The percentage of P2O5 in diammonium hydrogen phosphate (NH4)2HPO4 is [CPMT 1992] (A) 23.48 (B) 46.96 (C) 53.78 (D) 71.00

The percentage of P2O5 in diammonium
hydrogen phosphate (NH4)2HPO4 is
[CPMT 1992]
 (A) 23.48 (B) 46.96
 (C) 53.78 (D) 71.00
by

1 Answer

Answer :

(C) 53.78
by

Related questions

Tricresyl phosphate is chemically represented as (A) (CH3 C6 H4 )3 PO4 (B) Ca10 (PO4 )3F6 (C) (NH4 )2HPO4 (D) NH4H2PO4

Description : Tricresyl phosphate is chemically represented as (A) (CH3 C6 H4 )3 PO4 (B) Ca10 (PO4 )3F6 (C) (NH4 )2HPO4 (D) NH4H2PO4

Last Answer : (A) (CH3 C6 H4 )3 PO4

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Last Answer : NEED ANSWER

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Last Answer : Median will be a good representative of the data, because 1.each value occurs once. 2.the data is influenced by extreme values.

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

Description : Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

Last Answer : 43:7B:6C:DE:10:0

74.5 g of a metallic chloride contains 35.5 g of chlorine. The equivalent weight of the metal is [CPMT 1986] (A) 19.5 (B) 35.5 (C) 39.0 (D) 78.0

Description : 74.5 g of a metallic chloride contains 35.5 g of chlorine. The equivalent weight of the metal is [CPMT 1986] (A) 19.5 (B) 35.5 (C) 39.0 (D) 78.0

Last Answer : (C) 39.0

Which of the following pairs of substances illustrate the law of multiple proportions? [CPMT 1972, 78] (A) CO and CO2 (B) H2O and D2O (C) NaCl and NaBr (D) MgO and Mg(OH)2

Description : Which of the following pairs of substances illustrate the law of multiple proportions? [CPMT 1972, 78] (A) CO and CO2 (B) H2O and D2O (C) NaCl and NaBr (D) MgO and Mg(OH)2

Last Answer : (A) CO and CO2

Action of phosphoric acid on rock phosphate produces (A) Superphosphate (B) Triple superphosphate (C) Nitrophosphate (D) Diammonium phosphate

Description : Action of phosphoric acid on rock phosphate produces (A) Superphosphate (B) Triple superphosphate (C) Nitrophosphate (D) Diammonium phosphate

Last Answer : (B) Triple superphosphate

Reaction of nitric acid and sulphuric acid with phosphate rock produces (A) Nitrophosphate (B) Diammonium phosphate (C) Tricresyl phosphate (D) Tributyl phosphate

Description : Reaction of nitric acid and sulphuric acid with phosphate rock produces (A) Nitrophosphate (B) Diammonium phosphate (C) Tricresyl phosphate (D) Tributyl phosphate

Last Answer : (A) Nitrophosphate

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

The percentage of oxygen in NaOH is [CPMT 1979] (A) 40 (B) 60 (C) 8 (D) 10

Description : The percentage of oxygen in NaOH is [CPMT 1979] (A) 40 (B) 60 (C) 8 (D) 10

Last Answer : (A) 40

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

The human cell contains (a) 44 chromosomes (b) 48 chromosomes (c) 46 chromosomes (d) 23 chromosomes

Description : The human cell contains (a) 44 chromosomes (b) 48 chromosomes (c) 46 chromosomes (d) 23 chromosomes

Last Answer : Ans:(c)

The number of chromosomes present in normal human being are - (1) 23 (2) 46 (3) 22 (4) 48

Description : The number of chromosomes present in normal human being are - (1) 23 (2) 46 (3) 22 (4) 48

Last Answer : (2) 46 Explanation: A chromosomeis an organized structure of DNA and protein found in cells. It is a single piece of coiled DNA containing many genes, regulatory elements and other nucleotide sequences. ... genetic traits are linked to a person's sex and are passed on through the sex chromosomes.

