walk straight from one city to the next city which would be longer journey from Jerusalem to Ebla or from Thebes to Memphis?

Last Answer : they the same =.=

Description : Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Last Answer : speed=distancetimespeed=distancetime or time=distancespeedtime=distancespeed For travelling 1 km with 3 km/hr, Time taken = 1/3 hr = 20 min Now he has to reach school in 30 min,So he has cover another 1 km in = 30 -20 =10 min= 1/6 hr So speed should = distance /time= 1/(1/6) = 6 km/hr

Description : Two men walk into a resturant by the sea and sit at the bar. Both men are covered in water. Both men order a plate of Albatross and take one bite. After chewing and swallowing, the first man stands up, walks outside, and shoots himself, while the other finnishes his meal. Why? -Riddles

Last Answer : The two men were stranded out in the ocean with a third man when they were beginning to stave. When an albatross landed on their life boat and died they finally had food but it was not enough to ... eat real Albatross and the man who killed himself realized that he was the one that ate his friend.

Description : Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Last Answer : A Speed of the rider = 40km/hr. Distance covered in 1st hour = 40 km. He increased his speed in every 1 hour by 4 km/hr. Distance covered in every 1 hours will be, 44, 48, ,... upto 12 terms.(for 12 hours). ... (2(40)+(11)4) = 6(80 + 44) = 6(124) = 744. Hence, he covers 744 km in 12 hours.

Description : A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has ... father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

Last Answer : Time taken is same for both father and son Let x be the distance son travelled before being overtaken by his father Time taken by son = x/5 km/hour Time taken by father = (1000 + x) / 7.5 km/hr Since, time taken is same x/5 = (1000 + x) / 7.5 or x = 2000m Answer: b)

Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)

Description : Kathir bought some bananas at Rs.20 per dozen and bought the same number of bananas at Rs.16 per dozen. He sold these bananas at Rs.22 per dozen and gained Rs. 240. The total number of dozen bananas bought by him was:

Last Answer : Cost price : 1 dozen bananas = Rs. 20 1 dozen bananas = Rs. 16 2 dozen bananas= Rs. 36 1 dozen bananas = Rs. 18 Selling price: 1 dozen bananas = Rs.22 Profit per dozen is Rs. 4 Therefore x* profit = Rs. 240 x = 240/4 X = 60 dozen

Description : A body moves, from rest with a constant acceleration of 5 m per sec. The distance covered in 5 sec  is most nearly  (A) 38 m  (B) 62.5 m  (C) 96 m  (D) 124 m

Last Answer : (B) 62.5 m 

Description : Anushiya covered a definite distance at some speed. If she had moved 5 kmph faster, she would have taken 55minutes less. If he had moved 4 kmph slower, she would have taken 55 minutes more. What is the distance in km? a) 110 Km b) 220 km c) 330 km d) 440 km

Last Answer : C speed=2V1V2/(V1-V2) = 2*5*4/(5-4) =40 km/hr Distance= vt1 (1+v/v1) =40* 55/60(1+40/5) =40*11/12(1+8) =40*11/12*9 =330 km Therefore the distance is 330km

Description : If the total source voltage of the three-wire distribution system shown in the illustration is 240 volts, what is the voltage across load L5? [ NOTE: Kirchhoff's voltage and current laws apply ] EL-0075 A. 110.4 volts B. 112.2 volts C. 113.0 volts D. 114.8 volts

Last Answer : Answer: D

Description : If the total source voltage of the three-wire distribution system shown in the illustration is 240 volts, what is the voltage across load L1? [NOTE: Kirchhoff's voltage and current laws apply.] EL-0075 A. 110.4 volts B. 112.2 volts C. 113.3 volts D. 114.8 volts

Last Answer : Answer: D

Description : If the total source voltage of the three-wire distribution system shown in the illustration is 240 volts, what is the voltage across load L2? [NOTE: Kirchhoff's voltage and current laws apply.] EL-0075 A. 110.4 volts B. 112.2 volts C. 113.0 volts D. 114.8 volts

Last Answer : Answer: C

Description : If the total source voltage of the three-wire distribution system shown in the illustration is 240 volts, what is the voltage across load L3? [NOTE: Kirchhoff's voltage and current laws apply.] EL-0075 A. 110.4 volts B. 112.2 volts C. 113.0 volts D. 114.8 volts

Last Answer : Answer: B

Description : If the total source voltage of the three-wire distribution system shown in the illustration is 240 volts, what is the voltage across load L4? EL-0075 A. 110.4 volts B. 112.2 volts C. 113.0 volts D. 114.8 volts

Last Answer : Answer: A

Description : In a reservoir the average volume of sediment deposition is 0.15 million cubic per year. If the dead storage and total capacity of the reservoir are 8 million cubic metres and 36 million cubic metres respectively, (A) The ... reducing after 60 years (C) Both (a) and (b) (D) Neither (a) nor (b)

Last Answer : (C) Both (a) and (b)

Description : Mr. Grumper grumbles about bad time-keeping trains like everybody else. On one particular morning he was justified, though. The train left on time for the one hour journey and it arrived 5 minutes late. ... did on the morning journey, was the station clock fast or slow, and by how much? -Riddles

Last Answer : The station clock is 3 minutes fast. The morning journey took 65 minutes, and the evening journey therefore took 52 minutes, and the train arrived 57 minutes after it should have left, that is, 3 minutes early.

