A meter whose constant is 600 revolutions/kWh makes 5 revolutions in 20 seconds. Calculate the load in kW.

A meter whose constant is 600 revolutions/kWh makes 5 revolutions in 20 seconds. Calculate the load in kW. (1) 0.5 kW (2) 1 kW (3) 1.5 kW (4) 2 kW  
by

1 Answer

Answer :

1.5 kW 
by

Related questions

An energy meter has a constant of 600 rev/kWh. If the meter makes 10 revolutions in 20 s, ...

Description : An energy meter has a constant of 600 rev/kWh. If the meter makes 10 revolutions in 20 s, what is the load in kW?  (A) 0.75 kW (B) 1.5 kW (C) 3 kW (D) 6 kW 

Last Answer : 1.5 kW 

The meter constant of a single-phase 230 V induction watt hour meter is 400 revolutions per kWh....

Description : The meter constant of a single-phase 230 V induction watt hour meter is 400 revolutions per kWh. The speed of the meter disc for a current of 10 A of 0.9 pf lagging will be

Last Answer : The meter constant of a single-phase 230 V induction watt hour meter is 400 revolutions per kWh. The speed of the meter disc for a current of 10 A of 0.9 pf lagging will be 13.80 rpm

A single phase energy meter has a constant of 1200 revolution/kWh. When a load of 200 W is connected,...

Description : A single phase energy meter has a constant of 1200 revolution/kWh. When a load of 200 W is connected, the disc rotates at 4.2 revolutions per min. If the load is on for 10 hours, the meter records an excess of   (a) 0.1 kWh (b) 0.2 kWh (c) 1.0 kWh (d) 2.0 kWh 

Last Answer : 2

. Kick's law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick's constant is (A) kW. sec/kg (B) kWh/kg (C) kWh/sec. kg (D) kg/sec

Description : . Kick's law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick's constant is (A) kW. sec/kg (B) kWh/kg (C) kWh/sec. kg (D) kg/sec

Last Answer : (A) kW. sec/kg

The disc of a single phase Induction-type energy meter makes 60 revolutions in 6 minutes. Meter Constant is

Description : The disc of a single phase Induction-type energy meter makes 60 revolutions in 6 minutes. Meter Constant is 1200 rev/kWh. Power consumption in the load is (A) 1.2 kW (B) 1 kW (C) 600 W (D) 500 W

Last Answer : The disc of a single phase Induction-type energy meter makes 60 revolutions in 6 minutes. Meter Constant is 1200 rev/kWh. Power consumption in the load is 500 W

One single-phase energy meter operating on 230 V and 5 A for 5 hours makes 1940 revolutions. Meter...

Description : One single-phase energy meter operating on 230 V and 5 A for 5 hours makes 1940 revolutions. Meter constant is 400 rev/kWh. The power factor of the load is

Last Answer : One single-phase energy meter operating on 230 V and 5 A for 5 hours makes 1940 revolutions. Meter constant is 400 rev/kWh. The power factor of the load is 0.8

A consumer consume. 600 kWh per day at a load factor of 0.40....

Description : A consumer consumes. 600 kWh per day at a load factor of 0.40. If the consumer increases the load factor of 0.70 without increasing the maximum demand, what is the consumption of energy in kWh?

Last Answer : A consumer consume. 600 kWh per day at a load factor of 0.40. If the coneumer increases the load factor of 0.70 without increasing the maximum demand, 1050 kWh is the consumption of energy in kWh.

A flywheel rotating at 5 revolutions per second is brought to rest by a constant torque in 10 seconds. How many revolutions does the flywheel make while coming to a stop? w) 25 x) 50 y) 75 z) 100

Description : A flywheel rotating at 5 revolutions per second is brought to rest by a constant torque in 10 seconds. How many revolutions does the flywheel make while coming to a stop? w) 25 x) 50 y) 75 z) 100

Last Answer : ANSWER: W -- 25

A 150 kW electric motor has an efficiency of 92 %, when it operates at full load. Calculate the losses in the...

Description : A 150 kW electric motor has an efficiency of 92 %, when it operates at full load. Calculate the losses in the machine.  (A) 92 kW (B) 150 kW (C) 163 kW (D) 13 kW 

Last Answer : efficiency  -output /input * 100 150/0.92----------163(input) losses-----(163--150)  ---------13kw.

