There are two types of designs for communication subnets: they are ………… A. Point-to-Point channels and Broadcast channels B. packet-switched subnet and store-and-forward C. Multicasting and Broadcasting D. Point-to-Point channels and store-and-forward

There are two types of designs for communication subnets: they are …………
A. Point-to-Point channels and Broadcast channels
B. packet-switched subnet and store-and-forward
C. Multicasting and Broadcasting
D. Point-to-Point channels and store-and-forward
by

1 Answer

Answer :

A. Point-to-Point channels and Broadcast channels
by

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Which of the following is NOT true about User Datagram Protocol in transport layer?a. Works well in unidirectional communication, suitable for broadcast information. b. It does three way handshake before sending datagrams c. It provides datagrams, suitable for modeling other protocols such as in IP tunneling or Remote Procedure Call and the Network File System d. The lack of retransmission delays makes it suitable for real-time applications

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An organization is granted the block 130.34.12.64/26. It needs to have 4 subnets. Which of the following is not an address of this organization? a. 130.34.12.124 b. 130.34.12.89 c. 130.34.12.70 d. 130.34.12.132

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The required resources for communication between end systems are reserved for the duration of the session between end systems in ________ method. a) Packet switching b) Circuit switching c) Line switching d) Frequency switching

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You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

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Last Answer : Correct answer: A The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this equals 7. Convert the address 201.222.5.121 to binary- ... mask 255.255.255.248 to binary-11111111 11111111 11111111 11111000. AND them together to get: 11001001 1101111

You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, 15.16.199.255 * 255.255.248.0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

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Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.

You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12, 128.16.32.15 * 255.255.255.252, B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

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Last Answer : Correct answer: A * 255.255.255.248,

You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

Which transmission technique guarantees that data packets will be received by the receiver in the same order in which they were sent by the sender? (A) Broadcasting (B) Unicasting (C) Packet Switching (D) Circuit Switching

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Which of the following was selected as the official broadcaster of 2010 Commonwealth Games recently? a. Satellite Information Service Live b. International Games Broadcast Services c. Nimbus Sports International d. Canadian Broadcasting Corporation e. Big Productions

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