The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years

The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years
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The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after ... is 58. Find the ratio of their ages 3 years ago.
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The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5

The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Description : The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Last Answer : Answer: A

At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Last Answer : 45

When the average age of a father, mother and their son was 90 years, the son got married and a child was born just 6 year after the marriage when child turned 14 years the average age of the family is 80yrs. Find the age of daughter - in - law at present? A) 55 B) 56 C) 57 D) 58

Description : When the average age of a father, mother and their son was 90 years, the son got married and a child was born just 6 year after the marriage when child turned 14 years the average age of the family is 80yrs. Find the age of daughter - in - law at present? A) 55 B) 56 C) 57 D) 58

Last Answer : B) total age of father, mother and son at the time of son's marriage = 90*3 =270 present age of family father, mother, son, daughter-in-law, child = (father, mother, son age at the time of marriage ... 60)+ daughter-in-law present age + 14 = 80*5 =400 daughter-in-law present age= 400-344 = 56yrs

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17

Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17 

Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.

The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)

The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be as old as the present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

The sum of two children is ‘a’. The age of the father is twice the ‘a’. After twenty years, his age will be equal to the addition of the ages of his children. Find the age of father. -Maths 10th

Description : The sum of two children is ‘a’. The age of the father is twice the ‘a’. After twenty years, his age will be equal to the addition of the ages of his children. Find the age of father. -Maths 10th

Last Answer : Let the sum of the ages of two children will be x and age of father will be y. A.T.Q. , y = 2x ----------(i) and , After 20 years, x+40=y+20 ==> ... i), x-2x = -20 ==> x = 20 Now, put x= 20 in (i), y = 2 x 20 = 40 Hence age of father will be 40 years.

Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)

One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Last Answer : Answer: A

Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20

A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was: A.14 B.19 C.38 D.40 E.None of these

Description : A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was: A.14 B.19 C.38 D.40 E.None of these

Last Answer : Answer – A (14) Explanation – Let son’s present age be X years. Then, (38 – X) = X 2X = 38 X = 19 Son’s age 5 years back = (19 – 5) years = 14 years

The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years  1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Last Answer : C

The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Description : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Last Answer : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

if the ratio of the ages (in years) of x and y, 6 years ago was 9:8 then which of the following can be the sum of their ages 6 years from now?

Description : if the ratio of the ages (in years) of x and y, 6 years ago was 9:8 then which of the following can be the sum of their ages 6 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 6 years ago was 9:8 then which of the following can ... 89 years B. 85 years C. 91 years D. 92 years

if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Description : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be ... years from now? A. 82 B. 97 C. 75 D. 94

if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Description : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Last Answer : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be ... years from now? A. 90 B. 98 C. 92 D. 87

The ratio of the present ages of Raju and his wife is ` 5 : 4`. Which of the following cannot be the ratio of their ages 20 years hence ?

Description : The ratio of the present ages of Raju and his wife is ` 5 : 4`. Which of the following cannot be the ratio of their ages 20 years hence ?

Last Answer : The ratio of the present ages of Raju and his wife is ` 5 : 4`. Which of the following cannot be the ratio of their ... 5` C. ` 23 : 20` D. ` 13 : 10`

The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Description :  The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Last Answer : Answer: C)  Total age of K& L = 48*2 = 96 yrs----->1 Total age of L& M = 40*2 = 80yrs----->2 Total age of K& M = 44*2 = 88 yrs----->3 from 1, 2, 3 K+L+M =132---->4 from 1 & 4, M= 36 from 2 & 4, K=52 from 3 & 4, L=44 Hence the required answer is 52,44,36 

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

The ages of a father and son add up to 66. The father's age is the son's age reversed. How old could they be? (3 possible solutions). -Riddles

Description : The ages of a father and son add up to 66. The father's age is the son's age reversed. How old could they be? (3 possible solutions). -Riddles

Last Answer : 51 and 15. 42 and 24. 60 and 06.

Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)

Present ages of A and B are in the ratio 7:4, which of the following can be the difference between their ages after 8 years?

Description : Present ages of A and B are in the ratio 7:4, which of the following can be the difference between their ages after 8 years?

