Description : Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m
Last Answer : Answer: Option C
Description : The distance travelled by a moving vehicle during perception and brake reaction times, is known as (A) Sight distance (B) Stopping distance (C) Lag distance (D) None of these
Description : If V is the velocity in kmph, t the stopping distance S of the vehicle, is (A) 0.28V²t + V/0.01 (B) 0.28Vt + V²/0.1 (C) 0.28Vt + 0.01 (D) 0.28Vt + 0.01 V²/
Description : The absolute minimum radius of horizontal curve for a design speed 60 kmph is (A) 131 m (B) 210 m (C) 360 m (D) None of these
Last Answer : Answer: Option D
Description : A 270 m long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? A.180 B.230 C.245 D.235 E.None of these
Last Answer : Answer – B (230) Explanation – Relative speed = total lenghths /time [120 +80] x5/18 ={ 270 + other train length (say L) } / 9 sec (x5/18 to convert km/hr to m/sec ) 200 x (5/18) x9 = 270 + L 500 = 270 +L L=230 m Note: always do cutting ,avoid solving exact
Description : If L is the length of vehicles in metres, C is the clear distance between two consecutive vehicles (stopping sight distance), V is the speed of vehicles in km/hour, the maximum number N of vehicles/hour, is (A) N = 1000 V / (L + C ... ) / 1000 V (C) N = 1000 L / (C + V) (D) N = 1000 C / (L + V)
Last Answer : Answer: Option A
Description : Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on ... the brake with the deceleration of 5m/s2. Find the stopping distance of the car -Science
Last Answer : Here u=72 km/hr = 72×10003600m/s=2072×10003600m/s=20 m/s , v=0 a= -5 m/s2 Now using the relation v2=u2+2asv2=u2+2as 0=(20)2+2×(−5)×s0=(20)2+2×(−5)×s s=40ms=40m
Description : Non-passing sight distance along a road is the longest distance at which the driver of a moving vehicle, may see an obstacle on the pavement (A) 10 cm high (B) 25 cm high (C) 50 cm high (D) 100 cm high
Description : The safe stopping sight distance D, may be computed from the equation (A) D = 0.278 Vt + V²/254f (B) D = 0.254 Vt + V²/278f (C) D = 0.254 Vt + V²/225f (D) D = 0.225 Vt + V²/254f
Description : For night travel, the length of a valley curve should be such that the head light beam distance is the same as (A) Stopping sight distance (B) Overtaking sight distance (C) Sum of (a) and (b) (D) Difference of (a) and (b)
Description : A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours
Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours
Description : Design of horizontal and vertical alignments, super-elevation, sight distance and grades, is worst affected by (A) Width of the vehicle (B) Length of the vehicle (C) Height of the vehicle (D) Speed of the vehicle
Description : Extra widening required at a horizontal curve on a single lane hill road of radius 80 m for a design speed of 50 km ph and for a vehicle with wheel base 6.0 m is (A) 0.225 m (B) 0.589 m (C) 1.250 m (D) None of these
Last Answer : Answer: Option B
Description : What happens to the stopping distance when the vehicle speed increases?
Last Answer : The distance needed to stop also increases.
Description : The total value of extra widening required at a horizontal curve on a two lane hill road of radius 42 m for a design speed of 50 kmph and for vehicles with wheel base 6 m, is (A) 0.500 m (B) 0.589 m (C) 1.089 m (D) 0.089 m
Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs
Description : Define i) Stopping Sight distance ii) Overtaking sight distance
Last Answer : i) Stopping Sight Distance: SSD may be defined as the length of highway required to bring a vehicle to stop at various design speeds when the eye of the driver is 1200mm above the ... a vehicle intending to overtake the slow vehicle ahead safely against the traffic in the opposite direction.
