A man of height 160 cm walks at a rate of 1.1` m/sec from a lamp post which 6m high. Find the rate at which the length of his shadow increases when he

A man of height 160 cm walks at a rate of 1.1` m/sec from a lamp post which 6m high. Find the rate at which the length of his shadow increases when he
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A man of height 160 cm walks at a rate of 1.1` m/sec from a lamp post which 6m high. Find ... shadow increases when he is 1m away from the lamp post.
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What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6m -Maths 9th

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Last Answer : Solution: Height of conical tent, h = 8m Radius of base of tent, r = 6m Slant height of tent, l2 = (r2+h2) l2 = (62+82) = (36+64) = (100) or l = 10 Again, CSA of conical tent = πrl = (3.14 6 ... .2) 3] = 188.4 L-0.2 = 62.8 L = 63 Therefore, the length of the required tarpaulin sheet will be 63 m.

A flag staff 17.5 m high casts a shadow of length 40.25m. What will be the height of a building, which casts a shadow of length 28.75m under similar conditions? a) 14m b) 11.4m c) 13.5m d) 12.5 m

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Last Answer :  ANSWER:A Explanation:  Length of train P = 300 m  Length of train Q = 600 m  Speed of train p = 130 kmph  Convert km/hr into m/s,  Speed of train p =(130 *5/18)m/s  = 650/18 m/s  = 36.11 m/ ... train B)  = (300+600)m = 900 m We know, time =distance /speed  = 900/ 80.55  = 11.17seconds

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Last Answer : ANSWER : D  Explanation: Speed of person = 10km/hr  As the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed.  Relative speed = speed of train + speed of ... s  Distance = speed * time = 25 / 6 * 10 = 250/6 m/s = 41.6 m

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A man is walking down a road with a basket of eggs. As he is walking he meets someone who buys one-half of his eggs plus one-half of an egg. He walks a little further and meets another person who buys one-half of his eggs plus one-half of an egg. After proceeding further he meets another person who buys one-half of his eggs plus one half an egg. At this point he has sold all of his eggs, and he never broke an egg. How many eggs did the man have to start with? -Riddles

Description : A man is walking down a road with a basket of eggs. As he is walking he meets someone who buys one-half of his eggs plus one-half of an egg. He walks a little further and meets another person who buys ... of his eggs, and he never broke an egg. How many eggs did the man have to start with? -Riddles

Last Answer : 7 eggs. The first person bought one half of his eggs plus one half an egg (3 1/2 + 1/2 = 4 eggs) This left him 3 eggs. The second person bought one-half of his eggs plus one half an egg, (1 1/2 + ... last person bought one-half of his eggs plus one-half an egg, (1/2 + 1/2 = 1 egg) leaving no eggs.

A man walks 3 Km to his East then turns left and walks 3 Km towards North then turns left and walks 3Km towards West Indicate the correct direction in which he is in relation to his starting point: A. East B. West C. South D. North

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A man walks 3 Km to his East then turns left and walks 3 Km towards North then turns left and walks 3Km towards West Indicate the correct direction in which he is in relation to his starting point: A. East B. West C. South D. North

Description : A man walks 3 Km to his East then turns left and walks 3 Km towards North then turns left and walks 3Km towards West Indicate the correct direction in which he is in relation to his starting point: A. East B. West C. South D. North

Last Answer : ANSWER: B

The shadow of a tower standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the tower. -Maths 9th

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Last Answer : this is the answer

Mr. Sharma decided to walk down the escalator of a tube station. He found that if he walks down 26 steps, he requires 30 seconds to reach the bottom. However, if he steps down 34 stairs he would only require 18 seconds to get to the bottom. If the time is measured from the moment the top step begins to descend to the time he steps off the last step at the bottom, find out the height of the stair way in steps?

Description : Mr. Sharma decided to walk down the escalator of a tube station. He found that if he walks down 26 steps, he requires 30 seconds to reach the bottom. However, if he steps down 34 stairs he would only ... time he steps off the last step at the bottom, find out the height of the stair way in steps?

Last Answer : Answer: 46 steps.

Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Description : Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time? -Science

Last Answer : speed=distancetimespeed=distancetime or time=distancespeedtime=distancespeed For travelling 1 km with 3 km/hr, Time taken = 1/3 hr = 20 min Now he has to reach school in 30 min,So he has cover another 1 km in = 30 -20 =10 min= 1/6 hr So speed should = distance /time= 1/(1/6) = 6 km/hr

A person walks 10 m infront and 10 m to the right. Then every time turning to his left, he walks 5, 15 and 15 m respectively. How far is he now from his starting point? (A) 20 m (B) 15 m (C) 10 m (D) 5 m

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Last Answer : Answer: D

A retaining wall 6m high supports a backfill with a surcharge angle of 10°. The back of the wall is inclined to the vertical at a positive batter angle of 5°. If the angle of wall friction is 7°, then the resultant active earth pressure will act at a distance of 2 m above the base and inclined to the horizontal at an angle of (A) 7° (B) 10° (C) 12° (D) 17

Description : A retaining wall 6m high supports a backfill with a surcharge angle of 10°. The back of the wall is inclined to the vertical at a positive batter angle of 5°. If the angle of wall friction is 7°, then the resultant ... inclined to the horizontal at an angle of (A) 7° (B) 10° (C) 12° (D) 17

Last Answer : (C) 12°

For laying a sewer line in a trench of 2 m width, an offset line is marked on the ground parallel to the given centre line at a distance of A. 100 cm B. 120 cm C. 140 cm D. 160 cm

Description : For laying a sewer line in a trench of 2 m width, an offset line is marked on the ground parallel to the given centre line at a distance of A. 100 cm B. 120 cm C. 140 cm D. 160 cm

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A 8 metre long simply supported rectangular beam which carries a distributed load 45 kg/m. experiences a maximum fibre stress 160 kg/cm2 . If the moment of inertia of the beam is 640 cm4 , the overall depth of the beam is (A) 10 cm (B) 12 cm (C) 15 cm (D) 18 cm

Description : A 8 metre long simply supported rectangular beam which carries a distributed load 45 kg/m. experiences a maximum fibre stress 160 kg/cm2 . If the moment of inertia of the beam is 640 cm4 , the overall depth of the beam is (A) 10 cm (B) 12 cm (C) 15 cm (D) 18 cm

Last Answer : (A) 10 cm

An electron in potentiometer experiences a force `2.4xx10^(-19)N`. The length of potentiometer wire is 6m. The emf of the battery connected across the

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Find the flux density due to a conductor of length 6m and carrying a current of 3A(in 10 -7 order) a) 1 b) 10 c) 100 d) 0.1

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A man walks 30 m towards north, then 20 m, towards east and in the last `30sqrt(2)` m towards south - west. The displacement from origin is :

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A lamp is hanging at a height of `4 m` above a table. The lamp is lowered by `1 m` . The percentage increase in illuminace will be

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Keeping the instrument height as 1½ m, length of staff 4 m, the up gradient of the ground 1 in 10, the sight on the up slope must be less than (A) 25 cm (B) 20 m (C) 45 m (D) 10 m

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P walks around a circular field at the rate of two rounds per hour while Q runs around it at the rate of eight rounds per hour. They start in the opposite direction from the same point at 6.45 a.m. They shall first cross each other at? a) 6.45 a.m b) 6.50 a.m c) 7.51 a.m d) 6.51 a.m e) 7.45 am

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Last Answer : d Since P and Q move in the opposite direction along the circular field, so they will first meet each other when there is a difference of one round between the two. Relative speed of P and Q = 8+2 = 10 rounds per hour. Time ... 1/10 hr = 6 min. 6 Hrs 45 min + 6 min = 6 hrs 51 min i.e, 6.51 a.m

1 micron is equal to ___________ meter(s). A. 10-6m B. 10-3 m C. 106 m D. 109 m

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If h1 and h2 are the differences in level between ground and the formation levels, m is the slope of the sloping sides. D is the distance between the cross sections then, Prismoidal correction for a level section is (A) D/2m(h1 - h2) (B) D/3m(h1 - h2) (C) D/6m(h1 - h2)2(D) D/6m(h1 - h2)3

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Last Answer : (C) D/6m(h1 - h2)2

The degree of static indeterminacy of a rigid-jointed space frame is (A) m + r - 2j (B) m + r - 3j (C) 3m + r - 3j (D) 6m + r - 6j Where m, r and j have their usual meanings

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A man strolls into a hospital emergency room where there is a long line up to the reception desk. He walks right to the front and clamly asks to see the consultant in charge. No one gets angry and the receptionist immediately phones. The consultant has never met this man, yet she hurries away from the ward to see him.Why? -Riddles

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Last Answer : The man is a florist delievering a bouquet of flowers for the consultant.