The number of chromosomes present in normal human being are (1) 23 (2) 46 (3) 22 (4) 48

Description : The number of chromosomes present in normal human being are (1) 23 (2) 46 (3) 22 (4) 48

Last Answer : 46

______ the correct formula for ammonium phosphate. (1) N4H6PO4 (2) (NH4)3PO (3) (NH4)3PO4 (4) (NH4)2PO4

Description : ______ the correct formula for ammonium phosphate. (1) N4H6PO4 (2) (NH4)3PO (3) (NH4)3PO4 (4) (NH4)2PO4

Last Answer : (3) (NH4)3PO4 Explanation: (NH4)3PO4 is a the chemical formula for ammonium phosphate. For more chemistry related queries log on to website world of chemicals.

A phosphatic fertiliser contains 16% P2O5 . It could be (A) Dicalcium phosphate (B) Superphosphate(C) Triple superphosphate(D) None of these

Description : A phosphatic fertiliser contains 16% P2O5 . It could be (A) Dicalcium phosphate (B) Superphosphate (C) Triple superphosphate (D) None of these

Last Answer : (B) Superphosphate

Triple superphosphate which contains about 46% P2O5 is produced by the reaction of phosphate rock with ortho phosphoric acid of________ percent concentration. (A) 25-28 (B) 52-54 (C) 75-80 (D) > 98

Description : Triple superphosphate which contains about 46% P2O5 is produced by the reaction of phosphate rock with ortho phosphoric acid of________ percent concentration. (A) 25-28 (B) 52-54 (C) 75-80 (D) > 98

Last Answer : (B) 52-54

A dynamic RAM has refresh cycle of 32 times per msec. Each refresh operation requires 100 nsec and a memory cycle requires 250 nsec. What percentage of memory’s total operating time is required for refreshes? (A) 0.64 (B) 0.96 (C) 2.00 (D) 0.32

Description : A dynamic RAM has refresh cycle of 32 times per msec. Each refresh operation requires 100 nsec and a memory cycle requires 250 nsec. What percentage of memory’s total operating time is required for refreshes? (A) 0.64 (B) 0.96 (C) 2.00 (D) 0.32

Last Answer : Answer: D Explanation: in 1ms : refresh = 32 times Memory cycle = 1ms/250ns = 106ns/250ns = 4000 times Therefore, % of refresh time = (32 x 100ns)/(4000 x 250ns) = 3200ns/1000000 x 100% = 0.32%

Find the orbital angular moment of a dipole with angular velocity of 1.6m/s and radius 35cm(in 10-31 order) a) 1.78 b) 8.71 c) 7.18 d) 2.43

Description : Find the orbital angular moment of a dipole with angular velocity of 1.6m/s and radius 35cm(in 10-31 order) a) 1.78 b) 8.71 c) 7.18 d) 2.43

Last Answer : a) 1.78

The relative percentage of N2 , P2O5 and K2O” in a fertilizer

Description : The relative percentage of N2 , P2O5 and K2O” in a fertilizer

Last Answer : Ans. Fertilizer ratio

P2O5 percentage in the phosphoric acid produced by wet process is about (A) 10 (B) 30(C) 50 (D) 70

Description : P2O5 percentage in the phosphoric acid produced by wet process is about (A) 10 (B) 30 (C) 50 (D) 70

Last Answer : (B) 30

What is the % of H2O in Fe(CNS)3⋅3H2O [CPMT 1981] (A) 45 (B) 30 (C) 19 (D) 25

Description : What is the % of H2O in Fe(CNS)3⋅3H2O [CPMT 1981] (A) 45 (B) 30 (C) 19 (D) 25

Last Answer : (C) 19

In known elements, the maximum number is of [CPMT 1985] (A) Metals (B) Non-metals (C) Metalloids (D) None of these

Description : In known elements, the maximum number is of [CPMT 1985] (A) Metals (B) Non-metals (C) Metalloids (D) None of these

Last Answer : (A) Metals

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)

How many hydrogen atoms are in (NH4)2SO4?