Description : Power required for a train weighing 200 Mg to move at a uniform speed of 60 Kmph up an incline of 1 in 200 is (Resistance due to friction is negligible) a.16.67 KW b.163.5 KW c.1000 KW d.9810 KW e.Tapered bearing
Last Answer : b. 163.5 KW
Description : For a vehicle moving with a speed of 80 km per hour, the brake reaction time, in ordinary cases, is (A) 1 sec (B) 1.5 sec (C) 2.0 sec (D) 2.5 sec
Description : If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour
Description : While calculating the overtaking sight distance, the height of the object above road surface, is assumed (A) 50 cm (B) 75 cm (C) 100 cm (D) 120 cm
Description : The minimum design speed for hairpin bends in hill roads is taken as (A) 20 kmph (B) 30 kmph (C) 40 kmph (D) 50 kmph
Description : ECE Board Exam March 1996 What is the transmission rate of a system for transmitting the output of a microcomputer to a line printer operating at a speed of 30 lines/minute? Assume that the line printer has 8 bits ... and prints out 80 characters/line. A. 800 bps B. 400 bps C. 320 bps D. 640 bps
Last Answer : C. 320 bps
Description : A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km
Last Answer : Let the distance be x km. then (x/40) + (x/6) = 13 + (48/60) = 69/5 Answer is: d)
Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these
Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr
Description : What is the Highest speed of train in Indian Railway a. 140 KMPH b. 120 kmph c. 160 kmph* d. 130 kmph
Last Answer : c. 160 kmph*
Description : Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these
Last Answer : Answer – D (180 m) Explanation – When OPP. direction-PLUS Relative speed = (36 + 45) km/hr = [81 x 5/18] m/sec = [45/2] m/sec. Length of train = [45/2 x 8] m = 180 m.
Description : Which vehicle requires a longer stopping distance?
Last Answer : Trains require a long stopping distance.
Description : If the gross vehicle weight of a truck is 30 tonne and rolling resistance is 30 kg/tonne, then the tractive effort required to keep the truck moving at a uniform speed is (A) 30 kg (B) 300 kg (C) 900 kg (D) 1000 kg
Last Answer : (C) 900 kg
Description : If N is the algebraic difference of grades, S is the minimum sight distance in metres, the length (L) of a summit curve is (A) NS/4 (B) NS²/4 (C) N²S/4 (D) (NS)²/4
Description : If N is the net difference of grades, S is the minimum overtaken sight distance in metres, the length (L) of a summit curve, is (A) NS/4 (B) NS²/4 (C) NS²/4.8 (D) NS²/9.6
Description : Length of vehicles does not affect (A) Extra widening (B) Minimum radius of turning (C) Passing sight distance (D) Width of shoulders
Description : The total length of a valley formed by two gradients - 3% and + 2% curve between the two tangent points to provide a rate of change of centrifugal acceleration 0.6 m/sec2 , for a design speed 100 kmph, is (A) 16.0 m (B) 42.3 m (C) 84.6 m (D) None of these
Description : Track structure for private siding with operating speed 50 to 80 kmph is the same as track structure as specified for a)Group A route b) Group B route c) Group D route d)Group E route*
Last Answer : d)Group E route*
Description : Track Structure for private siding with operating speed of 80 to 100 kmph is same as the track structure as specified for a) Group B route b) Group A route c) Group D route* d)Group C route
Last Answer : c) Group D route*
Description : A goods train overtakes two boys who are walking in the same direction in which the train is going, at the rate of 4 kmph and 8 kmph and passes them completely in 18 and 20seconds respectively. The length of the goods train is : A) 50m B) 200m C) 160m D)80 m
Last Answer : ANSWER:B Explanation: Let the length of the goods train be x km and its speed be y km/hr. Then, speed relative to first boy = (y-4) km/hr. Speed relative to second boy = (y-8) km/hr. x/y-4 ... )- 72 / 3600 = 720/3600 = 0.2*1000 = 200 m Therefore the length of the goods train is 200m