A flywheel starting from rest and accelerating uniformly performs 25 revolutions in 5 sec. Its angular velocity in rpm after 10 seconds would be a.50 rpm b.20 rpm c.25 rpm d.60 rpm e.45 rpm

Description : A flywheel starting from rest and accelerating uniformly performs 25 revolutions in 5 sec. Its angular velocity in rpm after 10 seconds would be a.50 rpm b.20 rpm c.25 rpm d.60 rpm e.45 rpm

Last Answer : b. 20 rpm

A vessel is equipped with two ship's service generators. Generator #1 is rated at 900 kw and generator #2 is rated at 600 kw. During parallel operation, with a hotel load of 1,000 kw, what should be the kw load on generator #2? A. 100 kw B. 400 kw C. 500 kw D. 600 kw

Description : A vessel is equipped with two ship's service generators. Generator #1 is rated at 900 kw and generator #2 is rated at 600 kw. During parallel operation, with a hotel load of 1,000 kw, what should be the kw load on generator #2? A. 100 kw B. 400 kw C. 500 kw D. 600 kw

Last Answer : Answer: B

A 3-phase 50HZ SCIM takes a power input of 30 KW at its full load speed of 1440 rpm. Total stator losses are 1 KW. The slip and rotor ohmic losses at full load are a) 0.02, 600 W b) 0.04, 580 W c) 0.04, 1160 W d) 0.04, 1200 W

Description : A 3-phase 50HZ SCIM takes a power input of 30 KW at its full load speed of 1440 rpm. Total stator losses are 1 KW. The slip and rotor ohmic losses at full load are a) 0.02, 600 W b) 0.04, 580 W c) 0.04, 1160 W d) 0.04, 1200 W

Last Answer : Ans: 0.04, 1160 W

What all does FPL meters measure kw/kwh and what else?

Description : What all does FPL meters measure kw/kwh and what else?

Last Answer : Florida Power & Light Company only measures kw/kwh (kilowatt per kilowatt hour). However, your bill will include a standard customer charge to cover general maintenance and administration fees. Fuel charges, ... and taxes are also included in the bill. These charges are based on your electric usage.

The work index in Bond's law for crushing of solids has the following dimensions (A) No units (dimensionless) (B) kWh/ton (C) kW/ton (D) kWh.m1/2 /ton

Description : The work index in Bond's law for crushing of solids has the following dimensions (A) No units (dimensionless) (B) kWh/ton (C) kW/ton (D) kWh.m1/2 /ton

Last Answer : (B) kWh/ton

Which one is not an energy consumption benchmark parameter? a) kcal/kWh of electricity generated b) kg/ oC. c) kW/ton of refrigeration d) kWh/kg of yarn

Description : Which one is not an energy consumption benchmark parameter? a) kcal/kWh of electricity generated b) kg/ oC. c) kW/ton of refrigeration d) kWh/kg of yarn

Last Answer : b) kg/ oC.

A 50 KVA transformer has iron loss 2 kW on full load. Calculate its iron loss at 75% of full load.

Description : A 50 KVA transformer has iron loss 2 kW on full load. Calculate its iron loss at 75% of full load.

Last Answer : Iron loss is dependent on voltage and independent of load. Hence iron loss at 75% of Load = Iron loss at full load = 2 kW

kWh meter is the electric meter that measures the amount of electrical _________ in kWh that

Description : kWh meter is the electric meter that measures the amount of electrical _________ in kWh that was consumed in the house.  (A) Energy (B) Current (C) Voltage (D) None of the above

Last Answer : kWh meter is the electric meter that measures the amount of electrical Energy in kWh that was consumed in the house. 

A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg

The maximum demand of consumer is 2 kW and his daily energy consumption is 20 units. Its Load Factor is

Description : The maximum demand of consumer is 2 kW and his daily energy consumption is 20 units. Its Load Factor is (1) 10.15% (2) 41.6 % (3) 50 % (4) 60% 

Last Answer : Total maximum demand of energy in a day = 2kw*24= 48 units Consumer consumption is 20 units . Load factor = (number of units utilizing)/(total max. demand)      = 20/48 = 41.6%

A grinding wheel rotates at 3000 rpm. When power supply is cut-off the wheel stops in 10 seconds. The number of revolutions made by the wheel before coming to rest would be a.1500 b.3000 c.1000 d.250 e.500

Description : A grinding wheel rotates at 3000 rpm. When power supply is cut-off the wheel stops in 10 seconds. The number of revolutions made by the wheel before coming to rest would be a.1500 b.3000 c.1000 d.250 e.500

Last Answer : d. 250

A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64

Description : A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64

Last Answer : e. 7.64

How many revolutions will a turntable that rotates through an angle of 3 over 2 pi in one second make in 60 seconds?

Description : How many revolutions will a turntable that rotates through an angle of 3 over 2 pi in one second make in 60 seconds?

