For a constant volume process (A) dE = CpdT (B) dE = CvdT (C) dQ = dE + pdV (D) dW = pdV

For a constant volume process
(A) dE = CpdT
(B) dE = CvdT
(C) dQ = dE + pdV
(D) dW = pdV
by

1 Answer

Answer :

(B) dE = CvdT
by

Related questions

Which of the following equations is obtained on combining 1st and 2nd law of thermodynamics, for a system of constant mass?(A) dE = Tds - PdV (B) dQ = CvdT + PdV (C) dQ = CpdT + Vdp (D) Tds = dE - PdV

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First law of thermodynamics is mathematically stated as (A) dQ = dE + dW (B) dQ = dE - dW (C) dE = dQ + dW (D) dW = dQ + dE

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dW and dq are not the exact differential, because q and W are (A) State functions (B) Path functions (C) Intensive properties (D) Extensive properties

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