What are the value of p,q,r, and s for the following reaction `" "pO_(3) + qHI to rI_(2) + sH_(2)O`

1 Answer

Answer :

What are the value of p,q,r, and s for the following reaction `" "pO_(3) + qHI to rI_(2) + sH_(2)O` A. 1,6,3,1 B. 1,6,3,3 C. 1,6,6,3 D. 1,6,3,6

Related questions

Description : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for complete neutralization"),("(B)" 4.9 g H_(3)PO_(4),"(q) 200 mi

Last Answer : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for ... Na_(2)CO_(3),"(s)May react with an oxidising agent"):}`

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Description : Compounds P and R upon ozonolysis produce Q and S, respectively. The molecular formula of Q and S is `C_(8)H_(8)O`. Q undergoes cannizzaro reactions b

Last Answer : Compounds P and R upon ozonolysis produce Q and S, respectively. The molecular formula of Q and S is `C_(8) ... R , respectively is (are) A. B. C. D.

Description : Two aliphatic aldehydes P and Q react in th presence of aqueous `k_(2)CO_(3)` to give compound R, which upon treatment with HCN provides compound S. O

Last Answer : Two aliphatic aldehydes P and Q react in th presence of aqueous `k_(2)CO_(3)` to give compound R, which ... shown below: The compound S is B. C. D.

Description : `P_(4)(s) + 3OH^(-) (aq) + 3H_(2)O (I) rarr PH_(3) (g) + 3H_(2)PO_(2)^(-) (aq)` In the above equation, the species getting oxidized and reduced respec

Last Answer : `P_(4)(s) + 3OH^(-) (aq) + 3H_(2)O (I) rarr PH_(3) (g) + 3H_(2)PO_(2)^(-) (aq)` In the above equation ... ` C. `P_(4) and H_(2)O` D. `P_(4) and P_(4)`

Description : `P_(4)(s) + 3OH^(-) (aq) + 3H_(2)O (I) rarr PH_(3) (g) + 3H_(2)PO_(2)^(-) (aq)` In the above equation, the species getting oxidized and reduced respec

Last Answer : `P_(4)(s) + 3OH^(-) (aq) + 3H_(2)O (I) rarr PH_(3) (g) + 3H_(2)PO_(2)^(-) (aq)` In the above equation ... ` C. `P_(4) and H_(2)O` D. `P_(4) and P_(4)`

Description : Oxidation number of P in `PO_(4)^(3-)`, of S in `SO_(4)^(2-)` and that of `Cr_(2)O_(7)^(2-)` are respectively

Last Answer : Oxidation number of P in `PO_(4)^(3-)`, of S in `SO_(4)^(2-)` and that of `Cr_(2)O_(7)^(2-)` are ... . `+3, +6 and +5` D. `+5, +3, and +6`

Description : Match the four material (P, Q, R, S) given in List -I with the corresponding reaction schemes (I, II, III, IV) provided in List-II and select the corr

Last Answer : Match the four material (P, Q, R, S) given in List -I with the corresponding reaction schemes (I, II, III, IV) ... . `{:(P,Q,R,S),(4,1,3,2):}`

Description : Compound P on treatement with `CH_(2)N_(2)` (diazomethane) produces compound Q. compound Q on reaction with Hl produces two alkyl iodides R and S . Al

Last Answer : Compound P on treatement with `CH_(2)N_(2)` (diazomethane) produces compound Q. compound Q on reaction ... 2-methyl-2-propanol D. 2-methyl-1-propanol

Description : P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution containing the ions of the other metals, me

Last Answer : P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution ... P lt S` D. `Q lt P lt S lt R`

Description : P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution containing the ions of the other metals, me

Last Answer : P,Q, R and S are four metals whose typical reaction are given below (I) (II) When Q is added to a solution ... P lt S` D. `Q lt P lt S lt R`

Description : KI in acetone, undergoes `S_(N)2` reaction with each of `P,Q ,R` and S The rates of the reaction very as `underset(P)(H_(3)C-Cl)` .

Last Answer : KI in acetone, undergoes `S_(N)2` reaction with each of `P,Q ,R` and S The rates of the reaction very as ` ... R gt Q gt S D. R gt P gt S gt Q

Description : Molecularity of an elementary reaction, P + Q → R + S is (A) 1 (B) 2 (C) 3 (D) 4

Last Answer : (D) 4

Description : Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe(H_(2)O)_(6)]^(2+)` The correct order of the c

Last Answer : Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe( ... lt P` C. `R lt P lt Q` D. `Q lt P lt R`

Description : Assertion(A): In the fermentation process of molasses, along with yeast `(NH_(4))_(2)SO_(4), (NH_(4))_(3) PO_(4)` is added Reason (R): `(NH_(4))_(3)PO

Last Answer : Assertion(A): In the fermentation process of molasses, along with yeast `(NH_(4))_(2)SO_(4), (NH_(4))_ ... but R is false D. A is false but R is true

Description : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `

Last Answer : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2) ... and Friedel-Crafts acylation D. Dehydration and Friedel-Crafts acylation

Description : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `

Last Answer : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_ ... product S is The product S is A. B. C. D.