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Last Answer : The father going to see his son on death row

Man walks over, man walks under, in times of war he burns asunder.What is it? -Riddles

Description : Man walks over, man walks under, in times of war he burns asunder.What is it? -Riddles

Last Answer : A Bridge.

A man goes into a cabin deep in the country. All walls within this cabin face south and are made of wood. A bear walks by the window. What color is he? -Riddles

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Last Answer : Since all walls within this cabin face south, the only location on the face of the earth this is possible is the North Pole. So thus the bear is a polar bear and the color would have to be white!

A man walks a distance of 3 units from the origin towards the North-East `(N45^0E)` direction.From there, he walks a distance of 4 units towards the N

Description : A man walks a distance of 3 units from the origin towards the North-East `(N45^0E)` direction.From there, he walks a distance of 4 units towards the N

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Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec

Description :  If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec 

Last Answer : ANSWER:C Explanation: Speed of the train = 90 km/hr Converting the speed into m/sec 90 km/hr = (90* 5/18)m/s = 25m/s length of the train = distance travelled we know distance = speed * ...  Time = distance / speed  = ( 1800/25) sec  = 72 seconds  Hence the required answer is 72 seconds

Find the cost of digging a cuboidal pit 8m long, 6m broad and 3m deep at the rate of Rs 30 per m3 -Maths 9th

Description : Find the cost of digging a cuboidal pit 8m long, 6m broad and 3m deep at the rate of Rs 30 per m3 -Maths 9th

Last Answer : The given pit has its length(l) as 8m, width (b)as 6m and depth (h)as 3 m. Volume of cuboidal pit = l×b×h = (8×6×3) = 144 (using formula) Required Volume is 144 m3 Now, Cost of digging per m3 volume = Rs 30 Cost of digging 144 m3 volume = Rs (144×30) = Rs 4320

The average weight of M,N and O is 168 kg. If P joins the group, the average weight of the group becomes 160 kg. If another man Q who weighs 6kg more than P replaces M, then the average of N,O,P and Qbecomes158 kg. What is the weight of M? A) 175 B) 140 C) 145 D) 150

Description : The average weight of M,N and O is 168 kg. If P joins the group, the average weight of the group becomes 160 kg. If another man Q who weighs 6kg more than P replaces M, then the average of N,O,P and Qbecomes158 kg. What is the weight of M? A) 175 B) 140 C) 145 D) 150 

Last Answer : D) M+N+O =168 * 3 =504 M+N+O+P=160*4=640……(1) P=136 kg and Q =142 kg N+O+P+Q =158*4 =632 N+O+P =632-142 =490…..(2) from 1 & 2, M=640-490 =150kg

A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Description : A rocket is fired vertically from the ground with a resultant vertical acceleration of 10 m/sec the fuel is finished in one minute and it continues to move up. The maximum height reached will be a.2 km b.20 km c.36 km d.10 km e.80 km

Last Answer : a. 2 km

A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

Description : A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

Last Answer : (D) 533.33 m sec Explanation: The request has to go up and down, and the response has to go up and down. The total path length traversed is thus 160.000 km. The speed of light in air and vacuum is 300,000 km/sec, so the propagation delay alone is 160,000/300,000 sec or about 533 msec. 

For a homogeneous earth dam 50 m high having 2 m free broad, a flow net was constructed and the results were : Number of potential drops = 2.4 Number of flow channels = 0.4. If co-efficiency of permeability of the dam material is 3 × 10-3 cm3 /sec, the discharge per metre length of dam, is (A) 12 × 10-5 m3 /sec (B) 24 × 10-3 m3 /sec (C) 6 × 10-5 m3 /sec (D) 24 × 10-5 m3 /sec

Description : For a homogeneous earth dam 50 m high having 2 m free broad, a flow net was constructed and the results were : Number of potential drops = 2.4 Number of flow channels = 0.4. If co-efficiency of permeability of the dam material is ... 24 10-3 m3 /sec (C) 6 10-5 m3 /sec (D) 24 10-5 m3 /sec

Last Answer : (D) 24 × 10-5 m3 /sec

A person moves from a point S and walks along the path which is a square of each side 50 m. He runs east, south

Description : A person moves from a point S and walks along the path which is a square of each side 50 m. He runs east, south

Last Answer : A person moves from a point S and walks along the path which is a square of each side 50 m. He runs east, south, ... (B) 100 m (C) 50 m (D) zero

Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr