Description : If L is the length of vehicles in metres, C is the clear distance between two consecutive vehicles (stopping sight distance), V is the speed of vehicles in km/hour, the maximum number N of vehicles/hour, is (A) N = 1000 V / (L + C ... ) / 1000 V (C) N = 1000 L / (C + V) (D) N = 1000 C / (L + V)
Last Answer : Answer: Option A
Description : If the rate of gain of radial acceleration is 0.3 m per sec3 and full centrifugal ratio is developed. On the curve the ratio of the length of the transition curve of same radius on road and railway, is (A) 2.828 (B) 3.828 (C) 1.828 (D) 0.828
Last Answer : (A) 2.828
Description : If C is basic capacity per lane, V is velocity in km/hour, S is stopping distance plus length of the vehicles in metres, the formula C = 1000V/S is applicable to (A) District roads (B) Two lane roads (C) Two lane roads in one direction (D) None of these
Last Answer : Answer: Option C
Description : If A is the projected area of a vehicle in square metres, V is speed of the vehicles in kilometres per hour and C is a constant, then the wind resistance R to the moving vehicles, is given by (A) R = CAV (B) R = CAV2 (C) R = CAV3 (D) R = C 2AV
Last Answer : Answer: Option B
Description : If brakes of vehicles are effective, the vehicle-running at 30 km/hour comes to a stop in (A) 10 metres (B) 12 metres (C) 15 metres (D) 18 metres
Description : If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour
Description : Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m
Description : A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is (A) 1 in 40 (B) 1 in 50 (C) 1 in 60 (D) 1 in 70
Description : If V is the design speed in km/hour and R is the radius of the curve of a hill road, the superelevation (A) e = V / 127 R (B) e = V² / 127 R (C) e = V ²/ 225 R (D) e = V / 225 R
Description : If the coefficient of friction on the road surface is 0.15 and a maximum super-elevation 1 in 15 is provided, the maximum speed of the vehicles on a curve of 100 metre radius, is (A) 32.44 km/hour (B) 42.44 kg/hour (C) 52.44 km/hour (D) 62.44 km/hour
Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR
Last Answer : (D) GV²/gR
Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs
Description : A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed ... as the train? A.59 km/hr B.65 km/hr C.70 km/hr D.81 km/hr E. None of these
Last Answer : Answer-D (81 km/hr) Explanation4.5 km/hr =(4.5 x 5/18)m/sec =5m/4sec = 1.25 m/sec, and 5.4 km/hr =(5.4 x 5/18)m/sec =3m/2sec = 1.5 m/sec. Let the speed of the train be x m/sec. Then, (x - 1.25) ... - 12.75 => 0.1x = 2.25 => x = 22.5 Therefore Speed of the train =(22.5 x18 /5)km/hr = 81 km/hr.
Description : The normal concentration of vitamin A in blood in I.V/dl: (A) 20–55 (B) 24–60 (C) 30–65 (D) 35–70
Last Answer : Answer : B
Description : If V is speed in km/hour and R is radius of the curve, the super-elevation e is equal to (A) V²/125 R (B) V²/225 R (C) V²/325 R
Description : A soil mass coated with a thin layer of paraffin weighs 460 g. When immersed, it displaces 299 cc of water. The weight of paraffin is 10 g. If specific gravity of solids is 2.5 and that of paraffin 0.9, the void ratio of soil, is (A) 0.55 (B) 0.60 (C) 0.65 (D) 0.70
Description : The efficiency of a pump may be taken as (A) 0.55 (B) 0.60 (C) 0.65 (D) 0.70
Description : Percentage content of silica in window glass, is (A) 40 to 45 (B) 50 to 55 (C) 60 to 65 (D) 70 to 75
Last Answer : Answer: Option D
Description : The equation V = (1000 ID10²/60) × (1.8T + 42) which is used for determining the velocity of ground water flow in metres per day is known as (A) Meinzer's formula (B) Slichter's formula (C) Darcy's formula (D) Hazen formula
Description : Pick out the wrong statement pertaining to the turbine agitator. (A) Recommended peripheral speed for the turbine agitator is 200-250 metres/minute (B) Pitched blade turbine agitator gives only radial flow with ... l/4th of agitator diameter (with central disc, it is l/8th of the agitator diameter)
Last Answer : (B) Pitched blade turbine agitator gives only radial flow with complete absence of the axial flow
