Discharge from a 24 inch pipe of water at 10 ft/sec will be __________ ft 3 /sec. (A) 7.65 (B) 32.36 (C) 48.22 (D) 125.6

Discharge from a 24 inch pipe of water at 10 ft/sec will be __________
ft
3
/sec.
(A) 7.65
(B) 32.36
(C) 48.22
(D) 125.6
by

1 Answer

Answer :

(D) 125.6
by

Related questions

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

If Q is discharge is cubic metres per sec and D is the economical diameter of the pipe. According to Lea (A) D = 0.67 to 0.87 Q (B) D = 0.77 to 0.97 Q (C) D = 0.97 to 1.22 Q (D) D = 1.22 to 1.33 Q

Description : If Q is discharge is cubic metres per sec and D is the economical diameter of the pipe. According to Lea (A) D = 0.67 to 0.87 Q (B) D = 0.77 to 0.97 Q (C) D = 0.97 to 1.22 Q (D) D = 1.22 to 1.33 Q

Last Answer : (C) D = 0.97 to 1.22 Q

10 .Find out position of particle at \( t=20 \sec \) if it is at \( x=4 \) intially \( ( \) Take \( \pi=3) \) :(1) 24(2) 32(3) \( -24 \)(4) 36

Description : 10 .Find out position of particle at \( t=20 \sec \) if it is at \( x=4 \) intially \( ( \) Take \( \pi=3) \) :(1) 24(2) 32(3) \( -24 \)(4) 36

Last Answer : 10 . Find out position of particle at \( t=20 \sec \) if it is at \( x=4 \) intially \( ( \) Take \( \pi=3) \) : (1) 24 (2) 32 (3) \( -24 \) (4) 36

The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Description :  The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Last Answer : Answer: C)  Total age of K& L = 48*2 = 96 yrs----->1 Total age of L& M = 40*2 = 80yrs----->2 Total age of K& M = 44*2 = 88 yrs----->3 from 1, 2, 3 K+L+M =132---->4 from 1 & 4, M= 36 from 2 & 4, K=52 from 3 & 4, L=44 Hence the required answer is 52,44,36 

3 , 8 , 15 , 24 , ? 48 , 63 (a) 30 (b) 32 (c) 35 (d) 36

Description : 3 , 8 , 15 , 24 , ? 48 , 63 (a) 30 (b) 32 (c) 35 (d) 36

Last Answer : The numbers in this series are the squares of numbers in natural order minus 1 starting from 2.

In what ratio must a person mix three kinds of dall costing him Rs 12.25,Rs 12.50 and Rs 12.75 per Kg so that the mixture may be worth Rs 12.65 per Kg? a) 11:7:1 b) 22:3:6 c) 14:3:4 d) 2:7:4 e) 3:12:32

Description : In what ratio must a person mix three kinds of dall costing him Rs 12.25,Rs 12.50 and Rs 12.75 per Kg so that the mixture may be worth Rs 12.65 per Kg? a) 11:7:1 b) 22:3:6 c) 14:3:4 d) 2:7:4 e) 3:12:32

Last Answer : E Step1: Mix dall of first and third kind to get a mixture worth Rs 12.25 per Kg. C.P of 1 Kg dall of 1st kind 1225p C.P of 1 Kg dall of 3rd kind 1275p So they must be mixed in the ... So the Mixed ratio = 3:8 Thus the quantities of dall 1st : 2nd : 3rd  = 3:12:32

Is a 65 inch TV too big for my 5 ft. wall?

Description : Is a 65 inch TV too big for my 5 ft. wall?

Last Answer : Yes, there are 12 inches in one foot, which means that your wall is 60 inches wide. The 65 inch TV will be too large to fit on your wall. I would suggest finding a TV that is a bit smaller.

For a homogeneous earth dam 50 m high having 2 m free broad, a flow net was constructed and the results were : Number of potential drops = 2.4 Number of flow channels = 0.4. If co-efficiency of permeability of the dam material is 3 × 10-3 cm3 /sec, the discharge per metre length of dam, is (A) 12 × 10-5 m3 /sec (B) 24 × 10-3 m3 /sec (C) 6 × 10-5 m3 /sec (D) 24 × 10-5 m3 /sec

Description : For a homogeneous earth dam 50 m high having 2 m free broad, a flow net was constructed and the results were : Number of potential drops = 2.4 Number of flow channels = 0.4. If co-efficiency of permeability of the dam material is ... 24 10-3 m3 /sec (C) 6 10-5 m3 /sec (D) 24 10-5 m3 /sec

Last Answer : (D) 24 × 10-5 m3 /sec

How many cubic inches 3 inch diameter pipe 8 ft long?

Description : How many cubic inches 3 inch diameter pipe 8 ft long?

