you walk from home to town, a distance of 6km in 50minutes. find the average speed in m/s?

you walk from home to town, a distance of 6km in 50minutes. find the average speed in m/s?
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300 km/m
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A boat takes 4hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2km ph and the speed of the boat in still water is 4kmph, what is the distance between P and Q? A.9 km B.7 km C.5 km D.6km

Description : A boat takes 4hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2km ph and the speed of the boat in still water is 4kmph, what is the distance between P and Q? A.9 km B.7 km C.5 km D.6km

Last Answer : Answer- D Basic Formula: Speed of stream = ½ (a-b) km/hr Speed of still water = ½ (a+b) km/hr Explanation: Time taken by boat to travel upstream and downstream = 4 hours Velocity of the stream, ½ (a-b) = 2km/hr a ... + x / 6 = 4 3x + x / 6 = 4 4x = 24 so,x = 6 distance between P and Q = 6km

A boat takes 27 hrs to travel a distance upstream and takes 9hrs to travel the same distance downstream. If the speed of the boat in still water is 12km/hr, then what is the velocity of the stream? A) 8km/hr B) 6km/hr C) 4km/hr D) None of these

Description : A boat takes 27 hrs to travel a distance upstream and takes 9hrs to travel the same distance downstream. If the speed of the boat in still water is 12km/hr, then what is the velocity of the stream? A) 8km/hr B) 6km/hr C) 4km/hr D) None of these

Last Answer : ANSWER : B  Explanation: Let the velocity of the stream be ‘ y’ km/hr Then the speed of the downstream = (12 + y)km/hr The speed of the upstream = (12 – y)km/hr 9 (12 + y) = 27 (12 – y) 108 + 9y = 324 – 27y 27y + 9y = 324 - 108 36y = 216 y = 6 km/hr

A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Last Answer : (a) 3km/hr

A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Last Answer : (a) 3km/hr

A man rows 750m in 775 seconds against the stream and returns in 7 1/2 minutes. What is rowing speed in still water ? A.4.7km/hr B. 4km/hr C.3.5km/hr D.6km/hr

Description : A man rows 750m in 775 seconds against the stream and returns in 7 1/2 minutes. What is rowing speed in still water ? A.4.7km/hr B. 4km/hr C.3.5km/hr D.6km/hr

Last Answer : Answer-A Basic Formula: i) Speed in still water = ½ (a+b) kmph where a' is speed downstream and b' is speed upstream ii) a km / hr = a x 5/18 m /s iii) a m/sec = a x 18/5 km/hr Explanation: Speed upstream b' ... (750/450 + 750/675 ) x 18/5 km/hr = ½ (5/3 + 30/31) x 18/5 km/hr = 4.7 km/hr

Ashok can row upstream at 8kmph and downstream at 12kmph.What is the speed of the stream ? A.6km/hr B.3km/h C.2 km/hr D.4km/hr

Description : Ashok can row upstream at 8kmph and downstream at 12kmph.What is the speed of the stream ? A.6km/hr B.3km/h C.2 km/hr D.4km/hr

Last Answer : Answer -C Basic Formula: If the speed downstream is a kmph and the speed upstream is b kmph then Speed of the stream = ½ (a-b) kmph Explanation: Speed downstream a = 12kmph Speed upstream b = 8 kmph Speed of the stream = ½ (a-b) = ½ (12-8) = 4/2 = 2 kmph speed of the stream = 2kmph

6km=660m?

Description : 6km=660m?

Last Answer : 12

Refer to the following TAF for Zurich LSZH 261019 20018G30KT 9999 –RA SCT050 BKN080 TEMPO 23012KT 6000 –DZ BKN015 BKN030 BECMG 1518 23020G35KT 4000 RA OVC010= The lowest visibility forecast at ETA Zurich 1430 UTC is: a. 6km b. 6nm c. 4km d. 10km

Description : Refer to the following TAF for Zurich   LSZH 261019 20018G30KT 9999 –RA SCT050 BKN080 TEMPO 23012KT 6000 –DZ  BKN015 BKN030 BECMG 1518 23020G35KT 4000 RA OVC010=  The lowest visibility forecast at ETA Zurich 1430 UTC is:  a. 6km  b. 6nm  c. 4km  d. 10km

Last Answer : a. 6km

Refer to the following TAF for Zurich LSZH 261019 20018G30KT 9999 –RA SCT050 BKN080 TEMPO 23012KT 6000 –DZ BKN015 BKN030 BECMG 1518 23020G35KT 4000 RA OVC010= The lowest visibility forecast at ETA Zurich 1430 UTC is: a. 6km b. 6nm c. 4km d. 10km

Description : Refer to the following TAF for Zurich LSZH 261019 20018G30KT 9999 –RA SCT050 BKN080 TEMPO 23012KT 6000 –DZ BKN015 BKN030 BECMG 1518 23020G35KT 4000 RA OVC010= The lowest visibility forecast at ETA Zurich 1430 UTC is: a. 6km b. 6nm c. 4km d. 10km

Last Answer : a. 6km

Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr

A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

Description : A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

Last Answer : A person covered `5//8` of his journey and he has to walk 240 m more to complete his journey. Find the total distance of the journey

Do people in your town/city walk around in their PJs?