Description : The length of a transition curve, is governed by (A) Rate of change of radial acceleration (B) Rate of change of super-elevation (C) Both (a) and (b) (D) Neither (a) nor (b)
Description : Width of a rotary round should be equal to (A) Twice the width of narrowest radial road (B) Width of the widest road (C) Width of the widest road plus the width of one lane (D) Width of the widest road plus 2 metres
Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77
Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr
Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60
Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km
Description : While traveling in a straight line, a car uniformly changes its speed from 50 kilometers per hour to 110 kilometers per hour in 5 seconds. The acceleration of the car during this time is: w) 5 ... per hour per second y) 50 kilometers per hour per second z) 60 kilometers per hour per second
Last Answer : ANSWER: X -- 12 KILOMETERS PER HOUR PER SECOND
Description : What percentage is (i) Rs 15 of Rs 120? (ii) 36 minutes of 2 hours? (iii) 8 hours of 2 days (iv) 160 metres of 4 km? (v) 175 mL of 1 litre? (vi) 25 paise of Rs 4? -Maths
Last Answer : answer:
Description : The total length of a valley formed by two gradients - 3% and + 2% curve between the two tangent points to provide a rate of change of centrifugal acceleration 0.6 m/sec2 , for a design speed 100 kmph, is (A) 16.0 m (B) 42.3 m (C) 84.6 m (D) None of these
Description : A car travelling at a speed of 60 km/hour is braked and comes to rest 6 seconds after the brakes are applied. The minimum coefficient of driction between the wheels and the road would be a.0.107 b.0.3 c.0.283 d.0.417 e.0.5
Last Answer : c. 0.283
Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds
Last Answer : 15 min
Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr
Last Answer : A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr
Description : Two bodies of equal mass are moving in circular paths at equal speed. The first body moves in a circle whose radius is twice as great as that of the second. The ratio of the centripetal or radial acceleration of the first body to that of the second is: w) 1 to 4 x) 1 to 3 y) 1 to 2 z) 1 to 1
Last Answer : ANSWER: Y -- 1 TO 2
Description : A particle moving with uniform speed can possess : (a) radial acceleration (b) tangential acceleration © both radial and tangential accelerations (d) neither radial nor tangential acceleration
Last Answer : Neither radial nor tangential... as if it move in a straight line.. but it possess radial acceleration if it moves in a uniform circular path
Description : With usual notations, the expression V²/gR represents (A) Centrifugal force (B) Centrifugal ratio (C) Super elevation (D) Radial acceleration
Last Answer : (B) Centrifugal ratio
Description : If the rate of change of the super-elevation along a curved portion of a 7 metre wide road is 1 in 150 and the maximum super-elevation allowed is 1 in 15, the maximum length of the transition curve to be provided at either end, is (A) 65 m (B) 70 m (C) 75 m (D) 80 m
Description : The total value of extra widening required at a horizontal curve on a two lane hill road of radius 42 m for a design speed of 50 kmph and for vehicles with wheel base 6 m, is (A) 0.500 m (B) 0.589 m (C) 1.089 m (D) 0.089 m
Description : Design of horizontal curves on highways, is based on (A) Design speed of vehicles (B) Permissible friction on the road surface (C) Permissible centrifugal ratio (D) All the above
Description : There are two points on a highway a,b. They are 70 km apart. An auto starts from A and another auto starts from B simultaneously. If they travel in the same direction, they meet in 7 hours, but if they travel towards each other they meet in 1 hour. Find how fast the two autos are -Maths 10th
Last Answer : When they travel in same direction, suppose they meet when B travels for x m, then A will have travelled 70+x m in the same time Since, Speed =TimeDistance Speed of auto at A =7x+70 And Speed of auto at B =7x ... So, Speed of auto at A =7x+70 =7280 =40km/hr Speed of auto at B =7x =7210 =30km/hr
