5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

5 10 17 27 37 50 65
a) 10
b) 17
c) 27
d) 37
e) 50
by

1 Answer

Answer :

The series is +5, +7, +9, +11, ....
Answer: c)
by

Related questions

5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these

Description : 5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these

Last Answer : 7.5 – 5 = 2.5 11.25 – 7.5 = 3.75 => 3.75 – 2.5 = 1.25 11.25 – 7.5 = 3.75 17.5 – 11.25 = 6.25 => 6.25 – 3.75 = 2.5 Answer: a)

In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Last Answer : d) 85

12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)

A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings? A.30 B.37 C.40 D.45 E.None of these

Description : A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings? A.30 B.37 C.40 D.45 E.None of these

Last Answer : Answer – B (37) Explanation – Let the average after 16th innings be a, then total score after 17th innings => 16a+85 = 17 (a+3) a = 85-51 = 34 Average after 17 innings = a + 3 = 34 + 3 = 37

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

Find the next number in the following series: 2, 5, 10, 17, 26, 37, 50, ? (A) 63 (B) 65 (C) 67 (D) 69

Description : Find the next number in the following series: 2, 5, 10, 17, 26, 37, 50, ? (A) 63 (B) 65 (C) 67 (D) 69

Last Answer : Answer: B

Which number is missing in the following series ? 2, 5, 10, 17, 26, 37, 50, ? (A) 63 (B) 65 (C) 67 (D) 69

Description : Which number is missing in the following series ? 2, 5, 10, 17, 26, 37, 50, ? (A) 63 (B) 65 (C) 67 (D) 69

Last Answer : Answer: B Observe that 2, 5, 10, 17, 26, 37, 50, ? There is difference between two number is 3, 5, 7, 9, 11, 13 So next is 50 +15=65

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Description : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Last Answer : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 Sol: 322 + 372.6 = ? ÷4 694.6 x 4 = ? ? = 2778.4 Answer: a)

1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

Description : 1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

Last Answer : d) 8980.77

3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Description : Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and  they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Last Answer : Answer - C (3 : 2) Explanation - Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. relative speed = total ... 23x + 23y = 27x + 17 y 27x-23x= 23 y-17y 4x=6y x/y=6/4=3/2= 3:2

Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these

Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these

Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m

The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Description : The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Last Answer : Answer – B (56) Explanation – The total of 11 results = 11 x 50 = 550 The total of first 6 results = 6 x 49 = 294 The total of last 6 results = 6 x 52 = 312 The sixth result is common to both: Sixth result = 294 + 312 – 550 = 56

A dealer buys an article marked at Rs. 50,000 at 25% and 10% successive discount. He spends Rs. 5000 on its repair and sells it for Rs. 50,000. What is his loss or gain percentage? 1. 33.63% loss 2. 26.43% gain 3. 1.25% gain 4. 29.03% 5. 27.13% loss

Description : A dealer buys an article marked at Rs. 50,000 at 25% and 10% successive discount. He spends Rs. 5000 on its repair and sells it for Rs. 50,000. What is his loss or gain percentage? 1. 33.63% loss 2. 26.43% gain 3. 1.25% gain 4. 29.03% 5. 27.13% loss

Last Answer : CP of the article  

(32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these

Description : (32.3)2 ÷ 4 + √361 = ?2 + 50 a) 15 b) 13 c) 11 d) 17 e) None of these

Last Answer : 32*32 = 1024 1024/4 + 19 = 256+19= 275 Answer: a)

3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5

Description : 3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5

Last Answer : The series is ×2.5, ×2 alternately Answer: a)

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29

1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)

40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37  x = 7 Age of A = 2x + 2 = 16 years Answer: d)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: A.124 B.100 C.111 D.175 E.None of these

Description : The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: A.124 B.100 C.111 D.175 E.None of these

Last Answer : Answer – C (111) Explanation – Let the numbers be 37a and 37b. Then, 37a x 37b = 4107 ab = 3. Now, co-primes with product 3 are (1, 3). So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.

Secretin is made up of (A) 17 amino acids (B) 27 amino acids (C) 37 amino acids (D) 47 amino acids

Description : Secretin is made up of (A) 17 amino acids (B) 27 amino acids (C) 37 amino acids (D) 47 amino acids

Last Answer : Answer : B

Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39

Description : Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39

Last Answer : 1;  Total number of students

What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Description : What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Last Answer : Answer: d)

A trader sells 145 m of cloth for Rs 12325 at the profit of Rs 10 per metre of cloth. What is the cost price of 1 m of cloth? 1. Rs 65 2. Rs 75 3. Rs 95 4. Rs 85

Description : A trader sells 145 m of cloth for Rs 12325 at the profit of Rs 10 per metre of cloth. What is the cost price of 1 m of cloth? 1. Rs 65 2. Rs 75 3. Rs 95 4. Rs 85

Last Answer : 2. Rs 75

Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours

Description : Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours

Last Answer : b) 10 10/17 hours

[(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

Description : A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed ... as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these

Last Answer : Answer-D (81 km/hr) Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and 5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) ... - 12.75 => 0.1x = 2.25 => x = 22.5 Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.

