Molecularity of an elementary reaction, P + Q → R + S is (A) 1 (B) 2 (C) 3 (D) 4

Molecularity of an elementary reaction, P + Q → R + S is
(A) 1
(B) 2
(C) 3
(D) 4
by

1 Answer

Answer :

(D) 4
by

Related questions

The experimentally determined overall order of the reaction, A + B → C + D, is two. Then the (A) Reaction is elementary with a molecularity of 2 (B) Molecularity of the reaction is 2, but the reaction may not be elementary (C) Reaction may be elementary with molecularity of 2 (D) Reaction is elementary but the molecularity may not be 2

Description : The experimentally determined overall order of the reaction, A + B → C + D, is two. Then the (A) Reaction is elementary with a molecularity of 2 (B) Molecularity of the reaction is 2, ... Reaction may be elementary with molecularity of 2 (D) Reaction is elementary but the molecularity may not be 2

Last Answer : (A) Reaction is elementary with a molecularity of 2

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Last Answer : (C) According to the penetration theory, the mass transfer co-efficient decreases, if the exposure time of an eddy to the solute decreases

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For the chemical reaction P → Q, it is found that the rate of reaction doubles as the concentration of 'P' is doubled. If the reaction rate is proportional to Cp n , then what is the value of 'n' for this chemical reaction? (A) 0 (B) 1 (C) 2 (D) 3

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Last Answer : (B) 1

For reaction, P + 2 → 3R, molar rate of consumption of P is (A) Double of that of Q (B) Same as that of Q (C) Half of that of Q (D) 2/3rd of that of Q

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To maximise the formation of R in the simultaneous reaction A + B → R, rR = 2CA 0.5 .CB 2 A + B→ S, rS = 1.5 CA. CB We should have (A) Low CA , low CB (B) Low CA , high CB (C) High CA , low CB (D) High CA , high CB

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Last Answer : (B) Low CA , high CB

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Last Answer : (D) Both (B) and (C

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Sodium reacts with water to form sodium hydroxide and hydrogen gas. The balanced equation which represents the above reaction is (a) Na(s) + 2H20(l) → 2NaOH(aq) + 2H2(g) (b) 2Na(s) + 2H2O(l) → 2NaOH(aq) +H2(g) (c) 2Na(s) + 2H20(l) → NaOH(aq) + 2H2(g) (d) 2Na(s) + H20(l) - 2NaOH(aq) + 2H2(g)

Description : Sodium reacts with water to form sodium hydroxide and hydrogen gas. The balanced equation which represents the above reaction is (a) Na(s) + 2H20(l) → 2NaOH(aq) + 2H2(g) (b) 2Na(s) + 2H2O(l) → 2NaOH(aq) +H2(g) (c) 2Na(s) + 2H20(l) → NaOH(aq) + 2H2(g) (d) 2Na(s) + H20(l) - 2NaOH(aq) + 2H2(g)

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Which of the following statements about the given reaction are correct? 3Fe(s) + 4H2O(g) → Fe3O4 (s) + 4H2 (g) (a) Iron metal is getting oxidized. (b) Water is getting reduced. (c) Water is acting as reducing agent. (d)Water is acting as oxidizing agent. A) (A), (B) & (C) B) (C) & (D) C) (A), (B) & (D) D) (B) & (D)

Description : Which of the following statements about the given reaction are correct? 3Fe(s) + 4H2O(g) → Fe3O4 (s) + 4H2 (g) (a) Iron metal is getting oxidized. (b) Water is getting reduced. (c) Water is acting as reducing agent. (d)Water is acting as ... (B) & (C) B) (C) & (D) C) (A), (B) & (D) D) (B) & (D)

Last Answer : C) (A), (B) & (D)

I want to put "S.P.Q.R." on something. Any suggestions?

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Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Description : Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Last Answer : c.P-3, Q-4, R-2, S-1

3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.