Description : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Last Answer : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give ... (S) is: A. B. C. D.

Description : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Last Answer : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration ... respectively, are: A. B. C. D.

Description : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Last Answer : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give ... (P) is: A. B. C. D.

Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is

Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150

Description : In the following reaction `HC_(2)O_(4)^(-)(aq)+PO_(4)^(3-)(aq)hArrHPO_(4)^(-2)(aq)+C_(2)O_(4)^(2-)(aq)`, which are the two Bronsted bases?

Last Answer : In the following reaction `HC_(2)O_(4)^(-)(aq)+PO_(4)^(3-)(aq)hArrHPO_(4)^(-2)(aq)+C_(2)O_(4)^(2-)(aq)` ... 2-)` D. `HC_(2)O_(4)^(-)`and HPO_(4)^(2-)`

Description : How many toluidines on reaction with `NaNO_(2)//HCl` followed by `H_(3)PO_(2)` treatment gives Toluene.

Last Answer : How many toluidines on reaction with `NaNO_(2)//HCl` followed by `H_(3)PO_(2)` treatment gives Toluene.

Description : The unbalanced equation for the reaction of `P_(4)S_(3)` with nitrate in aqueous acidic medium is given below : `P_(4)S_(3)+NO_(3)^(-)rarrH_(3)PO_(4)+

Last Answer : The unbalanced equation for the reaction of `P_(4)S_(3)` with nitrate in aqueous acidic medium is given below : `P_(4) ... A. 18 B. `8//3` C. 8 D. 28

Description : Equivalent weight of `H_(3)PO_(4)` in each of the reaction will be respectively - `H_(3)+OH^(-)rarrH_(2)PO_(4)+H_(2)` `H_(3)PO_(4)+2OH^(-)rarrHPO_(4)^

Last Answer : Equivalent weight of `H_(3)PO_(4)` in each of the reaction will be respectively - `H_(3)+OH^(-)rarrH_(2)PO_(4 ... 67 C. 98, 32.67, 49 D. 32.67, 49, 98

Description : If a, b, c be the p^th, q^th, r^th terms of a GP, then the value of (q – r) log a + (r – p) -Maths 9th

Last Answer : (a) 0Let h be the first term and k be the common ratio of a GP, then a = hkp - 1, b = hkq - 1, c = hkr - 1∴ (q - r) log a + (r - p) log b + (p - q) log c = log [hkp -1]q - r + log [hkq -1]r - p + log[hkr -1]p - ... r + r - p + p - q) (kp - 1)q - r (kq -1)r - p (kr -1)p - q = log(ho ko) = log 1 = 0.

Description : If pqr = 1, the value of (1)/([1+p+q^-1]) + (1)/([1+q+r^-1])+ (1)/([1+r+p^-1]) will be equal to : -Maths 9th

Last Answer : answer:

Description : Find minimum value of `px+qy` where `p>0, q>0, x>0, y>0` when `xy=r,^2` without using derivatives.

Last Answer : Find minimum value of `px+qy` where `p>0, q>0, x>0, y>0` when `xy=r,^2` without using ... `pqsqrtr` B. `2pqsqrtr` C. `2rsqrtpq` D. None of these

Description : In the above figure, AB is parallel to CD. P and R are the points on AB and CD respectively. Q is in between AB and CD. Find the value of x in degrees

Last Answer : In the above figure, AB is parallel to CD. P and R are the points on AB and CD respectively. Q is in between AB and CD. Find the value of x in degrees

Description : In the circuit shown here, what is the value of the unknown resistor R so that the total resistance of the circuit between points P and Q is also equa

Last Answer : In the circuit shown here, what is the value of the unknown resistor R so that the total resistance of the ... ` C. `sqrt(69)Omega` D. `10 Omega`

Description : I want to put "S.P.Q.R." on something. Any suggestions?

Last Answer : Put it in your profile.

Description : Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Last Answer : c.P-3, Q-4, R-2, S-1

Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

Description : ABCD is a parallelogram in which P and Q are the mid-points of opposite sides AB and CD (Fig. 8.48). If AQ intersects DP at S and BQ intersects CP at R, show that -Maths 9th

Last Answer : Solution :-