11250 m3 If we take the vertical crossection of the face of the swimming pool, then it is a trapezium ABCD, with parallel sides AD and BC respectively of lengths 10 m and 20 m and distance between parallel sides as 50 m. The width of the swimming pool is 15 m. ∴ Volume of water in the swimming pool = Area of vertical cross section (ABCD) × width of swimming pool = [12(10+20)×50]×15[12(10+20)×50]×15 m3 = (15 x 50 x 15) m3 = 11250 m3.