What happens to the stopping distance when the vehicle speed increases?

1 Answer

Answer :

The distance needed to stop also increases.

Related questions

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Last Answer : Here u=72 km/hr = 72×10003600m/s=2072×10003600m/s=20 m/s , v=0 a= -5 m/s2 Now using the relation v2=u2+2asv2=u2+2as 0=(20)2+2×(−5)×s0=(20)2+2×(−5)×s s=40ms=40m

Description : The absolute minimum sight distance required for stopping a vehicle moving with a speed of 80 kmph, is (A) 120 m (B) 200 m (C) 640 m (D) None of these

Last Answer : Answer: Option A

Description : Which vehicle requires a longer stopping distance?

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Description : If V is the velocity in kmph, t the stopping distance S of the vehicle, is (A) 0.28V²t + V/0.01 (B) 0.28Vt + V²/0.1 (C) 0.28Vt + 0.01 (D) 0.28Vt + 0.01 V²/

Last Answer : Answer: Option C

Description : The distance travelled by a moving vehicle during perception and brake reaction times, is known as (A) Sight distance (B) Stopping distance (C) Lag distance (D) None of these

Last Answer : Answer: Option C

Description : Minimum stopping distance for moving vehicles on road with a design speed of 80 km/hour, is (A) 80 m (B) 100 m (C) 120 m (D) 150 m

Last Answer : Answer: Option C

Description : If L is the length of vehicles in metres, C is the clear distance between two consecutive vehicles (stopping sight distance), V is the speed of vehicles in km/hour, the maximum number N of vehicles/hour, is (A) N = 1000 V / (L + C ... ) / 1000 V (C) N = 1000 L / (C + V) (D) N = 1000 C / (L + V)

Last Answer : Answer: Option A

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Last Answer : Many states consider this a felony if you leave a scene of an accident where someone was injured or killed and this could leave to jail time.

Description : If you are found guilty of not stopping to help when the vehicle you were driving was involved in a crash causing death or person injury?

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Last Answer : c) It increases wear and Tear of wheel flanges*

Description : A car is travelling at 90 km/hour on a rough road where the coefficient of friction between the road and the tyre is 0.5. The distance the car will skid before stopping when the brakes are jammed suddenly would be a.127.4 m b.95.55 m c.63.7 m d.31.85 m e.90 m

Last Answer : c. 63.7 m

Description : The safe stopping sight distance D, may be computed from the equation (A) D = 0.278 Vt + V²/254f (B) D = 0.254 Vt + V²/278f (C) D = 0.254 Vt + V²/225f (D) D = 0.225 Vt + V²/254f

Last Answer : Answer: Option A

Description : If N is deviation angle, the length L, of a parabolic vertical curve for safe stopping distance S, is (A) NS²/4.4 if L > S (B) 2S - 4.4/N if L < S (C) 2S - 4.4/N if L > S (D) Both (a) and (b)

Last Answer : Answer: Option D

Description : If the velocity of moving vehicles on a road is 24 km/per hour, stopping distance is 19 metres and average length of vehicles is 6 metres, the basic capacity of lane, is (A) 500 vehicles per hour (B) 700 vehicles per hour (C) 1000 vehicles per hour (D) 1250 vehicles per hour

Last Answer : Answer: Option C

Description : For night travel, the length of a valley curve should be such that the head light beam distance is the same as (A) Stopping sight distance (B) Overtaking sight distance (C) Sum of (a) and (b) (D) Difference of (a) and (b)

Last Answer : Answer: Option A

Description : If C is basic capacity per lane, V is velocity in km/hour, S is stopping distance plus length of the vehicles in metres, the formula C = 1000V/S is applicable to (A) District roads (B) Two lane roads (C) Two lane roads in one direction (D) None of these

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Description : Define i) Stopping Sight distance ii) Overtaking sight distance

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Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr

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Description : The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first one hour was 35 kms, what was the total distance traveled in 12 hours? A.456 kms B.482 kms C.552 kms D.556 kms E.None of these

Last Answer : Answer – C (552 kms) Explanation – Total distance travelled in 12 hours = (35 + 37 + 39 + …… upto 12 terms) This is an A.P. with first term, a = 35, number of terms, n = 12, common difference, d =2. Required distance =12/2 (2 x 35 + (12 – 1) x 2) = 6(70 + 22) = 552 kms

Description : Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

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