Description : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered in two equal time intervals

Last Answer : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered ... /s C. 5.5 m/s D. 4.8 m/s

Description : If diameter of a wheel is 1.26 m, what the distance covered in 500 revolutions? (a) 1.38 km (b) 4.64 km (c) 2.46 km (d) 1.98 km

Last Answer : (d) 1.98 km

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr

Description : A this usual rowing rate, Mohit can travel 12 miles downstream in a certain river in 6 hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24 miles round trip, ... current in miles per hour? A.2.5m/hr B.4 m/hr C.8/3 m/hr D. 5/3m/hr

Last Answer : Answer-C Basic Formula: Speed of the stream = ½ (a-b) km/hr Explanation: Let the speed in still water be x m/hr Speed of stream be y m/hr Then, speed upstream = x-y m/hr and Speed downstream = x+y m/hr 12/x-y - ... 1] 3y^2 = 8 y so, y = 8/3 speed of the current = 8/3 m/hr = 2 (2/3) m/hr

Description : A man goes to work at the same time each day and travels part of his journey facing forwards and the remainder facing backwards. When he returns at the end of his working day, he only faces forwards.How can this be? -Riddles

Last Answer : He works in the engine room of a liner! To get to work, he walks along the decks from his cabin facing forwards, and down the ladders between decks facing backwards. However, when he finishes, he only needs to face forwards to climb the ladders again and walk along the deck back to his cabin.

Description : What did Columbus think he was on the rd day of his journey?

Last Answer : What is the answer ?

Description : Hello, My question is, to become a missionary, what steps do I need to take to start this new journey to spread Gods word around the world To fully serve Him and I believe in my heart and soul He has called me to do His work.Thank you&God bless, Jered D.?

Last Answer : Hello, Jared. We would love to talk with you about being a missionary. Check our web site. www.agapechildren.org or call me at (209) 543-9255

Description : How did Odysseus come to have only his own ship instead of the fleet with which he began the journey?

Last Answer : He then tells him of his voyage from Troy to Ismarus, city of Cicons, where they plundered the town until they were repulsed. They proceeded with their journey, but Zeus punished them by setting them off course. They instead arrived at the land of the Lotus eaters, then at the land of the Cyclopes.

Description : you walk from home to town, a distance of 6km in 50minutes. find the average speed in m/s?

Last Answer : 300 km/m

Description : I have four legs but never walk I may be covered in flowers but have no soil I hold food three times a day but never eat a meal.What am I? -Riddles

Last Answer : A table.

Description : Sasi is a badham merchant in kerala. He has badham in sealed wooden boxes of 15kg each. The price of the badham increases by Rs.30 per kg for every year, but at the same time, 10% of the badham are ... if he sells a sealed box after one year of storage, rather than selling it fresh ?( In Rs.)

Last Answer : Price of 1kg fresh batham= Rs.240 Therefore, price of 15kg = Rs.15*240= 3600  10% of 15kg which eaten by rodents = 10 x 15/100 = 1.5kg.  So, End of Year he had 15kg - 1.5kg = 13.5kg So, ... box with badham for Rs.3600 and sell that for Rs. 3645  So, profit = 3645-3600= Rs.45 more money he get.

Description : Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Last Answer : C) Given x= 168 , y = 112 Required average speed = (2xy / x + y) km/hr = 2 * 168 *112 / 168 + 112 = 37632 / 280 =134.4 km/hr

Description : he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th

Last Answer : Solution :- Fig. 3.12 represents the graph of the linear equation y = 4x+6.

Description : A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec

Last Answer : ANSWER:D Explanation:  Speed of the train = 270 km/hr. Converting the speed into m/sec  Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec  First, we have to find the length of the train  Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)

Description : A man decided to go for a walk. He made numerous stops during his stroll, hoping to hear some good news each time he stopped. Despite his usual excellent sense of direction, he realized he had ... bizarre-sounding narrative, and who/what was the sweet love of his life which was mentioned? -Riddles

Last Answer : The man gave a monetary donation to participate in a cake walk. Eventually, his number was called for the space he was standing on, and he went home with the dessert he truly loved ———— a beautiful cake!

Description : A hiker stands at the bottom of steep hill. The hiker may follow a straight line path to the top of the hill, a distance of 300 feet, or she may follow a zig-zag path to the top of the hill and walk a ... times the work going along the straight path? Is it: w) equal x) twice y) 4 times z) 8 times?

Last Answer : ANSWER: W -- EQUAL 

Description : An object travels from a fixed position 5 seconds to start the journey. After 20 m / s. Velocity is. Next 10 sec. How far will it cover ?

Last Answer : The distance covered by the object in the next 10 seconds s = vt s = 20 × 10 = 200m

Description : In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected ... appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800

Last Answer : Answer: C  Pondichery and Tamilnadu had an equal number of candidates appeared  In Pondicherry, 18% candidates got selected from the total appeared candidates  In tamilnadu, 21% candidates ... > total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000

Description : Two taps M and N can alone fill a tank in 80 minutes and 120 minutes respectively. But due to a leakage of tank, it took 12 more minutes to fill the tank. In how many hours, the leak can alone empty the full tank? A) 240 B) 230 C) 248 D) 256

Last Answer : A A and B can fill tank in (1/80 + 1/120) = 1/48 so 48minutes But it took 12 more minutes, this means the tank got full in 48+12= 60 minutes So (1/80 + 1/120 – 1/x) = 1/60 1/X=1/80+1/120-1/60 Solve, x = 240

Description : M = m0 / sqrt(1 - (v/c)^2): will humankind never journey to even the nearest star?

Last Answer : Just warp space and bring your starting and stopping distances closer together. Obviously. ;)

Description : A train starts its journey from a stationary position and after running for 1 minute in parallel, 30 m / s speed is obtained. Determine the speed of the train in 1 minute ?

Last Answer : Here , the initial velocity , u = 0 m / s end velocity , v = 30 m / s time , t = 1 min = 60 sec we know , acceleration , a = (v- u) / t = (30- 0) / 60 = 0.5 m / s ^ 2 Acceleration = 0.5 m / s ^ 2