In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected with 240 more than the candidates got selected in Pondicherry. What was the number of candidates appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800

In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected with 240 more than the candidates got selected in Pondicherry. What was the number of candidates appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800
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1 Answer

Answer :

Answer: C

 Pondichery and Tamilnadu had an equal number of candidates appeared

 In Pondicherry, 18% candidates got selected from the total appeared candidates

 In tamilnadu, 21% candidates got selected from the total appeared candidates

 But in Tamilnadu, 240 more candidates got selected than pondicherry

 From these, it is clear that 1% of the total appeared candidates in pondicherry = 240

 =>total appeared candidates in tamilnadu = 240 x 100 = 24000

 => total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000


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In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800

Description : In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800 

Last Answer : Answer: D Total number of votes = 15000 Given that 40% of Percentage votes were invalid => Valid votes = 60% Total valid votes = 15000* 60/100 1st candidate got 45% of the total valid votes. Hence ... votes that 2nd candidate got = total valid votes x 55/100  =15000*60/100*55/100  =4950

In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298

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Last Answer : Answer: B The number of students with first division = 56 % of 900  = 56/100 × 900 = 50400/100  = 504 And, the number of students with second division = 27 % of 900  = 27/100 × 900  =24300/100  = 243 Therefore, the number of students who just passed = 900 – (504 + 243)  = 900- 747  = 153

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

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In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814

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Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1

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Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989

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In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98

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From the salary of shreya, 15% is deducted as house rent, 15% she spends on children’s education and 20% on watching movies. If her savings are Rs.8450/- then her total salary is: a) 13500 b) 2360 c) 16900 d) 11520 e) 23198

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Two transformers A and B having equal outputs and voltage ratios but unequal percentage

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A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450

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In 2001, 6400 candidates appeared at the exam and 40% of them qualified. In 2005 the ratio between qualified males and females was 3:5. What is the total number of female candidates who qualified in these two years? A. 1120 B. 1220 C. 1330 D. 1150

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A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980

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Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5

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A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

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By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98

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A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180

Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180

Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45  x = (45 × 100)/25  x = (4500)/25  x = 180 Therefore, the total number of matches played is 180.

In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801

Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801

Last Answer : Answer: E  Number of boys in the college = 60 % of 1335  = 60/100 × 1335  = 80100/100  = 801  Number of girls in the college = Total number of students in the college - Number of boys  = 1335 – 801  =534

The divisional supdt may sanction up to Rs_____ in each case for hiring examination and for other purpose etc holding customers meet etc a) 25000/- b) 30000/- c) 5000/- d) 75000/

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In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

Description :  In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

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If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534

Description : If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534

Last Answer : Answer: C Required Production=140(1 + 16/100)2 lakh tones  =140(1 + 4/25)2  =140((25 + 4) /25)²  =140(29/25)²  =140(1.16)²  =140×1.3456  =188.384 lakh tonnes

The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272

Description : The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272

Last Answer : Answer: E After 2 years required population is  = 378000 (1-16/100) (1+10/100)  = 378000 (84/100) (110/100)  = 378000 (0.84) (1.1)  = 3,49,272

The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000  = (104/100) × (106/100) × (110/100) × 200000  = 1.04×1.06×1.1×200000  = 2,42,528

A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9

Description : A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9

Last Answer : Answer: E Price of the wooden a year before = $25200 Price of the wooden after a year = $11200 Decrease in price = $(25200 - 11200) = $14000 Therefore, decrease % = 14000/25200 × 100 %  = 55 5/9 %

The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Last Answer : Answer: E  Original cost = $140  Decrease in it = 30% of $140  = 30/100 × 140  = 4200/100  = $42  Therefore, decrease cost = $140 - $42 = $98

Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855

Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855

Last Answer : Answer: E  Increase = 90 % of 450  = 90/100 × 450  = 40500/100  = 405 Therefore, increase value = 450 + 405 = 855

The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8

Description : The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8 

Last Answer : Answer: D Population in a small town last year = 50000 Population in a small town after one year = 63750 Increase in population = 63750 - 50000 = 13750 Therefore,  percentage increase in population = ... /50000 100  = 1375000/50000  = 27.5% Thus, the increase in population is 27.5%