In how many ways can a mixed doubles game be arranged from amongst 8 married couples if no husband and wife play in the same game? -Maths 9th

In how many ways can a mixed doubles game be arranged from amongst 8 married couples if no husband and wife play in the same game? -Maths 9th
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1 Answer

Answer :

 For mixed doubles, we have 2 men and 2 women. 2 men out of 9 can be selected in 9C8​ ways Out of 9 women, 2 will be there wife 30 only 7 are remaining for selecting 2 Now out of them 2 possible combinations can be made. So, total number of ways =9C2​×7C2​×2                                           =3024 Hence the answer is 3024.
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