Description : A boat takes 38 hrs for travelling downstream from point p to point q and coming back to a point r midway between p and q. If the velocity of the stream is 8 km/hr and the speed of the boat in still water is 28 km/hr. What is the distance between p and q? A) 720 B) 640 C) 510 D) 450
Last Answer : ANSWER: A Explanation: Speed downstream = (28 + 8)km/hr = 36 km/hr Speed upstream = (28 – 8)km/hr = 20 km/hr Let the distance between p and q be ‘x’km Then, x/36 + (x/2)/20 = 38 x/36 +x/40 = 38 19x = 13680 X = 720 km Therefore the distance between p and q is 720km
Description : Two columns 50 cm 50 cm and 60 cm 60 cm carry 80 tonnes and 120 tonnes of loads respectively. The centre to centre distance between columns is 5.00 metres. The permissible bearing capacity of the soil is 20 t ... the foundation slab = 7.00 m (C) Area of footing slab = 11.00 m2 (D) All the above
Last Answer : Option D
Description : The maximum safe speed on roads, depends on the (A) Type of road surface (B) Type of curves (C) Sight distance (D) All the above
Description : The value for the ΔU of a system is -120 J. If the system is known to have absorbed 420 J of heat, how much work was done? a. -540 J b. -640 J c. -740 J d. -840 J formula: ΔU = q +w
Last Answer : -540 J
Description : Minimum speed restriction to be imposed for Track renewal is:- (a) Stop dead & 10 Kmph (b) 10 Kmph (c) 15 Kmph (d) 20 Kmph*
Last Answer : (d) 20 Kmph*
Description : In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is? a) 5 kmph b) 6 kmph c) 6.25 kmph d) 7.5 kmph e) None of these
Last Answer : Let Abhay's speed be x km/hr. Then, 30/x-30/2x= 3 6x = 30 x = 5 km/hr. Answer: a)
Description : A man can row 9 (1/3) kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. What is speed of the current ? A. 5km/hr B.3(1/2) km/hr C.4 (2/3) km/hr D.8 (3/2)km/hr
Last Answer : Answer- C Basic Formula: Speed of current = ½ (a-b) km/hr Explanation: Let man's rate upstream be x km/hr. Then his rate downstream is 3 x km/hr Given: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (a+b) = ... the current = ½ (a-b) = ½ (14 - 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr
Description : A man takes 10 hours to cover a distance while traveling upstream on a boat, whereas while traveling downstream it takes 6 hours. If the speed of the boat in still water is 6 kmph, what is the speed of the stream? 1 : 2.5 kmph 2 : 2.2 kmph 3 : 2 kmph 4 : 1.5 kmph 5 : None of these
Last Answer : 4 : 1.5 kmph
Description : Anushiya covered a definite distance at some speed. If she had moved 5 kmph faster, she would have taken 55minutes less. If he had moved 4 kmph slower, she would have taken 55 minutes more. What is the distance in km? a) 110 Km b) 220 km c) 330 km d) 440 km
Last Answer : C speed=2V1V2/(V1-V2) = 2*5*4/(5-4) =40 km/hr Distance= vt1 (1+v/v1) =40* 55/60(1+40/5) =40*11/12(1+8) =40*11/12*9 =330 km Therefore the distance is 330km
Description : The speed of a van increases by 5 kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours? a) 580km b) 116km c) 147km d) 240km
Last Answer : A Distance travelled in 1ST hour =55 km Speed of the van increases by 5 kmph after every one hour. Hence, distance travelled in 2nd hour =60 km distance travelled in 3rd hour =65 km and so on Total distance travelled =(55+60+……..+(8 terms)) =8/2(2*55+(8-1)5) =4(110+35) =580km
Description : While calculating the sight distances, the driver's eye above road surface, is assumed (A) 90 cm (B) 100 cm (C) 110 cm (D) 120 cm
Description : A 8 metre long simply supported rectangular beam which carries a distributed load 45 kg/m. experiences a maximum fibre stress 160 kg/cm2 . If the moment of inertia of the beam is 640 cm4 , the overall depth of the beam is (A) 10 cm (B) 12 cm (C) 15 cm (D) 18 cm
Last Answer : (A) 10 cm
Description : what 80 times what equals 640,000?
Last Answer : 8,000You find this by dividing 640,000 by 80.640,000 / 80 = 8000
Description : Ravi marked his Walkman at 60% above his cost price. If he had decreased his discount from 20% to 10%. he would have earned Rs.80 more. Find his cost price. a)640 b)600 c)500 d)800
Last Answer : c)500