39.98 × 85.01 – 79.9 × 34.9 + 175.03 × 12.08 = ? a) 4800 b) 4300 c) 2700 d) 2100 e) 3400

39.98 × 85.01 – 79.9 × 34.9 + 175.03 × 12.08 = ?
a) 4800
b) 4300
c) 2700
d) 2100
e) 3400
by

1 Answer

Answer :

? = 40 × 85 – 80 × 35 + 175 × 12 = 3400 – 2800 + 2100 = 2700
Answer: c)
by

Related questions

79.93 × 35.02 -59.93 × 85.08 + 74.98 × 44.04 =? a) 1420 b) 1000 c) 1580 d) 870 e) 1260

Description : 79.93 × 35.02 -59.93 × 85.08 + 74.98 × 44.04 =? a) 1420 b) 1000 c) 1580 d) 870 e) 1260

Last Answer : ? ≈ 80 × 35-60 × 85 + 75 × 44 =2800 – 5100 + 3300 = 1000 Answer: b)

2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)

(?)2 + (9.99)3 = (45.02)2 – (4.01)3 a) 34 b) 19 c) 26 d) 31 e) 12

Description : (?)2 + (9.99)3 = (45.02)2 – (4.01)3 a) 34 b) 19 c) 26 d) 31 e) 12

Last Answer : ?2 + 1000 = 2025 – 64 ?2 = 961  ? = 31 Answer: d)

23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Description : 23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Last Answer : 24× 62.5× 12 = ? × 30 24× 750 = ? × 30 ? = (24× 750) / 30 = 600 Answer: b)

When a article is sold for Rs.3400, there is a loss of 2%. What is the cost price of the commodity? A. Rs 3500.50 B. Rs 3200 C. Rs 3400.56 D. Rs 3469.34

Description : When a article is sold for Rs.3400, there is a loss of 2%. What is the cost price of the commodity? A. Rs 3500.50 B. Rs 3200 C. Rs 3400.56 D. Rs 3469.34

Last Answer : Answer – D. Rs 3469.34 Explanation – loss=2% so, 98%………….3400 100%………..? ?=(3400×100)/98=3469.34

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Description : 3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Last Answer : 3600 ÷ 225 × 23 = ? +17 × 11 =>16 × 23 = ? + 187 => ? = 368 – 187 =181 ≈ 180 Answer: c)

The percentage of fluoride present in normal bone is (A) 0.01–0.03 (B) 0.04–0.08 (C) 0.10–0.12 (D) 0.15–0.2

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Last Answer : Answer : A

It is desired to concentrate a 20% salt solution (20 kg of salt in 100 kg of solution) to a 30% salt solution in an evaporator. Consider a feed of 300 kg/min at 30°C. The boiling point of the solution is 110°C, the latent heat of vaporisation is 2100 kJ/kg and the specific heat of the solution is 4 kJ/kg.K. The rate at which the heat has to be supplied in (kJ/min) to the evaporator is (A) 3.06 × 10 5 (B) 6.12 × 10 5 (C) 7.24 × 10 5 (D) 9.08 × 10

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Last Answer : (A) 3.06 × 10

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

38% of 3976 +(32)2 – 13% of 8271 + 7/6 × 3400 =? a) 5427 b) 5325 c) 5537 d) 5612 e) 5554

Description : 38% of 3976 +(32)2 – 13% of 8271 + 7/6 × 3400 =? a) 5427 b) 5325 c) 5537 d) 5612 e) 5554

Last Answer : ?=3976 × (38/100) + 1024 – 8271 × (13 / 100) + (7/6) × 3400 =1510.88 + 1024-1075.23 + 3966.66 =5426.31 ≈ 5427 Answer: a)

Ashwin borrowed a sum of Rs.6, 300 from Mishra at the rate of 14% for 3 years. He then added some more money to the borrowed sum and lent it to Ramesh at the rate of 16% of simple interest for the same time. If Ashwin gained Rs.618/- in the whole transaction, then what sum did he lend to Ramesh? a) Rs.6600 b) Rs.6800 c) Rs.4800 d) Rs.9800 e) Rs.8500

Description : Ashwin borrowed a sum of Rs.6, 300 from Mishra at the rate of 14% for 3 years. He then added some more money to the borrowed sum and lent it to Ramesh at the rate of 16% of simple interest for the same time. If ... sum did he lend to Ramesh? a) Rs.6600 b) Rs.6800 c) Rs.4800 d) Rs.9800 e) Rs.8500

