The possible cases are: Case I : A man invites (3 ladies) and woman invites (3 gentlemen) 4 C 3 4 C 3 =16 Case II : A man invites (2 ladies,1 gentleman) and woman invites (2 gentleman, 1 lady) ( 4 C 2 3 C 1 )( 3 C 1 4 C 2 )=324 Case III : A man invites (1 lady, 2 gentlemen) and woman invites (2 ladies, 1 gentleman) ⇒( 4 C 1 3 C 2 )( 3 C 2 4 C 1 )=144 Case IV : A man invites (3 gentlemen) and woman invites (3 ladies) 3 C 3 3 C 3 =1 Total number of ways =16+324+144+1=485