What's the difference between EF and EF-S designation for Canon lenses?

What's the difference between EF and EF-S designation for Canon lenses?
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1 Answer

Answer :

EF means that it is an electronic focus lens, basically every lens made since the late 80s. Also called auto focus. EF-S are crop sensor camera lenses. They will only fit on APS-C cameras, which as of 2009 is everything but the 1D and 5D. EF lenses will work on APS-C bodies as well as full frame and film, but cost more in most cases. L series lenses are top of the line lenses. If you buy an L lens you know you are getting the best optical quality available. You will also pay dearly for it.
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Last Answer : i) F.B OF PQ = N 55°0 ’ E  B.B Of PQ = S 55°0 ’W  ii) F.B. Of EF = 280°0 ’   B.B OF EF = F.B -180°= 280°0 ’ -180° = 100°0 ’  iii) F.B OF CD = S 58°30’W  B.B OF CD = N 58°30’ E  iv) F.B OF GH = 180°  B.B OF GH = F.B -180°=180°-180°= 0°

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Description : I have a very generic carry-on bag from EF Tours for my trip, ideas on personalizing it?

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In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram (ii) quadrilateral BEFC is a parallelogram (iii) AD || CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]

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ABCD is a square. E and F are respectively the mid - points of BC and CD. If R is the mid point of EF. -Maths 9th

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EF is the transversal to two parallel lines AB and CD. GM and HL are the bisector of the corresponding angles EGB and EHD.Prove that GL parallel to HL. -Maths 9th

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Last Answer : Solution :-

idn34 ef djewfe ferkflew?

Description : idn34 ef djewfe ferkflew?

Last Answer : fiwjnefwkfew ;(

A square current carrying loop abcd is palced near an infinitely long another current carrying wire ef. Now, match the following two columns.

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Last Answer : A square current carrying loop abcd is palced near an infinitely long another current carrying wire ef. Now, match the following two columns.

How can the IMA of a first- class lever be increased Decrease the length between the applied effort and the pivot. Increase the length between the applied effort and the pivot. Decrease the applied ef?

Description : How can the IMA of a first- class lever be increased Decrease the length between the applied effort and the pivot. Increase the length between the applied effort and the pivot. Decrease the applied ef?

Last Answer : What is the answer ?

Diphtheria toxin inhibits (A) Prokaryotic EF-1 (B) Prokaryotic EF-2 (C) Eukaryotic EF-1 (D) Eukaryotic EF-2

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Translocation of the newly formed peptidyl tRNA at the A site into the empty P site involves (A) EF-II, GTP (B) EF-I, GTP (C) EF-I, GDP (D) Peptidyl transferase, GTP

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Last Answer : Answer : A

The newly entering amino acyl tRNA into A site requires (A) EF-II (B) Ribosomal RNA (C) mRNA (D) EF-I

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In the process of elongation of chain binding of amino acyl tRNA to the A site requires (A) A proper codon recognition (B) GTP (C) EF-II (D) GDP

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The formation of initiation complex during protein synthesis requires a factor: (A) IF-III (B) EF-I (C) EF-II (D) IF-I

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To calculate early start (ES) and early finish (EF) perform a: A. Backward pass B. Forward pass C. Lateral pass D. Critical pass

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In given figure, AD = 3 cm, AE = 5 cm, BD = 4 cm, CE = 4 cm, CF = 2 cm, BF = 2.5 cm, then (a) DE || BC (b) DF || AC (c) EF || AB (d) none of

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Last Answer : (D) All the above

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Description : The flow energy of 5 ft3 of a fluid passing a boundary to a system is 80,000 ft-lb. Determine the pressure at this point.  a. 222 psi  b. 333 psi  c. 444 psi  d. 111 psi formula: Ef= pV

Last Answer : 111 psi

The result of adding hexadecimal number A6 to 3A is (A) DD. (B) E0. (C) F0. (D) EF.

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The reverse polish notation equivalent to the infix expression ((A + B) * C + D)/(E + F + G) (A) A B + C * D + EF + G + / (B) A B + C D * + E F + G + / (C) A B + C * D + E F G + +/ (D) A B + C * D + E + F G + /

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In an n-type semiconductor, as the donor concentration ND increases, the Fermi level EF:

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