Last Answer : Suppose Ashwin lend Rs. x to Ramesh then, Xx16x3/100 - (X – 6300) × 14 × 3/100 = 618......(1) From equation I , x = Rs. 6800 Answer: b)

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Description : A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Last Answer : work finished by 33 days = 33 117 8 = 30888 man hours 4/7th of the job is finished. remaining work = 1-(4/7) = 3/7 if 4/7th of the work is 30888 hours, then 3/7th of the work = [30888 ... 9 number of men = 198 since, 117 men are already working, additional men required = 198 - 117 = 81 Answer: c)

A and B entered into a partnership investing Rs. 16000 and Rs. 12000 respectively. After 3 months, A withdrew Rs. 5000 while B invested Rs. 5000 more. After 3 more months C joins the business with a capital of Rs. 21000. The share of B exceeds that of C, out of a total profit of Rs. 26400 after one year by A.Rs. 2400 B.Rs. 3600 C.Rs. 3000 D.Rs. 4800

Description : A and B entered into a partnership investing Rs. 16000 and Rs. 12000 respectively. After 3 months, A withdrew Rs. 5000 while B invested Rs. 5000 more. After 3 more months C joins the business with a capital of Rs. 21000 ... of Rs. 26400 after one year by A.Rs. 2400 B.Rs. 3600 C.Rs. 3000 D.Rs. 4800 

Last Answer : Answer: B (Rs. 3600) Explanation: A:B: C = 16000 x3 + 11000×9:12000 x 3 + 17000 x 9:21000 x 6 = 147:189:126 = 7:9:6 Difference of B and C’s shares = Rs. [26400 x (9/22) — 26400 x (6/22)) = Rs. 3600.

Arun and Bharat started a business with investments of Rs.10000 and Rs.15000 respectively. Arun being a working partner gets Rs.100 every month as salary from the profit. At the end of one year the business makes a profit of Rs.4800. Find the total share of Arun out o this amount (in Rs.) a)2880 b)2640 c)3240 d)2760

Description : Arun and Bharat started a business with investments of Rs.10000 and Rs.15000 respectively. Arun being a working partner gets Rs.100 every month as salary from the profit. At the end of one year the business makes a ... the total share of Arun out o this amount (in Rs.) a)2880 b)2640 c)3240 d)2760

Last Answer : b)2640

The value of the coefficient of compressibility for water at ordinary pressure and temperature in kg/cm is equal to (A) 2100 (B) 2700 (C) 10,000 (D) 21,000

Description : The value of the coefficient of compressibility for water at ordinary pressure and temperature in kg/cm is equal to (A) 2100 (B) 2700 (C) 10,000 (D) 21,000

Last Answer : Answer: Option D

?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Description : ?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Last Answer : ?% × 725 +14 × 21=700 =>?% × 725 +294 =700 => ?% × 725 =406 =>?=406/725 × 100 =56 Answer: d)

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)

The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years  1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)

The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these

Description : The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: A.68 B.98 C.180 D.364 E.None of these

Last Answer : Answer – D (364) Explanation – L.C.M. of 6, 9, 15 and 18 is 90. Let required number be 90k + 4, which is multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4. Required number = (90 x 4) + 4 = 364.

12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

MIS account in multiple of Rs. 1500/- can be made instead of Rs. 1000/- MIS and the maximum limit of investment in a single account has been raised from Rs. 3 lakh to Rs. 4.5 lakh and in joint account opened by two or three adults; the maximum limit has been raised from Rs. 6 lakh to Rs. 9 Lakh. Wef a) 01.8.2007 b) 12.5.2008 c) 30.08.2009 d) None of these

Description : MIS account in multiple of Rs. 1500/- can be made instead of Rs. 1000/- MIS and the maximum limit of investment in a single account has been raised from Rs. 3 lakh to Rs. 4.5 lakh and in joint account opened by two ... to Rs. 9 Lakh. Wef a) 01.8.2007 b) 12.5.2008 c) 30.08.2009 d) None of these

Last Answer : a) 01.8.2007

Ganesha, Harish and Raghu started a business with investments of Rs.15000, Rs.18000 and Rs.21000. At the end of the one year, they earned a total profit of Rs.5400. Find the respective shares of Ganesh, Harish and Raghu in the profit (in Rs.) a)1500,1800,2100 b)1360,1800,2240 c)1750,2100,2450 d)1890,2100,2310

