Description : The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is: A.1 B.2 C.3 D.5 E.None of these
Last Answer : Answer – B (2) Explanation – Let the numbers 13a and 13b. Then, 13a x 13b = 2028 ab = 12. Now, the co-primes with product 12 are (1, 12) and (3, 4).
Description : The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: A.269 B.275 C.308 D.310 E.None of these
Last Answer : Answer – C (308) Explanation – Other number =[11 x 7700]/275 = 308
Description : The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: A.30 B.22 C.40 D.60 E.None of these
Last Answer : Answer – C (40) Explanation – Let the numbers be 2x and 3x. Then, their L.C.M. = 6x. So, 6x = 48 or x = 8. The numbers are 16 and 24. Hence, required sum = (16 + 24) = 40.
Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these
Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23
Description : The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these
Last Answer : Answer – D (548) Explanation – Required number = (L.C.M. of 12, 15, 20, 54) + 8 = 540 + 8 = 548.
Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these
Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110
Description : A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point ... A.15 minutes 15 seconds B.42 minutes 30 seconds C.42 minutes D.46 minutes 12 seconds E.None of these
Last Answer : Answer – D (46 minutes 12 seconds) Explanation – L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 see i.e., 46 min. 12 sec
Description : The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these
Last Answer : Answer – D (364) Explanation – L.C.M. of 6, 9, 15 and 18 is 90. Let required number be 90k + 4, which is multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4. Required number = (90 x 4) + 4 = 364.
Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these
Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16
Description : 112 111 119 92 156 31 ? a) 375 b) 287 c) 387 d) 247 e) None of these
Last Answer : Answer: d)
Description : A box contains 15bolts of which 5 are defective. If 5 bolts are selected at random from the box, what is the probability that at least one of them is defective? a) 91/143 b) 101/143 c) 111/143 d) 121/143 e) 131/143
Last Answer : Probability that at least one is defective = 1 – probability that none is defective Probability that none is defective = 10C5 / 15C5 = 12/143 Required Probability = 1-12/143 = 131/143 Answer: e)
Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98
Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)
Description : 39.98 × 85.01 – 79.9 × 34.9 + 175.03 × 12.08 = ? a) 4800 b) 4300 c) 2700 d) 2100 e) 3400
Last Answer : ? = 40 × 85 – 80 × 35 + 175 × 12 = 3400 – 2800 + 2100 = 2700 Answer: c)
Description : 210, 154, 182, 168, 175,171.5, ? a) 172.75 b) 173.25 c) 172.25 d) 173.75 e) 174.75
Last Answer : Starting from the third term, every term is the average of the previous two terms. Hence the next term is (175 + 171.5)/ 2 = 173.25 Answer: b)
Description : 175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200
Last Answer : Answer: b)
Description : √6889+√3721+√1024-√2401=? a) 129 b) 128 c) 127 d) 124 e) 123
Last Answer : √6889 + √3721 +√1024 - √2401 = ? Or,?= √(83)2 + √(61)2 + √(32)2 - √(49)2 =83+61+32 – 49 =127 Answer: c)
Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these
Last Answer : Answer: a)
Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180
Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)
Description : 37. Euro –II norm stipulate ‘sulphur’ level in diesel and petrol to be ... e) 400 ppm in diesel and 150 ppm in petrol. f) 350 ppm in diesel and 180 ppm in petrol. g) 100 ppm in diesel and 50 ppm in petrol. h) 350 ppm in diesel and 150 ppm in petrol.
Last Answer : h) 350 ppm in diesel and 150 ppm in petrol.
Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these
Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)
Description : 3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5
Last Answer : The series is ×2.5, ×2 alternately Answer: a)
Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50
Last Answer : The series is +5, +7, +9, +11, .... Answer: c)
Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84
Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)
Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40
Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)
Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598
Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)
Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none
Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)
Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these
Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37 x = 7 Age of A = 2x + 2 = 16 years Answer: d)
Description : A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings? A.30 B.37 C.40 D.45 E.None of these
Last Answer : Answer – B (37) Explanation – Let the average after 16th innings be a, then total score after 17th innings => 16a+85 = 17 (a+3) a = 85-51 = 34 Average after 17 innings = a + 3 = 34 + 3 = 37
Description : Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39
Last Answer : 1; Total number of students
Description : The product of 60% of a number and 125% of another number is what percent of the product of the original numbers? 1 : 90% 2 : 75% 3 : 80% 4 : 100% 5 : None of these
Last Answer : 2 : 75%
Description : The L.C.M of two numbers is 14 times their H.C.F . The sum of the L.C.M. and the H.C.F . is 600. If one number is 280 , then the other number is (a) 40 (b) 60 (c) 80 (d) 100
Last Answer : 80
Description : Assuming that the disk head is located initially at 32, find the number of disk moves required with FCFS if the disk queue of I/O block requests are 98, 37, 14, 124, 65, 67: (A) 310 (B) 324 (C) 320 (D) 321
Last Answer : (D) 321
Description : Consider a disk queue with request for input/output to block on cylinders 98, 183, 37, 122, 14, 124, 65, 67 in that order. Assume that disk head is initially positioned at cylinder 53 and moving ... and 252 cylinders (B) 640 and 236 cylinders (C) 235 and 640 cylinders (D) 235 and 252 cylinders
Last Answer : Answer: 236 and 208 cylinders Explanation: SSTF Initial head position =53 The closest queue to initial head position=65 head moves from 53 to 65=12 head moves from 65 to 67=2 head moves from 67 ... 122=24 head moves from 122 to 124=2 head moves from 124 to 183=59 Total head movement=208
Description : If the Disk head is located initially at track 32, find the number of disk moves required with FCFS scheduling criteria if the disk queue of I/O blocks requests are: 98, 37, 14, 124, 65, 67 (A) 320 (B) 322 (C) 321 (D) 319
Last Answer : (C) 321
Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these
Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000
Description : SNMP port is a) 37 b) 53 c) 111 d) 161
Last Answer : d) 161
Description : What is the pressure of the air, in atm, in the lungs when the gas expands to 175.0 mL at a body temperature of 37 ∘C, and the amount of gas remains constant?
Last Answer : I don’t understand the question
Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these
Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)
Description : Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours
Last Answer : b) 10 10/17 hours
Description : The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of ... . Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg
Last Answer : 3) 56 kg
Description : The sum of 2 numbers is 216, and their HCF is 27. How many such pairs of numbers exist? (A pair a unique set of 2 numbers, so (a, b) and (b, a) will be considered as 1 pair). a) 0 b) 1 c) 2 d) 3 e) 4
Last Answer : Let the numbers be a,b A = 27m, b = 27n where m, n are co-prime 27(m + n) = 216, or m+n = 8 M = 1, n = 7 and m = 3, n = 5 are the only 2 co – prime pairs possible. So we have 2 pairs: (27 , 189) and ( 81, 135) Answer: c)
Description : The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32
Last Answer : A:B = 7:8 B:C = 2:3 = 8:12 SO, A:B:C = 7:8:12 C:D = 4:5 = 12:15 A:B:C:D = 7:8:12:15 D:E = 5:7 = 15:21 SO, A:B:C:D:E = 7:8:12:15:21 given x(7+8+12+15+21) = 126 or 63x = 126 or x =2 E – A = 21X – 7X = 14X = 28 Answer: d)
Description : Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is: A.45 B.25 C.30 D.45 E.None of these
Last Answer : Answer – D (45) Explanation – Let the fourth number be a then hen, third number = 5a, second number= 5a/3 and first=10a/3 a+ 5a+ 5a/3 + 10/3 = 24.75 x 4 so,a=9 So, the numbers are 9, 45, 15 and 30
Description : What is the value of prime number x? I. X2 + x is a two digit number greater than 50 II. X3 is a three digit number. If the question can be answered with the help of statement I ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question
Last Answer : Answer : a
Description : If the digits of a two digit number are interchanged, the number formed is greater than the original number by 45. If the difference between the digits is 5.What is the original number? a) 18 b) 25 c) 36 d) Cannot be determined e) None of these
Last Answer : According to question both statements gives some equation which have two variable and it is not possible to find out two variable by single eg. Answer: d)
Description : There are two sets of five numbers each - set P and set Q. P is a set of consecutive even numbers and Q is a set of consecutive numbers. The sum of the numbers of P is 230. The second least number in Q is 33 less ... the sum of the numbers in Q. 1 : 260 2 : 250 3 : 240 4 : 270 5 : None of these
Last Answer : 1 : 260
Description : How many natural numbers are factors of 26 including the number 1 and itself? a) 1 b) 7 c) 6 d) 21
Last Answer : b) 7
Description : One horsepower is equal to (A) 550 lbf.ft/second (B) 550 kgf.m/second (C) Both (A) and (B) (D) 550 lbf.ft./h
Last Answer : (A) 550 lbf.ft/second
Description : Ashok can row upstream at 8kmph and downstream at 12kmph.What is the speed of the stream ? A.6km/hr B.3km/h C.2 km/hr D.4km/hr
Last Answer : Answer -C Basic Formula: If the speed downstream is a kmph and the speed upstream is b kmph then Speed of the stream = ½ (a-b) kmph Explanation: Speed downstream a = 12kmph Speed upstream b = 8 kmph Speed of the stream = ½ (a-b) = ½ (12-8) = 4/2 = 2 kmph speed of the stream = 2kmph