Last Answer : Present ages of A and B are in the ratio 7:4, which of the following can be the difference between their ... B. 10 years C. 15 years D. All of these

The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4

Description : The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4

Last Answer :  B At present: Ratio of their ages = 7 : 5. Therefore, 7: 5 will be 7x and 5x. kabil's age 6 years ago = 7x - 6 sahul's age after 6years = 5x + 6 Ratio of kabil's age 6years ago and sahul's age after 6 ... Ratio of sahul's age and kabil's age (7x + 6) / (5x - 6) = 48/24 =2/1 =2:1

A man told his son that he would give him $1000 if he could accomplish the following task. The father gave his son ten envelopes and a thousand dollars, all in one dollar bills. He told his son, 'Place the money in the envelopes in such a manner that no matter what number of dollars I ask for, you can give me one or more of the envelopes, containing the exact amount I asked for without having to open any of the envelopes. If you can do this, you will keep the $1000.' When the father asked for a sum of money, the son was able to give him envelopes containing the exact amount of money asked for. How did the son distribute the money among the ten envelopes? -Riddles

Description : A man told his son that he would give him $1000 if he could accomplish the following task. The father gave his son ten envelopes and a thousand dollars, all in one dollar bills. He told his ... exact amount of money asked for. How did the son distribute the money among the ten envelopes? -Riddles

Last Answer : The contents or the ten envelopes (in dollar bills) should be as follows: $1, 2, 4, 8, 16, 32, 64, 128, 256, 489. The first nine numbers are in geometrical progression, and their sum, deducted from 1,000, gives the contents of the tenth envelope.

Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Last Answer : answer:

The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Description : The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Last Answer : Answer – B (7 : 8) Explanation – Let A’s age and B’s age be 6X years and 7X years respectively Then, 7X – 6X = 4 X = 4 Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8

The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Description : The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Last Answer : A Let M age and N age be 8x years and 9x years. Then 9x - 8x = 6 <=> x = 6 So required ratio will be (8x+6): (9x+6) 54:60 9:10

Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

Description : Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

Last Answer : B We are given that age ratio of tom and ram = 5 : 6 Tom's age = 5x and Ram's age = 6x 3 years ago, their age was 5x and 6x. Hence at present, Tom's age = 5x +3 and Ram's age = 6x +3 After 12years, Tom's ... = 6 / 7 7 (5x + 15) = 6 (6x + 15) X = 15 Ram's present age = (6x + 3) = 93years 

Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years

The average age of two persons is 46 years. 16 years back the ratio between their ages were 1 : 2, then what is the difference between present ages of these two persons? 1) 16 years 2) 20 years 3) 24 years 4) 12 years 5) 8 years

Description : The average age of two persons is 46 years. 16 years back the ratio between their ages were 1 : 2, then what is the difference between present ages of these two persons? 1) 16 years 2) 20 years 3) 24 years 4) 12 years 5) 8 years

Last Answer : 2) 20 years

Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years.  4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8)  =33 years

Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28

12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.

The sum of the current ages of two persons M and N is 129. If the age of M is twice that of N, find the sum of their ages 8 years hence. a)125 b)145 c)137 d)149

Description : The sum of the current ages of two persons M and N is 129. If the age of M is twice that of N, find the sum of their ages 8 years hence. a)125 b)145 c)137 d)149

Last Answer : B M+N=129 Given M=2N From Which N =43,M=86 8 years their age will be 51 and 94 ,so the sum of their ages is 145

The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of

Description : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of

Last Answer : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, ... old . Find the present age of Rupa. (in years)

A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Description : A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Last Answer : 2 - 5 - 8 - 11 - 14 - 17 - 20 - 23 - 26

What is the product of Gary and his brother's ages if the sum of Gary's age and his brother's age is 34 and the difference between their ages is 4?

Description : What is the product of Gary and his brother's ages if the sum of Gary's age and his brother's age is 34 and the difference between their ages is 4?

Last Answer : 34 (the sum) divided by 2 (people) = 17Now, account for the "4" difference, while maintaining the sumof 34.In other words, add "1" to one age, while subtracting "1" fromthe other until the difference is " ... 3419 - 15 = 4However, the question is asking for the product of the ages.19 x 15 = 285.285

Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age? A.4 B.2 C.2.5 D.3 E.None of these

Description : Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age? A.4 B.2 C.2.5 D.3 E.None of these

Last Answer : Answer – B (2) Explanation – Let Monit’s present age be X years. Then, father’s present age = (X + 3X) years = 4X years. (4X + 8) =5/2 x (X + 8) 8X + 16 = 5X + 40 3X = 24 so, X=8 Hence, required ratio = (4X + 16) / (X + 16)=48 / 24 = 2