0.003 × ? × 0.0003 = 0.00009
a) 10
b) 3
c) 0.03
d) 0.003
e) None of these

1 Answer

Answer :

? = 0.00009 / 0.003 × 0.0003 = 100
Answer: e)

Related questions

Description : The shrinkage strain of concrete is generally taken as [ A ] 0.3 [ B ] 0.03 [ C ] 0.003 [ D ] 0.0003

Last Answer : [ D ] 0.0003

Description : Approximate value of shrinkage strain in concrete, is (A) 0.003 (B) 0.0003 (C) 0.00003 (D) 0.0

Last Answer : Answer: Option B

Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)

Description : 39.98 × 85.01 – 79.9 × 34.9 + 175.03 × 12.08 = ? a) 4800 b) 4300 c) 2700 d) 2100 e) 3400

Last Answer : ? = 40 × 85 – 80 × 35 + 175 × 12 = 3400 – 2800 + 2100 = 2700 Answer: c)

Description : 23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Last Answer : 24× 62.5× 12 = ? × 30 24× 750 = ? × 30 ? = (24× 750) / 30 = 600 Answer: b)

Description : 3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Last Answer : 3600 ÷ 225 × 23 = ? +17 × 11 =>16 × 23 = ? + 187 => ? = 368 – 187 =181 ≈ 180 Answer: c)

Description : The probability thata singlebit will be inerror on a typical public telephone lineusing 4800 bps modem is 10 to the power -3. If no error detection mechanism is used, the residual error ratefor a communicationline using 9-bit frames is ... to A. 0.003 B. 0.009 C. 0.991 D. 0.999 E. None of the above

Last Answer : 0.009

Description : The time of closing the cycle, in modern circuit breakers is (a) 0.003 sec (b) 0.001 sec (c) 0.01 sec (d) 0.10 sec (e) none of the above

Last Answer : (a) 0.003 sec

Description : What is the value of Fanning friction factor f ' for smooth pipe at NRe = 10 6 approximately? (A) 0.003 (B) 0.01 (C) 0.1 (D) 0.3

Last Answer : (A) 0.003

Description : A cantilever of length 2m carries a point load of 30KN at the free end.If I = 108 mm4 and E= 2×105 N/mm2. What is the slope of the cantilever at the free end? a.0.503 rad b.0.677 rad c. 0.003 rad d.0.008

Last Answer : c. 0.003 rad

Description : √(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Last Answer : Answer: d)

Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec

Description : Biomagnification of DDT in an aquatic food chain starting from water having a concentration of 0.003 ppb may go, in fish eating birds, upto:

Last Answer : Biomagnification of DDT in an aquatic food chain starting from water having a concentration of 0.003 ppb may go, in ... B. 50 ppm C. 25 ppm D. 2 ppm

Description : What is the significant figures of 0.003?

Last Answer : What is the answer ?

Description : What is 0.003 21 in words?

Last Answer : Need answer

Description : Is .003 seconds faster than 0.02 seconds?

Last Answer : .003 is faster than .005

Description : Is .003 seconds faster than 0.02 seconds?

Last Answer : .003 is faster than .005

Description : The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Last Answer : B

Description : If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105  N/mm2 ) when subjected to a twisting  moment, produces maximum shear stress of 50 N/mm2 , the angle of twist in radians, is  (A) 0.001  (B) 0.002  (C) 0.0025  (D) 0.003 

Last Answer : (C) 0.0025 

Description : According to Bazin's formula, the discharge over a rectangular weir is mL2g x H 3/2where m is equal to (A) 0.405 + (0.003/H) (B) 0.003 + (0.405/H) (C) 0.405 + (H/0.003) (D) 0.003 + (H/0.405)

Last Answer : Answer: Option A

Description : Consider a cube of material of sides 1 cm with a resistance of 0.003 Ω between its opposite faces. What is the resistance if the same volume of the material is drawn into a length of 50 cm with a uniform cross – section? A) 0.003 Ω B) 0.15 Ω C) 7.5 Ω D) None of these

Last Answer : Consider a cube of material of sides 1 cm with a resistance of 0.003 Ω between its opposite faces. What is the resistance if the same volume of the material is drawn into a length of 50 cm with a uniform cross – section? A) 0.003 Ω B) 0.15 Ω C) 7.5 Ω D) None of these

Description : As shown in the illustration, the function of the switch labeled 'PFSW' is to determine the ______________. EL-0003 A. bus frequency B. reactive volt amperes of the bus C. frequency of either generator D. power factor of either generator

Last Answer : Answer: D

Description : In the illustrated 450 VAC system, what should be provided between the bus and the device labeled 'F'? EL-0003 A. a potential transformer B. a current transformer C. an emergency disconnect device D. an audible alarm and indicating light