Last Answer : how many cubic inches in a 3 inch diameter pipe 8 ft long

A bullet is fired vertically upwards with a velocity of 2200 ft/s. Bullet ascends to a height of a.56,900 ft b.107 dynes c.75,000 ft d.48.300 ft e.65,800 ft

Description : A bullet is fired vertically upwards with a velocity of 2200 ft/s. Bullet ascends to a height of a.56,900 ft b.107 dynes c.75,000 ft d.48.300 ft e.65,800 ft

Last Answer : c. 75,000 ft

A fluid is pumped at the rate of 10 lb/sec to a height of 55 ft. The horse power required is __________ hp. (A) 1 (B) 10/55 (C) 5.5 (D) 1/55

Description : A fluid is pumped at the rate of 10 lb/sec to a height of 55 ft. The horse power required is __________ hp. (A) 1 (B) 10/55 (C) 5.5 (D) 1/55

Last Answer : (A) 1

A sewer pipe contains 1 mm sand particles of specific gravity 2.65 and 5 mm organic particles of specific gravity 1.2, the minimum velocity required for removing the sewerage, is A. 0.30 m/sec B. 0.35 m/sec C. 0.40 m/sec D. 0.45 m/sec

Description : A sewer pipe contains 1 mm sand particles of specific gravity 2.65 and 5 mm organic particles of specific gravity 1.2, the minimum velocity required for removing the sewerage, is A. 0.30 m/sec B. 0.35 m/sec C. 0.40 m/sec D. 0.45 m/sec

Last Answer : ANS: D

12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Description : 12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Last Answer : 12.28 × 1.5 - 15 = ? 18.42 - 15 = ? ? = 3.42 Answer: e)

Three 12 volt, lead-acid, batteries connected in series will develop __________. A. 12 volts B. 24 volts C. 36 volts D. 48 volts

Description : Three 12 volt, lead-acid, batteries connected in series will develop __________. A. 12 volts B. 24 volts C. 36 volts D. 48 volts

Last Answer : Answer: C

1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62  216:36 Answer: b)

If discharge of a pump is 0.16 cumecs, the economic diameter of pipe, is (A) 0.488 m (B) 4.88 cm (C) 48.8 cm (D) 4.88 m

Description : If discharge of a pump is 0.16 cumecs, the economic diameter of pipe, is  (A) 0.488 m  (B) 4.88 cm  (C) 48.8 cm  (D) 4.88 m 

Last Answer : (A) 0.488 m 

Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Description : Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Last Answer : Answer: C Observer 36/62, 39/63, 43/61, 48/64, ? series Upper part is increase by 3, 4, 5, 6 i.e 36+3= 39, 39+4 = 43, 43+5 = 48, 48 + 6 = 54.

A fluid (µ/ρ) = 0.01 cm2 /sec is moving at critical flow condition (NRe = 2100) through a pipe of dia 3 cms. Velocity of flow is __________ cm/sec. (A) 7 (B) 700 (C) 7000 (D) 630

Description : A fluid (µ/ρ) = 0.01 cm2 /sec is moving at critical flow condition (NRe = 2100) through a pipe of dia 3 cms. Velocity of flow is __________ cm/sec. (A) 7 (B) 700 (C) 7000 (D) 630

Last Answer : (A) 7

Flue gas discharge velocity through chimney of a big thermal power plant may be around __________ m/sec. (A) 0.5 (B) 10 (C) 50 (D) 500

Description : Flue gas discharge velocity through chimney of a big thermal power plant may be around __________ m/sec. (A) 0.5 (B) 10 (C) 50 (D) 500

Last Answer : (B) 10

A particle is of wieght 8 kg. When it is allowed to fall under the force of gravity its momentum at the time t = 2 sec would be a.8 kg sec b.32 kg sec c.2 kg sec d.16 kg sec e.48 kg sec

Description : A particle is of wieght 8 kg. When it is allowed to fall under the force of gravity its momentum at the time t = 2 sec would be a.8 kg sec b.32 kg sec c.2 kg sec d.16 kg sec e.48 kg sec

Last Answer : d. 16 kg sec

For calculation of economical diameter D of a pipe in metres for a discharge Q to be pumped in cumecs, Lea suggested the empirical formula (A) D = 0.22 Q (B) D = 1.22 Q (C) D = 2.22 Q (D) D = 3.22 Q

Description : For calculation of economical diameter D of a pipe in metres for a discharge Q to be pumped in  cumecs, Lea suggested the empirical formula  (A) D = 0.22 Q (B) D = 1.22 Q (C) D = 2.22 Q (D) D = 3.22 Q

Last Answer : (B) D = 1.22 Q

X, Y & Z rent a pasture. X puts 20 cows for 5 months , Y puts 24 cows for 7 months and Z puts 30 cows for 3 months for grazing. If the rent of the pasture is Rs. 150, how much must z pay as his share of rent? A) 32 B) 39.65 C) 37.70 D) 35.20