Mr. Xavier invested a certain amount in Debit and Equity funds in the ratio of 4 : 5 respectively. At the end of one year, he earned a total dividend of 30% on his investment. After one year he reinvested the amount including dividend in the ratio of 6 : 7 in Debt and Equity Funds. If the amount reinvested in Equity Funds was Rs. 94,500/-, what was the original amount invested in Equity Funds? (a) Rs. 75,000/- (b) Rs. 81,000/- (c) Rs. 60,000/- (d) Rs. 65,000/- (e) None of these

Description : Mr. Xavier invested a certain amount in Debit and Equity funds in the ratio of 4 : 5 respectively. At the end of one year, he earned a total dividend of 30% on his investment. After one year he reinvested the amount including ... . 81,000/- (c) Rs. 60,000/- (d) Rs. 65,000/- (e) None of these

Last Answer : (a) Rs. 75,000/-

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

Description : 8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

Last Answer : ? = (33/4) × (27/5) – (25/6) × (21/5) =891/20 -35/2 ≈ 44.5 – 17.5 =27 Answer: d)

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these

Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these 

Last Answer : Answer: a)

.What is the sum between money spent on bonus by these two companies? a) Rs.72 lakhs b) Rs.62 lakhs c) Rs.60 lakhs d) Rs.65 lakhs e) None of these

Description : .What is the sum between money spent on bonus by these two companies? a) Rs.72 lakhs b) Rs.62 lakhs c) Rs.60 lakhs d) Rs.65 lakhs e) None of these

Last Answer : e) None of these

The average domestic investment in the year 2011 is what percent of the average investment in Transport during the given four years? a) 201% b) 65.34% c) 125.45% d) 147.97% e) 167.23%

Description : The average domestic investment in the year 2011 is what percent of the average investment in Transport during the given four years? a) 201% b) 65.34% c) 125.45% d) 147.97% e) 167.23%

Last Answer : b) 65.34%

The sum of 2 numbers is 216, and their HCF is 27. How many such pairs of numbers exist? (A pair a unique set of 2 numbers, so (a, b) and (b, a) will be considered as 1 pair). a) 0 b) 1 c) 2 d) 3 e) 4

Description : The sum of 2 numbers is 216, and their HCF is 27. How many such pairs of numbers exist? (A pair a unique set of 2 numbers, so (a, b) and (b, a) will be considered as 1 pair). a) 0 b) 1 c) 2 d) 3 e) 4

Last Answer : Let the numbers be a,b A = 27m, b = 27n where m, n are co-prime 27(m + n) = 216, or m+n = 8 M = 1, n = 7 and m = 3, n = 5 are the only 2 co – prime pairs possible. So we have 2 pairs: (27 , 189) and ( 81, 135) Answer: c)

1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62  216:36 Answer: b)

1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Description : 1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Last Answer : Answer: d)

(3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Description : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Last Answer : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? Sol: 111.1 + 26.6 + 139.667 = ? ? = 277.367 Answer: d)

(3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Description : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Last Answer : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? Sol: 111.1 + 26.6 + 139.667 = ? ? = 277.367 Answer: d)

Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Description : Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Last Answer : According to question, l×b = ¶r2 l ×22 = 22/7 ×14 × 14 l = 22/7 ×14 × 14/22 cms = 28 cms. Answer: b)

If the positions of the digits of a two digit number are interchanged, the number obtained is smaller than the original number by 27. If the digits of the number are in the ratio of 1 : 2, what is the original number ? a) 25 b) 81 c) 36 d) Cannot be determined e) None of these

Description : If the positions of the digits of a two digit number are interchanged, the number obtained is smaller than the original number by 27. If the digits of the number are in the ratio of 1 : 2, what is the original number ? a) 25 b) 81 c) 36 d) Cannot be determined e) None of these

Last Answer : Cannot be determined Answer: d)

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Description : A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is  subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

A rectangular grassy plot 110 m by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq. Meter 1).Rs.680 2).Rs.860 3).Rs.608 4).None.

Description : A rectangular grassy plot 110 m by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq. Meter 1).Rs.680 2).Rs.860 3).Rs.608 4).None.

Last Answer : 1).Rs.680 Exp: overall area of the grassy plot is 110 x 65 =7150 sq. meters.The area of the grassy plot after applying the gravel path is 105 x 60=6300 sq. meters.Area of the gravel path is 7150 – 6300 = 850 sq.mtrs.Hence x 0.80=Rs.680 .

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.