Last Answer : Answer: A

Description : In the illustration, if one of the devices labeled 'TURB' should fail the ___________. EL-0003 A. device labeled 'EXC' will drive the alternator B. device labeled 'BKR' for that ... -alternator D. emergency generator should automatically start and be placed on line to supply emergency load centers

Last Answer : Answer: B

Description : The device labeled 'REG SW' in the illustration is used to ___________. EL-0003 A. shift from the automatic voltage regulator to the manual voltage regulator B. shift the governor control from manual to ... device 'REG ADJ' or device 'MAN ADJ' D. supply regulated control power to the switchboard

Last Answer : Answer: A

Description : Before servicing the device indicated as 'A' in panels #1 and #3 of the illustration, the device labeled 'CT' must __________. EL-0003 A. have the disconnected leads taped to prevent ... D. have one lead grounded to discharge static electricity for the prevention of damage to electronic components

Last Answer : Answer: C

Description : In the illustration, the component labeled 'EXC' is _______. EL-0003 A. a separate class II regulated DC generator for critical direct current loads B. a generator feeding the FLD ... to drive the governor for turbogenerator speed. D. the electronic driver for the switchboard metering circuits

Last Answer : Answer: B

Description : Rosy buys Oats at Rs.10/kg and sell it in order to earn a profit of 40%. However, her faulty balance shows 1000gm when it is actually 800gm. What is her actual gain percentage? a) 35% b) 70% c) 75% d) 25% e) None of the Above

Last Answer : Let price of 1 kg rice = Rs.10. CP of 800 gm rice = Rs.8. She wants to earn a profit of 40% on per Kg SP = 10 + 40% of 10 = Rs. 14 per kg. Faulty balance shows 800 gm = 1000 gm (1 kg) She sells 800 gm for Rs.14. Profit = 14 – 8 = Rs. 6. Profit(%) = 6/8 * 100 = 75%. Answer: c)

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

Description : Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut? a) 4 hours b) 3 hours c) 6 hours d) 8 hours e) 10 hours

Last Answer : portion of the tank filled by the pipe A in 1 hour = ½ of the tank let the portion of the tank emptied because of the leak in 1 hour be 1/x of the tank therefore, in 1 hour , portion of the tank filled = 1/2 - 1 ... 1/2 - 1/x = 1/2.5 or x = 10 hence, it takes 10 hours to empty a full tank Answer: e)

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

Description : 3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Last Answer : 3 1/7 + 4 2/5 - ? = -2 3/5 22/7 + 22/5 + 13/5 = 355/35 = 71/7 = 10 1/7 Answer: a)

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

Description : What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Last Answer : Answer: d)

Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)

Description : 15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Last Answer : The series is ×2, ÷3, ×4, ÷5, ... Answer: a)

Description : 10, 221, ____, 44443, 555554 a) 3333 b) 3321 c) 3332 d) 3341 e) 332

Last Answer : This series is formed by subtracting 1 from the series of 11, 222, 3333, 44444, 555555 and so on. So the missing tam is 3333-1 = 3332. Answer: c)

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

Description : The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Last Answer : Let the length of the park be x metres. Width = x × 10 / 21 = 10x / 21 Area = x × 10x / 21 = 3360 or, x^2 = 3360 × 21 / 10 = 7056 or, x = 84 Hence, length = x = 84m and width = 84 × 10 / 21 = 40 metres Difference = 84 – 40 = 44 metres Answer: b)

Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Last Answer : The series is +5, +7, +9, +11, .... Answer: c)

Description : 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Last Answer : Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b Work done by 6 men and 8 women in 1 day = 1/10 => 6m + 8b = 1/10 => 60m + 80b = 1 --- (1) Work done by 26 men and 48 ... 1 day = 15/100 + 20/200 =1/4 => Time taken by 15 men and 20 women in doing the work = 4 days Answer: a)

Description : A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Last Answer : Let quantities of milk and water in the mixture be 3x and 2x. Then if 4 litres of water is added to the mixture the ratio of milk and water become 1:1. It can be written as (3x): (2x + 4) = 1 ... Therefore, the milk in the mixture is 4x3 = 12 litres and quantity of water = 4x2 = 8 liters Answer: a)

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

Description : A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms ... he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Last Answer : Let x' be the distance between house and station. Time taken to travel a distance of x at the speed of 10km/hr, T1 = x/10 hours Time taken to travel a distance of x at the speed of 15km/hr, T2 = x/15 hours we ... the station at 5 pm, speed = 60/5 = 12 km/hr [12 pm - 5pm, time = 5 hours] Answer: a)

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

Description : [3/2 + 2(1/5) – 7/10] of ? = 1098 a) 463 b) 326 c) 276 d) 366 e) None of these

Last Answer : [15+22-7/10] * x = 1098 X = 1098/3 = 366 Answer: d)