Description : X, Y & Z rent a pasture. X puts 20 cows for 5 months , Y puts 24 cows for 7 months and Z puts 30 cows for 3 months for grazing. If the rent of the pasture is Rs. 150, how much must z pay as his share of rent? A) 32 B) 39.65 C) 37.70 D) 35.20

Last Answer : Answer: C) X : Y : Z = 20* 5 : 24* 7 : 30 * 3 = 100 : 168 : 90 =50 : 84 : 45 Therefore Z’s rent = Rs (150 * 45 / 179) = Rs.(6750/179) Rs.37.70

Calculate the energy in an electric field with flux density 6 units and field intensity of 4 units. a) 12 b) 24 c) 36 d) 48

Description : Calculate the energy in an electric field with flux density 6 units and field intensity of 4 units. a) 12 b) 24 c) 36 d) 48

Last Answer : a) 12

48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Description : 48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Last Answer : A 1 boy’s 1 day’s work = 1/(36*48) =1/1728 48 boy’s 24 day’s work=48*24/1728=2/3 Remaining work = 1-2/3=1/3 72 boy’s 1 day’s work =72/1728=1/24 1/24 work is done by them in 1 day. So, 1/3 work is done by them in 24/3= 8 days

A number gets reduced to its one-third when 48 is subtracted from it. What is two-third of that number? 1. 22 2. 76 3. 36 4. 48 5. None of these

Description : A number gets reduced to its one-third when 48 is subtracted from it. What is two-third of that number? 1. 22 2. 76 3. 36 4. 48 5. None of these

Last Answer : Answer:- 4 (48) Expalanation – let number be X X-48 = X/3 X-X/3 =48 2/3X= 48 so 2/3th of number=48

A tank can be filled by a tap in 6 hours and emptied by an outlet pipe in 8 hours. How long will it take to fill the cistern if both the taps are opened together? 1. 24 hours 2. 22 hours 3. 21 hours 4. 18 hours 5. 20 hours

Description : A tank can be filled by a tap in 6 hours and emptied by an outlet pipe in 8 hours. How long will it take to fill the cistern if both the taps are opened together? 1. 24 hours 2. 22 hours 3. 21 hours 4. 18 hours 5. 20 hours

Last Answer : 1;

The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Description : The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Last Answer : A:B = 7:8 B:C = 2:3 = 8:12 SO, A:B:C = 7:8:12 C:D = 4:5 = 12:15 A:B:C:D = 7:8:12:15 D:E = 5:7 = 15:21 SO, A:B:C:D:E = 7:8:12:15:21 given x(7+8+12+15+21) = 126 or 63x = 126 or x =2 E – A = 21X – 7X = 14X = 28 Answer: d)

If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec

Description :  If a train crosses a tree in 24 seconds while travelling at a speed of 90km/hr, then in how much time will the train cross a telegraph post of length 1200m at same speed? A) 26 sec B) 48 sec C) 72 sec D) 38 sec 

Last Answer : ANSWER:C Explanation: Speed of the train = 90 km/hr Converting the speed into m/sec 90 km/hr = (90* 5/18)m/s = 25m/s length of the train = distance travelled we know distance = speed * ...  Time = distance / speed  = ( 1800/25) sec  = 72 seconds  Hence the required answer is 72 seconds

1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)

In how many different ways can the letters of the word 'RAPINE' be arranged in such a way that the vowels occupy only the odd positions? A) 32 B) 48 C) 36 D) 60 E) 120

Description : In how many different ways can the letters of the word 'RAPINE' be arranged in such a way that the vowels occupy only the odd positions? A) 32 B) 48 C) 36 D) 60 E) 120

Last Answer : Answer: C)  There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.  Let us mark these positions as under:  (1) (2) (3) (4) (5) (6)  Now, 3 vowels can be placed at ... .  Number of ways of these arrangements = 3P3 = 3! = 6.  Total number of ways = (6 x 6) = 36

Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Description : Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Last Answer : 4 : 64 cm

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

Description : In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

Last Answer : A 14.18rad/sec

A short masonry pillar is 60 cm x 60 cm in cross-section, the core of the pillar is a square whose side is (A) 17.32 cm (B) 14.14 cm (C) 20.00 cm (D) 22.36 cm

Description : A short masonry pillar is 60 cm x 60 cm in cross-section, the core of the pillar is a square whose side is (A) 17.32 cm (B) 14.14 cm (C) 20.00 cm (D) 22.36 cm

Last Answer : (B) 14.14 cm

There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 km/hr while Varun sails on a boat at a speed of about 24km/hr. If the flow of water current is at the speed of 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48