Last Answer : I guess you mean 3 pi over 2, ie 3Ï€/2 though it may have been given to you as (3/2)Ï€ To solve this, find the total angle turned in 60 seconds and divide by the angle in a whole ... radians = 90Ï€/2Ï€ revolutions = 45 revolutions (45 rpm - the figure calculated - was the standard for a single).

A 40 kW engine has a mechanical efficiency of 80 %. If the frictional power is assumed to be constant with load, what is the approximate value of the mechanical efficiency at 50 % of the rated load? (a) 45% (b) 55 % (c) 65% (d) 75%

Description : A 40 kW engine has a mechanical efficiency of 80 %. If the frictional power is assumed to be constant with load, what is the approximate value of the mechanical efficiency at 50 % of the rated load? (a) 45% (b) 55 % (c) 65% (d) 75%

Last Answer : Ans :c

what is the reading in kwh of the electric meter shown in the exam figure below? -General Knowledge

Description : what is the reading in kwh of the electric meter shown in the exam figure below? -General Knowledge

Last Answer : 0631 is the reading in kwh of the electric meter shown in the exam figure below.

The meter installed in our homes measure electricity in _____. A. KWh B. WKh C. Hkw D. Khw

Description : The meter installed in our homes measure electricity in _____. A. KWh B. WKh C. Hkw D. Khw

Last Answer : ANSWER: A

The meter installed in our homes measure electricity in _____. A. KWh B. WKh C. Hkw D. Khw

Description : The meter installed in our homes measure electricity in _____. A. KWh B. WKh C. Hkw D. Khw

Last Answer : ANSWER: A

The meter installed in our homes measure electricity in _____. A. KWh B. WKh C. Hkw D. Khw

Description : The meter installed in our homes measure electricity in _____. A. KWh B. WKh C. Hkw D. Khw

Last Answer : ANSWER: A

In a 100 TPD Sponge Iron plant, the sponge iron is fed to the Induction melting furnace, producing molten steel at 88% yield. The Energy consumption details are as follows: Coal Consumption : 130 TPD GCV of coal : 4500 kcal/kg Power Purchased from Grid : 82400 kWh / day Specific Energy consumption for Kiln producing Sponge Iron: 120 kWh / ton sponge iron Calculate the following 1. Specific Energy Consumption of Induction melting furnace in terms of kWh/ton of molten steel 2. Specific Energy Consumption of the entire plant, in terms of kcal/kg of molten steel (product). 3. Total Energy Consumption of Plant in Tons of Oil Equivalent (TOE )

Description : In a 100 TPD Sponge Iron plant, the sponge iron is fed to the Induction melting furnace,  producing molten steel at 88% yield. The Energy consumption details are as follows: Coal Consumption : 130 ... molten  steel (product). 3. Total Energy Consumption of Plant in Tons of Oil Equivalent (TOE )

Last Answer :  a) Specific Energy Consumption of Induction Melting Furnace  Molten Steel Production from the Induction melting furnace per day  = 100 x 88/100 = 88 TPD Total Energy Consumption of the Plant = 82400 kWh ... mark c) Total Energy consumption of Plant in ToE  = 655864000/107  = 65.586 ToE

Two alternators rated are 200 KW at 4% regulation, 400 KW 5% regulation operating in parallel at 50HZ , when supply 600 KW the new frequency is a) 50 b) 49 c) 51.3 d) 47.7

Description : Two alternators rated are 200 KW at 4% regulation, 400 KW 5% regulation operating in parallel at 50HZ , when supply 600 KW the new frequency is a) 50 b) 49 c) 51.3 d) 47.7

Last Answer : Ans: 47.7

The rotor power output of a 3-phase induction motor is 15 KW and corresponding slip is 4%. The rotor copper loss will be (A) 600 W. (B) 625 W (C) 650 W (D) 700 W

Description : The rotor power output of a 3-phase induction motor is 15 KW and corresponding slip is 4%. The rotor copper loss will be (A) 600 W. (B) 625 W (C) 650 W (D) 700 W

Last Answer : Ans: B Rotor copper losses = rotor input- rotor output and output = (1-s) input ∴ Input = output/(1-s) = 15000 /1-0.04 = 15625 ∴ loss = 15625 -1500 = 625 watt

Determine the effective radiated power of 20 kW TV broadcast transmitter whose antenna has a field gain of 2. A. 40 kW B. 80,000 watts C. 40,000 watts D. 8,000 watts

Description : Determine the effective radiated power of 20 kW TV broadcast transmitter whose antenna has a field gain of 2. A. 40 kW B. 80,000 watts C. 40,000 watts D. 8,000 watts

Last Answer : B. 80,000 watts

How to calculate the rate of rotation, in revolutions per minute.