Description : Ganesha, Harish and Raghu started a business with investments of Rs.15000, Rs.18000 and Rs.21000. At the end of the one year, they earned a total profit of Rs.5400. Find the respective shares of Ganesh, Harish ... profit (in Rs.) a)1500,1800,2100 b)1360,1800,2240 c)1750,2100,2450 d)1890,2100,2310 

Last Answer : a)1500,1800,2100

210, 154, 182, 168, 175,171.5, ? a) 172.75 b) 173.25 c) 172.25 d) 173.75 e) 174.75

Description : 210, 154, 182, 168, 175,171.5, ? a) 172.75 b) 173.25 c) 172.25 d) 173.75 e) 174.75

Last Answer : Starting from the third term, every term is the average of the previous two terms. Hence the next term is (175 + 171.5)/ 2 = 173.25 Answer: b)

175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200

Description : 175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200

Last Answer : Answer: b)

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: A.124 B.100 C.111 D.175 E.None of these

Description : The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: A.124 B.100 C.111 D.175 E.None of these

Last Answer : Answer – C (111) Explanation – Let the numbers be 37a and 37b. Then, 37a x 37b = 4107 ab = 3. Now, co-primes with product 3 are (1, 3). So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.

34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Description : 34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Last Answer : 34.8% x 950 – 33.2% of 850 = ? Sol: 0.348 x 950 – 0.332 x 850=? 330.6 – 282.2=? ?= 48.4 Answer: b)

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

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Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C,D and E becomes 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)

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Last Answer : a) Rs.2814.28 Crore

What is the total number of illiterate people in city B & C together? 1) 57.34 lakh 2) 58.12 lakh 3) 59.64 lakh 4) 60.62 lakh 5) 61.32 lakh

Description : What is the total number of illiterate people in city B & C together? 1) 57.34 lakh 2) 58.12 lakh 3) 59.64 lakh 4) 60.62 lakh 5) 61.32 lakh

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0.003 × ? × 0.0003 = 0.00009 a) 10 b) 3 c) 0.03 d) 0.003 e) None of these

Description : 0.003 × ? × 0.0003 = 0.00009 a) 10 b) 3 c) 0.03 d) 0.003 e) None of these

Last Answer : ? = 0.00009 / 0.003 × 0.0003 = 100 Answer: e)

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

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40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

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A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? A.310 m B.350 m C.600 m D.490 m E.None of these

Description : A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? A.310 m B.350 m C.600 m D.490 m E.None of these

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The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Description : The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

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The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

Rewrite each list of number in order from least to gratest 9.08 8.98 98.1 9.8 9.88?

Description : Rewrite each list of number in order from least to gratest 9.08 8.98 98.1 9.8 9.88?

Last Answer : 8.98,9.08,9.8,98.1

7% of 77 + 77% of 777 + 777% of 7777 a) 58090.54 b) 60457.25 c) 68709.16 d) 71000.01 e) None of these

Description : 7% of 77 + 77% of 777 + 777% of 7777 a) 58090.54 b) 60457.25 c) 68709.16 d) 71000.01 e) None of these

Last Answer : 7% of 77 + 77% of 777 + 777% of 7777 = 0.07 × 77 + 0.77 × 777 + 7.77 × 7777 = 61030.97 Answer: e)

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

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Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110

Description : 501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110

Last Answer : Answer: b)

Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these

Description : Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these

Last Answer : Total money = 55x + 85x + 105x = 3920 245x = 3920 x = 16 Answer: c)

8, 17, 38, 85, 186, ? a) 318 b) 354 c) 397 d) 408 e) 427

Description : 8, 17, 38, 85, 186, ? a) 318 b) 354 c) 397 d) 408 e) 427

Last Answer : Answer: c)

67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Description : 67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Last Answer : The next term is obtained by adding the unit’s digit to the number. Hence the missing number =78+8=86 Answer: a)

(138)2 + (511)2 – (132)2 = (85)2 + ? a) 410416 b) 255516 c) 265918 d) 345622 e) 546056

Description : (138)2 + (511)2 – (132)2 = (85)2 + ? a) 410416 b) 255516 c) 265918 d) 345622 e) 546056

Last Answer : (138)2 + (511)2 – (132)2 = (85)2 + ? Sol: 19044 + 261121 – 17424 = 7225 + ? 19044 + 261121 – 17424 – 7225 = ? ? = 255516 Answer: b)

In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Last Answer : d) 85