Description : How many hydrogen atoms are in (NH4)2SO4?

Last Answer : 8

The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight of the group of 75 women? (rounded off to two digits after decimal) (a) 46.73 kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Description : The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight ... kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Last Answer : (a) 46.73 kg

If the boiling point of ethanol (molecular weight `= 46`) is `78^@ C`, the boiling point of dimethyl ether (molecular weight `= 46`) is

Description : If the boiling point of ethanol (molecular weight `= 46`) is `78^@ C`, the boiling point of dimethyl ether (molecular weight `= 46`) is

Last Answer : If the boiling point of ethanol (molecular weight `= 46`) is `78^@ C`, the boiling point of dimethyl ether (molecular ... ` C. `86^(@)C` D. `34^(@)C`

A jet of water discharging from a 40 mm diameter orifice has a diameter of 32 mm at its vena contracta. The coefficient of contraction is (A) 0.46 (B) 0.64 (C) 0.78 (D) 0.87

Description : A jet of water discharging from a 40 mm diameter orifice has a diameter of 32 mm at its vena contracta. The coefficient of contraction is (A) 0.46 (B) 0.64 (C) 0.78 (D) 0.87

Last Answer : Answer: Option B

What is the empirical formula for a molecule containing 46.8 Si and 53 O?

Description : What is the empirical formula for a molecule containing 46.8 Si and 53 O?

Last Answer : Since the ratio of atomic masses of silicon and oxygen is1:1.988, the empirical formula is SiO2.

What is the empirical formula for a molecule containing 46.8 Si and 53 O?

Description : What is the empirical formula for a molecule containing 46.8 Si and 53 O?

Last Answer : Since the ratio of atomic masses of silicon and oxygen is1:1.988, the empirical formula is SiO2.

The left face of a one dimensional slab of thickness 0.2 m is maintained at 80°C and the right face is exposed to air at 30°C. The thermal conductivity of the slab is 1.2 W/m.K and the heat transfer co-efficient from the right face is 10 W/m2 .K. At steady state, the temperature of the right face in °C is (A) 77.2 (B) 71.2 (C) 63.8 (D) 48.7

Description : The left face of a one dimensional slab of thickness 0.2 m is maintained at 80°C and the right face is exposed to air at 30°C. The thermal conductivity of the slab is 1.2 W/m.K and the heat transfer co-efficient from the ... temperature of the right face in °C is (A) 77.2 (B) 71.2 (C) 63.8 (D) 48.7

Last Answer : (D) 48.7

Pakistan won 50 overs cricket world cup on _____ march 1992. A. 23 March 1992 B. 24 March 1992 C. 25 March 1992 D. 26 March 1992

Description : Pakistan won 50 overs cricket world cup on _____ march 1992. A. 23 March 1992 B. 24 March 1992 C. 25 March 1992 D. 26 March 1992

Last Answer : ANSWER: C

Pakistan won 50 overs cricket world cup on _____ march 1992. A. 23 March 1992 B. 24 March 1992 C. 25 March 1992 D. 26 March 1992

Description : Pakistan won 50 overs cricket world cup on _____ march 1992. A. 23 March 1992 B. 24 March 1992 C. 25 March 1992 D. 26 March 1992

Last Answer : ANSWER: C

A=(-00,-49]U{-16,+00)B=[-96,-3)AnB=?

Description : A=(-00,-49]U{-16,+00)B=[-96,-3)AnB=?

Last Answer : ????

