P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution containing the ions of the other metals, me

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P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution ... P lt S` D. `Q lt P lt S lt R`

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Description : P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution containing the ions of the other metals, me

Last Answer : P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution ... P lt S` D. `Q lt P lt S lt R`

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Last Answer : Ans: option (d)

Description : Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X and ... R & Y are neighbors. Who is the only female in between X & R? a) Z b) P c) Y d) Q

Last Answer : Ans: option (c)

Description : Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X ... as well R & Y are neighbors. 10. Who is exactly opposite to X? a) Z b) P c) S d) W

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Last Answer : Answer: A) Ratio of shares P,Q, R, S = 48*3 : 20 *5 : 70*4 :42*3 = 144 : 100: 280 : 126 = 72:50:140:63 Let total rent be Rs x Then P’s share = Rs. 72x/325 72x /325 = 1420 X = Rs.6410

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Last Answer : Answer: C) 1 and 2 will give : R = Rs. (4000 x 9) for 1 year = Rs. 36000 for 1 year. P = Rs. (1/4 * 4000 * 12 ) for 1 year = Rs 12000 for 1 year Q = Rs 24000 for one year R:P:Q = ... Profit = 500 Now from the ratio and total profit we can get Share of R. R share will be = 500 * 2/6 = 166.66

Description : P, Q & R are three partners start a business. Thrice P’s capital is equal to four times Q’s capital and Q’s capital is 6 times R’s capital. Out of a total profit Rs.35860 at the end of the year, Q’s share is A) Rs.12334 B) Rs.14344 C) Rs. 21500 D) Rs.17600

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Description : A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2.  a. 339.4 K  b. 449.4 K  c. 559.4K  d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)

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Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

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Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.