Find the back bearing of the following lines having fore bearing as given below: (i) PQ = N 55° 0' E (ii) EF == 280° 0' (iii) CD = S 58° 30' W (iv) OM= 180° 0'

Find the back bearing of the following lines having fore bearing as given below: (i) PQ = N 55° 0' E (ii) EF == 280° 0' (iii) CD = S 58° 30' W (iv) OM= 180° 0'
by

1 Answer

Answer :

i) F.B OF PQ = N 55°0 ’ E 

B.B Of PQ = S 55°0 ’W 

ii) F.B. Of EF = 280°0 ’ 

 B.B OF EF = F.B -180°= 280°0 ’ -180° = 100°0 ’ 

iii) F.B OF CD = S 58°30’W 

B.B OF CD = N 58°30’ E 

iv) F.B OF GH = 180° 

B.B OF GH = F.B -180°=180°-180°= 0°
by

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