Description : Do people in your town/city walk around in their PJs?

Last Answer : Yeah, college kids apparently don’t get dressed anymore. When I’m on campus I see it everywhere.

How should I handle guys yelling aggressive sexual comments at me when I walk or jog through town?

Description : How should I handle guys yelling aggressive sexual comments at me when I walk or jog through town?

Last Answer : IGNORE. They want a reaction from you, so don't give it. If it's the same bunch every day, you have no choice but to either find another way of getting where you want to go or find someone to go ... is it coming home at night? I worry about you taking back roads. You need to be where the PEOPLE are.

A sprinter travels a distance of 200 m in a time of 18.53 seconds.What is the sprinter's average speed rounded to 4 sf?

Description : A sprinter travels a distance of 200 m in a time of 18.53 seconds.What is the sprinter's average speed rounded to 4 sf?

Last Answer : 5i446

A sprinter travels a distance of 200 m in a time of 18.53 seconds.What is the sprinter's average speed rounded to 4 sf?

Description : A sprinter travels a distance of 200 m in a time of 18.53 seconds.What is the sprinter's average speed rounded to 4 sf?

Last Answer : 5i446

Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Description :  Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr

You can walk 112 miles in 12 hour.What is your average speed?

Description : You can walk 112 miles in 12 hour.What is your average speed?

Last Answer : 3 mph

Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his average speed for the entire journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20

Description : Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20 

Last Answer : A Speed from home to annapark: (125*4/11)mph = (500/11)mph Speed from annapark to home: (125*4/9)mph = (500/9) mph Average speed = 2xy / (x+y) mph =[(2*500/11 *500/9) / (500/11+500/9)]mph =(500000/99) / ((4500+5500)/99) =(500000/99) / 10000 /99 =50mph

Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Description : Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Last Answer : speed=distancetimespeed=distancetime or time=distancespeedtime=distancespeed For travelling 1 km with 3 km/hr, Time taken = 1/3 hr = 20 min Now he has to reach school in 30 min,So he has cover another 1 km in = 30 -20 =10 min= 1/6 hr So speed should = distance /time= 1/(1/6) = 6 km/hr

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike speed is 20 km/hr and his walking speed is 1 km/hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered in two equal time intervals

Description : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered in two equal time intervals

Last Answer : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered ... /s C. 5.5 m/s D. 4.8 m/s

"yes, I'm travelling alone," valli answered curtly," and i've got ticket too." "yes, she's on her way to town ," said the conductor. ( turn into indirect speech)

Description : "yes, I'm travelling alone," valli answered curtly," and i've got ticket too." "yes, she's on her way to town ," said the conductor. ( turn into indirect speech)

Last Answer : yes, I'm travelling alone, valli answered curtly," and i've got ticket too." "yes, she's ... ," said the conductor. ( turn into indirect speech)

If you walk towards a plane mirror at a speed of 10 cm/s, at what speed does your image approach you? (a) 5 cm/s (b) 10 cm/s (c) 20 cm/s (d) Information inadequate

Description : If you walk towards a plane mirror at a speed of 10 cm/s, at what speed does your image approach you? (a) 5 cm/s (b) 10 cm/s (c) 20 cm/s (d) Information inadequate

Last Answer : Ans:(c)

At standard pressure and temperature the average speed of molecules is A. 400 m s-1 B. 500 m s-1 C. 600 m s-1 D. 700 m s-1

Description : At standard pressure and temperature the average speed of molecules is A. 400 m s-1 B. 500 m s-1 C. 600 m s-1 D. 700 m s-1

Last Answer : 400 m s-1

Water flow to a terminal 3 mm diameter and has an average speed of 2 m/s. What is the rate of flow in cubic meter/mm?  a. 0.0001m³/min  b. 0.076 m³/min  c. 0.085 m³/min  d. 0.097 m³/min

Description : Water flow to a terminal 3 mm diameter and has an average speed of 2 m/s. What is the rate of flow in cubic meter/mm?  a. 0.0001m³/min  b. 0.076 m³/min  c. 0.085 m³/min  d. 0.097 m³/min

