Show that p-1 is a factor of p10 -1 and also of p11 -1. -Maths 9th

Show that p-1 is a factor of p10 -1 and also of p11 -1. -Maths 9th
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Let g (p) = p10 -1 and h(p) = p11 -1. On putting p=1 in Eq. (i), we get g(1)=110-1= 1-1=0 Hence, p-1 is a factor of g(p). Again, putting p = 1 in Eq. (ii), we get h (1) = (1)11 -1 = 1 -1 = 0 Hence, p -1 is a factor of h(p).
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