Description : How to calculate the rate of rotation, in revolutions per minute.

Last Answer : answer:I’m going with 1.56 revs/min. Circumference = pi*d = 376.8 m Rate of rotation = 9.8 m/s, so it takes 38.4s to complete one rev. 60/38.4 = 1.56

The period of revolutions of Mars around th esun is 1.881 year and its mean distance from the sun is `1.524AU`. Calculate the mass of sun `(1AU=1.496x

Description : The period of revolutions of Mars around th esun is 1.881 year and its mean distance from the sun is `1.524AU`. Calculate the mass of sun `(1AU=1.496x

Last Answer : The period of revolutions of Mars around th esun is 1.881 year and its mean distance from the sun is `1. ... the mass of sun `(1AU=1.496xx10^(11)m)`.

What is the frequency of an alternator which has 2 poles and makes 3600 revolutions per minute?

Description : What is the frequency of an alternator which has 2 poles and makes 3600 revolutions per minute? A) 3600 HZ B) 60 Hz C) 120 Hz D) None of these

Last Answer : What is the frequency of an alternator which has 2 poles and makes 3600 revolutions per minute? A) 3600 HZ B) 60 Hz C) 120 Hz D) None of these

A spring with a force constant of 100 Newtons per meter is loaded with a mass of 1.0 kilogram. The period of vibration of this system is: w) .03 seconds x) .06 seconds y) .31 seconds z) .63 seconds

Description : A spring with a force constant of 100 Newtons per meter is loaded with a mass of 1.0 kilogram. The period of vibration of this system is: w) .03 seconds x) .06 seconds y) .31 seconds z) .63 seconds

Last Answer : ANSWER: Z -- .63 SECONDS 

A blender has a power of 0.3 kW. It is used to make a fruit smoothie, which takes 50 seconds. How much energy is used Give your answer in kilojoules.kJ?

Description : A blender has a power of 0.3 kW. It is used to make a fruit smoothie, which takes 50 seconds. How much energy is used Give your answer in kilojoules.kJ?

Last Answer : 15 KJ

Calculate the labour turnover rate according to Separation method from the following: No. of workers on the payroll: - At the beginning of the month: 500 - At the end of the month: 600 During the month, 5 workers left, 20 workers were discharged and 75 workers were recruited. Of these, 10 workers were recruited in the vacancies of those leaving and while the rest were engaged for an expansion scheme. (a) 4.55% (b) 1.82% (c) 6% (d) 3%

Description : Calculate the labour turnover rate according to Separation method from the following: No. of workers on the payroll: - At the beginning of the month: 500 - At the end of the month: 600 During the month, 5 workers left ... engaged for an  expansion scheme. (a) 4.55% (b) 1.82% (c) 6% (d) 3%

Last Answer : (a) 4.55%

Calculate the labour turnover rate according to replacement method from the following: No. of workers on the payroll: - At the beginning of the month: 500 - At the end of the month: 600 During the month, 5 workers left, 20 workers were discharged and 75 workers were recruited. Of these, 10 workers were recruited in the vacancies of those leaving and while the rest were engaged for an expansion scheme. (a) 4.55% (b) 1.82% (c) 6% (d) 3%

Description : Calculate the labour turnover rate according to replacement method from the following: No. of workers on the payroll: - At the beginning of the month: 500 - At the end of the month: 600 During the month, 5 workers left ... engaged for an expansion scheme. (a) 4.55% (b) 1.82% (c) 6% (d) 3%

Last Answer : (b) 1.82%

A 50 Hz, 4 pole turboalternator rated at 20 MVA. 13.2 KV has an inertia constant H = 4 KW sec/KVA.

Description : A 50 Hz, 4 pole turboalternator rated at 20 MVA. 13.2 KV has an inertia constant H = 4 KW sec/KVA. The K.E. stored in the rotor at synchronous speed is

Last Answer : A 50 Hz, 4 pole turboalternator rated at 20 MVA. 13.2 KV has an inertia constant H = 4 KW sec/KVA. The K.E. stored in the rotor at synchronous speed is 80 MJ

A dipole antenna requires to be fed with 20 kW of power to produce a given signal strength to a particular distant point. If the addition of a reflector makes the same field strength available with an input power of 11kW. What is the gain in dB, obtained by the use if the reflector. (Gain referred to this particular dipole). A. 4.75 B. 2.6 C. 1.81 D. 4.24