Last Answer : 0.085 m³/min

Two cars were involved in an accident in the center of town. The man who was driving a little green car, had overtaken a big black car. The driver had misjudged the distance between him and the on-coming traffic and had to swerve back in, causing the black car to swerve and crash into a shop window. When the occupants of the cars were examined everyone in the green car was okay, but in the black car was one dead man. However, the driver of the green car was not charged with manslaughter, why was this so? -Riddles

Description : Two cars were involved in an accident in the center of town. The man who was driving a little green car, had overtaken a big black car. The driver had misjudged the distance between him and the on ... . However, the driver of the green car was not charged with manslaughter, why was this so? -Riddles

Last Answer : The black car was a hearse and was on its way to a funeral.

Does it take more energy to cycle than the same distance to walk?

Description : Does it take more energy to cycle than the same distance to walk?

Last Answer : It would depend on the speed of the walker and the gear used by the biker.

What is distance in a 6 minute walk test?

Description : What is distance in a 6 minute walk test?

Last Answer : What is the answer ?

If your pace on a treadmill is 65 meters per minute how many minutes will it take for you to walk a distance of 7500 feet?

Description : If your pace on a treadmill is 65 meters per minute how many minutes will it take for you to walk a distance of 7500 feet?

Last Answer : 35 minutes

A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Description : A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Last Answer : Let the distance be x km. then (x/40) + (x/6) = 13 + (48/60) = 69/5 Answer is: d)

A hiker stands at the bottom of steep hill. The hiker may follow a straight line path to the top of the hill, a distance of 300 feet, or she may follow a zig-zag path to the top of the hill and walk a distance of 600 feet. The work done by the force of gravity along the zig-zag path is how many times the work going along the straight path? Is it: w) equal x) twice y) 4 times z) 8 times?

Description : A hiker stands at the bottom of steep hill. The hiker may follow a straight line path to the top of the hill, a distance of 300 feet, or she may follow a zig-zag path to the top of the hill and walk a ... times the work going along the straight path? Is it: w) equal x) twice y) 4 times z) 8 times?

Last Answer : ANSWER: W -- EQUAL 

The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed? -Science

Description : The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed? -Science

Last Answer : Average speed=total distancetime=50010=50Average speed=total distancetime=50010=50 km/hr Ratio of average speed to maximum speed= 50:90=5:9

A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with 60 km/h. Then its average speed is

Description : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with 60 km/h. Then its average speed is

Last Answer : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with ... 48 km/h C. 52 km/h D. 100 km/h

Distance travelled by a body in time ‘t’ is A. instantaneous speed B. average velocity C. average acceleration D. instantaneous acceleration

Description : Distance travelled by a body in time ‘t’ is A. instantaneous speed B. average velocity C. average acceleration D. instantaneous acceleration

Last Answer : average velocity

The average speed of a moving object during a given interval of time is always: A. the magnitude of its average velocity over the interval B. the distance covered during the time interval divided by the time interval (Answer) C. one-half its speed at the end of the interval D. its acceleration multiplied by the time interval E. one-half its acceleration multiplied by the time interval

Description : The average speed of a moving object during a given interval of time is always: A. the magnitude of its average velocity over the interval B. the distance covered during the time ... its acceleration multiplied by the time interval E. one-half its acceleration multiplied by the time interval

Last Answer : B. the distance covered during the time interval divided by the time interval (Answer)

The average speed of a train is 1 3/7 times the average speed of a car. The car covers a distance of 616 km in 8 hours. How much distance will the train cover in 13 hours? a) 1340 km b) 1423 km c) 1430 km d) 1936 km e) None of these

Description : The average speed of a train is 1 3/7 times the average speed of a car. The car covers a distance of 616 km in 8 hours. How much distance will the train cover in 13 hours? a) 1340 km b) 1423 km c) 1430 km d) 1936 km e) None of these

Last Answer : speed of the car = 616/8 = 77km/hr speed of the train = 10/7 × 77 = 110 km/hr Distance covered by train = 110 × 13 = 1430 km. Answer: c)

The average spacing of seeds or hills in field is obtained or determined by a) The ratio of linear or peripheral speed of seed pick up units (cells fingers, etc) to the forward speed of the planter b) The distance between the speed pick up units (cells) on the metering unit c) Both (a) and (b) d) None of the above

Description : The average spacing of seeds or hills in field is obtained or determined by a) The ratio of linear or peripheral speed of seed pick up units (cells fingers, etc) to the forward speed of the planter b) The distance ... up units (cells) on the metering unit c) Both (a) and (b) d) None of the above

Last Answer : c) Both (a) and (b)

Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr

Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Description : Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Last Answer : B Let the speed of jagging be x km/hr Total time taken = (27/18 hrs + 4.5 hrs) =(1.5 hrs + 4.5 hrs) =6 hrs Total distance covered = (27+4.5 x) km Therefore (27 +4.5x) / 6= 27 27+4.5x = 162 4.5x = 135 X=135/4.5 =30 So jagging speed is 30 km/hr

The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs covering a distance of 1600 km. the speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Description : The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs ... speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Last Answer : D Let the speed in return journey be x km/hr Then speed in upward journey = 150 /100 x = (3/2 x)km/hr Average speed = (2*3x/2*x) / (3x/2 +x) =3x2 / (5x/2) =6x2 / 5x =6x/5 km/hr Therefore (1600 ... 192x = 8000 X = 41.66 Speed in upward journey = (3/2 x ) km/hr =(3/2*41.66) =62.49 km/hr 

A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60

Description : A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60 

Last Answer : B Average speed =(2xy/( x+y)) km/hr Given x =60 km/hr y = 30km/hr Average speed = (2*60*30/ (60+30)) km/hr =(3600/ 90) =40 km/hr

Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Description : Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Last Answer : C) Given x= 168 , y = 112 Required average speed = (2xy / x + y) km/hr = 2 * 168 *112 / 168 + 112 = 37632 / 280 =134.4 km/hr

Average planting distance (R P) of guava is— (A) 5 m 5 m (B) 6 m 6 m (C) 8 m 8 m (D) 10 m 10 m

Description : Average planting distance (R P) of guava is— (A) 5 m 5 m (B) 6 m 6 m (C) 8 m 8 m (D) 10 m 10 m

Last Answer : (B) 6 m 6 m

In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is (A) 0.64 (B) 6.25 (C) 0.16 (D) None of these

Description : In a braking test, a vehicle travelling at 36 km ph was stopped at a braking distance of 8.0 m. The average value of the vehicle's skid resistance (friction coefficient) is (A) 0.64 (B) 6.25 (C) 0.16 (D) None of these

Last Answer : Answer: Option C

Pick up the incorrect statement from the following: (A) Lead is the average horizontal straight distance between the borrow pit and the place of spreading soil (B) The lead is calculated for each block of the excavated area (C) The unit of lead is 50 m for a distance upto 500 m (D) The unit of lead is 1 km where the lead exceeds 2 km

Description : Pick up the incorrect statement from the following: (A) Lead is the average horizontal straight distance between the borrow pit and the place of spreading soil (B) The lead is calculated for each block of the ... a distance upto 500 m (D) The unit of lead is 1 km where the lead exceeds 2 km

Last Answer : (D) The unit of lead is 1 km where the lead exceeds 2 km

What is the average school psychologist salary in a small town?

Description : What is the average school psychologist salary in a small town?

Last Answer : School psychologists average $64,000 a year, and the top 10% make over $100,000 per year. Private psychologists make between 20 and 60 an hour. Adjust your price based on what people or ... most often. If necessary offer limited hours and part time supplementing with a private practice off campus.

What is the distance traveled by the turtle during the seventh minute if it walked 0.3 m in the first minute then it tripled its speed each minute?

Description : What is the distance traveled by the turtle during the seventh minute if it walked 0.3 m in the first minute then it tripled its speed each minute?

Last Answer : Initial (average) speed = distance/time = 0.3 m / 1 min = 0.3m/minIf it triples its speed every minute:for the second minute it walks at 3 0.3m/minfor the third minute it walks at 3² 0.3 m/minfor the nth minute it ... time→ distance in 7th minute = 3⁶ 0.3 m/min 1 min = 3⁶ 0.3 m =218.7 m

Theoretical capacity of crushing rolls in tons/hr is given by (where, V = peripheral velocity, m/sec. W = width of rolls, m Dr = distance between rolls ρ = density of material to be crushed, kg/m3 here, V =πND where, N = speed of the rolls in rotation per second (rps) D = diameter of rolls, m). (A) 3.6 V.W.Dr.ρ (B) 3.6 V.W. ρ (C) 3.6 W.Dr.ρ (D) 3.6 V.W.Dr/ρ

Description : Theoretical capacity of crushing rolls in tons/hr is given by (where, V = peripheral velocity, m/sec. W = width of rolls, m Dr = distance between rolls ρ = density of material to be crushed, kg/m3 here, V =πND where, N = speed of the rolls ... V.W.Dr.ρ (B) 3.6 V.W. ρ (C) 3.6 W.Dr.ρ (D) 3.6 V.W.Dr/ρ

Last Answer : (A) 3.6 V.W.Dr.ρ