The following data, relates to manufacturing company for the year 2006-07– Net Profit as per P & L A/c–Rs. 2,40,000; Depreciation–Rs. 80,000; Goodwill written-off– Rs. 40,000, Profit on Sale of Fixed Assets–Rs. 16,000, Proposed Dividend–Rs. 96,000. The fund from operation would be– (A) Rs. 4,40,000 (B) Rs. 4,00,000 (C) Rs. 6,40,000 (D) None of the above

Description : The following data, relates to manufacturing company for the year 2006-07- Net Profit as per P & L A/c-Rs. 2,40,000; Depreciation-Rs. 80,000; Goodwill written-off- Rs. 40,000, Profit on Sale of Fixed Assets-Rs. 16,000, ... ) Rs. 4,40,000 (B) Rs. 4,00,000 (C) Rs. 6,40,000 (D) None of the above

Last Answer : Answer: None of the above

What is the moment of inertia acting on a circle of diameter 50 mm? a. 122.71 x 103 mm4 b. 306.79 x 103 mm4 c. 567.23 x 103 mm4 d. 800 x 103 mm4

Description : What is the moment of inertia acting on a circle of diameter 50 mm? a. 122.71 x 103 mm4 b. 306.79 x 103 mm4 c. 567.23 x 103 mm4 d. 800 x 103 mm4

Last Answer : b. 306.79 x 103 mm4

A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table: using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits

Description : A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table:  using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits

Last Answer : (D) 2,24,000 bits 

What is the gcf of 28 48 and 96?

Description : What is the gcf of 28 48 and 96?

Last Answer : The GCF is 4.

How much times does 48 go into 96?

Description : How much times does 48 go into 96?

Last Answer : twotwice48 + 48 = 9696/48 = 2

How many telegraph channels are there in the basic voice band channels? A. 24 B. 96 C. 48 D. 672

Description : How many telegraph channels are there in the basic voice band channels? A. 24 B. 96 C. 48 D. 672

Last Answer : A. 24

What is the perimeter of the sector with radius 10.5 cm and sector angle 60o? (a) 48 cm (b) 96 cm (c) 64 cm (d) 32 cm

Description : What is the perimeter of the sector with radius 10.5 cm and sector angle 60o? (a) 48 cm (b) 96 cm (c) 64 cm (d) 32 cm

Last Answer : (d) 32 cm

The power in a electromagnetic wave with electric field and magnetic field intensities 12 and 8 respectively is a) 96 b) 12 c) 8 d) 48

Description : The power in a electromagnetic wave with electric field and magnetic field intensities 12 and 8 respectively is a) 96 b) 12 c) 8 d) 48

Last Answer : d) 48

Find the flux density at the boundary when the charge density is given by 24 units. a) 12 b) 24 c) 48 d) 96

Description : Find the flux density at the boundary when the charge density is given by 24 units. a) 12 b) 24 c) 48 d) 96

Last Answer : b) 24

Find the resistance of a cylinder of area 200 units and length 100m with conductivity of 12 units. a) 1/24 b) 1/48 c) 1/12 d) 1/96

Description : Find the resistance of a cylinder of area 200 units and length 100m with conductivity of 12 units. a) 1/24 b) 1/48 c) 1/12 d) 1/96

Last Answer : a) 1/24

Find the work done moving a charge 2C having potential V = 24volts is a) 96 b) 24 c) 36 d) 48

Description : Find the work done moving a charge 2C having potential V = 24volts is a) 96 b) 24 c) 36 d) 48

Last Answer : d) 48

In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Description : In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Last Answer : Total ways = 4 ! x 2 ! = 4 × 3 × 2 x 2= 48 Answer: a)

The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Description : The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Last Answer : Answer- 4 (69) Explanation:- lets digit at tens and ones place be 2x and 3x So,number is 2x*10 + 3x After interchanging number will be 3x*10 +2x so, [3x*10 +2x] – [2x*10 + 3x]27 we get,x=3 so number =69

The elimination half life of Diazepam is in the range of: A. 2-5 hours B. 5-12 hours C. 12-30 hours D. 30-48 hours E. 48-96 hours

Description : The elimination half life of Diazepam is in the range of: A. 2-5 hours B. 5-12 hours C. 12-30 hours D. 30-48 hours E. 48-96 hours

Last Answer : C. 12-30 hours