Description : A belt conveyor used for the transportation of materials can (A) Run upto 1 km (B) Travel at a speed upto 300 metres/minute (C) Handle materials upto 5000 tons/hr (D) All (A), (B) and (C)
Last Answer : (D) All (A), (B) and (C)
Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these
Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr
Description : 2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188
Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr
Description : A hare is spotted by a tiger from a distance of 50 metres. When the tiger starts a chase, the hare also starts running. If the speed of the hare be 4 km/hr and that of a tiger 5 km/hr, how far the hare will have run before its over taken? a) 100m b) 200m c) 300m d) 400m
Last Answer : B Relative speed of the tiger = (5-4)km/hr =1 km/hr Time taken by tiger to cover 50 m, =(50/1000)hr =1/20hr In 1/20 hrs, the tiger cover a distance of (4*1/20)km =1/5km =>(1/5*1000)m =200m
Description : A metro train 200 metres long takes 12 seconds to cross a man walking at 10 km/hr in a opposite to that of the train. Find the speed of the train? A) 50 km/hr B) 60km/hr C) 130km/hr D) 140km/hr
Last Answer : ANSWER: A Explanation: Length of the train = 200 m Man walking speed = 10 km/hr Let the speed of the train be x' km/hr Speed of the train relative to man = (x +10) km/hr Convert km/hr into m/s ... = 60(x +10) 3600 = 60x +600 60x = 3000 X = 50 So speed of the train is 110km/hr.
Description : Two columns 50 cm 50 cm and 60 cm 60 cm carry 80 tonnes and 120 tonnes of loads respectively. The centre to centre distance between columns is 5.00 metres. The permissible bearing capacity of the soil is 20 t ... the foundation slab = 7.00 m (C) Area of footing slab = 11.00 m2 (D) All the above
Last Answer : Option D
Description : For design of sewers, percentage of sewage discharge is assumed A. 65 to 70% B. 70 to 75% C. 75 to 80% D. 85%
Last Answer : ANS: C
Description : Chemical score of milk proteins is (A) 70 (B) 65 (C) 60 (D) 40
Description : According to Census 2001, what is the percentage of Indian population below the age 40? (1) 75 (2) 70 (3) 65 (4) 60
Last Answer : (1) 75 Explanation: As per Census 2001, the population below 15 years was 35 percent, > 60 years was 8 percent, and between 15 and 59 years of age was 57 percent of the total population. India has ... census, the percentage of Indian population below the age 6 is 13.1% and above the age 6 is 86.9
Description : The number of heart beats on an average in an adult human is in the range of (1) 60-65 (2) 66-70 (3) 71-80 (4) 8590
Last Answer : (3) 71-80 Explanation: The average heart rate for adult humans is about 70 to 75 beats per minute in a normal relaxed mode. While we tend to think of the "normal" heart beat rate as being "72 beats per minute", in actuality the heart beat rate is not and should not be constant.
Description : The ordinary and maximum tolerance limit of sound by human being is – (1) 50 db to 70 db (decibel) (2) 60 db to 80 db (decibel) (3) 65 db to 75 db (decibel) (4) 70 db to 85 db (decibel)
Last Answer : (2) 60 db to 80 db (decibel) Explanation: Normal speech is about 60 dB (decibels). A dangerous sound is anything that is 80 dB or higher which can lead to hearing loss. At 70 dB or ... the risk of harm to healthy ears is negligible. Listening to sound above 80 decibels can cause profound deafness.
Description : According to the Income Tax act of 1961, the age of Super senior Citizens should be _______ A. 60 years B. 70 years C. 80 years D. 75 years E. 65 years
Last Answer : C. 80 years Explanation: According to the Income Tax act of 1961, the age of Super senior Citizens is 80 years.
Description : Account Receivables lag impacts sales. At no credit terms, the appeal falls to about ______ %, at 30 days, appeal is _____ %, at 60 days, appeal is ______%. a. 98.5, 92, 65 b. 65, 92, 98.5 c. 70, 85, 99 d. none of the above, there is no impact
Last Answer : b. 65, 92, 98.5