Description : A dipole antenna requires to be fed with 20 kW of power to produce a given signal strength to a particular distant point. If the addition of a reflector makes the same field strength available with an input power of 11kW ... Gain referred to this particular dipole). A. 4.75 B. 2.6 C. 1.81 D. 4.24

Last Answer : B. 2.6

A dipole antenna requires to be feed with 20 kW of power to produce a given signal strength to a particular distant point. If the addition of a reflector makes the same field strength available with an input power of 11 kW. What is the gain in dB obtain by the use of the reflector ? ( Gain referred to this particular dipole) A. 4.24 B. 1.81 C. 4.75 D. 2.6

Description : A dipole antenna requires to be feed with 20 kW of power to produce a given signal strength to a particular distant point. If the addition of a reflector makes the same field strength available with an input power of 11 ... ( Gain referred to this particular dipole) A. 4.24 B. 1.81 C. 4.75 D. 2.6

Last Answer : D. 2.6

One 200 KVA transformer has an iron loss of 1 KW and full load Cu loss of 2 KW. Its load KVA corresponding...

Description : One 200 KVA transformer has an iron loss of 1 KW and full load Cu loss of 2 KW. Its load KVA corresponding to maximum efficiency is:  (A) 100 KVA (B) 141.4 KVA (C) 50 KVA (D) 200 KVA 

Last Answer : 100

A three-phase alternator operates at 450 volts with a power factor of 0.8. If the ammeter indicates 250 amperes, what should be the KW meter reading? A. 90.00 KW B. 127.27 KW C. 155.70 KW D. 194.85 KW

Description : A three-phase alternator operates at 450 volts with a power factor of 0.8. If the ammeter indicates 250 amperes, what should be the KW meter reading? A. 90.00 KW B. 127.27 KW C. 155.70 KW D. 194.85 KW

Last Answer : Answer: C

A three-phase alternator is developing 300 amps, with a 0.8 power factor, at 450 volts. The true indicated power on the kilowatt meter, located on the main switchboard, will be ____________. A. 133 kw B. 155 kw C. 187 kw D. 212 kw

Description : A three-phase alternator is developing 300 amps, with a 0.8 power factor, at 450 volts. The true indicated power on the kilowatt meter, located on the main switchboard, will be ____________. A. 133 kw B. 155 kw C. 187 kw D. 212 kw

Last Answer : Answer: C

A three-phase alternator is operating at 450 volts with the switchboard ammeter indicating 300 amps. The kw meter currently indicates 163.6 KW, with a power factor of 0.7. If the power factor increases to 0.8, the KW meter would then read ____________. A. 181.4 KW B. 186.8 KW C. 194.2 KW D. 201.4 KW

Description : A three-phase alternator is operating at 450 volts with the switchboard ammeter indicating 300 amps. The kw meter currently indicates 163.6 KW, with a power factor of 0.7. If the power factor increases to 0.8, the KW meter would then read ____________. A. 181.4 KW B. 186.8 KW C. 194.2 KW D. 201.4 KW

Last Answer : Answer: B

A three-phase alternator is operating at 450 volts with the switchboard ammeter indicating 300 amps. The kw meter currently indicates 163.6 KW, with a power factor of 0.7. If the power factor increases to 0.8, the KW meter reading would increase by ___ A. 17.8 KW B. 23.2 KW C. 30.6 KW D. 37.8 KW

Description : A three-phase alternator is operating at 450 volts with the switchboard ammeter indicating 300 amps. The kw meter currently indicates 163.6 KW, with a power factor of 0.7. If the power factor increases to 0.8, the KW meter reading would increase by ___ A. 17.8 KW B. 23.2 KW C. 30.6 KW D. 37.8 KW

Last Answer : Answer: B

19. For a cement plant the parameter, ―kWh/MT of clinker ―indicates a) Energy Index parameter b) Utility factor c) Production factor d) Load factor

Description : For a cement plant the parameter, ―kWh/MT of clinker ―indicates a) Energy Index parameter b) Utility factor c) Production factor d) Load factor

Last Answer : Utility factor

For a cement plant the parameter, ―kWh/MT of clinker ―indicates c) Energy Index parameter c) Production factor d) Utility factor d) load factor

Description : For a cement plant the parameter, ―kWh/MT of clinker ―indicates c) Energy Index parameter c) Production factor d) Utility factor d) load factor

Last Answer :  Energy Index parameter

For a cement plant the parameter, ―kWh/MT of clinker ―indicates a) Energy Index parameter c) Production factor b) Utility factor d) load factor

Description : For a cement plant the parameter, ―kWh/MT of clinker ―indicates a) Energy Index parameter c) Production factor b) Utility factor d) load factor

Last Answer : Energy Index parameter