Description : There is a bridge besides a river. Two friends Arun and varun started their journey from place L, moved to the garden located at another place M & then returned to place L. Arun moves by swimming at a speed of 30 ... 12km/hr, what will be the average speed of boat sailor? A) 36 B) 18 C) 24 D) 48 

Last Answer : ANSWER:B Explanation: As Arun swims both the ways at the speed of 30km/hr, the average speed of swimming is 30 km/hr Being a boat sailor, varun moves downstream at speed =24 +12=36km/hr and upstream at speed = 24-12= ... Upstream Speed])] = (36*12)/0.5(36+12) km/hr = 432/24 km/hr = 18 km/hr

Water is flowing through a 1 foot diameter pipe at the rate of 10ft/sec. What is the volume flow rate of water in ft³/sec?  a. 7.85  b. 6.85  c. 8.85  d. 5.85 V = Aν

Description : Water is flowing through a 1 foot diameter pipe at the rate of 10ft/sec. What is the volume flow rate of water in ft³/sec?  a. 7.85  b. 6.85  c. 8.85  d. 5.85 V = Aν

Last Answer : 7.85

I.D. of 1/4" schedule 40 pipe is 0.364". I.D. of a 1/2" schedule 40 pipe would be __________ inch (A) 4.728 (B) 0.5 (C) 0.622 (D) 0.474

Description : I.D. of 1/4" schedule 40 pipe is 0.364". I.D. of a 1/2" schedule 40 pipe would be __________ inch (A) 4.728 (B) 0.5 (C) 0.622 (D) 0.474

Last Answer : (C) 0.622

When horizontal range of a projectile equal to the distance through which projectile will rise, then the angle of projection of the particle will be equal to a.36? b.24? c.48? d.107 dynes e.76?

Description : When horizontal range of a projectile equal to the distance through which projectile will rise, then the angle of projection of the particle will be equal to a.36? b.24? c.48? d.107 dynes e.76?

Last Answer : e. 76?

Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th

Description : Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th

Last Answer : Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they ... 5200 for their work, then find their individual shares.

The first Philippine Agila I will have how many transpoders. A. 36 B. 48 C. 24 D. 12

Description : The first Philippine Agila I will have how many transpoders. A. 36 B. 48 C. 24 D. 12

Last Answer : A. 36

How many transponder channels are realized in the commercial C-band without frequency re-use? A. 24 B. 12 C. 36 D. 48

Description : How many transponder channels are realized in the commercial C-band without frequency re-use? A. 24 B. 12 C. 36 D. 48

Last Answer : B. 12

What is the typical satellite transponder bandwidth? A. 24 MHz B. 500 MHz C. 36 MHz D. 48 MHz

Description : What is the typical satellite transponder bandwidth? A. 24 MHz B. 500 MHz C. 36 MHz D. 48 MHz

Last Answer : C. 36 MHz

Find the work done moving a charge 2C having potential V = 24volts is a) 96 b) 24 c) 36 d) 48

Description : Find the work done moving a charge 2C having potential V = 24volts is a) 96 b) 24 c) 36 d) 48

Last Answer : d) 48

If D = 2xy i + 3yz j + 4xz k, how much flux passes through x = 3 plane for which - 1<y<2 and 0<z<4? a) 12 b) 24 c) 36 d) 48

Description : If D = 2xy i + 3yz j + 4xz k, how much flux passes through x = 3 plane for which - 1

Last Answer : c) 36

On concrete roads, the camber generally provided, is (A) 1 in 20 to 1 in 24 (B) 1 in 30 to 1 in 48 (C) 1 in 36 to 1 in 48 (D) 1 in 60 to 1 in 72

Description : On concrete roads, the camber generally provided, is (A) 1 in 20 to 1 in 24 (B) 1 in 30 to 1 in 48 (C) 1 in 36 to 1 in 48 (D) 1 in 60 to 1 in 72

Last Answer : Answer: Option D

24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Description : 24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Last Answer : 72÷48×8+14 = (72/48) × 8 + 14 = (3/2) × 8 + 14 = 12 +14 = 26 24 + (72 ÷ 48 × 8 + 14) ×36 ÷ (3 × 4) + 36 ÷ 3 × 4 = 24 + 26 × 36÷12 + 36 ÷ 3 × 4 = 24 + 26 × 3 + 12 × 4 = 24 + 78 + 48 = 150 Answer: e)

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr

All electioneering campaigns during the time of elections are stopped. (1) 48 hours before the appointed time of election results (2) 48 hours before the actual poll (3) 24 hours before the actual poll (4) 36 hours before the actual poll

Description : All electioneering campaigns during the time of elections are stopped. (1) 48 hours before the appointed time of election results (2) 48 hours before the actual poll (3) 24 hours before the actual poll (4) 36 hours before the actual poll

Last Answer : (4) 36 hours before the actual poll